Re: [PHP] include question
Daniel Brown wrote: On Fri, Mar 6, 2009 at 08:53, Stuart stut...@gmail.com wrote: 1.) We use regular open tags to be compatible with all stock PHP configurations. 2.) We echo out the response from dirname() so that it's output to the HTML source. 3.) We use dirname() twice, so it gives the dirname() of the dirname(), rather than '..'. 4.) There are double underscores around FILE. The same is true with LINE, FUNCTION, etc. 5.) dirname() gives you the full path on disk, not the URL. Usually you can just remove the document root path to get the URL. This could be in $_SERVER['DOCUMENT_ROOT'] but you can't rely on that between servers or when the config changes. 6.) When used in conjunction with realpath()[1], it will resolve the absolute local pathname. ^1: http://php.net/realpath that's the way i do it, for example require_once realpath( dirname(__FILE__) . '/lib/LibAllTests.php' ); also I often use set_include_path to ensure everything works throughout, it's a lot simpler for require/includes set_include_path( get_include_path() . PATH_SEPARATOR . realpath( dirname(__FILE__) . DIRECTORY_SEPARATOR ) ); for example.. then all subsequent requires will be: require_once 'Folder/file.php'; regards -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
On Fri, Mar 6, 2009 at 08:37, PJ af.gour...@videotron.ca wrote: good morning all, How can I include src and href in include files that will refer the right paths from files in different hierarchies(directory tree levels)? Example: include dirname(_FILE_)./../lib/header1.php; ? This does not work: snippetysnip... LINK href=dirname(_FILE_).'/../lib/index.css' rel=stylesheet type=text/css /head Nor does this: (NOTE THE DIFFERENCES AND ' IN THE SRC AND HREF) div id=frame IMG SRC=dirname(_FILE_)./../images/bannerbae1.gif ...snippetysnip Perhaps it's not possible? It is when it's parsed by PHP. You're just putting it through as straight HTML, which - even though it may have a .php extension - won't work as you might be expecting. Instead, you have to instruct the parsing engine where and when to interpret, compile, and execute the code, like so: img src=?php echo dirname(dirname(__FILE__)); ?/images/bannerbae1.gif In the above snippet, notice a few very important things: 1.) We use regular open tags to be compatible with all stock PHP configurations. 2.) We echo out the response from dirname() so that it's output to the HTML source. 3.) We use dirname() twice, so it gives the dirname() of the dirname(), rather than '..'. 4.) There are double underscores around FILE. The same is true with LINE, FUNCTION, etc. -- /Daniel P. Brown daniel.br...@parasane.net || danbr...@php.net http://www.parasane.net/ || http://www.pilotpig.net/ 50% Off All Shared Hosting Plans at PilotPig: Use Coupon DOW1 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
2009/3/6 Daniel Brown danbr...@php.net On Fri, Mar 6, 2009 at 08:37, PJ af.gour...@videotron.ca wrote: good morning all, How can I include src and href in include files that will refer the right paths from files in different hierarchies(directory tree levels)? Example: include dirname(_FILE_)./../lib/header1.php; ? This does not work: snippetysnip... LINK href=dirname(_FILE_).'/../lib/index.css' rel=stylesheet type=text/css /head Nor does this: (NOTE THE DIFFERENCES AND ' IN THE SRC AND HREF) div id=frame IMG SRC=dirname(_FILE_)./../images/bannerbae1.gif ...snippetysnip Perhaps it's not possible? It is when it's parsed by PHP. You're just putting it through as straight HTML, which - even though it may have a .php extension - won't work as you might be expecting. Instead, you have to instruct the parsing engine where and when to interpret, compile, and execute the code, like so: img src=?php echo dirname(dirname(__FILE__)); ?/images/bannerbae1.gif In the above snippet, notice a few very important things: 1.) We use regular open tags to be compatible with all stock PHP configurations. 2.) We echo out the response from dirname() so that it's output to the HTML source. 3.) We use dirname() twice, so it gives the dirname() of the dirname(), rather than '..'. 4.) There are double underscores around FILE. The same is true with LINE, FUNCTION, etc. 5.) dirname() gives you the full path on disk, not the URL. Usually you can just remove the document root path to get the URL. This could be in $_SERVER['DOCUMENT_ROOT'] but you can't rely on that between servers or when the config changes. -Stuart -- http://stut.net/
Re: [PHP] include question
On Fri, Mar 6, 2009 at 08:53, Stuart stut...@gmail.com wrote: 1.) We use regular open tags to be compatible with all stock PHP configurations. 2.) We echo out the response from dirname() so that it's output to the HTML source. 3.) We use dirname() twice, so it gives the dirname() of the dirname(), rather than '..'. 4.) There are double underscores around FILE. The same is true with LINE, FUNCTION, etc. 5.) dirname() gives you the full path on disk, not the URL. Usually you can just remove the document root path to get the URL. This could be in $_SERVER['DOCUMENT_ROOT'] but you can't rely on that between servers or when the config changes. 6.) When used in conjunction with realpath()[1], it will resolve the absolute local pathname. ^1: http://php.net/realpath -- /Daniel P. Brown daniel.br...@parasane.net || danbr...@php.net http://www.parasane.net/ || http://www.pilotpig.net/ 50% Off All Shared Hosting Plans at PilotPig: Use Coupon DOW1 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
Daniel Brown wrote: On Fri, Mar 6, 2009 at 08:53, Stuart stut...@gmail.com wrote: 1.) We use regular open tags to be compatible with all stock PHP configurations. 2.) We echo out the response from dirname() so that it's output to the HTML source. 3.) We use dirname() twice, so it gives the dirname() of the dirname(), rather than '..'. 4.) There are double underscores around FILE. The same is true with LINE, FUNCTION, etc. 5.) dirname() gives you the full path on disk, not the URL. Usually you can just remove the document root path to get the URL. This could be in $_SERVER['DOCUMENT_ROOT'] but you can't rely on that between servers or when the config changes. 6.) When used in conjunction with realpath()[1], it will resolve the absolute local pathname. ^1: http://php.net/realpath Sorry, guys, but none of this works... I get the document root which is wonderful but it misses the vhost root completely. So what I get both with realpath and $SERVER['DOCUMENT_ROOT']is /usr/local/www/apache22/data/images/file.gif or /usr/local/www/apache22/data/../images/file.gif and that, of course misses the main directory for this site which is ptahhotep In /ptahhotep/file.php - the path for the image.gif is images/image.gif In /ptahhotep/admin/another_file.php/ the path for the image.gif is ../images/image.gif But as I try different variations, I finally see that adding the root directory name for the site does the trick. Have I discovered something new here? :-) -- unheralded genius: A clean desk is the sign of a dull mind. - Phil Jourdan --- p...@ptahhotep.com http://www.ptahhotep.com http://www.chiccantine.com/andypantry.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
