Re: [PHP] Re: Call to object function, want to PHP interpret returned string
Stuart wrote:
2009/7/6 John Allsopp j...@johnallsopp.co.uk:
David Robley wrote:
John Allsopp wrote:
Hi
At the top of a webpage I have:
?php
include_once(furniture.php);
$myFurniture = new furniture();
echo $myFurniture-getTop(my company title);
?
to deliver the first lines of HTML, everything in HEAD and the first
bits of page furniture (menu, etc).
In the furniture object in getTop(), I want to return a string that
includes the CSS file that I call with an include_once. But the
include_once isn't interpreted by PHP, it's just outputted. So from:
$toReturn = !DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0
Transitional//EN'
?php
include_once('styles3.txt');
?
...;
return $toReturn;
I get
?php
include_once('styles3.txt');
?
in my code.
Do I really have to break up my echo $myFurniture-getTop(my company
title); call to getTopTop, then include my CSS, then call getTopBottom,
or can I get PHP to interpret that text that came back?
PS. I may be stupid, this may be obvious .. I don't program PHP every day
Thanks in advance for your help :-)
Cheers
J
First guess is that your page doing the including doesn't have a filename
with a .php extension, and your server is set to only parse php in files
with a .php extension.
Cheers
Ah, thanks. It's a PHP object returning a string, I guess the PHP
interpreter won't see that.
So, maybe my object has to write a file that my calling file then includes
after the object function call. Doesn't sound too elegant, but is that how
it's gotta be?
You appear to be looking for the eval function: http://php.net/eval
However, in 99.99% of cases using eval is not the right solution. In
your case there are two ways to solve it.
The first way, assuming the thing you're trying to include is a
stylesheet, is to use an external link to a CSS file. That would be
the normal way to include a stylesheet in an HTML page and is far
more efficient that including it inline.
If it's not just a stylesheet that you're including then you'll want
to load the file in the getTop method. For example...
$toReturn = !DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0
Transitional//EN' ;
$toReturn.= file_get_contents('styles3.txt');
$toReturn.= '..';
Simple as that.
-Stuart
Thanks guys. Yes, actually file_get_contents didn't work for me, and yes
you're right, of course I should be including my CSS like LINK
rel='stylesheet' type='text/css' media='screen' href='style3.css'
title='style1' in the header.
The style3.txt file I was trying to PHP include was there so I could
include more than one stylesheet and make just one amendment. One for
printing and I'm guessing one for mobile. All that file contained was
the LINK... line above.
That was legacy code. Now I have a furniture object, of course, I can
put my stylesheet code in one place there just as part of the header,
and have no need for style3.txt.
Thanks for all your help.
J
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Re: [PHP] Re: Call to object function, want to PHP interpret returned string
David Robley wrote:
John Allsopp wrote:
Hi
At the top of a webpage I have:
?php
include_once(furniture.php);
$myFurniture = new furniture();
echo $myFurniture-getTop(my company title);
?
to deliver the first lines of HTML, everything in HEAD and the first
bits of page furniture (menu, etc).
In the furniture object in getTop(), I want to return a string that
includes the CSS file that I call with an include_once. But the
include_once isn't interpreted by PHP, it's just outputted. So from:
$toReturn = !DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0
Transitional//EN'
?php
include_once('styles3.txt');
?
...;
return $toReturn;
I get
?php
include_once('styles3.txt');
?
in my code.
Do I really have to break up my echo $myFurniture-getTop(my company
title); call to getTopTop, then include my CSS, then call getTopBottom,
or can I get PHP to interpret that text that came back?
PS. I may be stupid, this may be obvious .. I don't program PHP every day
Thanks in advance for your help :-)
Cheers
J
First guess is that your page doing the including doesn't have a filename
with a .php extension, and your server is set to only parse php in files
with a .php extension.
Cheers
Ah, thanks. It's a PHP object returning a string, I guess the PHP
interpreter won't see that.
