[PHP] mysql_fetch_array() vs mysql_fetch_assoc() WAS: Re: [PHP] Why does this script run out of memory?
On Fri, Oct 28, 2011 at 18:13, Paul Halliday paul.halli...@gmail.com wrote:
Whats the difference between fetch_assoc and fetch_row?
I use:
while ($row = mysql_fetch_row($theQuery)) {
doCartwheel;
}
on just under 300 million rows and nothing craps out. I have
memory_limit set to 4GB though. Although, IIRC I pushed it up for GD
not mysql issues.
Same OS and php ver, MySQL is 5.1.48
Please don't hijack other's threads to ask a question. I've
started this as a new thread to address this question.
mysql_fetch_array() grabs all of the data and places it in a
simple numerically-keyed array.
By contrast, mysql_fetch_assoc() grabs it and populates an
associative array. This means that the column names (or aliases, et
cetera) become the keys for the array. With mysql_fetch_assoc(), you
can still call an array key by number, but it's not vice-versa with
mysql_fetch_array().
The difference in overhead, if you meant that (in which case, my
apologies for reading it as a question of functional difference), is
variable: it's based mainly on the difference between the bytes
representing the integers used as keys in mysql_fetch_array() versus
the size in bytes of the strings used as keys in mysql_fetch_assoc().
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Re: [PHP] mysql_fetch_array() vs mysql_fetch_assoc() WAS: Re: [PHP] Why does this script run out of memory?
On Fri, Oct 28, 2011 at 06:19:56PM -0400, Daniel Brown wrote:
On Fri, Oct 28, 2011 at 18:13, Paul Halliday paul.halli...@gmail.com wrote:
Whats the difference between fetch_assoc and fetch_row?
I use:
while ($row = mysql_fetch_row($theQuery)) {
? ?doCartwheel;
}
on just under 300 million rows and nothing craps out. I have
memory_limit set to 4GB though. Although, IIRC I pushed it up for GD
not mysql issues.
Same OS and php ver, MySQL is 5.1.48
Please don't hijack other's threads to ask a question. I've
started this as a new thread to address this question.
mysql_fetch_array() grabs all of the data and places it in a
simple numerically-keyed array.
By contrast, mysql_fetch_assoc() grabs it and populates an
associative array. This means that the column names (or aliases, et
cetera) become the keys for the array. With mysql_fetch_assoc(), you
can still call an array key by number, but it's not vice-versa with
mysql_fetch_array().
I'm not seeing any numeric keys in my mysql_fetch_assoc() arrays.
However, mysql_fetch_row (by default) does both: the array will be
indexed numerically from 0 to N-1 corresponding to the table's N
columns, and the array will also have string key indices which
correspond to the query's column names. So by default,
mysql_fetch_row uses twice the amount of data, because each field
appears in the array twice.
var_dump( $row ) will show in graphic detail.
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Re: [PHP] mysql_fetch_array() vs mysql_fetch_assoc() WAS: Re: [PHP] Why does this script run out of memory?
On Fri, Oct 28, 2011 at 18:48, Jim Long p...@umpquanet.com wrote: I'm not seeing any numeric keys in my mysql_fetch_assoc() arrays. You're absolutely correct, that's my mistake: substitute mysql_fetch_row() for mysql_fetch_assoc(). Duh. Time to call it a week -- /Daniel P. Brown Network Infrastructure Manager http://www.php.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array
On 11/3/07, Eduardo Vizcarra [EMAIL PROTECTED] wrote:
Hi guys
After doing some changes, I believe it is partially working, what I did is
the following:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$primer_foto = reset($fotos_mostrar[0]); // This is to set the pointer
to
the first record
echo $primer_foto; // This displays the first column when doing a SELECT
However, my SELECT statement retrieves 2 columns from one table, how do I
display the second column ?
Thanks
Eduardo
Since you're pulling 2 columns, why don't you use MYSQL_ASSOC option?
Example...
[code]
$query = SELECT column1, column2 FROM table WHERE (...);
...
while ($row = mysql_fetch_array ($fotos, MYSQL_ASSOC)) {
$fotos_mostrar['col1'][] = $row['column1'];
$fotos_mostrar['col2'][] = $row['column2'];
}
...
// To view the contents of what you just created
echo pre;
print_r ($fotos_mostrar);
echo /pre;
[/code]
By doing it this way, you know exactly what you're storing and where.
Hopefully I didn't muddy things up! ;-)
~Philip
Re: [PHP] mysql_fetch_array
Eduardo Vizcarra wrote:
Hi guys
After doing some changes, I believe it is partially working, what I did is
the following:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$primer_foto = reset($fotos_mostrar[0]); // This is to set the pointer to
the first record
echo $primer_foto; // This displays the first column when doing a SELECT
if you notice you are referring to an index in your array.
You should be doing the reset on $fotos_mostrar like this
reset($fotos_mostrar);
var_dump($fotos_mostrar);
This will display the entire dataset.
also, if you read the first line just above the first example of use,
you will notice that it says that reset will return the first array
element or false.
The reason that you are getting the first column is because in your
reset call, you are referencing the first index entry in your array.
This would return you the first index of the first index in your array.
NO, I did not just repeat myself. re-read what I wrote and think it
through and it will make perfect sense.
So, try what I showed you at the beginning of my comments and you will
see the results you are wanting.
However, my SELECT statement retrieves 2 columns from one table, how do I
display the second column ?
Thanks
Eduardo
Jim Lucas [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
Eduardo Vizcarra wrote:
I have a WHILE sentence to retrieve all records from a SELECT query in a
database and am using mysql_fetch_array to store them in a matrix, the
sentence is like this:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
Regards
how are you checking to see the contents of the $fotos_mostrar array() ?
just after the while loop ends, do a var_dump() or print_r() on the array
and view the contents.
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Re: [PHP] mysql_fetch_array
Do you even need reset()? I've never used it.
On Nov 3, 2007 11:08 PM, Jim Lucas [EMAIL PROTECTED] wrote:
Eduardo Vizcarra wrote:
Hi guys
After doing some changes, I believe it is partially working, what I did is
the following:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$primer_foto = reset($fotos_mostrar[0]); // This is to set the pointer to
the first record
echo $primer_foto; // This displays the first column when doing a SELECT
if you notice you are referring to an index in your array.
You should be doing the reset on $fotos_mostrar like this
reset($fotos_mostrar);
var_dump($fotos_mostrar);
This will display the entire dataset.
also, if you read the first line just above the first example of use,
you will notice that it says that reset will return the first array
element or false.
The reason that you are getting the first column is because in your
reset call, you are referencing the first index entry in your array.
This would return you the first index of the first index in your array.
NO, I did not just repeat myself. re-read what I wrote and think it
through and it will make perfect sense.
So, try what I showed you at the beginning of my comments and you will
see the results you are wanting.
However, my SELECT statement retrieves 2 columns from one table, how do I
display the second column ?
Thanks
Eduardo
Jim Lucas [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
Eduardo Vizcarra wrote:
I have a WHILE sentence to retrieve all records from a SELECT query in a
database and am using mysql_fetch_array to store them in a matrix, the
sentence is like this:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
Regards
how are you checking to see the contents of the $fotos_mostrar array() ?
just after the while loop ends, do a var_dump() or print_r() on the array
and view the contents.
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Re: [PHP] mysql_fetch_array
[EMAIL PROTECTED] wrote: Do you even need reset()? I've never used it. Personally, I do not see the need. The op is building the array then wanting to work with it. At this point, the internal pointer should still be at the beginning. AFAIK Jim -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array
Eduardo Vizcarra wrote:
I have a WHILE sentence to retrieve all records from a SELECT query in a
database and am using mysql_fetch_array to store them in a matrix, the
sentence is like this:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
Regards
how are you checking to see the contents of the $fotos_mostrar array() ?
just after the while loop ends, do a var_dump() or print_r() on the
array and view the contents.
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Re: [PHP] mysql_fetch_array
Hi guys
After doing some changes, I believe it is partially working, what I did is
the following:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$primer_foto = reset($fotos_mostrar[0]); // This is to set the pointer to
the first record
echo $primer_foto; // This displays the first column when doing a SELECT
However, my SELECT statement retrieves 2 columns from one table, how do I
display the second column ?
Thanks
Eduardo
Jim Lucas [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
Eduardo Vizcarra wrote:
I have a WHILE sentence to retrieve all records from a SELECT query in a
database and am using mysql_fetch_array to store them in a matrix, the
sentence is like this:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
Regards
how are you checking to see the contents of the $fotos_mostrar array() ?
just after the while loop ends, do a var_dump() or print_r() on the array
and view the contents.
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[PHP] mysql_fetch_array
I have a WHILE sentence to retrieve all records from a SELECT query in a
database and am using mysql_fetch_array to store them in a matrix, the
sentence is like this:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
Regards
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Re: [PHP] mysql_fetch_array
this is most peculiar. your code should do exactly what you expect. have
you initialized the $fotos_mostrar array before the while loop?
