$output[] = array_slice ($textArray, $int_range[start][$i],
$int_range[end][$i]); is creating a multi-dimensional array as
$output. In my foreach loop I was treating $output as a
single-dimensional array. That's why it wasn't working. print_r() is
my friend. :-)
On 10/13/05, Rodney Green [EMAIL PROTECTED] wrote:
Thanks Connor. I changed the line to the following. Is it correct now?
The array $output[] is now being populated. However, when I go to
print the values of the $output array using a foreach loop, it prints
out the word Array for each array item.
$output[] = array_slice ($textArray, $int_range[start][$i],
$int_range[end][$i]);
On 10/12/05, Ethilien [EMAIL PROTECTED] wrote:
Are you trying to put each return from array_slice into $output as an
array? You need to replace $output = array_slice... with $output[] =
array_slice...
Also, you cannot just echo an array (even of characters). It must be a
string, or else echo will only produce the output 'Array'.
Hope this helps,
-Connor McKay
Rodney Green wrote:
Hello,
I'm using a for loop to iterate through an array and slice parts of
the array and add into another array.
When array_slice is called the variable $i is not being substituted
with the current value of
$i and the $output array is empty after running the script. Can
someone look at the code below and give me a clue as to why this
substitution is not happening? If I uncomment the echo $i; statement
the value of $i is printed just fine.
Thanks,
Rod
Here's my code:
$number = count ($int_range[start]);
//echo $number;
for ($i = 0; $i = $number; $i++) {
//echo $i;
$output = array_slice ($textArray, $int_range[start][$i],
$int_range[end][$i]);
}
foreach ($output as $value) {
echo $value;
}
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