Re: [PHP] image upload keeps file name ?

2010-04-01 Thread Ashley Sheridan
On Thu, 2010-04-01 at 10:51 +0100, Matthew Croud wrote:

 Hi Guys,
 
 Can someone confirm for me that the code below will move an uploaded  
 file and give it the same name as the original image file name ?
 
 
 $file_dir = /home/uploads;
 foreach($_FILES as $file_name = $file_array) {
   echo path: .$file_array[tmp_name].br/\n;
   echo name: .$file_array[name].br/\n;
   echo type: .$file_array[type].br/\n;
   echo size: .$file_array[size].br/\n;
   
   $UploadName[$num] = $file_array[name];
  $num++;
 
   if (is_uploaded_file($file_array[tmp_name])) {
   move_uploaded_file($file_array[tmp_name], $file_dir/. 
 $file_array[name]) or die (Couldn't copy);
   echo file was moved!br/;
   }
 }
 
 
 
 Many thanks,
 
 
 
 
 


Yes, the original filename comes from the [name] array element.
However, if someone is uploading a filename with the same name as one
that already exists, you will be overwriting it.

For peace of mind, I've always found it best to save the file using the
tmp_name given to it by PHP, and store this against the original
filename in a database. You can then use PHP to deliver the file back to
the user when it's needed as either a download or something displayed in
the browser. This works nicely with storing files outside of the web
root, which will prevent people from maliciously uploading files to
attempt to break your server and/or app.

Thanks,
Ash
http://www.ashleysheridan.co.uk




Re: [PHP] image upload keeps file name ?

2010-04-01 Thread Midhun Girish
  I use the follwing function for moving files:


public function moveFile($file,$targetdir=../uploads/images/)
  {
$fileName = $file['name'];
$ext = substr($fileName, strrpos($fileName, '.') + 1);
do
{

$targetfilename=md5(date(m.d.y.h.i.s).basename($fileName)).'.'.$ext;
  $fullname=$targetdir.$targetfilename;
}while(file_exists($fullname));
move_uploaded_file($file[tmp_name],$fullname);
return $fullname;
  }


Call the fn as :

foreach($_FILES as $file_name = $filearray)
{
if( $filearray['error']=='')
{
   $filenametobestored=moveFile($filearray);
   /*Enter name into db here*/
}
}


this will make sure you never over write anyfiles..


Midhun Girish

On Thu, Apr 1, 2010 at 3:25 PM, Ashley Sheridan 
a...@ashleysheridan.co.ukwrote:

 of the web
 root, which will prevent people from maliciously uploadi



Re: [PHP] Image upload

2007-02-05 Thread Jochem Maas
Robert Fitzpatrick wrote:
 I have a small application that ran on one server and now gives me a
 problem with uploading images on a new server. I am running PHP 4.4.4
 now on this server and hoping it is just something that needs adjusted
 in php.ini, but cannot seem to find. The file is posted as a file fields
 in a  multipart/form-data form, the application tests the file with
 getimagesize() shown below. I am getting the die response in the
 browser. I tried echo of the file and it prints a random file name under
 the /tmp directory on this CentOS Linux system. If I sleep for 10
 seconds, the file gets created and gone after the script finishes. Can
 someone suggest what my problem may be?

no. but start by stopping the assumption that getimagesize() returns something
equivelant to false to mean the same thing as that the file does not exist
(or is not an image file.)

this might help: http://php.net/is_uploaded_file

also check it's not a permissions issue (i.e. the file is being created but the
webserver cannot subsequently read the file)

 
 if (!getimagesize($_FILES['filPhoto']['tmp_name'])) {
   die('The file you are attempting to upload is not an image file.');
 } else {
 snip
 

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Re: [PHP] Image upload

2007-02-05 Thread Robert Fitzpatrick

Jochem Maas wrote:

Robert Fitzpatrick wrote:
  

I have a small application that ran on one server and now gives me a
problem with uploading images on a new server. I am running PHP 4.4.4
now on this server and hoping it is just something that needs adjusted
in php.ini, but cannot seem to find. The file is posted as a file fields
in amultipart/form-data form, the application tests the file with
getimagesize() shown below. I am getting the die response in the
browser. I tried echo of the file and it prints a random file name under
the /tmp directory on this CentOS Linux system. If I sleep for 10
seconds, the file gets created and gone after the script finishes. Can
someone suggest what my problem may be?



no. but start by stopping the assumption that getimagesize() returns something
equivelant to false to mean the same thing as that the file does not exist
(or is not an image file.)

this might help: http://php.net/is_uploaded_file

  
Yes, actually that is done first, the getimagesize is used it the script 
to test it as an image. This was written by someone else and worked 
prior to moving servers. This is a more complete snippet of the code:


if (is_uploaded_file($_FILES['filPhoto']['tmp_name'])) {

  // use getimagesize to make sure it's an image file
 if (!getimagesize($_FILES['filPhoto']['tmp_name'])) {

   die('The file you are attempting to upload is not an image 
file.');

snip

also check it's not a permissions issue (i.e. the file is being created but the
webserver cannot subsequently read the file)

  
The /tmp directory where it is created is set with 777 perms. I have not 
checked the destination, but the script does not appear to get back the 
above point, giving us the die response.