$fotos_mostrar = array();
Eduardo Vizcarra wrote:
I have a WHILE sentence to retrieve all records from a SELECT query in a
database and am using mysql_fetch_array to store them in a matrix, the
sentence is like this:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
Regards
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Re: [PHP] mysql_fetch_array
Yes, matrix has been defined just before this WHILE sentence
Cristian Vrabie [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
this is most peculiar. your code should do exactly what you expect. have
you initialized the $fotos_mostrar array before the while loop?
$fotos_mostrar = array();
Eduardo Vizcarra wrote:
I have a WHILE sentence to retrieve all records from a SELECT query in a
database and am using mysql_fetch_array to store them in a matrix, the
sentence is like this:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
Regards
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Re: [PHP] mysql_fetch_array
On Friday 02 November 2007 18:23:03 Eduardo Vizcarra wrote:
while($row=mysql_fetch_array($fotos))
{
$fotos_mostrar[] = $row;
}
$fotos contains all records found in a db table, the SELECT statement is
retrieving 2 columns from a table, how do I store all records in a 2
dimention table so I can use it later ?
this WHILE sentence seems to only store the last record only
That is peculiar; assuming that your query is properly executed and the code
you're using to display the contents of $fotos_mostrar is written properly.
Can you show us that code?
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[PHP] mysql_fetch_array to associative array
Hello,
I use the following GetArray for returning an array from mysql results.
But having a hard time modifying it for returning a simple associative array
Like:
$conn-GetAssoc('SELECT id, name from manufacturers')
Array ( [2] = BMW [1] = MAZDA [9] = FORD )
function GetArray($query) {
$get = $this-Execute ( $query );
$row_id = 0;
while ( $row = mysql_fetch_array($get) ) {
foreach ( $row as $key = $value )
$result[$row_id][$key] = $value;
$row_id++;
}
mysql_free_result($get);
return $result;
}
function GetAssoc($query) {
$get = $this-Execute ( $query );
$row_id = 0;
while ( $row = mysql_fetch_array($get) ) {
?
}
mysql_free_result($get);
return $result;
}
I searched a lot but didn't find anything.
Thanks for any help :)
Andras
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Re: [PHP] mysql_fetch_array to associative array
On Mon, 2007-07-16 at 07:41 -0700, Andras Kende wrote:
Hello,
I use the following GetArray for returning an array from mysql results.
But having a hard time modifying it for returning a simple associative array
Like:
$conn-GetAssoc('SELECT id, name from manufacturers')
Array ( [2] = BMW [1] = MAZDA [9] = FORD )
function GetArray($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
function GetAssoc($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
I searched a lot but didn't find anything.
Thanks for any help :)
You're welcome.
Cheers,
Rob.
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Re: [PHP] mysql_fetch_array to associative array
On Mon, 2007-07-16 at 10:52 -0400, Robert Cummings wrote:
On Mon, 2007-07-16 at 07:41 -0700, Andras Kende wrote:
Hello,
I use the following GetArray for returning an array from mysql results.
But having a hard time modifying it for returning a simple associative array
Like:
$conn-GetAssoc('SELECT id, name from manufacturers')
Array ( [2] = BMW [1] = MAZDA [9] = FORD )
function GetArray($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
function GetAssoc($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
You should probably use mysql_fetch_assoc() in the above line.
Cheers,
Rob.
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Re: [PHP] mysql_fetch_array to associative array
Andras Kende wrote:
Hello,
I use the following GetArray for returning an array from mysql results.
But having a hard time modifying it for returning a simple associative array
Like:
$conn-GetAssoc('SELECT id, name from manufacturers')
Array ( [2] = BMW [1] = MAZDA [9] = FORD )
function GetArray($query) {
$get = $this-Execute ( $query );
don't you need to check to make sure that $get is a valid resource???
$result = array();
while ( $row = mysql_fetch_array($get) ) {
All of this can be replace with this one line
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
function GetAssoc($query) {
$get = $this-Execute ( $query );
don't you need to check to make sure that $get is a valid resource???
$result = array();
while ( $row = mysql_fetch_assoc($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
I searched a lot but didn't find anything.
Thanks for any help :)
Andras
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Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
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by William Shakespeare
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RE: [PHP] mysql_fetch_array to associative array
-Original Message-
From: Robert Cummings [mailto:[EMAIL PROTECTED]
Sent: Monday, July 16, 2007 7:52 AM
To: Andras Kende
Cc: php-general@lists.php.net
Subject: Re: [PHP] mysql_fetch_array to associative array
On Mon, 2007-07-16 at 07:41 -0700, Andras Kende wrote:
Hello,
I use the following GetArray for returning an array from mysql results.
But having a hard time modifying it for returning a simple associative
array
Like:
$conn-GetAssoc('SELECT id, name from manufacturers')
Array ( [2] = BMW [1] = MAZDA [9] = FORD )
function GetArray($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
function GetAssoc($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
I searched a lot but didn't find anything.
Thanks for any help :)
You're welcome.
Cheers,
Rob.
--
...
SwarmBuy.com - http://www.swarmbuy.com
Leveraging the buying power of the masses!
...
Hi Rob,
Thanks for your help, its associative but I forget to mention its needs
To be a single dimensional associative array.
$result = array();
while ( $row = mysql_fetch_assoc($get) ) {
$result[] = $row;
}
This creates multi dimensional like:
Array ( [0] = Array ( [0] = 3 [1] = BMW ) [1] = Array ( [0] = 1 [1] =
Mercedes ) )
I tried to play with foreach and array_push but still not perfect
Thanks,
Andras
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RE: [PHP] mysql_fetch_array to associative array
On Mon, 2007-07-16 at 13:37 -0700, Andras Kende wrote:
Hi Rob,
Thanks for your help, its associative but I forget to mention its needs
To be a single dimensional associative array.
$result = array();
while ( $row = mysql_fetch_assoc($get) ) {
$result[] = $row;
}
This creates multi dimensional like:
Array ( [0] = Array ( [0] = 3 [1] = BMW ) [1] = Array ( [0] = 1 [1] =
Mercedes ) )
I tried to play with foreach and array_push but still not perfect
I'm not sure I understand... you have multiple rows being returned do
you not? How to you intend to handle them in a single level array?
Let's image the following rows are returned from the database:
array
(
'title' = 'The Dragonbone Chair',
'author' = 'Tad Williams',
),
array
(
'title' = 'Sword of Shannarah',
'author' = 'Terry Brooks',
),
Show me how you would like the final array to look and I can figure out
the code you need to organize it the way you want.
Cheers,
Rob.
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RE: [PHP] mysql_fetch_array to associative array
-Original Message-
From: Robert Cummings [mailto:[EMAIL PROTECTED]
Sent: Monday, July 16, 2007 1:46 PM
To: Andras Kende
Cc: php-general@lists.php.net
Subject: RE: [PHP] mysql_fetch_array to associative array
On Mon, 2007-07-16 at 13:37 -0700, Andras Kende wrote:
Hi Rob,
Thanks for your help, its associative but I forget to mention its needs
To be a single dimensional associative array.
$result = array();
while ( $row = mysql_fetch_assoc($get) ) {
$result[] = $row;
}
This creates multi dimensional like:
Array ( [0] = Array ( [0] = 3 [1] = BMW ) [1] = Array ( [0] = 1 [1]
=
Mercedes ) )
I tried to play with foreach and array_push but still not perfect
I'm not sure I understand... you have multiple rows being returned do
you not? How to you intend to handle them in a single level array?
Let's image the following rows are returned from the database:
array
(
'title' = 'The Dragonbone Chair',
'author' = 'Tad Williams',
),
array
(
'title' = 'Sword of Shannarah',
'author' = 'Terry Brooks',
),
Show me how you would like the final array to look and I can figure out
the code you need to organize it the way you want.
Cheers,
Rob.
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...
SwarmBuy.com - http://www.swarmbuy.com
Leveraging the buying power of the masses!
...
Hi Rob,
$conn-getassoc(select id,name from cars)
I would need a single array like: (its for used with pear:quickform
dropdown)
Array ( [2] = BMW [1] = FORD )
Or:
Array ( [The Dragonbone Chair] = 'Tad Williams' [Sword of Shannarah] =
'Terry Brooks' )
Thanks a lot,
Andras
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RE: [PHP] mysql_fetch_array to associative array
On Mon, 2007-07-16 at 13:37 -0700, Andras Kende wrote:
function GetAssoc($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
I'll focus on the above one since that's probably what's causing your
grief... I'm also going to rename it so it's more explanatory:
?php
function GetPairs( $query, $keyField, $valueField )
{
$pairs = array();
if( ($get = $this-Execute ( $query )) )
{
while( ($row = mysql_fetch_assoc( $get )) )
{
$pairs[$row[$keyField]] = $row[$valueField];
}
mysql_free_result( $get );
}
return $pairs;
}
?
That's the function... it creates an array of pair mappings based on the
table fields $keyField and $valueField. So let's say you have the
following table in your database:
CREATE TABLE cars
(
id int not null auto_increment,
namevarchar( 32 ) not null,
primary key( id )
);
Then you might issue the following function call:
?php
$query = SELECT id, name FROM cars ORDER BY name ASC ;
$pairs = GetPairs( $query, 'id', 'name' );
?
