It's failing becuase $abc is not valid PHP code, but is HTML.
to get eval to work correctly, only pass it valid PHP code.
This will print "Hello World";
$abc = '
print "$Message";
';
$Message="Hello World" ;
eval ($abc) ;
If you want to output HTML, enclose it within
a print "" statement, or something similar.
> -----Original Message-----
> From: Gord Gray [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, July 18, 2001 10:32 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Making php execute php
>
>
> I would like to store a mix of php and html in a database and then return
> the results. I can't figure out how to do this.
>
> $abc='<div class="bob"><?php echo "$Message" ; ?></div>' ;
> ...
> $Message="Hello World" ;
> ...
> echo eval ($abc) ;
>
> where $abc is actually retrieved from a database.
> Does not work, but may illustrate what I am trying to accompish. If anyone
> has any hints on how I can do this, I would be very grateful.
>
> Thanks,
>
> Gord.
>
>
>
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