On Monday 30 July 2001 03:10, Ben Bleything wrote:
I understand that the POST operation stores the data from the form in
the message headers... I just need to know which headers, so I can use
that information to write my own... I basically want to make it seem as
if the $failure var was
The easiest solution is to create the failure variable as a session
variable.
-Stewart
-Original Message-
From: Matt Rogers [mailto:[EMAIL PROTECTED]]
Sent: 30 July 2001 04:00
To: [EMAIL PROTECTED]
Subject: [PHP] Re: HTTP header question.
I don't know how to solve your problem, but I
still don't see the need to pass as a header...
?PHP
$success=0;
$failure_notice='';
if($login){
# lets say we are checking against database for valid user
#connect to db
#do your query
#get result in $valid_login, $valid_pass
if($login==$valid_login
Some of the original message:
still don't see the need to pass as a header...
you avoid the http://his.website.com/rams/login.php?failure=true as you
just get
login.php each time as far as the displayed URL.
my opinion, let the scripting handle all the logic and ease off the header
below
Some of the original message:
still don't see the need to pass as a header...
you avoid the http://his.website.com/rams/login.php?failure=true as you
just get
login.php each time as far as the displayed URL.
my opinion, let the scripting handle all the logic and ease off the header
-Original Message-
From: Dave [mailto:[EMAIL PROTECTED]]
Sent: Monday, July 30, 2001 8:05 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP] Re: HTTP header question.
below
Some of the original message:
still don't see the need to pass as a header...
you avoid the http://his.website.com/rams
Ahh, and a bit of clarification before you read the code, the page posts
to itself =
Ben
-Original Message-
From: Dave [mailto:[EMAIL PROTECTED]]
Sent: Monday, July 30, 2001 8:05 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP] Re: HTTP header question.
below
Some of the original message
I'm fully aware of that. The issue is not the refreshing (that works
fine)...
Here's a little more detail:
if(!$login)
{
if($failure)
// complain
// show the form
}
else
{
if(user_is_good)
// take them to the next page
else
Quoting Ben Bleything [EMAIL PROTECTED]:
I'm fully aware of that. The issue is not the refreshing (that works
fine)...
Here's a little more detail:
if(!$login)
{
if($failure)
// complain
// show the form
}
else
{
if(user_is_good)
What I'm looking for is a way to do this such that the user does not see
anything more than http://host.name.here/rams/login.php in their address
bar when it failed...
Doesn't using a form with its method set to post send the variables through
headers? If that's the case, couldn't you
to the page.
I'm having NO luck whatsoever with the HTTP RFC's... too thick =
Thanks,
Ben
-Original Message-
From: Philip Murray [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 29, 2001 6:06 PM
To: Ben Bleything
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Re: HTTP header question.
Quoting
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