Re: [PHP] Two cases going to same case?

2002-06-30 Thread Steve Edberg 

At 5:18 AM -0400 6/30/02, Leif K-Brooks wrote:
I have a switch in a script I'm working on.  I need to have case 1 
and 2 both to to case 3, but without case 1 going through case 2. 
Is this possible?


No, but you can do it this way:

switch ($foo) {

case 1:
   ...
   do_something();
   break;

case 2:
   ...
   do_something();
   break;

case 3:
   do_something();
   break;

}

function do_something() {

# this is the stuff that you want to do that is common to your
# cases 1, 2 and 3

}

This accomplishes the same thing.

-steve


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Re: [PHP] Two cases going to same case?

2002-06-30 Thread Tom Rogers 

Hi
One way to achieve the same effect:

fallthru = 0;
switch($whatever){
 case 1:
 do something1;
 $fallthru = 1;
 case 2:
 if(!$fallthrough){
 do something2;
 }
 case 3
 do something3;
 break;
}

Tom


At 05:18 AM 30/06/2002 -0400, Leif K-Brooks wrote:
I have a switch in a script I'm working on.  I need to have case 1 and 2 
both to to case 3, but without case 1 going through case 2.  Is this possible?


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Re: [PHP] Two cases going to same case?

2002-06-30 Thread Chris Shiflett 

Leif K-Brooks wrote:

 I have a switch in a script I'm working on.  I need to have case 1 and 
 2 both to to case 3, but without case 1 going through case 2.  Is this 
 possible? 


Does case 3 have to be in the switch? If not, just leave it to execute 
just after the end of the switch.

Otherwise, consider making your program modular. For case 3, include a 
file that has the code you're wanting to execute. Then all you have to 
do is include the same file at the bottom of both cases 1 and 2.

Chris



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