>
>- Original Message -----
>From: "Martin Towell" <[EMAIL PROTECTED]>
>To: "GENERAL PHP LIST" <[EMAIL PROTECTED]>
>Sent: Wednesday, November 14, 2001 3:19 AM
>Subject: RE: [PHP] take date and convert to day of year
>
>
>>I&#x
mp as you did in your earlier codes.
- Original Message -
From: "Martin Towell" <[EMAIL PROTECTED]>
To: "GENERAL PHP LIST" <[EMAIL PROTECTED]>
Sent: Wednesday, November 14, 2001 3:19 AM
Subject: RE: [PHP] take date and convert to day of year
> I'm r
L PHP LIST
Subject: Re: [PHP] take date and convert to day of year
I have tried to implement your code Martin, and I do thank you VERY MUCH
for the help, but your code seems to have the same trouble as mine, it
doesn't matter what date I start with, I end up with 364 as the day of
the year
I have tried to implement your code Martin, and I do thank you VERY MUCH
for the help, but your code seems to have the same trouble as mine, it
doesn't matter what date I start with, I end up with 364 as the day of
the year, I am on win32 though I don't know if that matters.
Here is what I tri
looking at the manual, getdate() is meant to be passed a unix time stamp,
so, you'll need to use strtotime() first thus:
$utime = strtotime("30-Nov-1971");
$dob = getdate($utime);
$dobnum = $dob['yday'];
print $dobnum;
Notice I changed the format of the date, when I tried using the original
form
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