On Mon, May 8, 2006 1:42 pm, PHP wrote: Normally I would, except that file does a lot of work, and it was too much to have on the same server. That is why I was including it remotely. Unless the remote server is HUMUNGOUS compared to the original server, or it just has nothing else to do but run this one script, methinks you aren't fixing anything useful... Which is evidenced by the fact that it's timing out. Maybe you need to try a different tack. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include() question
[snip] I am including a page from another server: (include(http://;)); Works fine, but if for some reason that server is not responding, the page that is calling it also never returns, so the user ends up with a time out. Is there something I can set that will not force the calling server to wait indefinetely for the remote server to respond, and just continue on? [/snip] This is; a. A Bad Thing [tm] 2. RTFM http://www.php.net/include Remote file may be processed at the remote server (depending on the file extension and the fact if the remote server runs PHP or not) but it still has to produce a valid PHP script because it will be processed at the local server. If the file from the remote server should be processed there and outputted only, readfile() is much better function to use. Otherwise, special care should be taken to secure the remote script to produce a valid and desired code. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
On Mon, May 8, 2006 12:55 pm, PHP wrote:
I am including a page from another server: (include(http://;));
Works fine, but if for some reason that server is not responding, the
page that is calling it also never returns, so the user ends up with a
time out.
Is there something I can set that will not force the calling server to
wait indefinetely for the remote server to respond, and just continue
on?
Try this:
$old = ini_set('default_socket_timeout', 0); //wait forever
include http://...;;
ini_set('default_socket_timeout', $old);
No promise it will work.
--
Like Music?
http://l-i-e.com/artists.htm
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Yeah... The page does produce valid code. However, the manual didn't say anything about timing out. - Original Message - From: Jay Blanchard [EMAIL PROTECTED] To: PHP [EMAIL PROTECTED]; php php-general@lists.php.net Sent: Monday, May 08, 2006 11:05 AM Subject: RE: [PHP] include() question [snip] I am including a page from another server: (include(http://;)); Works fine, but if for some reason that server is not responding, the page that is calling it also never returns, so the user ends up with a time out. Is there something I can set that will not force the calling server to wait indefinetely for the remote server to respond, and just continue on? [/snip] This is; a. A Bad Thing [tm] 2. RTFM http://www.php.net/include Remote file may be processed at the remote server (depending on the file extension and the fact if the remote server runs PHP or not) but it still has to produce a valid PHP script because it will be processed at the local server. If the file from the remote server should be processed there and outputted only, readfile() is much better function to use. Otherwise, special care should be taken to secure the remote script to produce a valid and desired code. -- No virus found in this outgoing message. Checked by AVG Free Edition. Version: 7.1.392 / Virus Database: 268.5.5/333 - Release Date: 5/5/2006 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Hey, what do you know, readfile() times out too. - Original Message - From: Jay Blanchard [EMAIL PROTECTED] To: PHP [EMAIL PROTECTED]; php php-general@lists.php.net Sent: Monday, May 08, 2006 11:05 AM Subject: RE: [PHP] include() question [snip] I am including a page from another server: (include(http://;)); Works fine, but if for some reason that server is not responding, the page that is calling it also never returns, so the user ends up with a time out. Is there something I can set that will not force the calling server to wait indefinetely for the remote server to respond, and just continue on? [/snip] This is; a. A Bad Thing [tm] 2. RTFM http://www.php.net/include Remote file may be processed at the remote server (depending on the file extension and the fact if the remote server runs PHP or not) but it still has to produce a valid PHP script because it will be processed at the local server. If the file from the remote server should be processed there and outputted only, readfile() is much better function to use. Otherwise, special care should be taken to secure the remote script to produce a valid and desired code. -- No virus found in this outgoing message. Checked by AVG Free Edition. Version: 7.1.392 / Virus Database: 268.5.5/333 - Release Date: 5/5/2006 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Bad programmer! No Donut! Just out of curiosity, why not just rsync the file over or copy it straight to the server you are running? That way you don't have to worry about it going missing. No telling when a server HD might go t*ts up and you'll be left holding the bag(s). Wolf PHP wrote: Hi, I am including a page from another server: (include(http://;)); SNIP! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Normally I would, except that file does a lot of work, and it was too much to have on the same server. That is why I was including it remotely. - Original Message - From: Wolf [EMAIL PROTECTED] To: PHP [EMAIL PROTECTED] Cc: php php-general@lists.php.net Sent: Monday, May 08, 2006 11:21 AM Subject: Re: [PHP] include() question Bad programmer! No Donut! Just out of curiosity, why not just rsync the file over or copy it straight to the server you are running? That way you don't have to worry about it going missing. No telling when a server HD might go t*ts up and you'll be left holding the bag(s). Wolf PHP wrote: Hi, I am including a page from another server: (include(http://;)); SNIP! -- No virus found in this outgoing message. Checked by AVG Free Edition. Version: 7.1.392 / Virus Database: 268.5.5/333 - Release Date: 5/5/2006 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Sounds like a good reason to lobby for new hardware!! :) Also sounds like why it might be timing out for you as well. Depending on how core that file is to your business and online presence (and they both matter equally), you might want to look at investing in new hardware for the server(s) so that the load can be distributed and such. From everything I have read, this sounds more like your solution then not getting that page's information. Just my $.02 Wolf PHP wrote: Normally I would, except that file does a lot of work, and it was too much to have on the same server. That is why I was including it remotely. SNIP! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include question
Thanks, worked wonders.