Cheers,
Rob.
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RE: [PHP] mysql_fetch_array to associative array
-Original Message-
From: Robert Cummings [mailto:[EMAIL PROTECTED]
Sent: Monday, July 16, 2007 6:12 PM
To: Andras Kende
Cc: php-general@lists.php.net
Subject: RE: [PHP] mysql_fetch_array to associative array
On Mon, 2007-07-16 at 13:37 -0700, Andras Kende wrote:
function GetAssoc($query) {
$get = $this-Execute ( $query );
$result = array();
while ( $row = mysql_fetch_array($get) ) {
$result[] = $row;
}
mysql_free_result($get);
return $result;
}
I'll focus on the above one since that's probably what's causing your
grief... I'm also going to rename it so it's more explanatory:
?php
function GetPairs( $query, $keyField, $valueField )
{
$pairs = array();
if( ($get = $this-Execute ( $query )) )
{
while( ($row = mysql_fetch_assoc( $get )) )
{
$pairs[$row[$keyField]] = $row[$valueField];
}
mysql_free_result( $get );
}
return $pairs;
}
?
That's the function... it creates an array of pair mappings based on the
table fields $keyField and $valueField. So let's say you have the
following table in your database:
CREATE TABLE cars
(
id int not null auto_increment,
namevarchar( 32 ) not null,
primary key( id )
);
Then you might issue the following function call:
?php
$query = SELECT id, name FROM cars ORDER BY name ASC ;
$pairs = GetPairs( $query, 'id', 'name' );
?
Cheers,
Rob.
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Rob,
THANKS
I also hacked together a version:
while ( $row = mysql_fetch_array($get) ) {
$result[$row[0]] = $row[1];
}
Best regards,
Andras
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Re: [PHP] mysql_fetch_array()
--- Anthony Ritter [EMAIL PROTECTED] wrote: When using mysql_fetch_array() is it necsessary to specify the second argument - meaning the constant of MYSQL_NUM or MYSQL_ASSOC? Whenever you have a question about a function, you can look it up using a URL formatted as follows: http://www.php.net/mysql_fetch_array Here, you will see: The optional second argument result_type in mysql_fetch_array() is a constant and can take the following values: MYSQL_ASSOC, MYSQL_NUM, and MYSQL_BOTH. This feature was added in PHP 3.0.7. MYSQL_BOTH is the default for this argument. By using MYSQL_BOTH, you'll get an array with both associative and number indices. Using MYSQL_ASSOC, you only get associative indices (as mysql_fetch_assoc() works), using MYSQL_NUM, you only get number indices (as mysql_fetch_row() works). Hope that helps. Chris = Chris Shiflett - http://shiflett.org/ PHP Security - O'Reilly Coming Fall 2004 HTTP Developer's Handbook - Sams http://httphandbook.org/ PHP Community Site http://phpcommunity.org/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array()
Thank you Chris.
My question was the call to
mysql_fetch_array()
will also return a result set without the additional argument constant as
in:
while ($row = mysql_fetch_array($sql))
{...
// no constant is being used
There are many times that I see that used in textbooks - without the
constant - just the variable from the sql query as the argument.
TR
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Re: [PHP] mysql_fetch_array()
--- Anthony Ritter [EMAIL PROTECTED] wrote:
My question was the call to
mysql_fetch_array()
will also return a result set without the additional argument
constant as in:
while ($row = mysql_fetch_array($sql))
{...
// no constant is being used
There are many times that I see that used in textbooks - without
the constant - just the variable from the sql query as the
argument.
This is what I was talking about, too. That optional argument is described
on the man page in the part I quoted.
If you don't put it, you get both the associative and enumerated arrays.
If you only want one or the other, you can use that optional second
parameter or the separate functions.
Chris
=
Chris Shiflett - http://shiflett.org/
PHP Security - O'Reilly
Coming Fall 2004
HTTP Developer's Handbook - Sams
http://httphandbook.org/
PHP Community Site
http://phpcommunity.org/
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[PHP] mysql_fetch_array()
When using mysql_fetch_array() is it necsessary to specify the second argument - meaning the constant of MYSQL_NUM or MYSQL_ASSOC? I have seen many examples where it is left out and it is coded: $row = mysql_fetch_array($sql); as opposed to $row = mysql_fetch_array($sql, MYSQL_BOTH); Thank you. TR -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array()
Anthony Ritter wrote: When using mysql_fetch_array() is it necsessary to specify the second argument - meaning the constant of MYSQL_NUM or MYSQL_ASSOC? I have seen many examples where it is left out and it is coded: $row = mysql_fetch_array($sql); as opposed to $row = mysql_fetch_array($sql, MYSQL_BOTH); Note that you can use mysql_fetch_row for the equiv. of MYSQL_NUM and mysql_fetch_assoc() for the equiv. of MYSQL_ASSOC. It's sort of a waste of resources to use mysql_fetch_array() when you really only use one or the other, but a lot of people do it. -- ---John Holmes... Amazon Wishlist: www.amazon.com/o/registry/3BEXC84AB3A5E/ php|architect: The Magazine for PHP Professionals www.phparch.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array problem? O.o
Jeff Ostapchuk wrote: Ok, I have no clue what version of PHP I have installed, 4.??.??, and I have like the newest version of MySQL insatlled, and PHP and MySQL work fine together, excpet when I use mysql_fetch_row($query) then I have problems, mysql_fetch_array($query) works fine, but not mysql_fetch_row($query). Why doesn't it work? I tried installing the new PHP 5 version, but when i extracted it from the zip file into the C:\PHP folder and then PHP didn't even work at all (so... u can kinda tell i'm a still a noobie at this ^.^;;; ) Thank in advance to whoever. mysql_fetch_row() will return false if you are already on the last row in your result set. You also need to pass both mysql_fetch_array() and mysql_fetch_row() the resource id from a successful mysql_query() call. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql_fetch_array problem? O.o
Ok, I have no clue what version of PHP I have installed, 4.??.??, and I have like the newest version of MySQL insatlled, and PHP and MySQL work fine together, excpet when I use mysql_fetch_row($query) then I have problems, mysql_fetch_array($query) works fine, but not mysql_fetch_row($query). Why doesn't it work? I tried installing the new PHP 5 version, but when i extracted it from the zip file into the C:\PHP folder and then PHP didn't even work at all (so... u can kinda tell i'm a still a noobie at this ^.^;;; ) Thank in advance to whoever. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array problem? O.o
Hello Jeff, Thursday, April 15, 2004, 3:18:53 AM, you wrote: JO Ok, I have no clue what version of PHP I have installed, 4.??.??, and I have Find out: ? echo phpinfo(); ? (view it in a browser) JO like the newest version of MySQL insatlled, and PHP and MySQL work fine JO together, excpet when I use mysql_fetch_row($query) then I have problems, What error does it give you? What actually happens? Post some of your code perhaps? More info needed, mysql_fetch_row certainly works so whatever the cause, it's AYE (at your end). -- Best regards, Richard Davey http://www.phpcommunity.org/wiki/296.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql_fetch_array
I have this query to select the date from my table... SELECT DATE_FORMAT(date1, '%W %M %Y') FROM table How do I know what name mysql_fetch_array assigned to the date_format ?
