true or false: when declaring a function, a given argument can be declared to pass by reference, or can be declared to have a default value, but never both.
i.e., you can only write one of: function foo(&$param) function foo($param = "bar") but never the equivalent of: function foo(&$param = "bar") is there a way to declare an argument with both pass-by-reference and default-value properties? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