--
Aaron Axelsen
Email: [EMAIL PROTECTED]
-Original Message-
From: Greg Donald [mailto:[EMAIL PROTECTED]
Sent: Monday, June 21, 2004 10:40 AM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] include question
On Mon, 21 Jun 2004 10:31:42 -0500 (CDT), Aaron Axelsen [EMAIL PROTECTED]
wrote:
Below is the chunk of code i am using. In the verify_faculty_info.php
file i call the search function. The search function is coded in the
function.php file which is included in the accesscontrol.php.
I thought that it would carry over to the verify_Faculty_info.php file.
Was I mistaken?
Thanks
?php
include('accesscontrol.php');
if (isset($_GET['action'])){
if ($_GET['action'] == add $_SESSION['role'] == 1) {
include('includes/add_product.php');
} elseif ($_GET['action'] == verify) {
echo verifying now;
search();
include('includes/verify_faculty_info.php');
} else {
echo action asked for is not specified; } } else {
echo action is not specified;
}
?
Looks like it would work to me. You might try function_exists() to help
track down the problem. Probably a typo or mispelled function name.
--
Greg Donald
http://destiney.com/
--
PHP General Mailing List (http://www.php.net/) To unsubscribe, visit:
http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
On Mon, 21 Jun 2004 10:31:42 -0500 (CDT), Aaron Axelsen
[EMAIL PROTECTED] wrote:
Below is the chunk of code i am using. In the verify_faculty_info.php
file i call the search function. The search function is coded in the
function.php file which is included in the accesscontrol.php.
I thought that it would carry over to the verify_Faculty_info.php file.
Was I mistaken?
Thanks
?php
include('accesscontrol.php');
if (isset($_GET['action'])){
if ($_GET['action'] == add $_SESSION['role'] == 1) {
include('includes/add_product.php');
} elseif ($_GET['action'] == verify) {
echo verifying now;
search();
include('includes/verify_faculty_info.php');
} else {
echo action asked for is not specified;
}
} else {
echo action is not specified;
}
?
Looks like it would work to me. You might try function_exists() to
help track down the problem. Probably a typo or mispelled function
name.
--
Greg Donald
http://destiney.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
Aaron,
I copied your code to a test file called test.php and created the following
pages as dummy includes:
verify_faculty_info.php, functions.php and accesscontrol.php
in functions.php, I created a dummy search function:
function search(){
return Found!BR;
}
in verify_faculty_info.php, I made a call to the search function thusly:
echo search();
the test page, when called with the action=verify outputs the following:
verifying nowFound!
Found!
If you are not getting the output you are expecting, it probably isn't
because of a function not being available, but more like variables are not
available to the function.
Are you getting any error messages at all?
Keith
At 08:31 AM 6/21/2004, Aaron Axelsen wrote:
Below is the chunk of code i am using. In the verify_faculty_info.php
file i call the search function. The search function is coded in the
function.php file which is included in the accesscontrol.php.
I thought that it would carry over to the verify_Faculty_info.php file.
Was I mistaken?
Thanks
?php
include('accesscontrol.php');
if (isset($_GET['action'])){
if ($_GET['action'] == add $_SESSION['role'] == 1) {
include('includes/add_product.php');
} elseif ($_GET['action'] == verify) {
echo verifying now;
search();
include('includes/verify_faculty_info.php');
} else {
echo action asked for is not specified;
}
} else {
echo action is not specified;
}
?
--
Aaron Axelsen
aim: aaak2
email: [EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
Hi Blake, If you're using Apache, try this: http://ca3.php.net/virtual Cheers, Lux On Friday, June 27, 2003, at 01:05 PM, Blake Schroeder wrote: Hey all I used to include a perl script via Sever Side Include how could I do this in php? example: !--#include virtual= /cgi-bin/something.pl?data=something-- -- Blake Schroeder [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- John Luxford President and Chief Developer __ SIMIAN systems Driving Web Content Management __ web : http://www.simian.ca/ email : [EMAIL PROTECTED] phone : 204.942.8630 fax : 309.218.3874 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include question
[snip] I used to include a perl script via Sever Side Include how could I do this in php? example: !--#include virtual= /cgi-bin/something.pl?data=something-- [/snip] exec(/cgi-bin/something.pl?data=something); HTH -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
Blake Schroeder wrote: Hey all I used to include a perl script via Sever Side Include how could I do this in php? example: !--#include virtual= /cgi-bin/something.pl?data=something-- You can't use SSI in PHP. PHP is not SSI. You can do something similar though, www.php.net/virtual. -- The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Include Question
Just a typo, but now I have other problems as well which I think have to do
with paths and includes. If I am in the root directory on page main.html
and click on a link that is in /other - because this is a restricted page I
include main.html with an error (which right now doesn't display) - but now
the paths are all screwed up. If I click on the same link again I get file
not found. Hope I am explaining this right as this is really getting on my
nerves.
TIA
- Original Message -
From: James E Hicks III [EMAIL PROTECTED]
To: Beauford.2002 [EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 4:15 PM
Subject: RE: [PHP] Include Question
If checklogin.php is only below, you shouldnn't get those errors. Anyway,
is password just a typo below or does your code omit the $ too?
if (!$name || !password) {
$message = $enter_info;
include (login.php);
exit;
}
-Original Message-
From: Beauford.2002 [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 4:07 PM
To: James E Hicks III
Subject: Re: [PHP] Include Question
Because I would get the error - headers already sent etc.
- Original Message -
From: James E Hicks III [EMAIL PROTECTED]
To: Beauford.2002 [EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 3:53 PM
Subject: RE: [PHP] Include Question
Why not try header(login.php) instead of include?
James Hicks
-Original Message-
From: Beauford.2002 [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 3:47 PM
To: PHP General
Subject: [PHP] Include Question
Hi,
First, I fixed my other problem of the stack overflow by moving the
files
back to the root directory (although I would rather have them in a login
directory). Anyway, I have a question regarding the include function. I
have
a login script in a file called login.php - in this file it includes
checklogin.php and loginerrors.php. If the user inputs an incorrect
login
I
assign $messages the appropriate error from loginerrors, then I
re-include
login.php where I want to show the error message, but no matter what I
do
the error message will not show up.