Re: [PHP] mysql_fetch_array
It would be position 0 in the array, or in your query after the date format function you could put AS blah and then it would come out as blah. On Fri, 2004-03-26 at 13:50, Chris Mach wrote: I have this query to select the date from my table... SELECT DATE_FORMAT(date1, '%W %M %Y') FROM table How do I know what name mysql_fetch_array assigned to the date_format ? -- Adam Voigt [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array
From: Adam Voigt [EMAIL PROTECTED] On Fri, 2004-03-26 at 13:50, Chris Mach wrote: I have this query to select the date from my table... SELECT DATE_FORMAT(date1, '%W %M %Y') FROM table How do I know what name mysql_fetch_array assigned to the date_format ? It would be position 0 in the array, or in your query after the date format function you could put AS blah and then it would come out as blah. Or you could use $row['DATE_FORMAT(date1, \'%W %M %Y\')'], but... umm.. yeah ;) ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array
Hi, Saturday, March 27, 2004, 4:50:27 AM, you wrote: CM I have this query to select the date from my table... CM SELECT DATE_FORMAT(date1, '%W %M %Y') FROM table CM How do I know what name mysql_fetch_array assigned to the date_format ? SELECT DATE_FORMAT(date1, '%W %M %Y') AS date_formatted FROM table Then access it as date_formatted -- regards, Tom -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql_fetch_array() not working as expected
Hey peeps. Let me make this simple. I've got the following sql query in a function: SELECT c.id , cc.id , cc.prod_id , p.name , cc.price , cc.qty FROM cart AS c INNER JOIN cart_contents AS cc ON cc.cart_id = c.id INNER JOIN products AS p ON p.id = cc.prod_id WHERE c.cust_id = '6' ORDER BY cc.id When I get the result and turn it into an array with mysql_fetch_array($var, MYSQL_BOTH) I see the following with print_r(): Array ( [0] = Array ( [0] = 2 [id] = 3 [1] = 3 [2] = SDG6004-XX-XXX [prod_id] = SDG6004-XX-XXX [3] = Model 6004 [name] = Model 6004 [4] = 89.00 [price] = 89.00 [5] = 2 [qty] = 2 ) ) Notice that index 1 does not have a textual companion like the other indexes do. I expected the array to be created like this: Array ( [0] = Array ( [0] = 2 [c.id] = 3 [1] = 3 [cc.id] = 3 [2] = SDG6004-XX-XXX [cc.prod_id] = SDG6004-XX-XXX [3] = Model 6004 [p.name] = Model 6004 [4] = 89.00 [cc.price] = 89.00 [5] = 2 [cc.qty] = 2 ) ) But alas... that's not how it works. Anyway to get what I want? Thanks, Chris. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array() not working as expected
Chris W. Parker wrote: Hey peeps. Let me make this simple. I've got the following sql query in a function: SELECT c.id , cc.id , cc.prod_id , p.name , cc.price , cc.qty FROM cart AS c INNER JOIN cart_contents AS cc ON cc.cart_id = c.id INNER JOIN products AS p ON p.id = cc.prod_id WHERE c.cust_id = '6' ORDER BY cc.id When I get the result and turn it into an array with mysql_fetch_array($var, MYSQL_BOTH) I see the following with print_r(): Array ( [0] = Array ( [0] = 2 [id] = 3 [1] = 3 [2] = SDG6004-XX-XXX [prod_id] = SDG6004-XX-XXX [3] = Model 6004 [name] = Model 6004 [4] = 89.00 [price] = 89.00 [5] = 2 [qty] = 2 ) ) Notice that index 1 does not have a textual companion like the other indexes do. I expected the array to be created like this: Array ( [0] = Array ( [0] = 2 [c.id] = 3 [1] = 3 [cc.id] = 3 [2] = SDG6004-XX-XXX [cc.prod_id] = SDG6004-XX-XXX [3] = Model 6004 [p.name] = Model 6004 [4] = 89.00 [cc.price] = 89.00 [5] = 2 [cc.qty] = 2 ) ) But alas... that's not how it works. Anyway to get what I want? Thanks, Chris. As you can see only column names create indexes, not table_name dot column_name. And thus your second id (cc.id) overwrites the first one (c.id) You can make the query: SELECT c.id , cc.id AS ccid , cc.prod_id , p.name and you will get $row['id'] and $row['ccid'] Marek -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] mysql_fetch_array() not working as expected
Marek Kilimajer mailto:[EMAIL PROTECTED] on Tuesday, October 07, 2003 12:26 PM said: (c.id) You can make the query: SELECT c.id , cc.id AS ccid , cc.prod_id , p.name doh! how obvious! thanks. c. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql_fetch_array(): supplied argument is not a valid MySQL result resource
I'm trying to make a PHP script that automaticly makes a link on the side
menu to the id page that was just made, under certain catagories. But I
edited my code to cleen up soem errors and all of a sudden 3 errors came up,
and I haven't been able to fix them! They are:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in C:\Inetpub\wwwroot\main\menu.php on line 29
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in C:\Inetpub\wwwroot\main\menu.php on line 41
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in C:\Inetpub\wwwroot\main\cat.php on line 39
The code for the menu and cat *.php files are below:
menu.php:
HTML
HEAD
link href=/css/base.css rel=STYLESHEET type=text/css
/HEAD
BODY
TABLE width=100% cellPadding=0 cellSpacing=0
TR
TD width=150 vAlign=top
?php
$register_globals;
$db = mysql_connect(localhost,root);
mysql_select_db(common,$db);
$result = mysql_query(SELECT * FROM main,$db);
echo centerMain/centerbr;
while ($row1 = mysql_fetch_array($result)) {
if ($row1[cat] == 1) {
printf(a href=\pages.php?cat=1id=%s\%s/abr,
$row1[id], $row1[title]);
}
}
echo centerMisc./centerbr;
while ($row1 = mysql_fetch_array($result)) {
if ($row1[cat] == 2) {
printf(a href=\pages.php?cat=2id=%s\%s/abr,
$row1[id], $row1[title]);
}
}
?
/TD
TD
cat.php:
?php
if ($submit) {
if ($id) {
$sql = UPDATE main SET content='$content', title='$title' cat='$cat'
WHERE id=$id;
} else {
$sql = INSERT INTO main (content,title,cat) VALUES
('$content','$title','$cat');
}
$result = mysql_query($sql);
echo Record updated/edited!pReturn to A
href=\pages.php?cat=$catid=$id\Index/a.;
} elseif ($delete == areyousure) {
$sql = SELECT * FROM main WHERE id=$id;
$result = mysql_query($sql);
echo Are you sure you want to delete $title?pa
href=\$PHP_SELF?cat=$catid=$iddelete=true\Yes/a | a
href=\$PHP_SELF\No/a;
} elseif ($delete == true) {
$sql = DELETE FROM main WHERE id=$id;
$result = mysql_query($sql);
echo $title Record deleted!pa
href=\$PHP_SELF?cat=$catid=$cat\Return/a;
} else {
$result = mysql_query(SELECT * FROM main,$db);
while ($row = mysql_fetch_array($result)) {
if ($id == $row[id] $cat == $row[cat]) {
printf(centerfont size=5%s/font/centerbrbr,
$row[title]);
printf(%sbrbr, $row[content]);
printf(a
href=\$PHP_SELF?cat=$catid=%sdelete=areyousure\(DELETE)/abr,
$row[id]);
printf(a
href=\$PHP_SELF?cat=$catid=%sedit_add=$cat\(EDIT)/abr,
$row[id]);
}
}
echo Pa href=\$PHP_SELF?cat=$catedit_add=$cat\ADD A
RECORD/aP;
}
?
?php
if ($edit_add) {
?
form method=post action=pages.php?cat=?php echo $cat ?
?php
if ($id) {
$sql = SELECT * FROM main WHERE id=$id;
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
$id = $row[id];
$title = $row[title];
$cat = $row[cat];
$content = $row[content];
?
input type=hidden name=id value=?php echo $id ?
?php
}
?
TABLE cellPadding=0 cellSpacing=0 border=0
TR
TDTitle:/TD
TDinput type=Text name=title value=?php echo $title ?/TD
TD rowSpan=2 vAlign=Top
TABLE border=0 cellPadding=0 cellSpacing=0
?php
$result = mysql_query(SELECT * FROM cat,$db);
while ($cat = mysql_fetch_array($result)) {
printf(TRTD%s/TDTDinput type=\radio\ name=\cat\
value=\%s\/TD/TR, $cat[name], $cat[id]);
}
?/TD/TR/TABLE/TD/TR
TR
TDMessage:/TD
TD rowSpan=3textarea name=content rows=7 cols=40
wrap=virtual?php echo $content ?/TEXTAREA/TD/TR/TABLE
input type=Submit name=submit value=Enter information
/form
?php
}
?
Anny help would be highly appreciated!
Thank You for your time.
-Ben
Re: [PHP] mysql_fetch_array(): supplied argument is not a validMySQL result resource
It has to do with you assuming everything will work 100% of the time. It won't. mysql_query() returns false on failure, check for that. Read this recent thread: http://marc.theaimsgroup.com/?l=php-generalm=105517588819420 Also, this faq explains it: http://www.php.net/manual/en/faq.databases.php#faq.databases.mysqlresource Btw, what do you expect: $register_globals; to do in your code? It won't do anything useful. Regards, Philip -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql_fetch_array problem
hi everyone! i'm new here (and new to php) and have a question. i'm trying
to run a simple blogger type script but am running into a problem i can't
seem to troubleshoot. first, the three items i put into the database aren't
showing up on my page and then when i try to go to the archive for the
month, i get the following:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in /home/blar/public_html/inc/main_inc.php on line 11
here's a part of my code of main_inc (first line is line 11):
function showPosts($result,$page)
{
if ($myrow = mysql_fetch_array($result))
{
do
{
$rawdate = $myrow[postDate];
$formdate = date(l, F j, Y,
(strtotime(ereg_replace('([0-9]*)-([0-9]*)-([0-9]*)','\2/\3/\1',
$rawdate;
if ($date != $formdate)
{
$date = $formdate;
?
!-- Formatting for date --
b?=$formdate;?/bbr
nbsp;br
?
}
if ($page == 1)
{
showArchivePost($myrow);
}
else
{
showMainPost($myrow);
}
}
while ($myrow = mysql_fetch_array($result));
}
}
/code
thank in advance for any help. :)
jonni b.
http://blar.org
http://uglypropaganda.com
Re: [PHP] mysql_fetch_array errors
A key to understanding your mysql errors is by using
the mysql_error() function. It's wonderful! Here's
a simple example with a little error checking:
?php
error_reporting(E_ALL);
$conn = mysql_connect('host','user','pass');
if (!$conn) {
print Could not connect to mysql : . mysql_error();
exit;
}
mysql_select_db('dbname');
$sql = SELECT foo,bar FROM blah;
$result = mysql_query($sql);
// mysql_query returns false on failure.
if (!$result) {
print Could not query DB ($sql) : . mysql_error();
exit;
}
while($row = mysql_fetch_assoc($result)) {
extract($row);
print Hello $foo, I like $bar too\n;
}
?