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Re: [PHP] Image upload

2007-02-05 Thread Richard Lynch
On Mon, February 5, 2007 4:29 pm, Robert Fitzpatrick wrote:
 I have a small application that ran on one server and now gives me a
 problem with uploading images on a new server. I am running PHP 4.4.4
 now on this server and hoping it is just something that needs adjusted
 in php.ini, but cannot seem to find. The file is posted as a file
 fields
 in a multipart/form-data form, the application tests the file with
 getimagesize() shown below. I am getting the die response in the
 browser. I tried echo of the file and it prints a random file name
 under
 the /tmp directory on this CentOS Linux system. If I sleep for 10
 seconds, the file gets created and gone after the script finishes. Can
 someone suggest what my problem may be?

The file always goes away when the script finishes.  See:
http://php.net/move_uploaded_file

 if (!getimagesize($_FILES['filPhoto']['tmp_name'])) {
   die('The file you are attempting to upload is not an image file.');

Try various things like file_exists on the file to see if you are
getting the file at all.

fopen/fread the first N bytes and compare them to what you are
uploading, to see if the data that gets there is the data you sent.

getimagesize() only reads the first N bytes and then interprets that
to decide what kind of file it is, and how big the width/height are,
etc.

I dunno exactly what N is, but it's relatively small.

Different file formats have different size N, and PHP has to figure
out what to do for all of them, so maybe it just reads the largest N,
or maybe it reads a few bytes and then decides how many to read for
the rest of the meta-info.

At any rate, if you can fread a couple hundred bytes, and it matches
what you uploaded, then you know that something is wrong with the
original image and getimagesize() -- You could FTP it up just like
your logo or buttons, and use getimagesize() on it, and it STILL
wouldn't work.

Actually, that's another good test to run:  FTP the file up to your
images directory and see what getimagesize does on that.

 } else {
 snip

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Re: [PHP] Image upload

2007-02-05 Thread Richard Lynch

PS I forgot that the $_FILES array also has an 'error' field in it.

Check that!


On Mon, February 5, 2007 4:29 pm, Robert Fitzpatrick wrote:
 I have a small application that ran on one server and now gives me a
 problem with uploading images on a new server. I am running PHP 4.4.4
 now on this server and hoping it is just something that needs adjusted
 in php.ini, but cannot seem to find. The file is posted as a file
 fields
 in a multipart/form-data form, the application tests the file with
 getimagesize() shown below. I am getting the die response in the
 browser. I tried echo of the file and it prints a random file name
 under
 the /tmp directory on this CentOS Linux system. If I sleep for 10
 seconds, the file gets created and gone after the script finishes. Can
 someone suggest what my problem may be?

 if (!getimagesize($_FILES['filPhoto']['tmp_name'])) {
   die('The file you are attempting to upload is not an image file.');
 } else {
 snip

 --
 Robert

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RE: [PHP] image upload problem

2006-06-29 Thread Jay Blanchard
[snip]
  The Code is running properly.But I dont Know Where The uploaded image
is Stored in the server.I checked /tmp directory,but image is  not
there,is there any function where i can specify the location of the
server where my image is to be stored i also tired move_uploaded_image()
function .but its not working .I am waiting reply from any one
[/snip]

http://www.php.net/move_uploaded_file

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Re: [PHP] image upload problem

2006-06-29 Thread Jochem Maas
suresh kumar wrote:
 Hi,

hi ([EMAIL PROTECTED]([EMAIL PROTECTED]([EMAIL PROTECTED](*%([EMAIL 
PROTECTED]([EMAIL PROTECTED]@#

 I am waiting reply from any one

do we have someone here called 'any one'? how about you reply to one
of the people who answer your questions.

PS - the tmp file is removed at the end of the request.
PPS - ?php echo it is temporarily stored at {$_FILES['ufile']['tmp_name']}; 
?

 
   
 -
  Yahoo! India Answers: Share what you know. Learn something new Click here
 Catch all the FIFA World Cup 2006 action on Yahoo! India Click here

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Re: [PHP] Image upload form

2005-06-15 Thread Jack Jackson

Okay, I started seeing some of my mistakes.

I am still having a great deal of trouble:


newfile returns: 0fdae2e9e6aa43f067a9dd780a5a36a6.jpg
image_file returns: images/jpg/test/0fdae2e9e6aa43f067a9dd780a5a36a6.jpg

images/jpg/test is set to 777 but I still get (Could not move file to 
destination).  What am I missing? Thanks!



