RE: [PHP] Baffled, line producing error
What is the exact error message are you seeing?
-Original Message-
From: Craig Vincent [mailto:[EMAIL PROTECTED]]
Sent: Saturday, June 01, 2002 11:29 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Baffled, line producing error
I was happily coding when I came across a mysterious
error. I've traced it
to this line
if ($player_password != $player_password_verify) {
$errmsg .= 'Password
don't match. Please try againBR'; $error = 1; }
commented out the script runs fine, if this line is
active an error is
produced. My eyes are going bug eyed trying to find
what the problem is and
I'm hoping a second pair of eyes may point out my error.
I've provided the entire script in case by chance the
error is actually
stemming from elsewhere in the script and I'm missing
that as well. The
error message from the compiler states the error is
stemming from line 15
(which is the line I posted above). Any suggestions?
?php
require('config.inc.php');
authenticate();
if ($action == 'add') {
// The connection/query commands will need to be
modified once the db
abstraction layer is ready
mysql_connect($mysql_host, $mysql_user, $mysql_pass);
mysql_select_db($mysql_database);
$errmsg = '';
if (mysql_num_rows(mysql_query(SELECT player_id FROM
eq_guildmembers WHERE
player_name = '$player_name')) 0) { $errmsg .=
'Player name already
existsBR'; $error = 1; }
if (!$player_password) { $errmsg .= 'You must specify
a password for this
userBR'; $error = 1; }
# For some weird reason the line below produces an
error...I can't find
anything wrong
if ($player_password != $player_password_verify) {
$errmsg .= 'Password
don't match. Please try againBR'; $error = 1; }
if (!$error) {
mysql_query(INSERT INTO eq_guildmembers (player_name,
date_joined,
player_email_address, player_icq, priv_admin,
player_password) VALUES
('$player_name',NOW(),
'$player_email_address','$player_icq','$priv_admin','$p
layer_password'));
else { echo 'Submission successful...A
HREF=admin_roster.phpclick here
to return to the roster/A'; exit; }
}
}
?
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RE: [PHP] Baffled, line producing error
If the error is a warning about undefined variable, then set a default
value for $errmsg before you start adding strings to it.
$errmsg .= this;
That by itself means $errmsg = $errmsg . this;, but if $errmsg isnt'
defined, you'll get the warning.
Set $errmsg = ''; at the beginning of your script if that is the
problem...
For future reference, always give the exact error when posting.
Trying to be psychic,
---John Holmes...
-Original Message-
From: Craig Vincent [mailto:[EMAIL PROTECTED]]
Sent: Saturday, June 01, 2002 11:29 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Baffled, line producing error
I was happily coding when I came across a mysterious error. I've
traced
it
to this line
if ($player_password != $player_password_verify) { $errmsg .=
'Password
don't match. Please try againBR'; $error = 1; }
commented out the script runs fine, if this line is active an error is
produced. My eyes are going bug eyed trying to find what the problem
is
and
I'm hoping a second pair of eyes may point out my error.
I've provided the entire script in case by chance the error is
actually
stemming from elsewhere in the script and I'm missing that as well.
The
error message from the compiler states the error is stemming from line
15
(which is the line I posted above). Any suggestions?
?php
require('config.inc.php');
authenticate();
if ($action == 'add') {
// The connection/query commands will need to be modified once the db
abstraction layer is ready
mysql_connect($mysql_host, $mysql_user, $mysql_pass);
mysql_select_db($mysql_database);
$errmsg = '';
if (mysql_num_rows(mysql_query(SELECT player_id FROM eq_guildmembers
WHERE
player_name = '$player_name')) 0) { $errmsg .= 'Player name already
existsBR'; $error = 1; }
if (!$player_password) { $errmsg .= 'You must specify a password for
this
userBR'; $error = 1; }
# For some weird reason the line below produces an error...I can't
find
anything wrong
if ($player_password != $player_password_verify) { $errmsg .=
'Password
don't match. Please try againBR'; $error = 1; }
if (!$error) {
mysql_query(INSERT INTO eq_guildmembers (player_name, date_joined,
player_email_address, player_icq, priv_admin, player_password) VALUES
('$player_name',NOW(),
'$player_email_address','$player_icq','$priv_admin','$player_password')
);
else { echo 'Submission successful...A HREF=admin_roster.phpclick
here
to return to the roster/A'; exit; }
}
}
?
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Re: [PHP] Baffled, line producing error
If the error is a warning about undefined variable, then set a default value for $errmsg before you start adding strings to it. $errmsg .= this; That by itself means $errmsg = $errmsg . this;, but if $errmsg isnt' defined, you'll get the warning. Set $errmsg = ''; at the beginning of your script if that is the problem... For future reference, always give the exact error when posting. Trying to be psychic, You'll notice a few lines up I have defined $errmsg =) It's a standard parsing error I'm getting Parse error: parse error in admin_add_player.php on line 15 Since this message does not arise when line 15 is removed I can only assume the error is actually on that line and not a missing quote or bracket somewhere else in the script. Sincerely, Craig Vincent -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Baffled, line producing error
You have:
if ($player_password != $player_password_verify) {
$errmsg .= 'Password don't match. Please try againBR';
$error = 1;
}
Notice the ' inside the '', this is bad syntax. For more
information on using strings in PHP, see:
http://www.zend.com/zend/tut/using-strings.php
http://www.php.net/manual/en/language.types.string.php
One thing you can do is escape it: \'
regards,
Philip Olson
On Sun, 2 Jun 2002, Craig Vincent wrote:
If the error is a warning about undefined variable, then set a default
value for $errmsg before you start adding strings to it.
$errmsg .= this;
That by itself means $errmsg = $errmsg . this;, but if $errmsg isnt'
defined, you'll get the warning.
Set $errmsg = ''; at the beginning of your script if that is the
problem...
For future reference, always give the exact error when posting.
Trying to be psychic,
You'll notice a few lines up I have defined $errmsg =) It's a standard
parsing error I'm getting
Parse error: parse error in admin_add_player.php on line 15
Since this message does not arise when line 15 is removed I can only assume
the error is actually on that line and not a missing quote or bracket
somewhere else in the script.
Sincerely,
Craig Vincent
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Re: [PHP] Baffled, line producing error
Notice the ' inside the '', this is bad syntax. For more information on using strings in PHP, see: Sheesh you're right, as I said it was probably a dumb error, three other people have looked at this that I'm aware of and missed it toolol glad your eyes are better than ours. Thank you for pointing out the mistake Sincerely, Craig Vincent -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
