RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched arrays.

2002-02-24 Thread Matthew Darcy 

fixed the connection problem,

I am still getting no output to the option menu.

The output HTML page looks like this.






The Search Page








 food 
Search



 









if I do a select * from food_type_menu;
at the sql prompt it returns 4 rows. as this is the same sql query I run in
the php script I would expect it to return 4 rows also ? I am a little lost
to why my menu has no options.

Thanks,

Matt.


-Original Message-
From: Martin Towell [mailto:[EMAIL PROTECTED]]
Sent: 24 February 2002 23:43
To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


original line:
while ($row = mysql_fetch_array($results);
new line:
while ($row = mysql_fetch_array($results))

-Original Message-
From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 25, 2002 10:37 AM
To: Martin Towell; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched
arrays.Thanks Martin.

That looks perfect.
I have adaprted what you sent to use in my test application and I am getting
an error on line 22 which is the $row= line.

Take a look and see if you can spot my error as it all looks fine to me
(again )

Thanks,

Matt.







 Search for food











  food Search






 

".$row["food_type"];

}

?>











  -Original Message-
  From: Martin Towell [mailto:[EMAIL PROTECTED]]
  Sent: 24 February 2002 23:13
  To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
  Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


  try this: (I don't have experience w/ mysql, but I do with other dbs)

  
  ".$row["col2"];
  }
  ?>
  

  -Original Message-
  From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
  Sent: Monday, February 25, 2002 10:06 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] RE: (HTML related) helping to creating dropdown lists
  from fetched arrays.



  it does help a little.

  I know the html is wrong I used this as an example to what I wanted.

  What I need to know is how to use PHP to generate the options in the list
  from col1 and show the option 2.
  The data for these is got from an array.

  so really what I want to know is how to code in PHP



  
col2($row1)
col2($row2)
col2($row3)
  

  you get the idea ?

  Thanks,

  Matt.





  -Original Message-
  From: Cece [mailto:[EMAIL PROTECTED]]On Behalf Of Heilig (Cece) Szabolcs
  Sent: 24 February 2002 23:07
  To: [EMAIL PROTECTED]
  Cc: [EMAIL PROTECTED]
  Subject: OT:(HTML related) helping to creating dropdown lists from
  fetched arrays.



  > I want to create a dropdown list with options from a table.

  > 
  > $sql_select = "select * from dropdown_options";
  > $results = mysql_query($sql
  > _select);
  >
  > while ($row = mysql_fetch_array($results);
  > {
  >   echo ""
  > }

  Hi!

  The problem is simple: wrong HTML
  You have to make html code similar that:

  
female
male
not known :)
  

  Hope it helps

  Cece



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  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php



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RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched arrays.

2002-02-24 Thread Matthew Darcy 

apologies,

my fault forgot to include the dbconnect at the top of the page. I was
trying to access the database without loggin onto it.

Sorry all.

Matt.


-Original Message-
From: Martin Towell [mailto:[EMAIL PROTECTED]]
Sent: 24 February 2002 23:43
To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


original line:
while ($row = mysql_fetch_array($results);
new line:
while ($row = mysql_fetch_array($results))

-Original Message-
From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 25, 2002 10:37 AM
To: Martin Towell; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched
arrays.Thanks Martin.

That looks perfect.
I have adaprted what you sent to use in my test application and I am getting
an error on line 22 which is the $row= line.

Take a look and see if you can spot my error as it all looks fine to me
(again )

Thanks,

Matt.







 Search for food











  food Search






 

".$row["food_type"];

}

?>











  -Original Message-
  From: Martin Towell [mailto:[EMAIL PROTECTED]]
  Sent: 24 February 2002 23:13
  To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
  Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


  try this: (I don't have experience w/ mysql, but I do with other dbs)

  
  ".$row["col2"];
  }
  ?>
  

  -Original Message-
  From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
  Sent: Monday, February 25, 2002 10:06 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] RE: (HTML related) helping to creating dropdown lists
  from fetched arrays.



  it does help a little.

