Re: [PHP] Help with Functions
I would recomend for sanity and clean code that you define your functions
outside of the file you will be calling it from and include that file in any
file you need to call a function from.
Here's a function that I defined in my db.php file.
/***
* FUNCTION: DBCheckByMin($min)
* DESCRIPTION: Checks to see if the user's min already exists
* RETURNED: exist (1 or 0)
**/
function DBCheckByMin($min)
{
$record = mysql_query( SELECT `min` FROM `user` WHERE `min` LIKE '$min' );
for($i=0; $holder[$i]=mysql_fetch_array( $record ); $i++);
if($min==$holder[0][0])
{
$exist=1;
}
else
{
$exist=0;
}
return $exist;
}
The first line of the file I call this function in includes my function
list:
include db.php;
And my call to the function itself:
$check=DBCheckByMin($min);
Let's say my user is entering his MIN as 1234567890
What the function does is catch the value of the variable $min which is
1234567890 when it's called and pass it to the function. Then DBCheckByMin
takes the value 1234567890 and assignes it to the variable $min. (I've named
both variables the same so I know what they are) Now that the function has
it's own variable, $min that has a value of 1234567890 It then does some
basic SQL work to find if that MIN already exists in my databse. Then it
sets $exist to either 1 or 0. It sets it to 1 if this is a duplicate entry
and 0 if it's not a duplicate. And let's just say that it did indeed find a
duplicate record so $exist will have the value of 1. Next on the return
line, the function sends back the value of $exist which is 1. Please
remember when I called the function I had a variable before the function was
called $check=DBCheckByMin($min); This way $check will catch whatever
value the function returns, in this case, that value is 1. Now that check
has a value which indicates that this user already exists I can send a
message to the user saying that it already exists and to try again.
Did that make a bit more sense about how variables are passed between
functions? It's all in the call and definition.
Andrew Darrow
Kronos1 Productions
www.pudlz.com
- Original Message -
From: Tom Chubb [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Saturday, July 30, 2005 9:23 AM
Subject: [PHP] Help with Functions
I am trying to start using functions on some pages to layout a header
row in a table.
I have defined the function as below...
?php
function (headerrow)
{ ?
table width=750 border=0 cellpadding=0 cellspacing=0
bgcolor=#FF0066
tr
td class=table_head?php echo $tablehead; ?/td
td width=20img src=/nav/images/pspromo_table_rhs.gif
width=20 height=20/td
/tr
/table
?php
}
?
What I can't seem to work out is a way to set the text. Here I've
echoed the $tablehead value, but it I was to use more than one table
on the same page then it wouldn't work. Can I do something like
headerrow(text goes here) or something?
I can't understand the use of arguments and it's really confusing me!
Any help would be really appreciated.
Thanks,
Tom
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Re: [PHP] Help with Functions
You're declaring your function wrong.
You're doing:
function (function_name)
You should be doing
function function_name($arg1, $arg2, $arg3) // with as many comma
seperated arguments as you want.
or if you don´t want to pass any arguments
function function_name()
Try this out:
function make_table($arg1, $arg2){
?
table
tr
td?php echo $arg1; ?/td
td?php echo $arg2; ?/td
/tr
/table
?php
}
note that I have to go back into PHP twice to get the variables.
I could also (although tbh you should wait until you have more
experience before you read on)
function make_table($arg1, $arg2){
echo ENDOFTABLE
table
tr
td$arg1/td
td$arg2/td
/tr
/table
ENDOFTABLE;
}
On 7/30/05, Tom Chubb [EMAIL PROTECTED] wrote:
I am trying to start using functions on some pages to layout a header
row in a table.
I have defined the function as below...
?php
function (headerrow)
{ ?
table width=750 border=0 cellpadding=0 cellspacing=0
bgcolor=#FF0066
tr
td class=table_head?php echo $tablehead; ?/td
td width=20img src=/nav/images/pspromo_table_rhs.gif
width=20 height=20/td
/tr
/table
?php
}
?
