Re: [PHP] Check if a word is in my string.

[Philip Olson]

see :

  http://www.php.net/strstr
  http://www.php.net/stristr

Regards,
Philip


On Tue, 28 Aug 2001, Brandon Orther wrote:

 Hello,
  
 I have a variable with a string in it.  I want to check if in that
 string a certain word is in it.  Example
  
 $var = This is a good sentence;
  
 $check = look(good, $var);
  
  
 and $check would equal 1 since good is in that string
  
  
  
  
 does anyone know how to do this?
 


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Re: [PHP] Check if a word is in my string.

[daniel james]

if you're just looking for the 1st occurrence of the
string, it's--

$check = good;
$var = This is a good...;

if (!strstr($var, $check)) {
print($check not found);
}

also, i think strstr() is case-insensitive, so it
won't be able to differentiate between 'Good' and
'good', and will NOT return FALSE if 'Good' precedes
'good' in the string...

-dj


--- Brandon Orther [EMAIL PROTECTED] wrote:
 Hello,
  
 I have a variable with a string in it.  I want to
 check if in that
 string a certain word is in it.  Example
  
 $var = This is a good sentence;
  
 $check = look(good, $var);
  
  
 and $check would equal 1 since good is in that
 string
  
  
  
  
 does anyone know how to do this?
 


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RE: [PHP] Check if a word is in my string.

[scott [gts]]

use regexps.  that's what their specialty is ;-)

// case insensitive
if ( preg_match(/$text/i, $string) ) {
print $text is in $string;
}

// case sensitive
if ( preg_match(/$text/, $string) ) {
print $text is in $string;
}

 -Original Message-
 From: daniel james [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, August 28, 2001 6:11 PM
 To: Brandon Orther; PHP User Group
 Subject: Re: [PHP] Check if a word is in my string.
 
 
 if you're just looking for the 1st occurrence of the
 string, it's--
 
 $check = good;
 $var = This is a good...;
 
 if (!strstr($var, $check)) {
 print($check not found);
 }
 
 also, i think strstr() is case-insensitive, so it
 won't be able to differentiate between 'Good' and
 'good', and will NOT return FALSE if 'Good' precedes
 'good' in the string...
 
 -dj
 
 
 --- Brandon Orther [EMAIL PROTECTED] wrote:
  Hello,
   
  I have a variable with a string in it.  I want to
  check if in that
  string a certain word is in it.  Example
   
  $var = This is a good sentence;
   
  $check = look(good, $var);
   
   
  and $check would equal 1 since good is in that
  string
   
   
   
   
  does anyone know how to do this?
  
 
 
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RE: [PHP] Check if a word is in my string.

[Jason Murray]

 use:
 preg_match('/\Wgood\W/',$var);
 or
 preg_match('/\bgood\b/',$var);

Or, you could just try strstr($haystack, $needle) ...

Jason

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Web Developer, Melbourne IT
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