  I know the html is wrong I used this as an example to what I wanted.

  What I need to know is how to use PHP to generate the options in the list
  from col1 and show the option 2.
  The data for these is got from an array.

  so really what I want to know is how to code in PHP



  
col2($row1)
col2($row2)
col2($row3)
  

  you get the idea ?

  Thanks,

  Matt.





  -Original Message-
  From: Cece [mailto:[EMAIL PROTECTED]]On Behalf Of Heilig (Cece) Szabolcs
  Sent: 24 February 2002 23:07
  To: [EMAIL PROTECTED]
  Cc: [EMAIL PROTECTED]
  Subject: OT:(HTML related) helping to creating dropdown lists from
  fetched arrays.



  > I want to create a dropdown list with options from a table.

  > 
  > $sql_select = "select * from dropdown_options";
  > $results = mysql_query($sql
  > _select);
  >
  > while ($row = mysql_fetch_array($results);
  > {
  >   echo ""
  > }

  Hi!

  The problem is simple: wrong HTML
  You have to make html code similar that:

  
female
male
not known :)
  

  Hope it helps

  Cece



  --
  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php



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RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched arrays.

2002-02-24 Thread Matthew Darcy 

Getting there now...

all looks well, very tidy etc.

However my drop down box is empty ?? I know there is data in the table I am
running the select on though ???

Any ideas ?

Thanks,

Matt.


-Original Message-
From: Martin Towell [mailto:[EMAIL PROTECTED]]
Sent: 24 February 2002 23:43
To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


original line:
while ($row = mysql_fetch_array($results);
new line:
while ($row = mysql_fetch_array($results))

-Original Message-
From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 25, 2002 10:37 AM
To: Martin Towell; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched
arrays.Thanks Martin.

That looks perfect.
I have adaprted what you sent to use in my test application and I am getting
an error on line 22 which is the $row= line.

Take a look and see if you can spot my error as it all looks fine to me
(again )

Thanks,

Matt.







 Search for food











  food Search






 

".$row["food_type"];

}

?>











  -Original Message-
  From: Martin Towell [mailto:[EMAIL PROTECTED]]
  Sent: 24 February 2002 23:13
  To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
  Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


  try this: (I don't have experience w/ mysql, but I do with other dbs)

  
  ".$row["col2"];
  }
  ?>
  

  -Original Message-
  From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
  Sent: Monday, February 25, 2002 10:06 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] RE: (HTML related) helping to creating dropdown lists
  from fetched arrays.



  it does help a little.

  I know the html is wrong I used this as an example to what I wanted.

  What I need to know is how to use PHP to generate the options in the list
  from col1 and show the option 2.
  The data for these is got from an array.

  so really what I want to know is how to code in PHP



  
col2($row1)
col2($row2)
col2($row3)
  

  you get the idea ?

  Thanks,

  Matt.





  -Original Message-
  From: Cece [mailto:[EMAIL PROTECTED]]On Behalf Of Heilig (Cece) Szabolcs
  Sent: 24 February 2002 23:07
  To: [EMAIL PROTECTED]
  Cc: [EMAIL PROTECTED]
  Subject: OT:(HTML related) helping to creating dropdown lists from
  fetched arrays.



  > I want to create a dropdown list with options from a table.

  > 
  > $sql_select = "select * from dropdown_options";
  > $results = mysql_query($sql
  > _select);
  >
  > while ($row = mysql_fetch_array($results);
  > {
  >   echo ""
  > }

  Hi!

  The problem is simple: wrong HTML
  You have to make html code similar that:

  
female
male
not known :)
  

  Hope it helps

  Cece



  --
  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php



-- 
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RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched arrays.

2002-02-24 Thread Matthew Darcy 

RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched
arrays.genius - didn't notice that, forgot to close the query.

Thanks,

Matt.