What I can't seem to work out is a way to set the text. Here I've
echoed the $tablehead value, but it I was to use more than one table
on the same page then it wouldn't work. Can I do something like
headerrow(text goes here) or something?
I can't understand the use of arguments and it's really confusing me!
Any help would be really appreciated.
Thanks,
Tom
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Re: [PHP] Help with Functions
Thanks guys for all your help.
I've managed to get it working.
I tried calling the function from within the file and it turned out
that somehow I had messed up my include statement.
I understood about adding argument variables to the syntax, but I
needed to add a text argument as I couldn't think of a way of setting
the variable in a way that I could distinguish between different
values for different tables on the same page.
Anyway, thanks to you all for taking some time to help me out.
T
On 30/07/05, Rory Browne [EMAIL PROTECTED] wrote:
You're declaring your function wrong.
You're doing:
function (function_name)
You should be doing
function function_name($arg1, $arg2, $arg3) // with as many comma
seperated arguments as you want.
or if you don´t want to pass any arguments
function function_name()
Try this out:
function make_table($arg1, $arg2){
?
table
tr
td?php echo $arg1; ?/td
td?php echo $arg2; ?/td
/tr
/table
?php
}
note that I have to go back into PHP twice to get the variables.
I could also (although tbh you should wait until you have more
experience before you read on)
function make_table($arg1, $arg2){
echo ENDOFTABLE
table
tr
td$arg1/td
td$arg2/td
/tr
/table
ENDOFTABLE;
}
On 7/30/05, Tom Chubb [EMAIL PROTECTED] wrote:
I am trying to start using functions on some pages to layout a header
row in a table.
I have defined the function as below...
?php
function (headerrow)
{ ?
table width=750 border=0 cellpadding=0 cellspacing=0
bgcolor=#FF0066
tr
td class=table_head?php echo $tablehead; ?/td
td width=20img src=/nav/images/pspromo_table_rhs.gif
width=20 height=20/td
/tr
/table
?php
}
?
What I can't seem to work out is a way to set the text. Here I've
echoed the $tablehead value, but it I was to use more than one table
on the same page then it wouldn't work. Can I do something like
headerrow(text goes here) or something?
I can't understand the use of arguments and it's really confusing me!
Any help would be really appreciated.
Thanks,
Tom
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Tom Chubb
[EMAIL PROTECTED]
07915 053312
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Re: [PHP] Help with functions()
Beauford 2002 wrote:
Hi,
I have form that a user would input information and that info is sent to
a function, but I need to be able to return a result of this function
and is where I am having a problem.
For example:
testfunction($var1, $var2, $var3, $var4); //the form fills these
values.
echo $meat;
function testfunction($a, $b, $c, $d) {
The $meat of the function goes here;
Now I need to return the result of $meat;
return $meat;
}
$return_value = testfunction (
echo $return_value;
HTH
Chris
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Re: [PHP] Help with functions()
Try:
$meat = testfunction ($var1, $var2, $var3, $var4);
echo $meat;
Or, alternatively,
print (testfunction ($var1, $var2, $var3, $var4));
hope this helps.
--t
On 11/20/02 8:40 PM, Beauford 2002 [EMAIL PROTECTED] wrote:
Hi,
I have form that a user would input information and that info is sent to
a function, but I need to be able to return a result of this function
and is where I am having a problem.
For example:
testfunction($var1, $var2, $var3, $var4); //the form fills these
values.
echo $meat;
function testfunction($a, $b, $c, $d) {
The $meat of the function goes here;
Now I need to return the result of $meat;
return $meat;
}
This does not work. I'm new to funtions and obviously missing something,
but I haven't been able to find a good tutorial on this. The PHP manual
isn't much help.
Any help is appreciated.
--
Tracy F. Rotton
[EMAIL PROTECTED]
http://www.taupecat.com/
... I like the 49ers because they're pure of heart,
Seattle because they've got something to prove,
and the Raiders because they always cheat.