Example.
Login.php
Enter your Name:
Enter Your Password:
if ($message) { echo $message; }
Checklogin.php
if (!$name || !password) {
$message = $enter_info;
include (login.php);
exit;
}
Any help is appreciated.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Include Question
If your include is located somewhere on the site you should refer to it as
$_SERVER[DOCUMENT_ROOT]/pathtofile/filename.php so that your paths don't get
messed up from chaning the includes etc.
-Original Message-
From: Beauford.2002 [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 2:28 PM
To: James E Hicks III
Cc: PHP General
Subject: Re: [PHP] Include Question
Just a typo, but now I have other problems as well which I think have to do
with paths and includes. If I am in the root directory on page main.html
and click on a link that is in /other - because this is a restricted page I
include main.html with an error (which right now doesn't display) - but now
the paths are all screwed up. If I click on the same link again I get file
not found. Hope I am explaining this right as this is really getting on my
nerves.
TIA
- Original Message -
From: James E Hicks III [EMAIL PROTECTED]
To: Beauford.2002 [EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 4:15 PM
Subject: RE: [PHP] Include Question
If checklogin.php is only below, you shouldnn't get those errors. Anyway,
is password just a typo below or does your code omit the $ too?
if (!$name || !password) {
$message = $enter_info;
include (login.php);
exit;
}
-Original Message-
From: Beauford.2002 [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 4:07 PM
To: James E Hicks III
Subject: Re: [PHP] Include Question
Because I would get the error - headers already sent etc.
- Original Message -
From: James E Hicks III [EMAIL PROTECTED]
To: Beauford.2002 [EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 3:53 PM
Subject: RE: [PHP] Include Question
Why not try header(login.php) instead of include?
James Hicks
-Original Message-
From: Beauford.2002 [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 27, 2003 3:47 PM
To: PHP General
Subject: [PHP] Include Question
Hi,
First, I fixed my other problem of the stack overflow by moving the
files
back to the root directory (although I would rather have them in a login
directory). Anyway, I have a question regarding the include function. I
have
a login script in a file called login.php - in this file it includes
checklogin.php and loginerrors.php. If the user inputs an incorrect
login
I
assign $messages the appropriate error from loginerrors, then I
re-include
login.php where I want to show the error message, but no matter what I
do
the error message will not show up.
Example.
Login.php
Enter your Name:
Enter Your Password:
if ($message) { echo $message; }
Checklogin.php
if (!$name || !password) {
$message = $enter_info;
include (login.php);
exit;
}
Any help is appreciated.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
It would probably be best to include the absolute path to the images. so instead of: img src=file.gif use: img src='c:\project\htmls\file.gif' Is something like that possible? Otherwise at the very least you should use: img src='htmls\file.gif' HTH -Brad Ryan wrote: Hello all, I'm have a PHP script that works in a folder.. for the sake of clarity we'll call it c:\project In c:\project\htmls there are several HTML documents which refer to images in the project\htmls directory with tags like img src=file.gif In my PHP script in c:\project I include htmls/file.html and the HTML file renders alright from the script, but the image's path is c:\project\file.gif when the page is rendered, not c:\project\htmls\file.gif like it should be. Is there any way to change the working directory so when I include a file images are on the page, too? Thanks in advance! -- Ryan Cassin [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include question
No unfortunately something like that isn't possible... The HTML files are generated by a closed-source application. -Original Message- From: Brad Bonkoski [mailto:[EMAIL PROTECTED]] Sent: Wednesday, January 15, 2003 5:04 PM To: Ryan Cc: [EMAIL PROTECTED] Subject: Re: [PHP] include question It would probably be best to include the absolute path to the images. so instead of: img src=file.gif use: img src='c:\project\htmls\file.gif' Is something like that possible? Otherwise at the very least you should use: img src='htmls\file.gif' HTH -Brad Ryan wrote: Hello all, I'm have a PHP script that works in a folder.. for the sake of clarity we'll call it c:\project In c:\project\htmls there are several HTML documents which refer to images in the project\htmls directory with tags like img src=file.gif In my PHP script in c:\project I include htmls/file.html and the HTML file renders alright from the script, but the image's path is c:\project\file.gif when the page is rendered, not c:\project\htmls\file.gif like it should be. Is there any way to change the working directory so when I include a file images are on the page, too? Thanks in advance! -- Ryan Cassin [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
[EMAIL PROTECTED] (Brad Bonkoski) wrote: It would probably be best to include the absolute path to the images. so instead of: img src=file.gif use: img src='c:\project\htmls\file.gif' Is something like that possible? ??? forget this... this will only work on some browsers and as long as you keep the files exactly there. Otherwise at the very least you should use: img src='htmls\file.gif' img src=htmls/file.gif (slash instead of back slash). In c:\project\htmls there are several HTML documents which refer to images in the project\htmls directory with tags like img src=file.gif In my PHP script in c:\project I include htmls/file.html and the HTML file renders alright from the script, but the image's path is c:\project\file.gif when the page is rendered, not c:\project\htmls\file.gif like it should be. If you include a file into a php script like you do, the HTML-paths will be relative to that php script, not to the original HTML-file. PHP includes the file as is (imagine it puts the HTML code at the place of the include statement) The browser does not know that there is another HTML file, it only sees the output of the php script. Christoph -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
Variables don't get parsed in single quotes, use double quotes. RClark wrote: Hello all, I am passing a variable like so: a href=link.php?foo=bar.php On the link.php page, I have this simple code: ?php $job = $_GET['foo']; echo $job; // for error checking include 'path/to/$job'; ? The 'echo $job;' statement works just fine, but the outbout for the include statement looks like this: bar.php Warning: Failed opening 'scripts/$job' for inclusion (include_path='.:/usr/local/lib/php') in /usr/local/www/data-dist/link.php on line 142 Can I not use a $variable in an include 'something.php '; statement? Thanks in advance, Ron Clark -- The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
