Re: [PHP] I can't echo object variables
Try enclosing it in curly braces.
echo p${db-field('name_long')};
Martin Clifford
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Michael Zornek [EMAIL PROTECTED] 07/16/02 01:45PM
We all know this works:
echo p$someVar;
However this does not:
echo p$db-field('name_long');
I know this slight variation will make it work:
echo p . $db-field('name_long');
But it's cumbersome .. Anyway to get the first way to work?
~ Mike
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Re: [PHP] I can't echo object variables
Twas 7/16/02 1:47 PM, when Martin Clifford [EMAIL PROTECTED] said:
Try enclosing it in curly braces.
echo p${db-field('name_long')};
Parse error :-(
~ Mike
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Mike Zornek | Project Leader
Apple Student Developers
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http://www.applestudentdevelopers.org
Personal Site:
http://www.mikezornek.com
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Re: [PHP] I can't echo object variables
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Michael Zornek wrote:
We all know this works:
echo p$someVar;
However this does not:
echo p$db-field('name_long');
I know this slight variation will make it work:
echo p . $db-field('name_long');
But it's cumbersome .. Anyway to get the first way to work?
~ Mike
In your example you try and execute a method within a quoted string.
That would not work even with a traditional function call, AFAIK.
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tHe TeSt, YeS iT iS
ThE tEsT, yEs It Is
tHe TeSt, YeS iT iS
ThE tEsT, yEs It Is...
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Re: [PHP] I can't echo object variables
On Tue, Jul 16, 2002 at 01:45:01PM -0400, Michael Zornek wrote:
I know this slight variation will make it work:
echo p . $db-field('name_long');
That's not an object variable name. That's a function call. You're
asking to echo p and then echoing the value returned by the field()
function in the $db object when called with the 'name_long' argument.
That's the way you have to do it.
--Dan
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