RE: [PHP] variable issue

2001-11-09 Thread Clint Tredway 

thanks for all the help. I realized that I did not need the else, and the isset() 
works great! Now I have my calendar working the way I want it to!

Thanks!
Clint

-- Original Message --
From: "Matthew Luchak" <[EMAIL PROTECTED]>
Date: Fri, 9 Nov 2001 15:07:22 -0500

if(!isset($dte))
{
$dte=date("j", time()+$ctime);}

You don't need the else statement.

 
Matthew Luchak 
Webmaster
Kaydara Inc. 
[EMAIL PROTECTED]


-Original Message-
From: Clint Tredway [mailto:[EMAIL PROTECTED]]
Sent: Friday, November 09, 2001 2:37 PM
To: PHP General
Subject: [PHP] variable issue


Hey everyone, I need some help with a variable issue. How can I delcare
a variable and then if a url variable of the same name is present use
that value instead?

this is what I have:
if(!$dte)
{
$dte=date("j", time()+$ctime);
}
else
{
$dte=$dte;
}
and this causing an error in the 'if' expression.

Thanks!
clint

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RE: [PHP] variable issue

2001-11-09 Thread Matthew Luchak 

if(!isset($dte))
{
$dte=date("j", time()+$ctime);}

You don't need the else statement.

 
Matthew Luchak 
Webmaster
Kaydara Inc. 
[EMAIL PROTECTED]


-Original Message-
From: Clint Tredway [mailto:[EMAIL PROTECTED]]
Sent: Friday, November 09, 2001 2:37 PM
To: PHP General
Subject: [PHP] variable issue


Hey everyone, I need some help with a variable issue. How can I delcare
a variable and then if a url variable of the same name is present use
that value instead?

this is what I have:
if(!$dte)
{
$dte=date("j", time()+$ctime);
}
else
{
$dte=$dte;
}
and this causing an error in the 'if' expression.

Thanks!
clint

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To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
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Re: [PHP] variable issue

2001-11-09 Thread R'twick Niceorgaw 

replace the if statement  if(!$dte)
with
if (!isset($dte))

- Original Message -
From: "Johnson, Kirk" <[EMAIL PROTECTED]>
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Friday, November 09, 2001 2:35 PM
Subject: RE: [PHP] variable issue


> The else clause can be removed, since it is not doing anything. What is
the
> error message?
>
> Kirk
>
> > Hey everyone, I need some help with a variable issue. How can
> > I delcare a variable and then if a url variable of the same
> > name is present use that value instead?
> >
> > this is what I have:
> > if(!$dte)
> > {
> > $dte=date("j", time()+$ctime);
> > }
> > else
> > {
> > $dte=$dte;
> > }
> > and this causing an error in the 'if' expression.
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>
>


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RE: [PHP] variable issue

2001-11-09 Thread Johnson, Kirk 

The else clause can be removed, since it is not doing anything. What is the
error message?

Kirk

> Hey everyone, I need some help with a variable issue. How can 
> I delcare a variable and then if a url variable of the same 
> name is present use that value instead?
> 
> this is what I have:
> if(!$dte)
> {
> $dte=date("j", time()+$ctime);
> }
> else
> {
> $dte=$dte;
> }
> and this causing an error in the 'if' expression.

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