Hi, Friday, December 13, 2002, 12:07:05 AM, you wrote: R Hello all, R I am passing a variable like so: R a href=link.php?foo=bar.php R On the link.php page, I have this simple code: R ?php R $job = $_GET['foo']; R echo $job; // for error checking R include 'path/to/$job'; ? R The 'echo $job;' statement works just fine, but the outbout for the R include statement looks like this: R bar.php R Warning: Failed opening 'scripts/$job' for inclusion R (include_path='.:/usr/local/lib/php') in /usr/local/www/data-dist/link.php R on line 142 R Can I not use a $variable in an include 'something.php '; statement? R Thanks in advance, R Ron Clark You have to use double quotes like: include path/to/$job or add like this: include 'path/to/'.$job -- regards, Tom -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include question
Thanks! Works perfect with double quotes! RC -Original Message- From: Tom Rogers [mailto:[EMAIL PROTECTED]] Sent: Thursday, December 12, 2002 8:21 AM To: Ronald Clark Cc: [EMAIL PROTECTED] Subject: Re: [PHP] include question Hi, Friday, December 13, 2002, 12:07:05 AM, you wrote: R Hello all, R I am passing a variable like so: R a href=link.php?foo=bar.php R On the link.php page, I have this simple code: R ?php R $job = $_GET['foo']; R echo $job; // for error checking R include 'path/to/$job'; ? R The 'echo $job;' statement works just fine, but the outbout for the R include statement looks like this: bar.php R Warning: Failed opening 'scripts/$job' for inclusion R (include_path='.:/usr/local/lib/php') in /usr/local/www/data-dist/link.php R on line 142 R Can I not use a $variable in an include 'something.php '; statement? R Thanks in advance, R Ron Clark You have to use double quotes like: include path/to/$job or add like this: include 'path/to/'.$job -- regards, Tom CONFIDENTIALITY NOTICE: The information contained in this ELECTRONIC MAIL transmission is confidential. It may also be privileged work product or proprietary information. This information is intended for the exclusive use of the addressee(s). If you are not the intended recipient, you are hereby notified that any use, disclosure, dissemination, distribution [other than to the addressee(s)], copying or taking of any action because of this information is strictly prohibited.
Re: [PHP] include() question...
use header ob_start() $temp = website.php?var=.$var; header (Location: $temp); Puru - Original Message - From: Phil Schwarzmann [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, June 20, 2002 4:31 PM Subject: [PHP] include() question... Okay, let's say I want to send a user to a certain webpage... usually I would use... include(website.php); but, if i want to send a user to a website along with a variable like... $temp = website.php?var=.$var; include($temp); ...this doesn't work. any suggestions?? THANKS!! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question...
but, if i want to send a user to a website along with a variable like... $temp = website.php?var=.$var; include($temp); ...this doesn't work. Example: ?php $var = 'foo'; include 'somefile.php'; ? somefile.php now has access to $var. This is talked about in the manual too: http://www.php.net/include In your case above, $var will already be available to website.php if you simply include it. Regards, Philip Olson -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include() question...
Okay, let's say I want to send a user to a certain webpage... usually I would use... include(website.php); but, if i want to send a user to a website along with a variable like... $temp = website.php?var=.$var; include($temp); ...this doesn't work. If you are just including the file in what's already loading then all you need to do is make sure that $var is already set when you include the file. Including is logically the same as opening up the other file and then doing a copy/paste into the current page. It's exactly the same as if the contents of your included file was in the file that's doing the including. If you are actually trying to load a new page and pass a variable to it then you probably want to look at using header(Location: website.php?var=$var); instead. This will actually load a whole new page in the browser rather than just including an extra file in a page that's already being loaded. CYA, Dave -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Include question
Umm...that's what it's supposed to do...it's including it... ---John Holmes... -Original Message- From: Tom Ray [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 11, 2002 9:29 PM To: [EMAIL PROTECTED] Subject: [PHP] Include question I'm trying to use the include function in some PHP scripts, but when I do include 'config.inc'; or include 'config.php; It returns all the information in the file when I look at my test php file (which calls the include) Anyone know why this is? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Include question
Yes, but according to http://www.php.net/manual/en/function.include.php I should be able to delcare the include and then pull the information out normally. So by what the manual says I can do this somefile.php ? $apple = 'green'; $pear = 'yellow'; ? callfile.php ? include 'somefile.php'; echo Apples are $apple and Pears are $pear; \\ which would return the line with green and yellow in the correct spots. ? But when I just do ? include 'somefile.php'; ? It prints: $apple = 'green'; $pear = 'yellow': Why is that? John Holmes wrote: Umm...that's what it's supposed to do...it's including it... ---John Holmes... -Original Message- From: Tom Ray [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 11, 2002 9:29 PM To: [EMAIL PROTECTED] Subject: [PHP] Include question I'm trying to use the include function in some PHP scripts, but when I do include 'config.inc'; or include 'config.php; It returns all the information in the file when I look at my test php file (which calls the include) Anyone know why this is? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php . -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Include question
Check that you actually have ? ? wrapped around the PHP code in somefile.php that you include. Justin French on 12/06/02 11:36 AM, Tom Ray ([EMAIL PROTECTED]) wrote: Yes, but according to http://www.php.net/manual/en/function.include.php I should be able to delcare the include and then pull the information out normally. So by what the manual says I can do this somefile.php ? $apple = 'green'; $pear = 'yellow'; ? callfile.php ? include 'somefile.php'; echo Apples are $apple and Pears are $pear; \\ which would return the line with green and yellow in the correct spots. ? But when I just do ? include 'somefile.php'; ? It prints: $apple = 'green'; $pear = 'yellow': Why is that? John Holmes wrote: Umm...that's what it's supposed to do...it's including it... ---John Holmes... -Original Message- From: Tom Ray [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 11, 2002 9:29 PM To: [EMAIL PROTECTED] Subject: [PHP] Include question I'm trying to use the include function in some PHP scripts, but when I do include 'config.inc'; or include 'config.php; It returns all the information in the file when I look at my test php file (which calls the include) Anyone know why this is? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php . -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Include question