Regards,
Philip Olson
On Sun, 19 May 2002, Justin Latham wrote:
I am trying to clone my webserver because I am switching ISPs. So I copied
the MySQL database, and then I copied the php pages. But my new server
insists that any query I do is not a valid result resource when I try to use
it in a mysql_fetch_array command. I know that both php and the database
are functional (to an extent) because all other commands work.
I'm using PHP 4.something over MySQL 3.2.3 running RedHat 7.0.
Thanks
Justin
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[PHP] mysql_fetch_array errors
I am trying to clone my webserver because I am switching ISPs. So I copied the MySQL database, and then I copied the php pages. But my new server insists that any query I do is not a valid result resource when I try to use it in a mysql_fetch_array command. I know that both php and the database are functional (to an extent) because all other commands work. I'm using PHP 4.something over MySQL 3.2.3 running RedHat 7.0. Thanks Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array errors
At 9:38 PM -0400 19/5/02, Justin Latham wrote: insists that any query I do is not a valid result resource when I try to use it in a mysql_fetch_array command. I know that both php and the database So what errors are being returned by all the mysql_* calls? Error messages are their to help the programmer find problems... not as an annoyance to be turned off and/or ignored. ...R. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mysql_fetch_array()
Hi All, I am new to PHP and am having a bit of trouble. I have a recordset using... $events = mysql_fetch_array($recordset); this drags in 3 columns from my table... event_id, event_title, event_date I want to search the recordset for a given date, if found I want to be able to reference event_id event_title from the row. I am using PHP 4.01. TIA Phil Ewington. --- P.S. If there are any ColdFusion developers on this list, what is the PHP equivalent of a structure? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql_fetch_array()
$db = mysql_open();
$results = mysql_query( select * from something, $db );
while( $row = mysql_fetch_array( $results ) ) {
processing using $row[column] as reference
}
Ben
At 11:21 05/04/2002, Phil Ewington wrote:
Hi All,
I am new to PHP and am having a bit of trouble. I have a recordset using...
$events = mysql_fetch_array($recordset);
this drags in 3 columns from my table...
event_id, event_title, event_date
I want to search the recordset for a given date, if found I want to be able
to reference event_id event_title from the row. I am using PHP 4.01.
TIA
Phil Ewington.
---
P.S. If there are any ColdFusion developers on this list, what is the PHP
equivalent of a structure?
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RE: [PHP] mysql_fetch_array()
Jason,
This is for an events calendar, I want all the dates form the db but when I
am generating the individual days for the calendar I need to know whether
there is an event for that day, hence pulling out all the dates from the db.
As I am looping through all the days in a month to dynamically create the
calendar, I do not want to loop through the entire recordset to look for a
date for that day in each iteration. Does your method find any row in the
recordset with a given date?
I am at present exploring the possibility of creating individual arrays for
each row in the recordset using the date as the name of the array, then
testing to see if it exists. That way I can check for the existence of a
given date at any point in my code and reference the associated values
without looping through the recordset each time. My code is as follows...
while ($row = mysql_fetch_assoc($events)) {
$a = date_ . $row[event_date];
$$a = array($row[event_id], $row[event_title]);
}
if ($date_2002-04-15) { do_something(); }
Any comments will be greatfully received.
Phil.
-Original Message-
From: Jason Wong [mailto:[EMAIL PROTECTED]]
Sent: 05 April 2002 11:31
To: [EMAIL PROTECTED]
Subject: Re: [PHP] mysql_fetch_array()
On Friday 05 April 2002 18:21, you wrote:
Hi All,
I am new to PHP and am having a bit of trouble. I have a
recordset using...
$events = mysql_fetch_array($recordset);
this drags in 3 columns from my table...
event_id, event_title, event_date
I want to search the recordset for a given date, if found I
want to be able
to reference event_id event_title from the row. I am using PHP 4.01.
Shouldn't you be doing your searching and selecting from within
your mysql
query?
But if you insist on doing it in PHP then:
if ($events['event_date'] == whatever) {
do_something();
}
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
/*
You will engage in a profitable business activity.
*/
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RE: [PHP] mysql_fetch_array()
At 05.04.2002 12:31, you wrote:
Jason,
This is for an events calendar, I want all the dates form the db but when I
am generating the individual days for the calendar I need to know whether
there is an event for that day, hence pulling out all the dates from the db.
As I am looping through all the days in a month to dynamically create the
calendar, I do not want to loop through the entire recordset to look for a
date for that day in each iteration. Does your method find any row in the
recordset with a given date?
As I understand your problem, I would suggest, that you just select the days
in the month, where there are events
f.e. select count(ref#) from DB where date 'inside your scope' and events
'are there events'
this gives you the number of lines.
If there are any, you could ask more detailed, using the informations stored.
If there are no events, make the calendar as normal.
Thats also a good explanation for the column ref# (autoincrement, unique)
Even you only have to deal with one select, and can order your result, so
that it makes
you no pain showing them
I am at present exploring the possibility of creating individual arrays for
each row in the recordset using the date as the name of the array, then
testing to see if it exists. That way I can check for the existence of a
given date at any point in my code and reference the associated values
without looping through the recordset each time. My code is as follows...
while ($row = mysql_fetch_assoc($events)) {
$a = date_ . $row[event_date];
$$a = array($row[event_id], $row[event_title]);
}
Here the select could be
Assuming you have the DB´s 'event_ref ' where 'event date' and 'event
reference number' put in
and 'event_content' where other useful informations are stored
selct a.event_title, from event_ref a, event_content b where b.ref = a.ref
and a.date='2002-04-15'
No dealing with arrays and var_vars, just straight sql.
HTH Oliver
if ($date_2002-04-15) { do_something(); }
Any comments will be greatfully received.
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RE: [PHP] mysql_fetch_array()
On Fri, 5 Apr 2002, Phil Ewington wrote:
This is for an events calendar, I want all the dates form the db but when I
am generating the individual days for the calendar I need to know whether
there is an event for that day, hence pulling out all the dates from the db.
As I am looping through all the days in a month to dynamically create the
calendar, I do not want to loop through the entire recordset to look for a
date for that day in each iteration.
That sounds like a lot of work (both for you and for the server). Assuming
you want to draw a monthly calendar where each day appears whether or not
it holds any events (it's even easier if you don't need that)...
Just make sure the database returns your results in date order.
SELECT eventtitle, eventdate FROM event WHERE eventdate='2002-03-01'
AND eventdate'2002-04-01' ORDER BY eventdate
Then loop through the days and draw any events that happen to occur on
each day as you get to it:
$row = mysql_fetch_assoc($sql);
for ($day = 1; $day = $num_days_in_month; $day++)
{
print h3$day/h3;
while ($row (date('j', strtotime($row['eventdate'])) == $day))
{
print p{$row['eventtitle']}/p;
$row = mysql_fetch_assoc($sql);
}
}
miguel
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Re: [PHP] mysql_fetch_array
you can also do $queryString = select table1.uid as 'my_uid' , table2.uid as 'their_uid' from table1, table2 where ... ; Greg Sidelinger wrote: Subject: [PHP] mysql_fetch_array From: Greg Sidelinger [EMAIL PROTECTED] Date: Sun, 30 Dec 2001 18:44:44 -0500 To: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Ok I have use mysql_fetch_array to dump the results of a select query with a join in it. if my tables contain a column with the same name how can I distinguish from them. I'm used to table_name.value method in other languages but when I tried $row['table_name.value'] I don't get any values. can anyone point me in the right direction. -- Vincent Stoessel [EMAIL PROTECTED] Java Linux Apache Mysql Php (JLAMP) Engineer (301) 362-1750 Mobile (410) 419-8588 AIM, MSN: xaymaca2020 , Yahoo Messenger: vks_jamaica -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] mysql_fetch_array
Ok I have use mysql_fetch_array to dump the results of a select query with a join in it. if my tables contain a column with the same name how can I distinguish from them. I'm used to table_name.value method in other languages but when I tried $row['table_name.value'] I don't get any values. can anyone point me in the right direction. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] mysql_fetch_array
If everything else fails, you should consider using mysql_fetch_row() instead. Bogdan Greg Sidelinger wrote: Ok I have use mysql_fetch_array to dump the results of a select query with a join in it. if my tables contain a column with the same name how can I distinguish from them. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] mysql_fetch_array
Hi, In your SQL, you can say select t1.col colt1, t2.col colt2 from table1 t1, table2 t2 where t1.something = t2.samething In other words, you can name your columns differently in your select clause. I Bogdan Stancescu [EMAIL PROTECTED] wrote: If everything else fails, you should consider using mysql_fetch_row() instead. Bogdan Greg Sidelinger wrote: Ok I have use mysql_fetch_array to dump the results of a select query with a join in it. if my tables contain a column with the same name how can I distinguish from them. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] Mehmet Erisen http://www.erisen.com - Do You Yahoo!? Send your FREE holiday greetings online at Yahoo! Greetings.