?php

error_reporting(E_ALL);

  $uploaddir = images/jpg/test/;


  print_r($_FILES);

  $local_file = $_FILES['userfile']['tmp_name'];



if (sizeof($local_file))
  {

//try to get image size; this returns false if this is not an actual 
image file.

  $image_test = getimagesize($local_file);

if ($image_test !== false) {
   $mime_type = $_FILES['userfile']['type'];
   switch($mime_type) {
   case image/jpeg:
   $pext = 'jpg';
   break;
   case image/tiff:
   $pext = 'tif';
   break;
   default:
		   echo The file you are trying to upload is an image, but it is not 
a tif or jpeg and therefore unacceptable.;	

   }
} else {
   echo The file you are trying to upload is not a valid image file;
}

 $newfile = md5(date(l-F-j-Y i:s)).'.'.$pext;

 $image_file = $uploaddir . $newfile;

// print_r($newfile);
// print_r($image_file);

 if(!move_uploaded_file($newfile,$image_file)) {

 echo 'Could not move file to destination';
 exit;
 }

 else {
 echo 'image file ?php echo $newfile ? uploaded.';



 }



  }

  ?

  form enctype=multipart/form-data action=?php echo 
$_SERVER['PHP_SELF']; ? method=POST

input type=hidden name=MAX_FILE_SIZE value=30 /
!-- Name of input element determines name in $_FILES array --
Cartoon: input name=userfile type=file /
input type=submit value=Upload File /
/form

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Re: [PHP] Image upload form

2005-06-15 Thread Jack Jackson



Richard Davey wrote:

Hello Jack,

Wednesday, June 15, 2005, 5:38:11 PM, you wrote:

JJ newfile returns: 0fdae2e9e6aa43f067a9dd780a5a36a6.jpg
JJ image_file returns:
JJ images/jpg/test/0fdae2e9e6aa43f067a9dd780a5a36a6.jpg

JJ images/jpg/test is set to 777 but I still get (Could not move file to
JJ destination).  What am I missing? Thanks!

This directory needs to be absolute - i.e. the COMPLETE path:

/usr/home/jack/images/jpg/test




Thanks, Richard,

Still no soap: I changed

  $uploaddir = /home/jack/public_html/amyportnoy/images/jpg/test;

and
  $image_file = $uploaddir . '/' . $newfile;

Now $image_file returns the valid path of:

/home/jack/public_html/amyportnoy/images/jpg/test/09992d5379dd0a0cf376aab82241a66d.jpg

but it still  does not copy the file to that location. However the error 
has changed:


 if (is_uploaded_file($newfile)) {

 if(!move_uploaded_file($newfile,$image_file)) {

 echo 'Could not move file to destination';
 exit;
 }

 else {
 echo 'image file ?php echo $newfile ? uploaded.';
  }

 }

 else {
echo 'Problem with ' . $newfile;
  }

  }
And I'm getting an error message of Problem with 
6a26590fb45fd86e58954ba91d5580a4.jpg


So i guess it's not uploading for some reason?

Here's the whole thing I have so far once again, with several mods:



?php

error_reporting(E_ALL);

  $uploaddir = /home/jack/public_html/amyportnoy/images/jpg/test;

  print_r($_FILES);


  if ($_FILES['userfile']['error']  0) {

echo 'Problem: ';

switch ($_FILES['userfile']['error']) {
  case 1:
	 echo 'File exceeds maximum upload size limit 
(upload_max_filesize).';

 break;
  case 2:
 echo 'File exceeds maximum size limit (max_file_size).';
 break;
  case 3:
 echo 'File was only partially uploaded.';
 break;
  case 4:
 echo 'No file was uploaded.';
 break;

  }//end switch

  }//end if error 0

  $local_file = $_FILES['userfile']['tmp_name'];

if (sizeof($local_file))
  {

//try to get image size; this returns false if this is not an actual 
image file.

  $image_test = getimagesize($local_file);

if ($image_test !== false) {
   $mime_type = $_FILES['userfile']['type'];
   switch($mime_type) {
   case image/jpeg:
   $pext = 'jpg';
   break;
   case image/tiff:
   $pext = 'tif';
   break;
   default:
		   echo The file you are trying to upload is an image, but it is not 
a tif or jpeg and therefore unacceptable.;	

   }
} else {
   echo The file you are trying to upload is not a valid image file;
}

 $newfile = md5(date(l-F-j-Y i:s)).'.'.$pext;

 $image_file = $uploaddir . '/' . $newfile;

// print_r($newfile);
 print_r($image_file);


 if (is_uploaded_file($newfile)) {

 if(!move_uploaded_file($newfile,$image_file)) {

 echo 'Could not move file to destination';
 exit;
 }

 else {
 echo 'image file ' . $newfile . 'uploaded.';
  }

 }

 else {
echo 'Problem with ' . $newfile;
  }

  }

  ?