Tom, just did ur test on win2k php 4.2.1 with apache and when i just did .. ? include 'somefile.php'; ? i get a blank screen as I should the only way you should be getting anything is by calling the values... -Original Message- From: Tom Ray [mailto:[EMAIL PROTECTED]] Sent: Wednesday, 12 June 2002 11:36 AM To: [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: Re: [PHP] Include question Yes, but according to http://www.php.net/manual/en/function.include.php I should be able to delcare the include and then pull the information out normally. So by what the manual says I can do this somefile.php ? $apple = 'green'; $pear = 'yellow'; ? callfile.php ? include 'somefile.php'; echo Apples are $apple and Pears are $pear; \\ which would return the line with green and yellow in the correct spots. ? But when I just do ? include 'somefile.php'; ? It prints: $apple = 'green'; $pear = 'yellow': Why is that? John Holmes wrote: Umm...that's what it's supposed to do...it's including it... ---John Holmes... -Original Message- From: Tom Ray [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 11, 2002 9:29 PM To: [EMAIL PROTECTED] Subject: [PHP] Include question I'm trying to use the include function in some PHP scripts, but when I do include 'config.inc'; or include 'config.php; It returns all the information in the file when I look at my test php file (which calls the include) Anyone know why this is? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php . -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Include question
Well I got it solved. It would help if I formatted my files correctly. Sorry about that, i've been messing with PHP for about a year now, but am now really diving into it so I may have stupid questions here and there :) TIA to all for help. John Holmes wrote: Umm...that's what it's supposed to do...it's including it... ---John Holmes... -Original Message- From: Tom Ray [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 11, 2002 9:29 PM To: [EMAIL PROTECTED] Subject: [PHP] Include question I'm trying to use the include function in some PHP scripts, but when I do include 'config.inc'; or include 'config.php; It returns all the information in the file when I look at my test php file (which calls the include) Anyone know why this is? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Include question
somefile.php ? $apple = 'green'; $pear = 'yellow'; ? callfile.php ? include 'somefile.php'; echo Apples are $apple and Pears are $pear; \\ which would return the line with green and yellow in the correct spots. ? But when I just do ? include 'somefile.php'; ? It prints: $apple = 'green'; $pear = 'yellow': Looks to me like your include file isn't being interpreted as php for some reason. Is the information here your exact test case or is it different. Certainly, as you've got it here, it would work - at least it does for the numerous php projects I've done. CYA, Dave -- -- Outback Queensland Internet Longreach ** New Web Site Online * Queensland Australia W: www.outbackqld.net.au -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Include question
You're right, that wouldn't prove my point. However, you might try a
little piece of code like the following:
?
$a=foo;
$b=bar;
$c=foobar;
if ($a==foo) {
include($b.php);
} else {
include($c.php);
}
?
I hope this proves that includes are included at runtime because PHP
wouldn't know what $b and $c are beforehand. Apart from that, I'm
positive I read about it in a man page, but can't recall which, that's
why I didn't direct you to it ;-)
Bogdan
John Holmes wrote:
The global var wouldn't work. Even if both are loaded into memory before
the script is ran, only one include will actually be executed along with
the code, so only one would end up affecting a global var either way.
What I'm looking at is if each include .html file is 50K, am I loading
100K into memory and then running the script, or running the script and
only loading the appropriate 50K into memory when it's needed?
---John Holmes...
-Original Message-
From: Bogdan Stancescu [mailto:[EMAIL PROTECTED]]
Sent: Saturday, June 01, 2002 11:12 PM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Include question
Your second guess. But you could've tested it easily with two includes
appending stuff to the same global var.
Bogdan
John Holmes wrote:
Hi. When I've got code like the following:
if($this) { include(this.html); }
elseif($that) { include(that.html); }
When are the includes() evaluated? Does the Zend engine do the
includes
first, pull in all of the code, then process it and produce output.
Or
does the engine start processing the code and only load the includes
when it gets to them?
Thanks for any explanations.
---John Holmes.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Include question
Hey John: On Sun, Jun 02, 2002 at 12:10:27AM -0400, John Holmes wrote: What I'm looking at is if each include .html file is 50K, am I loading 100K into memory and then running the script, or running the script and only loading the appropriate 50K into memory when it's needed? As of 4.0.2, stuff is only loaded when it's needed. So, in your example, only 50k is brought in. Note, this is yet another case where it pays for me to read the manual before posting! I was still thinking in the old way, where include() was conditional and require() was always done. Ciao! --Dan -- PHP classes that make web design easier SQL Solution | Layout Solution | Form Solution sqlsolution.info | layoutsolution.info | formsolution.info T H E A N A L Y S I S A N D S O L U T I O N S C O M P A N Y 4015 7 Av #4AJ, Brooklyn NY v: 718-854-0335 f: 718-854-0409 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Include question
Your second guess. But you could've tested it easily with two includes
appending stuff to the same global var.
Bogdan
John Holmes wrote:
Hi. When I've got code like the following:
if($this) { include(this.html); }
elseif($that) { include(that.html); }
When are the includes() evaluated? Does the Zend engine do the includes
first, pull in all of the code, then process it and produce output. Or
does the engine start processing the code and only load the includes
when it gets to them?
Thanks for any explanations.
---John Holmes.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Include question
The global var wouldn't work. Even if both are loaded into memory before
the script is ran, only one include will actually be executed along with
the code, so only one would end up affecting a global var either way.
What I'm looking at is if each include .html file is 50K, am I loading
100K into memory and then running the script, or running the script and
only loading the appropriate 50K into memory when it's needed?
---John Holmes...
-Original Message-
From: Bogdan Stancescu [mailto:[EMAIL PROTECTED]]
Sent: Saturday, June 01, 2002 11:12 PM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Include question
Your second guess. But you could've tested it easily with two includes
appending stuff to the same global var.
Bogdan
John Holmes wrote:
Hi. When I've got code like the following:
if($this) { include(this.html); }
elseif($that) { include(that.html); }
When are the includes() evaluated? Does the Zend engine do the
includes
first, pull in all of the code, then process it and produce output.