So, maybe my object has to write a file that my calling file then
includes after the object function call. Doesn't sound too elegant, but
is that how it's gotta be?
Cheers
J
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Re: [PHP] Re: Call to object function, want to PHP interpret returned string
2009/7/6 John Allsopp j...@johnallsopp.co.uk:
David Robley wrote:
John Allsopp wrote:
Hi
At the top of a webpage I have:
?php
include_once(furniture.php);
$myFurniture = new furniture();
echo $myFurniture-getTop(my company title);
?
to deliver the first lines of HTML, everything in HEAD and the first
bits of page furniture (menu, etc).
In the furniture object in getTop(), I want to return a string that
includes the CSS file that I call with an include_once. But the
include_once isn't interpreted by PHP, it's just outputted. So from:
$toReturn = !DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0
Transitional//EN'
?php
include_once('styles3.txt');
?
...;
return $toReturn;
I get
?php
include_once('styles3.txt');
?
in my code.
Do I really have to break up my echo $myFurniture-getTop(my company
title); call to getTopTop, then include my CSS, then call getTopBottom,
or can I get PHP to interpret that text that came back?
PS. I may be stupid, this may be obvious .. I don't program PHP every day
Thanks in advance for your help :-)
Cheers
J
First guess is that your page doing the including doesn't have a filename
with a .php extension, and your server is set to only parse php in files
with a .php extension.
Cheers
Ah, thanks. It's a PHP object returning a string, I guess the PHP
interpreter won't see that.
So, maybe my object has to write a file that my calling file then includes
after the object function call. Doesn't sound too elegant, but is that how
it's gotta be?
You appear to be looking for the eval function: http://php.net/eval
However, in 99.99% of cases using eval is not the right solution. In
your case there are two ways to solve it.
The first way, assuming the thing you're trying to include is a
stylesheet, is to use an external link to a CSS file. That would be
the normal way to include a stylesheet in an HTML page and is far
more efficient that including it inline.
If it's not just a stylesheet that you're including then you'll want
to load the file in the getTop method. For example...
$toReturn = !DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0
Transitional//EN' ;
$toReturn.= file_get_contents('styles3.txt');
$toReturn.= '..';
Simple as that.
-Stuart
--
http://stut.net/
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Re: [PHP] Re: Call to object function, want to PHP interpret returned string
John Allsopp wrote:
David Robley wrote:
John Allsopp wrote:
Hi
At the top of a webpage I have:
?php
include_once(furniture.php);
$myFurniture = new furniture();
echo $myFurniture-getTop(my company title);
?
to deliver the first lines of HTML, everything in HEAD and the first
bits of page furniture (menu, etc).
In the furniture object in getTop(), I want to return a string that
includes the CSS file that I call with an include_once. But the
include_once isn't interpreted by PHP, it's just outputted. So from:
$toReturn = !DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0
Transitional//EN'
?php
include_once('styles3.txt');
?
...;
return $toReturn;
I get
?php
include_once('styles3.txt');
?
in my code.
Do I really have to break up my echo $myFurniture-getTop(my company
title); call to getTopTop, then include my CSS, then call getTopBottom,
or can I get PHP to interpret that text that came back?
PS. I may be stupid, this may be obvious .. I don't program PHP every
day
Thanks in advance for your help :-)
Cheers
J
First guess is that your page doing the including doesn't have a filename
with a .php extension, and your server is set to only parse php in files
with a .php extension.
Cheers
Ah, thanks. It's a PHP object returning a string, I guess the PHP
interpreter won't see that.
So, maybe my object has to write a file that my calling file then
includes after the object function call. Doesn't sound too elegant, but
is that how it's gotta be?
Cheers
J
I think I misunderstood your explanation :-) Can you show the actual content
of furniture.php? I wonder if there are missing ?php ? tags??
Cheers
--
David Robley
And it's only ones and zeros.
Today is Boomtime, the 41st day of Confusion in the YOLD 3175.
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