  form enctype=multipart/form-data action=?php echo 
$_SERVER['PHP_SELF']; ? method=POST

input type=hidden name=MAX_FILE_SIZE value=30 /
!-- Name of input element determines name in $_FILES array --
Cartoon: input name=userfile type=file /
input type=submit value=Upload File /
/form



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Re: [PHP] Image upload form

2005-06-15 Thread Jason Wong
On Thursday 16 June 2005 00:38, Jack Jackson wrote:

 //try to get image size; this returns false if this is not an actual
 image file.
$image_test = getimagesize($local_file);
   if ($image_test !== false) {
  $mime_type = $_FILES['userfile']['type'];

$_FILES['userfile']['type'] contains the mime-type that is provided by the 
browser and will vary depending on browser and hence extremely 
unreliable.

In fact the returned value from getimagesize() already has mime-type info, 
use that instead.

   $newfile = md5(date(l-F-j-Y i:s)).'.'.$pext;

   $image_file = $uploaddir . $newfile;

 // print_r($newfile);
 // print_r($image_file);

   if(!move_uploaded_file($newfile,$image_file)) {

echo 'Could not move file to destination';
exit;
   }

The file pointed to by $newfile doesn't exist. You need to move ...

       $local_file = $_FILES['userfile']['tmp_name'];

... $localfile


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Re: [PHP] Image upload form

2005-06-15 Thread Jack Jackson

Yes, Jason,
Those did it!

Thanks so much for the help!



Jason Wong wrote:

On Thursday 16 June 2005 00:38, Jack Jackson wrote:



//try to get image size; this returns false if this is not an actual
image file.
  $image_test = getimagesize($local_file);
if ($image_test !== false) {
   $mime_type = $_FILES['userfile']['type'];



$_FILES['userfile']['type'] contains the mime-type that is provided by the 
browser and will vary depending on browser and hence extremely 
unreliable.


In fact the returned value from getimagesize() already has mime-type info, 
use that instead.




 $newfile = md5(date(l-F-j-Y i:s)).'.'.$pext;

 $image_file = $uploaddir . $newfile;

// print_r($newfile);
// print_r($image_file);

 if(!move_uploaded_file($newfile,$image_file)) {

 echo 'Could not move file to destination';
 exit;
 }



The file pointed to by $newfile doesn't exist. You need to move ...



  $local_file = $_FILES['userfile']['tmp_name'];



... $localfile




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Re: [PHP] Image upload not working correctly

2004-10-14 Thread Dave Grant
Thanks for the reponse.  Yes, the destination paths look fine and the PHP 
error log displays no errors.  Any other ideas?

Thanks.


Jason Wong [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]
 On Thursday 14 October 2004 02:40, Dave Grant wrote:

 echo Thumb image uploaded to .$thumbPath.br /\n;
 echo Full image uploaded to .$fullPath.br /\n;

 Do these look OK?

 Everything works fine, except that the images are simply not there when 
 we
 go look for them.  The best explanation I can come up with is that they 
 are
 not moved, but I have no idea why.  I've done this with no problem on my
 personal site.  Is it a problem with the move_uploaded_file function? 
 Any
 ideas?

 What does the PHP error log say?

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Re: [PHP] Image upload not working correctly

2004-10-14 Thread Dave Grant
Just to clarify, everything looks like it works fine except for moving the 
images to the destination path.  The images upload, the server recognizes 
them, but they don't get moved to the destination path.

Thanks.


Jason Wong [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]
 On Thursday 14 October 2004 02:40, Dave Grant wrote:

 echo Thumb image uploaded to .$thumbPath.br /\n;
 echo Full image uploaded to .$fullPath.br /\n;

 Do these look OK?

 Everything works fine, except that the images are simply not there when 
 we
 go look for them.  The best explanation I can come up with is that they 
 are
 not moved, but I have no idea why.  I've done this with no problem on my
 personal site.  Is it a problem with the move_uploaded_file function? 
 Any
 ideas?

 What does the PHP error log say?

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Re: [PHP] Image upload not working correctly

2004-10-14 Thread Jason Wong
Please do not top-post.

On Thursday 14 October 2004 23:52, Dave Grant wrote:
 Thanks for the reponse.  Yes, the destination paths look fine and the PHP
 error log displays no errors.  Any other ideas?

move_uploaded_file() _will_ spit out an error if there are any problems. So if 
you're _positive_ FULL error reporting is enabled  logged and the error log 
shows nothing then I would be inclined to assume that the 
move_uploaded_file() operation was executed successfully. In that case, are 
you positive you're looking in the correct place for the destination file?

