[PHP] password field validation
Hi All,
I have an input field with type=password.
I am trying to do some error checking to see if the user puts a value
in after they submit the form (i.e not left it blank)
Here is what I have:
on form:
Password: input id=PASSWORD name=PASSWORD type=password
size=15
In PHP error checking:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
even though I am putting characters in the field before I submit I am
always getting TRUE returned.
This same tactic works for other fields I have that I need to make
sure they put values in, just I have never done this before with a
password field.
What am I doing wrong? I just want to make sure they put something
there!
-Jason
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Re: [PHP] password field validation
On Thu, Mar 12, 2009 at 3:05 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
Hi All,
I have an input field with type=password.
I am trying to do some error checking to see if the user puts a value in
after they submit the form (i.e not left it blank)
Here is what I have:
on form:
Password: input id=PASSWORD name=PASSWORD type=password size=15
In PHP error checking:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
even though I am putting characters in the field before I submit I am always
getting TRUE returned.
This same tactic works for other fields I have that I need to make sure they
put values in, just I have never done this before with a password field.
What am I doing wrong? I just want to make sure they put something there!
-Jason
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
Andrew
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Re: [PHP] password field validation
On Thu, Mar 12, 2009 at 15:05, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
[snip!]
What am I doing wrong?
Spelling.
Password only has two S's.
--
/Daniel P. Brown
daniel.br...@parasane.net || danbr...@php.net
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Re: [PHP] password field validation
Andrew Ballard wrote:
On Thu, Mar 12, 2009 at 3:05 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
Hi All,
I have an input field with type=password.
I am trying to do some error checking to see if the user puts a value in
after they submit the form (i.e not left it blank)
Here is what I have:
on form:
Password: input id=PASSWORD name=PASSWORD type=password size=15
In PHP error checking:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
even though I am putting characters in the field before I submit I am always
getting TRUE returned.
This same tactic works for other fields I have that I need to make sure they
put values in, just I have never done this before with a password field.
What am I doing wrong? I just want to make sure they put something there!
-Jason
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
Andrew
try if trim() gives you any different result:
if (empty(trim($_POST['PASSWORD'])))
{ $GERROR='TRUE'; }
afan
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Re: [PHP] password field validation
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
It is official I am a DOPE! Thank you, yes, I did not see the SSS in
an hour of looking!
Why enclose in quotes? I have never done this!
-Jason
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Re: [PHP] password field validation
Afan Pasalic schreef:
Andrew Ballard wrote:
On Thu, Mar 12, 2009 at 3:05 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
Hi All,
I have an input field with type=password.
I am trying to do some error checking to see if the user puts a value in
after they submit the form (i.e not left it blank)
Here is what I have:
on form:
Password: input id=PASSWORD name=PASSWORD type=password
size=15
In PHP error checking:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
even though I am putting characters in the field before I submit I am
always
getting TRUE returned.
This same tactic works for other fields I have that I need to make
sure they
put values in, just I have never done this before with a password field.
What am I doing wrong? I just want to make sure they put something
there!
-Jason
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
Andrew
try if trim() gives you any different result:
if (empty(trim($_POST['PASSWORD'])))
{ $GERROR='TRUE'; }
definitely gives a different result.
$ php -r '
$r = ; var_dump(empty(trim($r)));'
PHP Fatal error: Can't use function return value in write context in Command
line code on line 2
you can only pass variables to empty() *not* expressions.
afan
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Re: [PHP] password field validation
On Thu, Mar 12, 2009 at 2:39 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
It is official I am a DOPE! Thank you, yes, I did not see the SSS in an hour
of looking!
Why enclose in quotes? I have never done this!
Because if it's not in quotes, you run the risk of colliding with one
of PHP's reserved words/constants/etc.
--
// Todd
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Re: [PHP] password field validation
Jochem Maas wrote:
Afan Pasalic schreef:
Andrew Ballard wrote:
On Thu, Mar 12, 2009 at 3:05 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
Hi All,
I have an input field with type=password.
