Thank YOU! It worked wonderful, I used a blank to separate the
content like this: $displn = implode("",$new_data);
Thank you again and thank you to everyone for helping me through this!
At 01:15 PM 9/19/2001 +0930, David Robley wrote:
>On Wed, 19 Sep 2001 12:28, Scott wrote:
> > That works, t
On Wed, 19 Sep 2001 12:28, Scott wrote:
> That works, thank you, but it prints at the top of my page, is there
> a way to store that array into a single variable?
>
Yes - implode()
--
David Robley Techno-JoaT, Web Maintainer, Mail List Admin, etc
CENTRE FOR INJURY STUDIES Flinders Uni
If you want to store all the values in the array in one variable (just as a
string with delimiters maybe?) Try this:
foreach ($array as $value) {
$temp .= $value . "|";
}
Josh Hoover
KnowledgeStorm, Inc.
[EMAIL PROTECTED]
Searching for a new IT solution for your company? Need to improve
;[EMAIL PROTECTED]>
>To: "Scott" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
>Sent: Tuesday, September 18, 2001 7:29 PM
>Subject: RE: [PHP] re: array question
>
>
> > perhaps i'm misunderstanding you, but why not use a for loop?
> >
> > fo
= $value";
}
- Original Message -
From: "Jack Dempsey" <[EMAIL PROTECTED]>
To: "Scott" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Tuesday, September 18, 2001 7:29 PM
Subject: RE: [PHP] re: array question
> perhaps i'm misunderstanding you,
Jack-
Thanks for the response, but I don't want to echo the array, I want to
bundle it into a new variable that will be called as part of a str_replace.
The array is created from a loop through all the navigation items in a
database.
The code is below, if I echo the code is formatted in the wron
perhaps i'm misunderstanding you, but why not use a for loop?
for($i=0;$imailto:[EMAIL PROTECTED]]
Sent: Tuesday, September 18, 2001 10:11 PM
To: [EMAIL PROTECTED]
Subject: [PHP] re: array question
Oh, that works wonders and for the first time in 24 hours I am
smiling! One more
thing to make i
You wrote:
> Also, consider using print or echo as opposed to printf. And lastly,
you
> really don't need to use mysql_free_result, PHP does this
automagically
> after the script dies. Sorry for picking on you, you may have your
> reasons. ;-)
Really? Then why was it that, when I neglected to
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