If you're still having problems, post some self-contained, concise[1] code to 
illustrate your problem.

[1] concise meaning the bare minimum, eg in your case code to handle either 
thumb image or full image but not both, etc.

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Re: [PHP] Image upload not working correctly

2004-10-13 Thread Jason Wong
On Thursday 14 October 2004 02:40, Dave Grant wrote:

 echo Thumb image uploaded to .$thumbPath.br /\n;
 echo Full image uploaded to .$fullPath.br /\n;

Do these look OK?

 Everything works fine, except that the images are simply not there when we
 go look for them.  The best explanation I can come up with is that they are
 not moved, but I have no idea why.  I've done this with no problem on my
 personal site.  Is it a problem with the move_uploaded_file function?  Any
 ideas?

What does the PHP error log say?

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Re: [PHP] image upload woes

2004-06-26 Thread Marek Kilimajer
Edward Peloke wrote --- napísal::
I have code which attempts to upload some files and create thumbnails.  The
same code on one server works ok, the same code on another server throws an
error everytime I hit submit that says The document contains no data...it
appears to be a javascript error.  It is not an error that I am throwing.
Has anyone ever had this problem?
Thanks,
Eddie
I bet that the script is dying for some reason. Turn display_errors on 
or check the logs, the real reason should be there somewhere. And it's 
not javascript.

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RE: [PHP] image upload woes

2004-06-25 Thread Jay Blanchard
[snip]
I have code which attempts to upload some files and create thumbnails.
The same code on one server works ok, the same code on another server
throws an error everytime I hit submit that says The document contains
no data...it
appears to be a javascript error.  It is not an error that I am
throwing. Has anyone ever had this problem?
[/snip]

I am sure that someone has had a problem like this, but if you believe
it to be a JavaScript problem why would you not ask a JavaScript list?

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Re: [PHP] image upload woes

2004-06-25 Thread Curt Zirzow
* Thus wrote Edward Peloke:
 I have code which attempts to upload some files and create thumbnails.  The
 same code on one server works ok, the same code on another server throws an
 error everytime I hit submit that says The document contains no data...it
 appears to be a javascript error.  It is not an error that I am throwing.
 Has anyone ever had this problem?

diff -u otherserver:/usr/local/lib/php.ini /usr/local/lib/php.ini


  WARNING:  The information contained in this message and any attachments is
 intended only for the use of the individual or entity to which it is

for some reason I'm always tempted to make some sort of comment
here.



Curt
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Re: [PHP] image upload

2003-10-06 Thread Yury B .
Sorry, there was typo in the code I sent previously. Here is the 
right code but the same problem - secont image is with incorrect 
header:

?php
$nw=100; //The Width Of The Thumbnails
//$rw=400;

$ipath = ./pics; //Path To Place Where Images Are Uploaded.
$tpath = ./thumbs;//Path To Place Where Thumbnails Are Uploaded

function LoadJpeg ($imgname) {
   $im = @imagecreatefromjpeg ($imgname); /* Attempt to open */
   if (!$im) { /* See if it failed */
   $im  = imagecreate (150, 30); /* Create a blank image */
   $bgc = imagecolorallocate ($im, 255, 255, 255);
   $tc  = imagecolorallocate ($im, 0, 0, 0);
   imagefilledrectangle ($im, 0, 0, 150, 30, $bgc);
   /* Output an errmsg */
   imagestring ($im, 1, 5, 5, Error loading $imgname, $tc);
   }
   return $im;
}

$dimensions = getimagesize($file);

$thname = $tpath/$file_name;
//$rname = $ipath/$file_name;

$w=$dimensions[0];
$h=$dimensions[1];

$c=$nw/$w;
//$c2=$rw/w;
$nh=$h*$c; //The Height Of The Thumbnails
//$rh=$h*$c2; //The Height Of The Large Pictures

$img = LoadJpeg($file);
//$img2 = LoadJpeg($file);
$thumb = imagecreatetruecolor($nw,$nh);
//$large = imagecreatetruecolor($rw,$rh);

imagecopyresampled($thumb,$img,0,0,0,0,$nw,$nh,$w,$h);
//  imagecopyresampled($large,$img2,0,0,0,0,$rw,$rh,$w,$h);
imagejpeg($thumb,$thname,95);
//  imagejpeg($large,$rname,95);

imagedestroy($img2);
?

On 6 Oct 2003 at 8:09, Jason Wong wrote:

 On Monday 06 October 2003 00:32, Yury B. wrote:
  Hi I need to upload two resized images out from one jpg image. I use
  following code to do it:
 
 [snip]
 
 
  This code is working perfectly but produces only one uploaded and
  resized image (I comented out the lines that I add for second image)
  If I take out comments from the code on the second image - this
  script doesn't work - it produces two files on the server but only
  one of them is working the other one shows error of wrong hedding.
  How should I upload two resized files? I know it's possible but how
  can I fit everything in one portion of code?
 