I am trying to do some error checking to see if the user puts a value in
after they submit the form (i.e not left it blank)
Here is what I have:
on form:
Password: input id=PASSWORD name=PASSWORD type=password
size=15
In PHP error checking:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
even though I am putting characters in the field before I submit I am
always
getting TRUE returned.
This same tactic works for other fields I have that I need to make
sure they
put values in, just I have never done this before with a password field.
What am I doing wrong? I just want to make sure they put something
there!
-Jason
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
Andrew
try if trim() gives you any different result:
if (empty(trim($_POST['PASSWORD'])))
{ $GERROR='TRUE'; }
definitely gives a different result.
$ php -r '
$r = ; var_dump(empty(trim($r)));'
PHP Fatal error: Can't use function return value in write context in Command
line code on line 2
you can only pass variables to empty() *not* expressions.
:-)
yup... didn't think that way...
though, I was giving an idea
$password = trim($_POST['PASSWORD']);
if (empty($password)
{ $GERROR='TRUE'; }
;-)
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Re: [PHP] password field validation
On Thu, Mar 12, 2009 at 3:39 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
It is official I am a DOPE! Thank you, yes, I did not see the SSS in an hour
of looking!
Why enclose in quotes? I have never done this!
-Jason
If you don't enclose them in quotes, PHP first looks for a constant
with that name. Thus, it the constant PASSWORD was defined as 'some
silly string', your code would evaluate to $_POST['some silly string']
instead of the string 'PASSWORD' that you probably intended it to use.
That, and it generates an E_NOTICE. On a production server, these are
usually hidden from public view, but it is still good practice to
avoid them.
Andrew
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Re: [PHP] password field validation
haliphax wrote:
On Thu, Mar 12, 2009 at 2:39 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
If that's a direct copy/paste from your actual code, there is an extra
S in PASSWORD. Also, you should enclose the array key in quotes:
if (empty($_POST['PASSWORD']))
{ $GERROR='TRUE'; }
It is official I am a DOPE! Thank you, yes, I did not see the SSS in an hour
of looking!
Why enclose in quotes? I have never done this!
Because if it's not in quotes, you run the risk of colliding with one
of PHP's reserved words/constants/etc.
I would use
$GERROR = false;
if (empty($_POST['PASSWORD']))
{ $GERROR = true;}
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Re: [PHP] password field validation
prueba con trim() :
$pass=trim($_POST[PASSSWORD]);
if (empty($pass))
{
$GERROR=TRUE;
}
Atte.
Rodrigo
(09) 7 7996571
On Thu, Mar 12, 2009 at 4:05 PM, Jason Todd Slack-Moehrle
mailingli...@mailnewsrss.com wrote:
Hi All,
I have an input field with type=password.
I am trying to do some error checking to see if the user puts a value in
after they submit the form (i.e not left it blank)
Here is what I have:
on form:
Password: input id=PASSWORD name=PASSWORD type=password size=15
In PHP error checking:
if (empty($_POST[PASSSWORD]))
{ $GERROR=TRUE;}
even though I am putting characters in the field before I submit I am
always getting TRUE returned.
This same tactic works for other fields I have that I need to make sure
they put values in, just I have never done this before with a password
field.
What am I doing wrong? I just want to make sure they put something there!
-Jason
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Re: [PHP] password field validation
On Thu, Mar 12, 2009 at 16:04, Rodrigo Escares
rodrigo.esca...@gmail.com wrote:
prueba con trim() :
$pass=trim($_POST[PASSSWORD]);
if (empty($pass))
{
$GERROR=TRUE;
}
Incorrecto, Rodrigo. Tambien, utilice por favor solamente el
ingles en esta lista --- usted puede encontrar la lista de usuario
espanola en:
http://php.net/mailinglists
iGracias!
--
/Daniel P. Brown
daniel.br...@parasane.net || danbr...@php.net
http://www.parasane.net/ || http://www.pilotpig.net/
50% Off All Shared Hosting Plans at PilotPig: Use Coupon DOW1
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