I think you can't achieve this with the example you've provided.
Perhaps something like this will work:
query = ;
mysql_query(SELECT * FROM table . $query );
query = WHERE date = '2001-01-01'; // This should return all rows with
2001-01-01 as date.
query = WHERE date '1995-01-01'; // All items newer than 1995-01-01.
query = WHERE date '1995-01-01'; // All items older than 1995-01-01.
query = WHERE date '1995-01-01' AND date '1998-01-01'; // All items
between 1995-01-01 and 1998-01-01.
Hope this helps
/Joakim
-Original Message-
From: Craig Westerman [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 25, 2002 7:34 PM
To: [EMAIL PROTECTED]
Subject: [PHP] php - assigning date variables
$query =
mysql_query(SELECT * FROM table WHERE date LIKE '%. $query .%');
// returns all items in database
$query = 2001-01-01
mysql_query(SELECT * FROM table WHERE date LIKE '%. $query .%');
// returns all rows that have 2001-01-01 as the date
What is proper way to define a variable to include all dates
newer than
1995-01-01?
$query = ???
What is proper way to define a variable to include all dates
older than
1995-01-01?
$query = ???
What is proper way to define a variable to include all dates between
1995-01-01 and 1998-12-31?
$query = ???
Everything I tried gives me a error. This has to be simple,
but I must be
overlooking something. Where would I find the answer?
Thanks
Craig
[EMAIL PROTECTED]
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