Re: [PHP] mysql_fetch_array() doesn't work
echo a href='$PHP_SELF?offset=$i*$step' target='_top'
Missing end quote and semicolon on this line may be the reason...
Try properly indenting and formatting your code. Also take advantage of
going in and out of php mode to seperate your code from your display of
content...
Ex:
instead of this:
? echo(td align=\center\ width=\$nWidth\$sContent/td); ?
Try this:
td align=center width=? echo($nWidth); ?? echo($sContent); ?/td
Or even this:
td align=center width=?=$nWidth??=$sContent?/td
It makes it MUCH easier to read and maintain, and seperates the PHP code
from the HTML content as much as possible.
Any questions, please ask me.
-Jason Garber
Lead Programmer - www.pulseaday.com
[EMAIL PROTECTED]
---
At 12:48 PM 9/27/2001 +0800, you wrote:
System: PHP4.06 + Mysql3.23.41 Win32 + Apache 1.3.20 Win32 + Win98
When PHP is running at the line: $arr=mysql_fetch_array($res);
The IE always show info as below:
Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING' in c:\program files\apache
group\apache\htdocs\web\site1\list.php on line --[the number of line]
What's the problem wiht mysql_fetch_array() or other?
What does the T_STRING' or `T_VARIABLE' or `T_NUM_STRING' mean?
THANKS
Mike
The full code below:
?
$link=mysql_connect(localhost,,);
if($link==false){
echo Failed linking to database.;
exit();
}
$handler=mysql_select_db(database1);
if($handler==false)
echo Failed linking to database.;
$query=selct count(*) from users where sign=1;
$res=mysql_query($query);
$row=mysql_fetch_row($res);
$all=$row[0];
$step=5;
$pages=ceil($all/$step); /*the number of pages needed to listed */
if(empty($offset))
$offset=0;
$query=select user_id, user_name, time, status, comment from users
where sign=1
order by user_name
limit $offset, $step;
$res=mysql_query($query);
echo tabletd align=centerUser/td
td align=centerAdded time/tdtd align=centerStatus/td/tr;
$num=mysql_num_rows($res);
for($i=0; $i$num; $i++) {
$arr=mysql_fetch_array($res); /* HERE is line where the error occurs!!!
*/
echo trtd align=centera href=\profile.php?id=$arr['user_id']\
target='_top'
$arr['user_name']/a/td;
echo td align=center$arr['time']/td;
echo td align=center$arr['status']/td/tr;
echo tr colspan=3td$arr['comment']/td/tr;
}
echo /tablebrbrbr;
echo tabletrtd align='center'; /* show others in multi-pages */
for($i=0; $i$pages; $i++){
echo a href='$PHP_SELF?offset=$i*$step' target='_top'
echo ($i+1)./a;
echo nbsp;nbsp;;
}
echo /td/tr/table;
?
-
create table users (
user_id int not null auto_increment primary key,
user_name varchar(30),
time datetime,
status tinyint(1),
comment text,
sign tinyint(1) default '1'
);
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Re: [PHP] mysql_fetch_array() doesn't work
Hi Mike,
The query
$query=selct count(*) from users where sign=1;
should be select not selct
-and in future to know if there is any error in your queries you might want to check
this way:
if(mysql_query($query)
{
--do statements--
}
else
-error msg-
or even the following would be a convenient way to get your recordset and check for
invalid query.
just try this
$result = mysql_query (SELECT my_col FROM my_tbl)
or die (Invalid query);
IN YOUR CASE try:
$res=mysql_query($query) or die (Invalid query);
and let me know if you still have a problem.
-Naintara
- Original Message -
From: Web user [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, September 27, 2001 10:18 AM
Subject: [PHP] mysql_fetch_array() doesn't work
System: PHP4.06 + Mysql3.23.41 Win32 + Apache 1.3.20 Win32 + Win98
When PHP is running at the line: $arr=mysql_fetch_array($res);
The IE always show info as below:
Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING' in c:\program files\apache
group\apache\htdocs\web\site1\list.php on line --[the number of line]
What's the problem wiht mysql_fetch_array() or other?
What does the T_STRING' or `T_VARIABLE' or `T_NUM_STRING' mean?
THANKS
Mike
The full code below:
?
$link=mysql_connect(localhost,,);
if($link==false){
echo Failed linking to database.;
exit();
}
$handler=mysql_select_db(database1);
if($handler==false)
echo Failed linking to database.;
$query=selct count(*) from users where sign=1;
$res=mysql_query($query);
$row=mysql_fetch_row($res);
$all=$row[0];
$step=5;
$pages=ceil($all/$step); /*the number of pages needed to listed */
if(empty($offset))
$offset=0;
$query=select user_id, user_name, time, status, comment from users
where sign=1
order by user_name
limit $offset, $step;
$res=mysql_query($query);
echo tabletd align=centerUser/td
td align=centerAdded time/tdtd align=centerStatus/td/tr;
$num=mysql_num_rows($res);
for($i=0; $i$num; $i++) {
$arr=mysql_fetch_array($res); /* HERE is line where the error occurs!!!
*/
echo trtd align=centera href=\profile.php?id=$arr['user_id']\
target='_top'
$arr['user_name']/a/td;
echo td align=center$arr['time']/td;
echo td align=center$arr['status']/td/tr;
echo tr colspan=3td$arr['comment']/td/tr;
}
echo /tablebrbrbr;
echo tabletrtd align='center'; /* show others in multi-pages */
for($i=0; $i$pages; $i++){
echo a href='$PHP_SELF?offset=$i*$step' target='_top'
echo ($i+1)./a;
echo nbsp;nbsp;;
}
echo /td/tr/table;
?
-
create table users (
user_id int not null auto_increment primary key,
user_name varchar(30),
time datetime,
status tinyint(1),
comment text,
sign tinyint(1) default '1'
);
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[PHP] mysql_fetch_array() doesn't work
System: PHP4.06 + Mysql3.23.41 Win32 + Apache 1.3.20 Win32 + Win98
When PHP is running at the line: $arr=mysql_fetch_array($res);
The IE always show info as below:
Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING' in c:\program files\apache
group\apache\htdocs\web\site1\list.php on line --[the number of line]
What's the problem wiht mysql_fetch_array() or other?
What does the T_STRING' or `T_VARIABLE' or `T_NUM_STRING' mean?
THANKS
Mike
The full code below:
?
$link=mysql_connect(localhost,,);
if($link==false){
echo Failed linking to database.;
exit();
}
$handler=mysql_select_db(database1);
if($handler==false)
echo Failed linking to database.;
$query=selct count(*) from users where sign=1;
$res=mysql_query($query);
$row=mysql_fetch_row($res);
$all=$row[0];
$step=5;
$pages=ceil($all/$step); /*the number of pages needed to listed */
if(empty($offset))
$offset=0;
$query=select user_id, user_name, time, status, comment from users
where sign=1
order by user_name
limit $offset, $step;
$res=mysql_query($query);
echo tabletd align=centerUser/td
td align=centerAdded time/tdtd align=centerStatus/td/tr;
$num=mysql_num_rows($res);
for($i=0; $i$num; $i++) {
$arr=mysql_fetch_array($res); /* HERE is line where the error occurs!!!
*/
echo trtd align=centera href=\profile.php?id=$arr['user_id']\
target='_top'
$arr['user_name']/a/td;
echo td align=center$arr['time']/td;
echo td align=center$arr['status']/td/tr;
echo tr colspan=3td$arr['comment']/td/tr;
}
echo /tablebrbrbr;
echo tabletrtd align='center'; /* show others in multi-pages */
for($i=0; $i$pages; $i++){
echo a href='$PHP_SELF?offset=$i*$step' target='_top'
echo ($i+1)./a;
echo nbsp;nbsp;;
}
echo /td/tr/table;
?
-
create table users (
user_id int not null auto_increment primary key,
user_name varchar(30),
time datetime,
status tinyint(1),
comment text,
sign tinyint(1) default '1'
);
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Re: [PHP] mysql_fetch_array() doesn't work
hi. this doesn't have to do with mysql_fetch_array. the following will
create that error :
echo a $b['c'] d e f;
the following will not :
echo a $b[c] d e {$f['g']} h i $j[$k] l 'm' n o p;
adjust accordingly. just posted a few words on this topic recently, can
view them here :
http://marc.theaimsgroup.com/?l=php-generalm=100152166602273
regards,
Philip Olson
On Thu, 27 Sep 2001, Web user wrote:
System: PHP4.06 + Mysql3.23.41 Win32 + Apache 1.3.20 Win32 + Win98
When PHP is running at the line: $arr=mysql_fetch_array($res);
The IE always show info as below:
Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING' in c:\program files\apache
group\apache\htdocs\web\site1\list.php on line --[the number of line]
What's the problem wiht mysql_fetch_array() or other?