 Check the values of all your variables -- in particular $rw, as it doesn't 
 seem to be initialised.
 
 -- 
 Jason Wong - Gremlins Associates - www.gremlins.biz
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *
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Re: [PHP] image upload

2003-10-06 Thread Yury B .
Thank you for all help I have just figured out that there is other 
variable prob. See pointer ---:

?php
$nw=100; //The Width Of The Thumbnails
//$rw=400;

$ipath = ./pics; //Path To Place Where Images Are Uploaded.
$tpath = ./thumbs;//Path To Place Where Thumbnails Are Uploaded

function LoadJpeg ($imgname) {
   $im = @imagecreatefromjpeg ($imgname); /* Attempt to open */
   if (!$im) { /* See if it failed */
   $im  = imagecreate (150, 30); /* Create a blank image */
   $bgc = imagecolorallocate ($im, 255, 255, 255);
   $tc  = imagecolorallocate ($im, 0, 0, 0);
   imagefilledrectangle ($im, 0, 0, 150, 30, $bgc);
   /* Output an errmsg */
   imagestring ($im, 1, 5, 5, Error loading $imgname, $tc);
   }
   return $im;
}

$dimensions = getimagesize($file);

$thname = $tpath/$file_name;
//$rname = $ipath/$file_name;

$w=$dimensions[0];
$h=$dimensions[1];

$c=$nw/$w;
-- //$c2=$rw/w; 
$nh=$h*$c; //The Height Of The Thumbnails
//$rh=$h*$c2; //The Height Of The Large Pictures

$img = LoadJpeg($file);
//$img2 = LoadJpeg($file);
$thumb = imagecreatetruecolor($nw,$nh);
//$large = imagecreatetruecolor($rw,$rh);

imagecopyresampled($thumb,$img,0,0,0,0,$nw,$nh,$w,$h);
//  imagecopyresampled($large,$img2,0,0,0,0,$rw,$rh,$w,$h);
imagejpeg($thumb,$thname,95);
//  imagejpeg($large,$rname,95);

imagedestroy($img2);
?

On 6 Oct 2003 at 8:09, Jason Wong wrote:

 On Monday 06 October 2003 00:32, Yury B. wrote:
  Hi I need to upload two resized images out from one jpg image. I use
  following code to do it:
 
 [snip]
 
 
  This code is working perfectly but produces only one uploaded and
  resized image (I comented out the lines that I add for second image)
  If I take out comments from the code on the second image - this
  script doesn't work - it produces two files on the server but only
  one of them is working the other one shows error of wrong hedding.
  How should I upload two resized files? I know it's possible but how
  can I fit everything in one portion of code?
 
 Check the values of all your variables -- in particular $rw, as it doesn't 
 seem to be initialised.
 
 -- 
 Jason Wong - Gremlins Associates - www.gremlins.biz
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *
 --
 Search the list archives before you post
 http://marc.theaimsgroup.com/?l=php-general
 --
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 It's likely to last.
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 */
 

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Re: [PHP] image upload

2003-10-05 Thread Jason Wong
On Monday 06 October 2003 00:32, Yury B. wrote:
 Hi I need to upload two resized images out from one jpg image. I use
 following code to do it:

[snip]


 This code is working perfectly but produces only one uploaded and
 resized image (I comented out the lines that I add for second image)
 If I take out comments from the code on the second image - this
 script doesn't work - it produces two files on the server but only
 one of them is working the other one shows error of wrong hedding.
 How should I upload two resized files? I know it's possible but how
 can I fit everything in one portion of code?

Check the values of all your variables -- in particular $rw, as it doesn't 
seem to be initialised.

-- 
Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design  Hosting * Internet  Intranet Applications Development *
--
Search the list archives before you post
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*/

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RE: [PHP] image upload question

2003-03-12 Thread Tyler Durdin
Nothing really. I did happen across a couple of tutorials from 
phpbuilder.com
   http://www.phpbuilder.com/columns/michael20020712.php3?print_mode=1
and
   http://www.phpbuilder.com/columns/bealers2904.php3?page=3print_mode=1

may be able to piece something together from these two articles. let me know 
if you find out anything.

thanks,
TD

Hey Tyler,
Did you get any progress on this? I'm trying to do the same thing.
Johnny


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Re: [PHP] Image upload into database

2002-07-24 Thread Tyler Longren

Are you trying to upload the same image as you did at home?  If so,
size isn't the problem if you can do it from home.  It might be a
timeout issue.  There might be something in php.ini you can set for
timeout.  You can specify the max filesize to upload in php.ini also.

Good luck,
Tyler


On Wed, 24 Jul 2002 19:43:37 -0400 (EDT)
Jesse Lawrence [EMAIL PROTECTED] wrote:

 I've setup an image upload feature on a site, which
 uploads images into a mysql database.
 