Or
does the engine start processing the code and only load the includes
when it gets to them?
Thanks for any explanations.
---John Holmes.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include() question
Try to simplify the problem $file='index.php?var='; $file.=$var; include($file); -Original Message- From: Phil Schwarzmann [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 14, 2002 1:20 PM To: [EMAIL PROTECTED] Subject: [PHP] include() question Why doesn't this work... include(index.php?var='$var'); I want to include a page in my code and send a variable to it but I get some funky error. THANKS!! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
you can't use a variable as a parameter for the included file... because
include does nothing else then putting the text of the include file on the
place of the include statement...
so this should work:
$var = 'bladibla';
include('index.php');
Greets,
Edward
- Original Message -
From: Phil Schwarzmann [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, March 14, 2002 10:20 PM
Subject: [PHP] include() question
Why doesn't this work...
include(index.php?var='$var');
I want to include a page in my code and send a variable to it but I get
some funky error.
THANKS!!
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
On Thursday, March 14, 2002, at 04:34 PM, Edward van Bilderbeek - Bean IT wrote: you can't use a variable as a parameter for the included file... because include does nothing else then putting the text of the include file on the place of the include statement... Are you sure about this? I'm almost positive that PHP is flexible about accepting variables or strings as function arguments in most cases. I just tested it, and it seems to work fine... $includefile = './leftnavigation.inc'; include($includefile); I posted a question on this list about a month ago, and someone said that you can use variables or strings in many cases -- just remember that the variable expands to the string BEFORE being processed by the function. Erik Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Hmmm, now I'm in doubt... I always had errors using it, so I stopped using it... I also have problems with variables that have the same name and are in both the original file and the included file... might it have something to do with the PHP version you're working on? Greets, Edward - Original Message - From: Erik Price [EMAIL PROTECTED] To: Edward van Bilderbeek - Bean IT [EMAIL PROTECTED] Cc: Phil Schwarzmann [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Thursday, March 14, 2002 10:58 PM Subject: Re: [PHP] include() question On Thursday, March 14, 2002, at 04:34 PM, Edward van Bilderbeek - Bean IT wrote: you can't use a variable as a parameter for the included file... because include does nothing else then putting the text of the include file on the place of the include statement... Are you sure about this? I'm almost positive that PHP is flexible about accepting variables or strings as function arguments in most cases. I just tested it, and it seems to work fine... $includefile = './leftnavigation.inc'; include($includefile); I posted a question on this list about a month ago, and someone said that you can use variables or strings in many cases -- just remember that the variable expands to the string BEFORE being processed by the function. Erik Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Jep, that was what I meant... sorry Erik, didn't read your question right... Edward - Original Message - From: Jan Rademaker [EMAIL PROTECTED] To: Erik Price [EMAIL PROTECTED] Cc: Edward van Bilderbeek - Bean IT [EMAIL PROTECTED]; Phil Schwarzmann [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Thursday, March 14, 2002 11:03 PM Subject: Re: [PHP] include() question On Thu, 14 Mar 2002, Erik Price wrote: On Thursday, March 14, 2002, at 04:34 PM, Edward van Bilderbeek - Bean IT wrote: you can't use a variable as a parameter for the included file... because include does nothing else then putting the text of the include file on the place of the include statement... Are you sure about this? I'm almost positive that PHP is flexible about accepting variables or strings as function arguments in most cases. I just tested it, and it seems to work fine... $includefile = './leftnavigation.inc'; include($includefile); I think what Edward means is that you can't pass parameters to an included file, like include(some.inc?var=value); That's true, at least for local files. include(http://remotesite/some.php?var=value;) will work, as long as remotesite has php installed, of course. -- Jan Rademaker [EMAIL PROTECTED] http://www.ottobak.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
On Thursday, March 14, 2002, at 05:03 PM, Jan Rademaker wrote:
I think what Edward means is that you can't pass parameters to an
included
file, like include(some.inc?var=value);
That's true, at least for local
files. include(http://remotesite/some.php?var=value;) will work, as
long
as remotesite has php installed, of course.
yes, a very clean way to do it (that I've used successfully) is
something like:
$current_page = User Login;
if ($badlogin) {
header(Location: http://domain.com/~eprice/badlogin.php?errormsg=; .
$current_page);
}
This cleanly separates the string from the variable, but they are
concatenated before being passed as an argument to the header()
function. This passes the name of the script as a querystring variable
called $_GET['errormsg'], so that the receiving script can take some
action based on where the user was sent from.
Erik
Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
Oh I see. Sorry, i was thinking apples and you guys were talking about oranges. I just ran into this problem a little while ago, that's why I felt the need to butt in. Erik On Thursday, March 14, 2002, at 05:08 PM, Edward van Bilderbeek - Bean IT wrote: Jep, that was what I meant... sorry Erik, didn't read your question right... Edward - Original Message - From: Jan Rademaker [EMAIL PROTECTED] To: Erik Price [EMAIL PROTECTED] Cc: Edward van Bilderbeek - Bean IT [EMAIL PROTECTED]; Phil Schwarzmann [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Thursday, March 14, 2002 11:03 PM Subject: Re: [PHP] include() question On Thu, 14 Mar 2002, Erik Price wrote: On Thursday, March 14, 2002, at 04:34 PM, Edward van Bilderbeek - Bean IT wrote: you can't use a variable as a parameter for the included file... because include does nothing else then putting the text of the include file on the place of the include statement... Are you sure about this? I'm almost positive that PHP is flexible about accepting variables or strings as function arguments in most cases. I just tested it, and it seems to work fine... $includefile = './leftnavigation.inc'; include($includefile); I think what Edward means is that you can't pass parameters to an included file, like include(some.inc?var=value); That's true, at least for local files. include(http://remotesite/some.php?var=value;) will work, as long as remotesite has php installed, of course. -- Jan Rademaker [EMAIL PROTECTED] http://www.ottobak.com Erik Price Web Developer Temp Media Lab, H.H. Brown [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include() question
On Thu, 2002-03-14 at 13:20, Phil Schwarzmann wrote:
Why doesn't this work...
include(index.php?var='$var');
I want to include a page in my code and send a variable to it but I get
some funky error.
