RE: [PHP] Creating arrays using results from MySQL query

2002-03-18 Thread Mark Heintz PHP Mailing Lists
I should have been more exact in my original reply. The second query isn't necessary. Try this: File: login.php # if $employee_1, query db workgroups table to check if $emp_login_id belongs to any groups $sql_2 = "SELECT * FROM workgroups WHERE emp_id='$emp_login_id'"; $result_2 = @mysql_query

RE: [PHP] Creating arrays using results from MySQL query

2002-03-18 Thread Mullin, Reginald
: > Array ( [0] => 222 [1] => 333 ). For some reason, it seems to be skipping > the first record. > > O From Now 'Till Then, > \->Reginald Alex Mullin > /\ 212-894-1690 > > -Original Message- > From: Mullin, Reginald > Sent: Monday, March 18,

RE: [PHP] Creating arrays using results from MySQL query

2002-03-18 Thread Mullin, Reginald
>Reginald Alex Mullin /\ 212-894-1690 > -Original Message- > From: Mark Heintz PHP Mailing Lists [SMTP:[EMAIL PROTECTED]] > Sent: Monday, March 18, 2002 1:26 PM > To: Mullin, Reginald > Cc: [EMAIL PROTECTED] > Subject: Re: [PHP] Cre

Re: [PHP] Creating arrays using results from MySQL query

2002-03-18 Thread Mark Heintz PHP Mailing Lists
You have to call mysql_fetch_array for each record in your result set... $emp_login_wkgrp_id = array (); $emp_login_grp_id = array (); $emp_login_role_id = array (); $i = 0; while($employee_2 = mysql_fetch_array($result_2)){ $emp_login_wkgrp_id[$i] = $employee_2["wkgrp_id"]; $emp_login_grp_i