On Friday, January 11, 2002, at 05:42 PM, Nick Wilson wrote:
> That's not it. Your first $result is a resource indicator (container for
> results) so if you re-assign it (put another value into it) it becomes
> useless as your while statement depends on it.
(This may be redundant, but I'm hopi
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* On 11-01-02 at 23:39
* Erik Price said
>
> EXCELLENT!
> It worked perfect.
> So $result can't be used twice -- I wonder if it somehow is altered by
> the mysql_fetch_array() that is performed upon it.
That's not it. Your first $result is a
EXCELLENT!
It worked perfect.
So $result can't be used twice -- I wonder if it somehow is altered by
the mysql_fetch_array() that is performed upon it.
Thanks Nick.
On Friday, January 11, 2002, at 05:23 PM, Nick Wilson wrote:
> I'll most likely be corrected (I just joined the list to brush u
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* On 11-01-02 at 23:08
* Erik Price said
> I am curious if using the same mysql_query() function twice causes some
> kind of problem.
>
> It seems that if I use
>
> $result = mysql_query($sql, $db);
> if (mysql_fetch_array($result)) {
>
I am curious if using the same mysql_query() function twice causes some
kind of problem.
It seems that if I use
$result = mysql_query($sql, $db);
if (mysql_fetch_array($result)) {
while ($row = mysql_fetch_array($result) or die("You lose. No data
fetched.")) {
// print some dat
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