What does the T_STRING' or `T_VARIABLE' or `T_NUM_STRING' mean?
THANKS
Mike
The full code below:
?
$link=mysql_connect(localhost,,);
if($link==false){
echo Failed linking to database.;
exit();
}
$handler=mysql_select_db(database1);
if($handler==false)
echo Failed linking to database.;
$query=selct count(*) from users where sign=1;
$res=mysql_query($query);
$row=mysql_fetch_row($res);
$all=$row[0];
$step=5;
$pages=ceil($all/$step); /*the number of pages needed to listed */
if(empty($offset))
$offset=0;
$query=select user_id, user_name, time, status, comment from users
where sign=1
order by user_name
limit $offset, $step;
$res=mysql_query($query);
echo tabletd align=centerUser/td
td align=centerAdded time/tdtd align=centerStatus/td/tr;
$num=mysql_num_rows($res);
for($i=0; $i$num; $i++) {
$arr=mysql_fetch_array($res); /* HERE is line where the error occurs!!!
*/
echo trtd align=centera href=\profile.php?id=$arr['user_id']\
target='_top'
$arr['user_name']/a/td;
echo td align=center$arr['time']/td;
echo td align=center$arr['status']/td/tr;
echo tr colspan=3td$arr['comment']/td/tr;
}
echo /tablebrbrbr;
echo tabletrtd align='center'; /* show others in multi-pages */
for($i=0; $i$pages; $i++){
echo a href='$PHP_SELF?offset=$i*$step' target='_top'
echo ($i+1)./a;
echo nbsp;nbsp;;
}
echo /td/tr/table;
?
-
create table users (
user_id int not null auto_increment primary key,
user_name varchar(30),
time datetime,
status tinyint(1),
comment text,
sign tinyint(1) default '1'
);
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[PHP] mysql_fetch_array() doesn't work
System: PHP4.06 + Mysql3.23.41 Win32 + Apache 1.3.20 Win32 + Win98
?
..
..
$res=mysql_query($query);
$num=mysql_num_rows($res);
for($i=0; $i$num; $i++){
$arr=mysql_fetch_array($res);
...
}
...
When PHP is running at the line: $arr=mysql_fetch_array($res);
The IE always show info as below:
Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING' in
c:\program files\apache group\apache\...\page.php on line ...
What's the problem wiht mysql_fetch_array() or other?
Thanks!
Mike
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[PHP] mysql_fetch_array
Can someone tell me what i'm doing wrong here?
?php
//Connect to db
$db = mysql_pconnect(localhost,login,pass);
mysql_select_db(database,$db);
//Check for the IP
$result2 = mysql_query(SELECT ip FROM ip where ip = '$REMOTE_ADDR',$db);
while($myrowmysql_fetch_array($result2))
{
echo Print some text here!;
}
?
Basically I just want to print text if the IP address was not found in the database,
and if it was found then I want to print Print some text here!
Please help!
Thanks,
Nate
Re: [PHP] mysql_fetch_array
On Thu, 6 Sep 2001 18:09, [EMAIL PROTECTED] wrote:
Can someone tell me what i'm doing wrong here?
?php
//Connect to db
$db = mysql_pconnect(localhost,login,pass);
mysql_select_db(database,$db);
//Check for the IP
$result2 = mysql_query(SELECT ip FROM ip where ip =
'$REMOTE_ADDR',$db);
while($myrowmysql_fetch_array($result2))
{
echo Print some text here!;
}
?
Basically I just want to print text if the IP address was not found in
the database, and if it was found then I want to print Print some text
here!
Please help!
Thanks,
Nate
I think it would make more sense to check the number of rows found, and
act accordingly. If you don't need to use any of the info from the DB,
you could do a SELECT COUNT(ip) WHERE
Alternatively, test mysql_num_rows($result2).
--
David Robley Techno-JoaT, Web Maintainer, Mail List Admin, etc
CENTRE FOR INJURY STUDIES Flinders University, SOUTH AUSTRALIA
He who laughs last probably made a backup.
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Re: [PHP] mysql_fetch_array
hi,
just go thru ur code once u'll getout with the bug.
$myrowmysql_fetch_Array($result2);
what is $myrow and to which value should the left part should
compare.
try this :
?php
file://Connect to db
$db = mysql_pconnect(localhost,login,pass);
mysql_select_db(database,$db);
file://Check for the IP
$result2 = mysql_query(SELECT ip FROM ip where ip = '$REMOTE_ADDR',$db);
$myrow=mysql_fetch_Array($result2);
if($myrow)
// if there is a record then the code goes here
else
echo(print some text here);
?
/sagar
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, September 06, 2001 2:09 PM
Subject: [PHP] mysql_fetch_array
Can someone tell me what i'm doing wrong here?
?php
file://Connect to db
$db = mysql_pconnect(localhost,login,pass);
mysql_select_db(database,$db);
file://Check for the IP
$result2 = mysql_query(SELECT ip FROM ip where ip = '$REMOTE_ADDR',$db);
while($myrowmysql_fetch_array($result2))
{
echo Print some text here!;
}
?
Basically I just want to print text if the IP address was not found in the
database, and if it was found then I want to print Print some text here!
Please help!
Thanks,
Nate
_
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[PHP] mySql_fetch_array($result) question.
Hello All, Another question. Here is the problem: - One SQL query - 1 result. I have a form that has more than one drop down lists. I like to use the mysql_fetch_array($result) to populate the select options. The problem is that after the first use, the mysql_fetch_array($result) does not return anything. Any suggestion. note: As a workaround, I am running the select statement (The SQL) 10 time. I think it's not a good solution though!! Thanks, Mehmet. = Mehmet Erisen http://www.erisen.com __ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] mysql_fetch_array()
Greetings!
I am using PHP and MySQL in RedHat 6.0.
I have used mysql_fetch_array() to display the datas in web page but all the
columns are printed twice. What can be the wrong with my code:
?php
$connection=mysql_connection(...);
$db=mysql_select_db(.);
$sql="select * from my db";
$sql_result=$mysql_query($sql,$connection);
print "table";
while ($row=mysql_fetch_array($sql_result))
{
print "tr";
foreach ($row as $field)
print "td$field/td";
print "tda href=\"search.php?ID=$row[ID]\"";
print "Get it";
print "/a/td";
print "/tr";
}
print "/table";
?
But it works fine with mysql_fetch_row() however it does not pass the pass
the variable ID.
Looking forward to hearing from you.
Warm regards,
DT
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RE: [PHP] mysql_fetch_array()
?php
$connection=mysql_connection(...);
$db=mysql_select_db(.);
$sql="select * from my db";
$sql_result=mysql_query($sql,$connection);
print "table";
while ($row=mysql_fetch_array($sql_result))
{
print "tr";
foreach ($row as $field)
print "td$field/td";
print "tda href=\"search.php?ID=$row[ID]\"";
print "Get it";
print "/a/td";
print "/tr";
}
print "/table";
?
Try that, you tried to call $mysql_query, when you needed to call
mysql_query. In your code, $mysql_query isn't a variable, it's a function
in PHP.
-Original Message-
From: Deependra B. Tandukar [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 07, 2001 9:34 PM
To: [EMAIL PROTECTED]
Subject: [PHP] mysql_fetch_array()
Greetings!
I am using PHP and MySQL in RedHat 6.0.
I have used mysql_fetch_array() to display the datas in web page but all the
columns are printed twice. What can be the wrong with my code:
?php
$connection=mysql_connection(...);
$db=mysql_select_db(.);
$sql="select * from my db";
$sql_result=$mysql_query($sql,$connection);
print "table";
while ($row=mysql_fetch_array($sql_result))
{
print "tr";
foreach ($row as $field)
print "td$field/td";
print "tda href=\"search.php?ID=$row[ID]\"";
print "Get it";
print "/a/td";
print "/tr";
}
print "/table";
?
But it works fine with mysql_fetch_row() however it does not pass the pass
the variable ID.
Looking forward to hearing from you.
Warm regards,
DT
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Re: [PHP] mysql_fetch_array()
On Thu, 8 Mar 2001 14:03, Deependra B. Tandukar wrote:
Greetings!
I am using PHP and MySQL in RedHat 6.0.
I have used mysql_fetch_array() to display the datas in web page but
all the columns are printed twice. What can be the wrong with my code:
?php
$connection=mysql_connection(...);
$db=mysql_select_db(.);
$sql="select * from my db";
$sql_result=$mysql_query($sql,$connection);
print "table";
while ($row=mysql_fetch_array($sql_result))
{
print "tr";
foreach ($row as $field)
print "td$field/td";
print "tda href=\"search.php?ID=$row[ID]\"";
print "Get it";
print "/a/td";
print "/tr";
}
print "/table";
?
But it works fine with mysql_fetch_row() however it does not pass the
pass the variable ID.
Looking forward to hearing from you.
Warm regards,
First up, shouldn't you have {} to delineate what is actually the foreach
procedure(s)?