-- Lisa Simpson, Lisa the Greek
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Re: [PHP] Help with functions()
You don't need the () around print.
print testfunction($var1, $var2, $var3, $var4);
Jason
On Wed, 2002-11-20 at 17:48, Tracy Finifter Rotton wrote:
Try:
$meat = testfunction ($var1, $var2, $var3, $var4);
echo $meat;
Or, alternatively,
print (testfunction ($var1, $var2, $var3, $var4));
hope this helps.
--t
On 11/20/02 8:40 PM, Beauford 2002 [EMAIL PROTECTED] wrote:
Hi,
I have form that a user would input information and that info is sent to
a function, but I need to be able to return a result of this function
and is where I am having a problem.
For example:
testfunction($var1, $var2, $var3, $var4); //the form fills these
values.
echo $meat;
function testfunction($a, $b, $c, $d) {
The $meat of the function goes here;
Now I need to return the result of $meat;
return $meat;
}
This does not work. I'm new to funtions and obviously missing something,
but I haven't been able to find a good tutorial on this. The PHP manual
isn't much help.
Any help is appreciated.
--
Tracy F. Rotton
[EMAIL PROTECTED]
http://www.taupecat.com/
... I like the 49ers because they're pure of heart,
Seattle because they've got something to prove,
and the Raiders because they always cheat.
-- Lisa Simpson, Lisa the Greek
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Re: [PHP] Help with functions()
echo testfunction($var1, $var2, $var3, $var4);
Or if you need to do something else with the value before echo()ing it:
$meat = testfunction($var1, $var2, $var3, $var4);
//Do something with $meat
Beauford 2002 wrote:
Hi,
I have form that a user would input information and that info is sent to
a function, but I need to be able to return a result of this function
and is where I am having a problem.
For example:
testfunction($var1, $var2, $var3, $var4); //the form fills these
values.
echo $meat;
function testfunction($a, $b, $c, $d) {
The $meat of the function goes here;
Now I need to return the result of $meat;
return $meat;
}
This does not work. I'm new to funtions and obviously missing something,
but I haven't been able to find a good tutorial on this. The PHP manual
isn't much help.
Any help is appreciated.
--
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Re: [PHP] Help with functions.
I need some help with functions. Does anyone know of a good place to learn
about functions? Will someone be willing to teach me what I need to know
about
functions in PHP? Thank you,
Here's a really simple example:
?
// regular variable that exists outside any functions
$global_var = 5;
// we will pass this variable to the function
$passed_var = 7;
// define the function
function function_name ($passed_var){
// pull in any needed global variables not local or passed to the function
global $global_var;
// regular variable that exists only in this function
$local_var = 10;
// build up the html
$html = Now inside function_name()...br\n;
// build up some more html
$html .= \$global_var + \$local_var + \$passed_var = . $global_var +
$local_var + $passed_var . br\n;
// pass the $html back to the caller
return $html;
}
// call the function
echo function_name ($passed_var);
?
Usually you wanna use funtions for code you intend to use multiple times.
Greg Donald - http://destiney.com/
http://phprated.com/ | http://phplinks.org/ | http://phptopsites.com/
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Re: [PHP] Help!! IP functions!!!
Use the variable $REMOTE_ADDR. It contains the request ip address. Jason - Original Message - From: "Bruno Freire" [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, February 19, 2001 12:34 PM Subject: [PHP] Help!! IP functions!!! Hi!! My name is Bruno, From Brazil!!! I need to know how can i discovery the ip address when somebody access my home page What function can I use Thanks!! Bruno. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Help!! IP functions!!!
Mensaje citado por: Bruno Freire [EMAIL PROTECTED]: Hi!! My name is Bruno, From Brazil!!! I need to know how can i discovery the ip address when somebody access my home page What function can I use Bruno, check the phpinfo() function, which will give you lots of information about variables that are passed from the browser to the server. I think that HTTP_SERVER_VARS["REMOTE_ADDR"] is what you're looking for. Saludos... :-) Martn Marqus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
