Hi folks,
Linux, PHP3
I have the following problem:
I have an object, which creates a form, wherein there are selects, which
names accord to values in the database.
But I didnīt get it to have a variable var, Iīm sure itīs just a small
thing, but I cannot see it
Any suggestions ?
TIA Oliver
echo '<form name="g94" action="'.$to_go.'" method="get">';
// Already tried post, no difference
echo '<table border="1" width="100%" cellpadding="1" cellspacing="1">';
while($da=$MKA -> getDbAns()) // This gives back an array named $da
while there are answers
{
$xwert=$da[1];
// $da[1] contains "abc" the var $xwert will be "abc"
// now Iīd like to see the value of $abc but thereīs nothing in
echo '<tr><td> '.$$xwert.'</td><td>';
// set the new select named "abc"
echo '<select name="'.$da[1].'">';
// forget the rest, just for understanding what while does
for($i=0; $i < 11 ; $i++)
{
if(isset($$da[1])) // just for testing
{
echo "<option selected >".$i."</option>";
}
else
{
echo "<option>".$i."</option>";
}
} // end for
echo '</select>';
echo '</td>';
echo '<td>'.$da[1].'</td>';
echo '<td>'.$da[2].'</td>';
echo '<td align="right">'.$da[3].' EUR</td>';
echo '</tr>';
} // end while
echo '</table>';
echo '<br><br><input type="submit" value="CalC !">';
echo "</form>";
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