Thank you, I figured it out 30 seconds after I posted the question, you
were right about the problem.
- Victor www.argilent.com
-Original Message-
From: Chris Wesley [mailto:[EMAIL PROTECTED]]
Sent: Monday, September 02, 2002 4:11 PM
To: 'PHP'
Cc: Victor
Subject: Re: [PHP] help, array values echoed as Array on loop!
On Mon, 2 Sep 2002, Victor wrote:
$ID_arr[] = explode(',', $pictures); # make db data into array
This is the string:
15,16,17,18,19
why does it echo as Array?
... because you've created an array ($ID_arr) with an array as the first
value (the result of the call to explode()). Take the brackets off
$ID_arr, and you'll get what you want. You don't want your array in an
array ... you just want an array.
$ID_arr = explode(',', $pictures);
If you really wanted your array in the array, then loop over $ID_arr[0].
(I doubt that's what you were going for, though.)
hth,
~Chris
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