I would suggest using extract within your While loop to make the table
fields available as variables.
while ($row=mysql_fetch_array($sql_result))
{
extract($row);
echo "tr";
echo "td$field/td"; \\ or whatever the field is called
echo "tda href=\"search.php?ID=$ID\"";
echo "Get it";
echo "/a/td";
echo "/tr";
}
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[PHP] mysql_fetch_array and row referencing under 4.0.4pl1
Have I lost something somewhere? I have code which runs under PHP3.0.15, and PHP4.0.2 which references the result of a $row = mysql_fetch_array($result_of_query); by doing things like: $row["this_is_a_field_name"] Seems simple, right? Well - I compiled a new copy of Apache 1.3.17, pushed PHP up to 4.0.4pl1, and upgraded mysql to the new stable version at the same time... Now the above code doesnt work. But if I do a: $row[this_is_a_field_name] Then the code does work. Have I messed up something in the PHP configuration that doesnt allow these quoted identifiers anymore? Or is this just a new (less-than-compatible) upgrade to PHP that I've missed reading about?? Heelp me ... I dont want to have to rebuild all my sites just because of these stupid quotes -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] mysql_fetch_array and row referencing under 4.0.4pl1
I'd be curious to see others' answers on this because I upgraded everything the other day (been at php4 for a while though) and I don't have a problem with the quotes. On 2/12/01 11:11 PM this was written: Have I lost something somewhere? I have code which runs under PHP3.0.15, and PHP4.0.2 which references the result of a $row = mysql_fetch_array($result_of_query); by doing things like: $row["this_is_a_field_name"] Seems simple, right? Well - I compiled a new copy of Apache 1.3.17, pushed PHP up to 4.0.4pl1, and upgraded mysql to the new stable version at the same time... Now the above code doesnt work. But if I do a: $row[this_is_a_field_name] Then the code does work. Have I messed up something in the PHP configuration that doesnt allow these quoted identifiers anymore? Or is this just a new (less-than-compatible) upgrade to PHP that I've missed reading about?? Heelp me ... I dont want to have to rebuild all my sites just because of these stupid quotes -- Thomas Deliduka IT Manager - New Eve Media The Solution To Your Internet Angst http://www.neweve.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] mysql_fetch_array and row referencing under 4.0.4pl1
"Scott Brown" [EMAIL PROTECTED] wrote: I have code which runs under PHP3.0.15, and PHP4.0.2 which references the result of a $row["this_is_a_field_name"] Well - I compiled a new copy of Apache 1.3.17, pushed PHP up to 4.0.4pl1, and upgraded mysql to the new stable version at the same time... Now the above code doesnt work. But if I do a: What error messages do you get? Add this to beginning of your code and you might get more error output that will help diagnose. ?php error_reporting(E_ALL); ? $row[this_is_a_field_name] Then the code does work. Odd. I've noticed the non-quoted versions causing PHP to choke if error_reporting() is set high enough. I've never know the opposite to be true. Have I messed up something in the PHP configuration that doesnt allow these quoted identifiers anymore? Or is this just a new (less-than-compatible) upgrade to PHP that I've missed reading about?? It could be a configuration option or a php.ini setting. Create a page with ?php phpinfo(); ? in it and post your configuration options to the list. -- Steve Werby COO 24-7 Computer Services, LLC Tel: 804.817.2470 http://www.247computing.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] mysql_fetch_array and row referencing under 4.0.4pl1
"Scott Brown" [EMAIL PROTECTED] wrote: $row["this_is_a_field_name"] Seems simple, right? Well - I compiled a new copy of Apache 1.3.17, pushed PHP up to 4.0.4pl1, and upgraded mysql to the new stable version at the same time... Now the above code doesnt work. But if I do a: Forgot to ask - does referencing an array with double quotes around the key work for arrays not associated with a MySQL result? I doubt it's specific to MySQL result arrays, but it doesn't hurt to check. Make a small array and test. -- Steve Werby COO 24-7 Computer Services, LLC Tel: 804.817.2470 http://www.247computing.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] mysql_fetch_array and row referencing under 4.0.4pl1
Forgot to ask - does referencing an array with double quotes
around the key work for arrays not associated with a MySQL
result? I doubt it's specific to MySQL result arrays, but
it doesn't hurt to check. Make a small array and test.
I grabbed an example of of php.net dealing with just arrays and it works ...
Here's what I'm seeing - THIS WORKS:
HTML
HEAD
TITLEmysqltest/TITLE
/HEAD
BODY BGCOLOR="#FF"
?
require($DOCUMENT_ROOT . "/subs/sub.php");
openDSN();
echo "table\n";
$rslt = mysql_query("select * from pricing");
while ( $row = mysql_fetch_array($rslt) )
{
echo "TR\n";
echo "TD$row[ID]/tD";
echo "TD$row[ProdCode]/tD";
echo "TD$row[Price_effdate]/tD";
echo "TD$row[ProdSetup]/tD";
echo "TD$row[ProdMonthly]/tD";
echo "TD$row[5]/tD";
echo "/TR\n";
}
echo "/table\n";
?
/BODY
/HTML
But put any one of these $row[...] with quotes around their fieldnames and I
get:
Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING' in /home/testnexus/public_html/test.php on line 16
(when line 16 =
echo "TD$row["ID"]/tD";
)
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RE: [PHP] mysql_fetch_array and row referencing under 4.0.4pl1
I'd be curious to see others' answers on this because I upgraded everything the other day (been at php4 for a while though) and I don't have a problem with the quotes. I've probably just putzed something somewhere during the build it's been one of those days. But the thing is it's consistant... if I quote my field names (single or double) I get an error... if I dont, I get my result. (see my response to Steve...) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] mysql_fetch_array strangeness
Because, basically, in php an array is a hash with just numbers as keys. m. -- Markus Fischer, http://josefine.ben.tuwien.ac.at/~mfischer/ EMail: [EMAIL PROTECTED] PGP Public Key: http://josefine.ben.tuwien.ac.at/~mfischer/C2272BD0.asc PGP Fingerprint: D3B0 DD4F E12B F911 3CE1 C2B5 D674 B445 C227 2BD0 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] mysql_fetch_array strangeness
Hi,
I'm trying to echo out the field names used as key values in a
mysql_fetch_array:
$link_id = mysql_connect("localhost", "root", $pass);
mysql_select_db("database", $link_id);
$result = mysql_query("select * from lists where id = 1", $link_id);
$rowData = mysql_fetch_array($result);
while (list($fieldName) = each($rowData))
{ echo "$fieldName,"; }
I'm expecting to get this:
id,listname,joinconfirm,leaveconfirm,homepage,author,canjoin,bannedemails,de
scription,subject,masteremail,
but instead getting this:
0,id,1,listname,2,joinconfirm,3,leaveconfirm,4,homepage,5,author,6,canjoin,7
,bannedemails,8,description,9,subject,10,masteremail,
Why are the index numbers for the array showing up? From the docs,
mysql_fetch_array should create an array of field names to field values...?
To make things worse, if I also echo the data:
while (list($fieldName, $fieldValue) = each($rowData))
{ echo "$fieldName,$fieldValue," ;}
Then a value is echoed after both the index number and the field value, eg:
0,1,id,1,1,testlist,listname,testlist, etc...
What am I doing wrong?
Regards,
Jaxon
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Re: [PHP] mysql_fetch_array strangeness
each() assigns four elements... (0 = index), (1 = value), (key = index), (value =
value)
You are concerned with key and value.
So: list ($fieldname, $value) = each($row)
You may not be using $value but you still need to assign the data to a variable. Or
list will only assign $fieldname the numerical
index and not the char index. At least that's from what I understand. Anyone, please
feel free to correct me.
Kristi
Beware of the false gods we sometimes
worship--money, power and fame--for they
are all fleeting, especially in death and often
in mortality.
-Anonymous
- Original Message -
From: "Jaxon" [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Sunday, January 21, 2001 8:07 PM
Subject: [PHP] mysql_fetch_array strangeness
Hi,
I'm trying to echo out the field names used as key values in a
mysql_fetch_array:
$link_id = mysql_connect("localhost", "root", $pass);
mysql_select_db("database", $link_id);
$result = mysql_query("select * from lists where id = 1", $link_id);
$rowData = mysql_fetch_array($result);
while (list($fieldName) = each($rowData))
{ echo "$fieldName,"; }
I'm expecting to get this:
id,listname,joinconfirm,leaveconfirm,homepage,author,canjoin,bannedemails,de
scription,subject,masteremail,
but instead getting this:
0,id,1,listname,2,joinconfirm,3,leaveconfirm,4,homepage,5,author,6,canjoin,7
,bannedemails,8,description,9,subject,10,masteremail,
Why are the index numbers for the array showing up? From the docs,
mysql_fetch_array should create an array of field names to field values...?
To make things worse, if I also echo the data:
while (list($fieldName, $fieldValue) = each($rowData))
{ echo "$fieldName,$fieldValue," ;}
Then a value is echoed after both the index number and the field value, eg:
0,1,id,1,1,testlist,listname,testlist, etc...
What am I doing wrong?
Regards,
Jaxon
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