Hi again!
If it would be so simple I would not ask...
OK, once more:
#!/usr/local/bin/php -q
?php
$link1 = mysql_connect(localhost,user,passwd)
|| die (Fehler! Zeile .__LINE__.:\n.$php_errormsg.\n.mysql_error());
echo Link 1: $link1\n;
if (mysql_select_db(test, $link1)) {
echo Successful
On Friday 01 February 2002 16:23, Berthold wrote:
Hi again!
If it would be so simple I would not ask...
OK, once more:
#!/usr/local/bin/php -q
1) Has the mysql functions ever worked for you on that system?
2) Are you only get this problem when using php from the command line?
--
Jason
Hi!
1) Yes of course. I only have to delete the $link-variables...
But then - of course - I can only use the last connection.
2) It made no sense. Shell or Apache.
And the settings in php.ini are '-1' for 'unlimited'.
And I use the right php.ini, even with the shell-version.
Jason
Hi!
mysql_error returns nothing...
The error arrives while selecting the database via:
$link = mysql_connect(host,user,passwd);
mysql_select_db(bla, $link);
echo $link returns always '1'!
David Robley wrote:
In article [EMAIL PROTECTED], [EMAIL PROTECTED] says...
So,
I've testet
In article [EMAIL PROTECTED], [EMAIL PROTECTED] says...
Hi!
mysql_error returns nothing...
The error arrives while selecting the database via:
$link = mysql_connect(host,user,passwd);
mysql_select_db(bla, $link);
echo $link returns always '1'!
David Robley wrote:
In
Hi!
Thank you.
But I cannot use that $link1 and/or $link2 to select two databases on
different servers...
If I use $link1 the first time to select the first database on the first
server I got that error. But without that $link1-variable AND only one
connection in the script it works.
And it
On Friday 01 February 2002 15:38, Berthold wrote:
Hi!
Thank you.
But I cannot use that $link1 and/or $link2 to select two databases on
different servers...
If I use $link1 the first time to select the first database on the first
server I got that error. But without that $link1-variable AND
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