  -Original Message-
  From: Martin Towell [mailto:[EMAIL PROTECTED]]
  Sent: 24 February 2002 23:43
  To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
  Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


  original line:
  while ($row = mysql_fetch_array($results);
  new line:
  while ($row = mysql_fetch_array($results))

  -Original Message-
  From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
  Sent: Monday, February 25, 2002 10:37 AM
  To: Martin Towell; [EMAIL PROTECTED]
  Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
  from fetched arrays.



  RE: [PHP] RE: (HTML related) helping to creating dropdown lists from
fetched
  arrays.Thanks Martin.

  That looks perfect.
  I have adaprted what you sent to use in my test application and I am
getting
  an error on line 22 which is the $row= line.

  Take a look and see if you can spot my error as it all looks fine to me
  (again )

  Thanks,

  Matt.

  

  

  

   Search for food

  

  

  

  

  

food Search
  

  

  

   

  ".$row["food_type"];

  }

  ?>

  

  

  

  

  

-Original Message-
From: Martin Towell [mailto:[EMAIL PROTECTED]]
Sent: 24 February 2002 23:13
To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
  from fetched arrays.



try this: (I don't have experience w/ mysql, but I do with other dbs)


".$row["col2"];
}
?>


-Original Message-
From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 25, 2002 10:06 AM
To: [EMAIL PROTECTED]
Subject: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.




it does help a little.

I know the html is wrong I used this as an example to what I wanted.

What I need to know is how to use PHP to generate the options in the
list
from col1 and show the option 2.
The data for these is got from an array.

so really what I want to know is how to code in PHP





  col2($row1)
  col2($row2)
  col2($row3)


you get the idea ?

Thanks,

Matt.






-Original Message-
From: Cece [mailto:[EMAIL PROTECTED]]On Behalf Of Heilig (Cece) Szabolcs
Sent: 24 February 2002 23:07
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: OT:(HTML related) helping to creating dropdown lists from
fetched arrays.




> I want to create a dropdown list with options from a table.

> 
> $sql_select = "select * from dropdown_options";
> $results = mysql_query($sql
> _select);
>
> while ($row = mysql_fetch_array($results);
> {
>   echo ""
> }

Hi!

The problem is simple: wrong HTML
You have to make html code similar that:


  female
  male
  not known :)


Hope it helps

Cece




--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched arrays.

2002-02-24 Thread Martin Towell 

original line:
while ($row = mysql_fetch_array($results);
new line:
while ($row = mysql_fetch_array($results))

-Original Message-
From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 25, 2002 10:37 AM
To: Martin Towell; [EMAIL PROTECTED]
Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched
arrays.Thanks Martin.

That looks perfect.
I have adaprted what you sent to use in my test application and I am getting
an error on line 22 which is the $row= line.

Take a look and see if you can spot my error as it all looks fine to me
(again )

Thanks,

Matt.







 Search for food











  food Search






 

".$row["food_type"];

}

?>











  -Original Message-
  From: Martin Towell [mailto:[EMAIL PROTECTED]]
  Sent: 24 February 2002 23:13
  To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
  Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


  try this: (I don't have experience w/ mysql, but I do with other dbs)

  
  ".$row["col2"];
  }
  ?>
  

  -Original Message-
  From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
  Sent: Monday, February 25, 2002 10:06 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] RE: (HTML related) helping to creating dropdown lists
  from fetched arrays.



  it does help a little.

  I know the html is wrong I used this as an example to what I wanted.

  What I need to know is how to use PHP to generate the options in the list
  from col1 and show the option 2.
  The data for these is got from an array.

  so really what I want to know is how to code in PHP



  
col2($row1)
col2($row2)
col2($row3)
  

  you get the idea ?

  Thanks,

  Matt.





  -Original Message-
  From: Cece [mailto:[EMAIL PROTECTED]]On Behalf Of Heilig (Cece) Szabolcs
  Sent: 24 February 2002 23:07
  To: [EMAIL PROTECTED]
  Cc: [EMAIL PROTECTED]
  Subject: OT:(HTML related) helping to creating dropdown lists from
  fetched arrays.



