Hi Ken, > As we all know, this copies an object in PHP: > $obj2 = $obj1 > Preferable a way to fix PHP not to copy the object, but the reference.
this will do want you want: $obj2 = &$obj1; -- Jimmy ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Always keep a cool head and a warm heart -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
