RE: [PHP] newbie: help with date arithmetic[Scanned]
This is a great help. Thanks ya'll. And I will continue to, and do regulary RTFM 8-) I find that it generally sucks for a newbie. >>> "Michael Egan" <[EMAIL PROTECTED]> 11/12/02 10:42AM >>> Robert, I've been looking at this myself over the past couple of days. I gather the best approach is to convert your dates into UNIX timestamps. For example: $first_unix_time = mktime($hour1, $minutes1, $seconds1, $month1, $day1, $year1); $second_unix_time = mktime($hour2, $minutes2, $seconds2, $month2, $day2, $year2); Subtract the one from the other to give the difference: $difference = $first_unix_time - $second_unix_time; The result will be in seconds so you'll need to convert this depending on the format you require. For example, to convert the difference to years you might do: $years = floor($difference / (365 * 24 * 60 * 60)); Hope this helps, Michael Egan -Original Message- From: ROBERT MCPEAK [mailto:RMCPEAK@;jhuccp.org] Sent: 12 November 2002 15:31 To: [EMAIL PROTECTED] Subject: [PHP] newbie: help with date arithmetic[Scanned] I'm trying to add/subract two dates. I think I need to use mktime() but I can't quite figure out how. I'd like to do something like this: (2002-11-15)-(2002-11-10)=5 or (2002-12-10)-(2002-11-10)=20 Obviously taking into account number of days in a given month. Does somebody have some code handy that does this? Any help would be greatly appreciated! Thanks. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] newbie: help with date arithmetic[Scanned]
Robert, I've been looking at this myself over the past couple of days. I gather the best approach is to convert your dates into UNIX timestamps. For example: $first_unix_time = mktime($hour1, $minutes1, $seconds1, $month1, $day1, $year1); $second_unix_time = mktime($hour2, $minutes2, $seconds2, $month2, $day2, $year2); Subtract the one from the other to give the difference: $difference = $first_unix_time - $second_unix_time; The result will be in seconds so you'll need to convert this depending on the format you require. For example, to convert the difference to years you might do: $years = floor($difference / (365 * 24 * 60 * 60)); Hope this helps, Michael Egan -Original Message- From: ROBERT MCPEAK [mailto:RMCPEAK@;jhuccp.org] Sent: 12 November 2002 15:31 To: [EMAIL PROTECTED] Subject: [PHP] newbie: help with date arithmetic[Scanned] I'm trying to add/subract two dates. I think I need to use mktime() but I can't quite figure out how. I'd like to do something like this: (2002-11-15)-(2002-11-10)=5 or (2002-12-10)-(2002-11-10)=20 Obviously taking into account number of days in a given month. Does somebody have some code handy that does this? Any help would be greatly appreciated! Thanks. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] newbie: help with date arithmetic
At 16:30 12.11.2002, ROBERT MCPEAK spoke out and said:
[snip]
>I'm trying to add/subract two dates. I think I need to use mktime() but I
>can't quite figure out how.
>
>I'd like to do something like this:
>
>(2002-11-15)-(2002-11-10)=5
>
>or
>
>(2002-12-10)-(2002-11-10)=20
>
>Obviously taking into account number of days in a given month.
[snip]
:)) rtfm, again :))
1) http://www.php.net/manual/en/function.strtotime.php
2) http://www.gnu.org/manual/tar-1.12/html_chapter/tar_7.html
3) your second equation would return 30, not 20 ;->
4) try this:
/* untested */
function days($str_from, $str_to) {
$from = strtotime(isset($str_from) ? $str_from : 'now');
$to = strtotime(isset($str_to) ? $str_to : 'now');
if ($from > $to) {
$x = $from; $from = $to; $to = $x;
}
$rslt = $to - $from; // number in seconds
return (int)($rslt / 86400); // return days (1d = 86400 secs)
}
Hope this helps,
--
>O Ernest E. Vogelsinger
(\) ICQ #13394035
^ http://www.vogelsinger.at/
[PHP] newbie: help with date arithmetic
I'm trying to add/subract two dates. I think I need to use mktime() but I can't quite figure out how. I'd like to do something like this: (2002-11-15)-(2002-11-10)=5 or (2002-12-10)-(2002-11-10)=20 Obviously taking into account number of days in a given month. Does somebody have some code handy that does this? Any help would be greatly appreciated! Thanks. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