  > I want to create a dropdown list with options from a table.

  > 
  > $sql_select = "select * from dropdown_options";
  > $results = mysql_query($sql
  > _select);
  >
  > while ($row = mysql_fetch_array($results);
  > {
  >   echo ""
  > }

  Hi!

  The problem is simple: wrong HTML
  You have to make html code similar that:

  
female
male
not known :)
  

  Hope it helps

  Cece



  --
  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php

RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched arrays.

2002-02-24 Thread Matthew Darcy 

RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched
arrays.Thanks Martin.

That looks perfect.
I have adaprted what you sent to use in my test application and I am getting
an error on line 22 which is the $row= line.

Take a look and see if you can spot my error as it all looks fine to me
(again )

Thanks,

Matt.







 Search for food











  food Search






 

".$row["food_type"];

}

?>











  -Original Message-
  From: Martin Towell [mailto:[EMAIL PROTECTED]]
  Sent: 24 February 2002 23:13
  To: '[EMAIL PROTECTED]'; [EMAIL PROTECTED]
  Subject: RE: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


  try this: (I don't have experience w/ mysql, but I do with other dbs)

  
  ".$row["col2"];
  }
  ?>
  

  -Original Message-
  From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
  Sent: Monday, February 25, 2002 10:06 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] RE: (HTML related) helping to creating dropdown lists
  from fetched arrays.



  it does help a little.

  I know the html is wrong I used this as an example to what I wanted.

  What I need to know is how to use PHP to generate the options in the list
  from col1 and show the option 2.
  The data for these is got from an array.

  so really what I want to know is how to code in PHP



  
col2($row1)
col2($row2)
col2($row3)
  

  you get the idea ?

  Thanks,

  Matt.





  -Original Message-
  From: Cece [mailto:[EMAIL PROTECTED]]On Behalf Of Heilig (Cece) Szabolcs
  Sent: 24 February 2002 23:07
  To: [EMAIL PROTECTED]
  Cc: [EMAIL PROTECTED]
  Subject: OT:(HTML related) helping to creating dropdown lists from
  fetched arrays.



  > I want to create a dropdown list with options from a table.

  > 
  > $sql_select = "select * from dropdown_options";
  > $results = mysql_query($sql
  > _select);
  >
  > while ($row = mysql_fetch_array($results);
  > {
  >   echo ""
  > }

  Hi!

  The problem is simple: wrong HTML
  You have to make html code similar that:

  
female
male
not known :)
  

  Hope it helps

  Cece



  --
  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php

RE: [PHP] RE: (HTML related) helping to creating dropdown lists from fetched arrays.

2002-02-24 Thread Martin Towell 

try this: (I don't have experience w/ mysql, but I do with other dbs)


".$row["col2"];
}
?>


-Original Message-
From: Matthew Darcy [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 25, 2002 10:06 AM
To: [EMAIL PROTECTED]
Subject: [PHP] RE: (HTML related) helping to creating dropdown lists
from fetched arrays.


it does help a little.

I know the html is wrong I used this as an example to what I wanted.

What I need to know is how to use PHP to generate the options in the list
from col1 and show the option 2.
The data for these is got from an array.

so really what I want to know is how to code in PHP



  col2($row1)
  col2($row2)
  col2($row3)


you get the idea ?

Thanks,

Matt.




-Original Message-
From: Cece [mailto:[EMAIL PROTECTED]]On Behalf Of Heilig (Cece) Szabolcs
Sent: 24 February 2002 23:07
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: OT:(HTML related) helping to creating dropdown lists from
fetched arrays.


> I want to create a dropdown list with options from a table.

> 
> $sql_select = "select * from dropdown_options";
> $results = mysql_query($sql
> _select);
>
> while ($row = mysql_fetch_array($results);
> {
>   echo ""
> }

Hi!

The problem is simple: wrong HTML
You have to make html code similar that:


  female
  male
  not known :)


Hope it helps

Cece


-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php