Instead of check for $ready2be_checked, use a hidden form field instead of relying on the submit button to be pressed. If the Javascript auto-submits the form the hidden field will still be there. -Kevin
----- Original Message ----- From: "Riccardo Sepe" <[EMAIL PROTECTED]> To: "php-general" <[EMAIL PROTECTED]> Sent: Friday, September 27, 2002 2:19 PM Subject: [PHP] PHP and JavaScript on a form validation task > Hi every1 I'm buidin' up a form that should perform a couple of checks > before submit. > I used javascript but as the form has got option fields also and some > field changes upon the checkbox chosen > the script has to know when I'm just changing the option or when I'm > tryin' 2 send the form... > (in order to change the option or eventually perform the check). > Can I do that on the same page? ..I mean can I pass a variable through > javascript 2 php? > > The problem is that if I call the submit button "ready2be_checked" and I > use an onclick(validate_the_form) handle, > javascript works fine but it misses the variable "ready2be_checked" so > the "isset" statement for ex. if(isset($ready2be_checked)){ ....} > doesn't work! > Using onsubmit instead, > javascript performs the check and sends the form anyway cause the isset > check finds the variable $ready2be_checked !! > ? ? ? ? ? ? ? > > Sorry if I posted it twice > Thanx in advance > Ricky > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php