Thanks Marek, That's exactly what I was looking for. I also found
another solution, which was to build a second array with the information
I want and merge the two arrays together with +. I like eval better :)
thanks again.
For anyone that is interested this works too.
$a = "'THREE'";
$b = "3";
$data1 = array('ONE'=>1,'TWO'=>2);
$data2[$a] = $b;
$test = $data1 + $data2;
-Original Message-
From: Marek Kilimajer [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, September 18, 2002 1:54 AM
To: PHP
Subject: Re: [PHP] Please, Help dynamicaly creating an Array
Try eval(), like this:
$str= "'THREE'=>3, 'FOUR'=>4";
eval("\$data2 = array('ONE'=>1,'TWO'=>2,$str);");
Max Sullivan wrote:
>I am trying to populate array values and keys from a variable with no
>luck.
>
>Lets say I have the following array.
>
>$data1 = array('ONE'=>1,'TWO'=>2,'THREE'=>3,'FOUR'=>4);
>
>And I want to create part of the array with the string below:
>
>$str= "'THREE'=>3, 'FOUR'=>4";
>$data2 = array('ONE'=>1,'TWO'=>2,$str);
>
>
>How can I create $data2 to work the same as $data1. When I try the
>above for $data2 a new key is created ([0]) for $str. And I end up with
>...'TWO'=>2, [0] => 'THREE'=>3, 'FOUR'=>4. It doesn't "interpret" the
>variable how I expect it to, instead it see's $str as a value. I guess
>the question is how can I make php use the string literally.
>
>I've tried everything I can think of and I think my head is about to
>explode :). Is it possible to create an Array this way? Any help is
>appreciated!!
>
>
>print_r($data1):
>Array
>(
>[ONE] => 1
>[TWO] => 2
>[THREE] => 3
>[FOUR] => 4
>)
>
>
>print_r($data2):
>Array
>(
>[ONE] => 1
>[TWO] => 2
>[0] => 'THREE'=>3, 'FOUR'=>4
>)
>
>
>
>
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