 The uploads are working absolutely as expected on my
 local computer (the server), but when someone else
 tried to upload, only 1/3 of the image was uploaded. 
 Could it be a matter of size?  I was originally using
 just a Blob, and have since switched to a Long Blob.
 Any thoughts or comments on this would be greatly
 appreciated. 
 
 Thanks a bunch,
 
 Jesse 
 
 __
 
 Post your ad for free now! http://personals.yahoo.ca
 
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RE: [PHP] Image upload into database

2002-07-24 Thread Brian V Bonini

Just curious why you don't upload the image to a dir and just store the link
in the db?

 -Original Message-
 From: Jesse Lawrence [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, July 24, 2002 7:44 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Image upload into database


 I've setup an image upload feature on a site, which
 uploads images into a mysql database.

 The uploads are working absolutely as expected on my
 local computer (the server), but when someone else
 tried to upload, only 1/3 of the image was uploaded.
 Could it be a matter of size?  I was originally using
 just a Blob, and have since switched to a Long Blob.
 Any thoughts or comments on this would be greatly
 appreciated.

 Thanks a bunch,

 Jesse

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Re: [PHP] Image upload into database

2002-07-24 Thread Justin French

You need to look at the differences between your server and the live one.

The only real way to test is to have both you AND another tester (preferably
on a slow computer with 56k connection) to try uploading the SAME IMAGE FILE
to both servers.

This will rule out problems with the data type (eg blob).

Then test with larger images/files.



Likely problems will be:

- the file size is too big, and the PHP script is timing out before it can
finish (check php.ini for differences in script timeouts)

- there is a maximum file size for uploaded files on the server, which is
different to 

- the file isn't too big, but the script is still timing out (check php.ini
for differences in script timeouts)

- the 56k connection (different to your office set-up) means that files
upload way too slow, or get interrupted


If possible you should compare your php.ini to the one of the live server,
and try to match them up, which will help.


Justin French






on 25/07/02 9:43 AM, Jesse Lawrence ([EMAIL PROTECTED]) wrote:

 I've setup an image upload feature on a site, which
 uploads images into a mysql database.
 
 The uploads are working absolutely as expected on my
 local computer (the server), but when someone else
 tried to upload, only 1/3 of the image was uploaded.
 Could it be a matter of size?  I was originally using
 just a Blob, and have since switched to a Long Blob.
 Any thoughts or comments on this would be greatly
 appreciated. 
 
 Thanks a bunch,
 
 Jesse 
 
 __
 Post your ad for free now! http://personals.yahoo.ca


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Re: [PHP] Image upload and scaling

2002-03-11 Thread Samuel Ottenhoff

Someone just mentioned ImageMagick... Check it out:

http://www.imagemagick.org/

ImageMagickTM is a robust collection of tools and libraries to read, write,
and manipulate an image in many image formats (over 68 major formats)
including popular formats like TIFF, JPEG, PNG, PDF, PhotoCD, and GIF. With
ImageMagick you can create images dynamically, making it suitable for Web
applications. You can also resize, rotate, sharpen, color reduce, or add
special effects to an image and save your completed work in the same or
differing image format. Image processing operations are available from the
command line, as well as through C, C++, Perl, or Java programming
interfaces.

Or you can check out the built in gd functions.

http://www.php.net/manual/en/ref.image.php

Sam


On 3/11/02 12:21 PM, P.Agenbag [EMAIL PROTECTED] wrote:

 Hi, I am trying to make a util whereby ppl can upload their own images to my
 server for me to automatically display them.
 The below code works fine, but I have the following problem.
 It only works fne if everyone complies to a standard of a set width and height
 for the image. This is not always possible, so I'm looking for a way to accept
 the image in any form they have and then to scale it
 to fit within an acceptable height/width range.
 This I need help with, so if someone could hep me ( at the hand of my current
 code) I would be very pleased.
 
 Thanks
 
 Petre
 
 below my code snippet


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Re: [PHP] Image Upload

2002-01-24 Thread Bogdan Stancescu

This is a very good exercise you shouldn't skip by using prefabricated tools.
Just use a input type=file for the first part and the PHP documentation
for the second - the procedure in itself is really simple, but you'll have
the opportunity to understand some nice technicalities in the process.

Bogdan

[EMAIL PROTECTED] wrote:

 Does anyone have a good script for uploading an image and storing it in a
 mySQL database.

 Thanks

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Re: [PHP] image upload - determining image resolution in pixels ?

2001-05-22 Thread Chris Lee

open the file with gd and use imagesx() and imagesy()

?php
$img = imagecreatefromjpeg($file_name)
$x = imagesx($img);
$y = imagesy($img);
?

gd does not handel quicktime, only jpeg, gif (older, dont go there), png,
tiff I think thts it. I havent checked. but never the less, images, not
movies.

