Re: [PHP] supplied argument errors

2009-06-24 Thread David Robley
PJ wrote:

> Lex Braun wrote:
>>
>>
>> On Tue, Jun 23, 2009 at 4:10 PM, PJ > > wrote:
>>
>> I think there is something I do not understand in the manual about
>> mysql_fetch_assoc(), mysql_affected_rows()
>> The code works, but I get these annoying messages.
>> snippet:
>>
>> 
>> What are the warnings?
> 1 .supplied argument is not a valid MySQL result resource
> 2. supplied argument is not a valid MySQL-link resource
> 
> snippet:
> $result = mysql_query($sql, $db); // this is following an UPDATE
>   $row = mysql_fetch_assoc($result); // warning... 1.
>   if (mysql_affected_rows($result) !== -1) //warning...2.
> print_r($result); // returns 1
> 
> another:
>  $sql = "DELETE FROM book_categories WHERE bookID = $bid";
> $result = mysql_query($sql, $db); // warning...1.
>   $row = mysql_fetch_assoc($result); // warning...1.
> if (mysql_num_rows($result) !== 0) {
> the last:
>   $result = mysql_query($sql,$db); // following an INSERT
> if (mysql_affected_rows($result) == -1) {  // warning2.
> 
> 
> 

Oh for $deity's sake, haven't you yet learned to a) echo your query and b)
use mysql_error() as aids to debugging errors with mysql ???



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-- 
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Today is Setting Orange, the 29th day of Confusion in the YOLD 3175. 


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Re: [PHP] supplied argument errors

2009-06-23 Thread Shawn McKenzie
kranthi wrote:
> the code works?
> 
> the above warnings suggest that ter is a mysql syntax error.
> 
> moreover the documentation of mysql_affected_rows suggests that u should
> supply a valid recource identifier but not a mysql result resource.
> i.e., the above should be mysql_affected_rows($db)
> 

Yes, so:

1.  It was an UPDATE and not a SELECT, how would it return any f'ing
rows?!?! $rows is either TRUE or FALSE, because it returns whether the
UPDATE was successful or not.

2. Please read the f'ing manual about what kranthi said!

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Re: [PHP] supplied argument errors

2009-06-23 Thread kranthi
the code works?

the above warnings suggest that ter is a mysql syntax error.

moreover the documentation of mysql_affected_rows suggests that u should
supply a valid recource identifier but not a mysql result resource.
i.e., the above should be mysql_affected_rows($db)


Re: [PHP] supplied argument errors

2009-06-23 Thread Lex Braun
On Tue, Jun 23, 2009 at 4:10 PM, PJ  wrote:

> I think there is something I do not understand in the manual about
> mysql_fetch_assoc(), mysql_affected_rows()
> The code works, but I get these annoying messages.
> snippet:
>

What are the warnings?


Re: [PHP] supplied argument errors

2009-06-23 Thread PJ
Lex Braun wrote:
>
>
> On Tue, Jun 23, 2009 at 4:10 PM, PJ  > wrote:
>
> I think there is something I do not understand in the manual about
> mysql_fetch_assoc(), mysql_affected_rows()
> The code works, but I get these annoying messages.
> snippet:
>
> 
> What are the warnings?
1 .supplied argument is not a valid MySQL result resource
2. supplied argument is not a valid MySQL-link resource

snippet:
$result = mysql_query($sql, $db); // this is following an UPDATE
  $row = mysql_fetch_assoc($result); // warning... 1.
  if (mysql_affected_rows($result) !== -1) //warning...2.
print_r($result); // returns 1

another:
 $sql = "DELETE FROM book_categories WHERE bookID = $bid";
$result = mysql_query($sql, $db); // warning...1.
  $row = mysql_fetch_assoc($result); // warning...1.
if (mysql_num_rows($result) !== 0) {
the last:
  $result = mysql_query($sql,$db); // following an INSERT
if (mysql_affected_rows($result) == -1) {  // warning2.



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   http://www.chiccantine.com/andypantry.php


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[PHP] supplied argument errors

2009-06-23 Thread PJ
I think there is something I do not understand in the manual about
mysql_fetch_assoc(), mysql_affected_rows()
The code works, but I get these annoying messages.
snippet:
$result = mysql_query($sql, $db); // this is following an UPDATE
  $row = mysql_fetch_assoc($result); // warning...
  if (mysql_affected_rows($result) !== -1) //warning...
print_r($result); // returns 1

another:
 $sql = "DELETE FROM book_categories WHERE bookID = $bid";
$result = mysql_query($sql, $db); // warning...
  $row = mysql_fetch_assoc($result); // warning...
if (mysql_num_rows($result) !== 0) {
the last:
  $result = mysql_query($sql,$db); // following an INSERT
if (mysql_affected_rows($result) == -1) {  // warning

I have read the manual entries but I think I could use some
clarification/explanation.
TIA

-- 
Hervé Kempf: "Pour sauver la planète, sortez du capitalisme."
-
Phil Jourdan --- p...@ptahhotep.com
   http://www.ptahhotep.com
   http://www.chiccantine.com/andypantry.php


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