Hi,
Another solution I have used when I have to do conditional includes which
may cause the same page to be included twice
At the top of the code to be included (the separate file) put something
like:
if ($theFileAlreadyInclude != 1) {
and at the bottom you may put:
}
$theFileAlreadyIncluded =1;
depending on the way your coding you may need make the variable global.
Hope this helps.
Gerard
-Original Message-
From: Jason Wood [mailto:[EMAIL PROTECTED]]
Sent: Friday, October 26, 2001 3:43 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Error: Can't redeclare already declared function (PHP
3.0.15)
I had the same type of problem. ( i think)
I had one main page (say index.php) that had a bare bones html page. No
functions or anything.
Then i had separate pages that would be included only if i was using them
(like, say, a category.php for displaying categories, then products.php for
showing products.)
I had a function called printlist(); that would create a drop down menu
with categories/subcategories; this was in both category.php and
products.php. Niether of those files were included at the same time though,
and it'd give me the redeclare error... what i did was rename the function
in each file (like for category.php, rename it to printlist1(); and then in
products.php rename it to printlist2();... this is a quick fix). Let me
know if this was any help :)
--
Jason Wood
Chief Technology Officer
Expressive Tek, Inc.
407 Kehrs Mill Road
Ballwin, MO 63011
Phone 636.256.1362
www.expressivetek.com
"Patrick Dunford" <[EMAIL PROTECTED]> wrote in message
001501c15e27$1a738b80$bd84a7cb@patricks">news:001501c15e27$1a738b80$bd84a7cb@patricks...
> I have a script (let's call it a.php3) that brings in another script
b.php3
> with the include or require call.
>
> In script b.php3 there is an include or require call to bring in script
> c.php3.
>
> Script a.php3 after making one and only one include (the include is not
> repeated anywhere in a.php3) then calls a function x which is defined in
> script b.php3.
>
> The first time the function is called it executes without any problems.
The
> second time in which it is called, in exactly the same way, with the same
> parameters, it errors with the message
> Can't redeclare already declared function in c.php3 at line of the first function declaration in c.php3>
>
> The function is not actually named in the error message. This is the code
> block in c.php3 which the error occurs:
>
>
>
> function getDirNames($sourceDir,$includeBase)
> {
> global $pathList;
>
> function findAllDirsInDir($sourceDir)
> {
>global $pathList;
>$dirHandle=opendir($sourceDir);
>while (($subDir=readdir($dirHandle))!=false)
>{
> if (is_dir($sourceDir."/".$subDir))
> {
> if ($subDir != "." && $subDir != "..")
> {
> $dirList[] = $sourceDir."/".$subDir;
> $pathList[] = $sourceDir."/".$subDir;
> }
> }
>}
>closedir($dirHandle);
>return $dirList;
> }; <>
>
> function buildDirList($sourceDir,$recurse)
> {
>$subDirList=findAllDirsInDir($sourceDir);
>if (count($subDirList) != 0)
> $recurse=true;
>else
> $recurse=false;
>for($i=0; $i{
> $currentSubDir=$subDirList[$i];
> if ($recurse==true)
> buildDirList($currentSubDir,$recurse);
>}
> }
>
> buildDirList($sourceDir,true);
> if ($includeBase == TRUE)
>$pathList[] = $sourceDir;
> return $pathList;
> }
>
> There are no multiple calls to include or require:
>
> * a.php3 which is the script that calls the function several times to
output
> data, contains only one call to include() that is not inside any kind of
> loop. It is called once just before the first function call.
>
> *b.php3 which is the script that is included by a.php3. It includes c.php3
> ONCE ONLY, NOT IN A LOOP.
>
> *c.php3 which is the script in which the error is occurring.
>
> Debugging b.php3 shows that the error message is thrown when execution
> reaches the line in which the function from c.php3 is called. Therefore I
> surmise that the error message is ambiguous.
>
>
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