THANKS!!
Please read this page carefully, especially the third paragraph and
Examples 11.3 and 11.5:
http://www.php.net/manual/en/function.include.php
Hopefully that's help clear it up.
Essentially, you should be doing this:
$var = 'someval';
include('index.php');
Hope this helps,
Torben
--
Torben Wilson [EMAIL PROTECTED]
http://www.thebuttlesschaps.com
http://www.hybrid17.com
http://www.inflatableeye.com
+1.604.709.0506
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] include() question
Missing close for one. v include(index.php?var='$var'); ^ and you don't need to pass the $var to the include since it will be included, and obviously you already have it declared. if index.php contained ? echo $var; ? and the file you are in contained ? $var='blah'; include(index.php); ? then PHP reads this as ? $var='blah'; echo $var; ? as such, no need to pass $var to the file since the file is included then parsed. Dave -Original Message- From: Phil Schwarzmann [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 14, 2002 4:20 PM To: [EMAIL PROTECTED] Subject: [PHP] include() question Why doesn't this work... include(index.php?var='$var'); I want to include a page in my code and send a variable to it but I get some funky error. THANKS!! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] include question
At 02:03 AM 9/18/2001 +0200, Chris Hayes wrote: 2) let them make a real template, either a file or a database cell, for instance fhkhfsakuhfewhehfaalkuhfwe[DATA1]/lkuhfwe and do a str replace [DATA1] parts -- database content. Chris- YOU ROCK! Thank you for the thought starter, I have been beating my head on this most of the day. I have to confess that this site was done in ASP and I have been moving parts over to PHP and was not thinking clearly. I was thinking I was still under the ASP limitations :) Anyway, here is the code I am using. I will keep the templates in the db and call them, but I put a [BODY DATA] block in the template file, and then do a string replace as such: $temp = str_replace([BODY DATA], $body,$template); echo $temp; Can anyone tell me the limit or format to do multiple replaces, example: I have 5 fields that I need to replace, do I create a variable for each replacement? $temp = str_replace([BODY DATA], $body,$template); $temp2 = str_replace([TOP_GRAPHIC],$top_graphic, $temp); and so on -OR- can I do it in one statement? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP]include question, WHY doesn't this work...
Is the lib direcotory under the working directory, I mean, if your
program is excuting under temp directory, the lib directory has to be
below temp directory. If you are running this program from the root
directory then lib has to be below root directory.
Your code looks good to me.
One more thing I can think of is, do you read access to lib directory,
just curious.
Chris Cocuzzo wrote:
hey-
I have a piece of code which does a simply INSERT query into an mp3 table.
I've tested it out, and it completes the query, however there is one bug
that I just have no clue about.
this code does not work when i try to connect to the db:
include(lib/db_config.php);
$connection = db_connect(fplg);
if(!connection) {
die(sql_error());
}
the include fails and so the db_connect function is undefined.
this code works:
include(db_config.php);
$connection = db_connect(fplg);
if(!connection) {
die(sql_error());
}
I DO have a directory called lib in my root folder. am I calling the include
wrong in that first piece. Note that I also tried the first one with a
foward slash in front of the 'lib', but had no luck.
help!
chris
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP]include question, WHY doesn't this work...
the lib directory is under the root directory, or the www directory, where
all the normal files have been put. i figured out that the include worked
better when I specified the entire system path.
chris
- Original Message -
From: Unni [EMAIL PROTECTED]
To: Chris Cocuzzo [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Monday, July 23, 2001 3:52 PM
Subject: Re: [PHP]include question, WHY doesn't this work...
Is the lib direcotory under the working directory, I mean, if your
program is excuting under temp directory, the lib directory has to be
below temp directory. If you are running this program from the root
directory then lib has to be below root directory.
Your code looks good to me.
One more thing I can think of is, do you read access to lib directory,
just curious.
Chris Cocuzzo wrote:
hey-
I have a piece of code which does a simply INSERT query into an mp3
table.
I've tested it out, and it completes the query, however there is one bug
that I just have no clue about.
this code does not work when i try to connect to the db:
include(lib/db_config.php);
$connection = db_connect(fplg);
if(!connection) {
die(sql_error());
}
the include fails and so the db_connect function is undefined.
this code works:
include(db_config.php);
$connection = db_connect(fplg);
if(!connection) {
die(sql_error());
}
I DO have a directory called lib in my root folder. am I calling the
include
wrong in that first piece. Note that I also tried the first one with a
foward slash in front of the 'lib', but had no luck.
help!
chris
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP]include question, WHY doesn't this work...
have you tried giving the absolute path to the included file?
include(/some/path/to/a/file.php);
--
Austin Gonyou
Systems Architect, CCNA
Coremetrics, Inc.
Phone: 512-796-9023
email: [EMAIL PROTECTED]
-Original Message-
From: Unni [mailto:[EMAIL PROTECTED]]
Sent: Monday, July 23, 2001 2:53 PM
To: Chris Cocuzzo
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP]include question, WHY doesn't this work...
Is the lib direcotory under the working directory, I mean, if your
program is excuting under temp directory, the lib directory
has to be
below temp directory. If you are running this program from the root
directory then lib has to be below root directory.
Your code looks good to me.
One more thing I can think of is, do you read access to lib
directory,
just curious.
Chris Cocuzzo wrote:
hey-
I have a piece of code which does a simply INSERT query
into an mp3 table.
I've tested it out, and it completes the query, however
there is one bug
that I just have no clue about.
this code does not work when i try to connect to the db:
include(lib/db_config.php);
$connection = db_connect(fplg);
if(!connection) {
die(sql_error());
}
the include fails and so the db_connect function is undefined.
this code works:
include(db_config.php);
$connection = db_connect(fplg);
if(!connection) {
die(sql_error());
}
I DO have a directory called lib in my root folder. am I
calling the include
wrong in that first piece. Note that I also tried the first
one with a
foward slash in front of the 'lib', but had no luck.
help!
chris
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail:
[EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
