Re: [PHP] Undefined constant error

[Sascha Cunz]

> make sure you have register_globals on in php.ini or your next question
> will be 'why isn't $compteur set to the value posted?'  Better would be to
> change the line to the new magic globals, and learn the right way from
> scratch:

I agree with you as far, as to learn the right way from scratch - but this is 
no POST-Var here. 

> echo " if ($_POST['compteur'] == 1) {
>   echo "checked"; 
> }
> echo ">";

This is another bug in the script. Considering that, it would be correctly:
(Note the space between '"' and 'checked')

  echo "";

or shorter:

  echo
"";

Regards Sascha

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Re: [PHP] Undefined constant error

[Matt]

> From: "Voisine" <[EMAIL PROTECTED]>
> Sent: Sunday, September 29, 2002 7:52 PM
> Subject: [PHP] Undefined constant error


> I'm learning PHP from a book "PHP for newbie writen in French" and I
> have an error on one of the exemple. Undifined constant 'compteur' on
> line 15 which is :
> if (compteur == 1) {
>
> What I'm doing wrong? This is the script
>
>  include("config.inc.php");
> $query = "SELECT * FROM Type ORDER BY animalType";
> $result = mysql_query($query) or die ("Exécution de la sélection
> impossible");
>
> echo "CatalogueQuel type d'animal
> cherchez-vous ?\n";
> echo "\n";
> echo "";
> $compteur = 1;
> while ($ligne = mysql_fetch_array($result)) {
>  extract($ligne);
>  echo "";
>  echo "";
>  if (compteur == 1) {
you're missing the $ in from of compteur.  Should be:
if ($compteur == 1) {
make sure you have register_globals on in php.ini or your next question will
be 'why isn't $compteur set to the value posted?'  Better would be to change
the line to the new magic globals, and learn the right way from scratch:

if ($_POST['compteur'] == 1) {

For the full explaination see:
http://www.php.net/manual/fr/language.variables.predefined.php

>   echo "checked";
>  }

Also, I think this code needs to place the 'checked' within the  tag
so you end up with:

echo "";





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Re: [PHP] Undefined constant error

[Sascha Cunz]

There seems to be a print-error in this book. It's missing a '$'
This line:
>  if (compteur == 1) {
should be:
>  if ($compteur == 1) {

Sascha

Am Montag, 30. September 2002 01:52 schrieb Voisine:
> Hello,
>
> I'm learning PHP from a book "PHP for newbie writen in French" and I
> have an error on one of the exemple. Undifined constant 'compteur' on
> line 15 which is :
> if (compteur == 1) {
>
> What I'm doing wrong? This is the script
>
>  include("config.inc.php");
> $query = "SELECT * FROM Type ORDER BY animalType";
> $result = mysql_query($query) or die ("Exécution de la sélection
> impossible");
>
> echo "CatalogueQuel type d'animal
> cherchez-vous ?\n";
> echo "\n";
> echo "";
> $compteur = 1;
> while ($ligne = mysql_fetch_array($result)) {
>  extract($ligne);
>  echo "";
>  echo "";
>  if (compteur == 1) {
>   echo "checked";
>  }
>  echo " size='+1'>$animalType$typeDescription";
>
>  $compteur++;
> }
> echo "";
> echo "";
> ?>


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