--

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  [EMAIL PROTECTED]


Nicolas Mermet [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Hi,
 I was wondering if there is a way to analize an uploaded jpeg file in
 order to extract its resolution in pixels.
 Would that be also possible with a quicktime movie ?
 thanks,
 Nicolas

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Re: [PHP] image upload - determining image resolution in pixels ?

2001-05-22 Thread Markus Fischer

On Tue, May 22, 2001 at 10:38:32AM -0700, Nicolas Mermet wrote : 
 I was wondering if there is a way to analize an uploaded jpeg file in
 order to extract its resolution in pixels.

GetImageSize() is a favourite one here.

 Would that be also possible with a quicktime movie ?

Possibly, but no one has done a constribution yet to php.

- Markus

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Re: [PHP] Image Upload??

2001-05-16 Thread Brave Cobra

Done that, doesn't work!

Brave Cobra
- Original Message - 
From: Toby Dacre [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 16, 2001 3:29 AM
Subject: Re: [PHP] Image Upload??


 
 chmod the file or directory so that php can access it
 
 it doesn't run as you!
 
 
 
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Re: [PHP] Image Upload??

2001-05-16 Thread Brave Cobra

Maybe I ought to mention that I don't have direct access to this server.
It's a F2S account, I'm trying to upload to.

BC
- Original Message -
From: Brave Cobra [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 16, 2001 10:01 AM
Subject: Re: [PHP] Image Upload??


 Done that, doesn't work!

 Brave Cobra
 - Original Message -
 From: Toby Dacre [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, May 16, 2001 3:29 AM
 Subject: Re: [PHP] Image Upload??


 
  chmod the file or directory so that php can access it
 
  it doesn't run as you!
 
 
 
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Re: [PHP] Image Upload??

2001-05-16 Thread Brave Cobra

And then I found the answer.
The PHP module of the Apache server at F2S is running in Safe mode(like the
error said), meaning that you can't do uploads in PHP. This safe mode
prohibits that.
The only alternative is uploading in CGI or Perl.
Another challange to let PHP and CGI work together!

BC
- Original Message -
From: Brave Cobra [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 16, 2001 12:52 PM
Subject: Re: [PHP] Image Upload??


 Maybe I ought to mention that I don't have direct access to this server.
 It's a F2S account, I'm trying to upload to.

 BC
 - Original Message -
 From: Brave Cobra [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, May 16, 2001 10:01 AM
 Subject: Re: [PHP] Image Upload??


  Done that, doesn't work!
 
  Brave Cobra
  - Original Message -
  From: Toby Dacre [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Wednesday, May 16, 2001 3:29 AM
  Subject: Re: [PHP] Image Upload??
 
 
  
   chmod the file or directory so that php can access it
  
   it doesn't run as you!
  
  
  
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Re: [PHP] Image Upload??

2001-05-16 Thread James Holloway

From phpinfo() on f2s.com

upload_max_filesize 2M

So, something like,

@copy($file, /path/to . $file_name)
or die (Blam, something's up!);

should work - haven't got time to try it at the moment.

James.


 What am I doing wrong here?
 Is there a way to get around the temporary folder?

 Tnx

 Brave Cobra





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Re: [PHP] Image Upload??

2001-05-16 Thread Brave Cobra

But as you can see too : upload_tmp_dir has no value, so I'm guessing this
won't work. I'm still getting errors with PHP, no problem in CGI though.

BC
- Original Message -
From: James Holloway [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 16, 2001 2:47 PM
Subject: Re: [PHP] Image Upload??


 From phpinfo() on f2s.com

 upload_max_filesize 2M

 So, something like,

 @copy($file, /path/to . $file_name)
 or die (Blam, something's up!);

 should work - haven't got time to try it at the moment.

 James.


  What am I doing wrong here?
  Is there a way to get around the temporary folder?
 
  Tnx
 
  Brave Cobra
 
 



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Re: [PHP] Image Upload??

2001-05-15 Thread Toby Dacre


chmod the file or directory so that php can access it

it doesn't run as you!



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Re: [PHP] Image Upload

2001-05-07 Thread Geir Eivind Mork

Kyle Mathews wrote:

 I'm looking for some code that will upload images to my server from a form
 submission.
 I'd also like it to check for a max file size of the images.
 Any help would be appreciated.

what about reading the manual? there are variables that contain the file size.

http://www.php.net/manual/en/features.file-upload.php

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Re: [PHP] Image Upload

2001-05-06 Thread Henrik Hansen

Kyle Mathews [EMAIL PROTECTED] wrote:

  Hello:
  
  I'm looking for some code that will upload images to my server from a form
  submission.
  I'd also like it to check for a max file size of the images.
  

look at the getimagesize() function

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