foreach iterates over an array or a object (see Traversable ).
If you pass anything different he complains
wrote:
> Miller, Terion wrote:
>
>> Why is this an invalid argument?
>>
>> foreach(($row['inType']) as $inType){
>>
>> echo $inType,'';}
>>
>> I am trying to output results from a data base
Actually this ended up doing what I needed:
$result =
mysql_query($sql) or die(mysql_error());
$header = false;
while
Miller, Terion wrote:
Why is this an invalid argument?
foreach(($row['inType']) as $inType){
echo $inType,'';}
I am trying to output results from a data base that may have multiple
results for the same name
So trying to use an array and foreach that is the right track ...right?
Loo
On Thu, 2009-07-16 at 15:41 -0400, Miller, Terion wrote:
> Why is this an invalid argument?
>
> foreach(($row['inType']) as $inType){
>
> echo $inType,'';}
>
> I am trying to output results from a data base that may have multiple
> results for the same name
>
> So trying to use an array an
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