Re: [PHP] Variables with - in their name

2012-11-18 Thread Nathan Nobbe
On Sat, Nov 17, 2012 at 11:09 PM, Ron Piggott 
ron.pigg...@actsministries.org wrote:

 I have made the following variable in a form:  (I am referring the
 select )

 ?php

 $row['promo_code_prefix']  = 42;
 $row['promo_code_suffix'] = 2;

 echo select name=\distributor- . $row['promo_code_prefix'] . - .
 $row['promo_code_suffix'] . \ style=\text-align: center;\\r\n;

 ?

 It could be wrote:

 ?php

 echo  $distributor-42-2;

 ?

 Only PHP is treating the hyphen as a minus sign --- which in turn is
 causing a syntax error.

 How do I retrieve the value of this variable and over come the “minus”
 sign that is really a hyphen?


php  ${distributor-42-2} = 5;
php  echo ${distributor-42-2};
5

I think that's it.

-nathan


Re: [PHP] Variables with - in their name

2012-11-18 Thread Ashley Sheridan
On Sun, 2012-11-18 at 01:37 -0700, Nathan Nobbe wrote:

 On Sat, Nov 17, 2012 at 11:09 PM, Ron Piggott 
 ron.pigg...@actsministries.org wrote:
 
  I have made the following variable in a form:  (I am referring the
  select )
 
  ?php
 
  $row['promo_code_prefix']  = 42;
  $row['promo_code_suffix'] = 2;
 
  echo select name=\distributor- . $row['promo_code_prefix'] . - .
  $row['promo_code_suffix'] . \ style=\text-align: center;\\r\n;
 
  ?
 
  It could be wrote:
 
  ?php
 
  echo  $distributor-42-2;
 
  ?
 
  Only PHP is treating the hyphen as a minus sign --- which in turn is
  causing a syntax error.
 
  How do I retrieve the value of this variable and over come the “minus”
  sign that is really a hyphen?
 
 
 php  ${distributor-42-2} = 5;
 php  echo ${distributor-42-2};
 5
 
 I think that's it.
 
 -nathan


I'd just try and avoid the hyphens in the variable names in the first
place if you can. Can you guarantee that everyone working on this system
will know when to encapsulate the variables in braces?

Thanks,
Ash
http://www.ashleysheridan.co.uk




Re: [PHP] Variables with - in their name

2012-11-18 Thread tamouse mailing lists
On Sun, Nov 18, 2012 at 5:12 AM, Ashley Sheridan
a...@ashleysheridan.co.uk wrote:
 On Sun, 2012-11-18 at 01:37 -0700, Nathan Nobbe wrote:

 On Sat, Nov 17, 2012 at 11:09 PM, Ron Piggott 
 ron.pigg...@actsministries.org wrote:

  I have made the following variable in a form:  (I am referring the
  select )
 
  ?php
 
  $row['promo_code_prefix']  = 42;
  $row['promo_code_suffix'] = 2;
 
  echo select name=\distributor- . $row['promo_code_prefix'] . - .
  $row['promo_code_suffix'] . \ style=\text-align: center;\\r\n;
 
  ?
 
  It could be wrote:
 
  ?php
 
  echo  $distributor-42-2;
 
  ?
 
  Only PHP is treating the hyphen as a minus sign --- which in turn is
  causing a syntax error.
 
  How do I retrieve the value of this variable and over come the “minus”
  sign that is really a hyphen?
 

 php  ${distributor-42-2} = 5;
 php  echo ${distributor-42-2};
 5

 I think that's it.

 -nathan


 I'd just try and avoid the hyphens in the variable names in the first
 place if you can. Can you guarantee that everyone working on this system
 will know when to encapsulate the variables in braces?

 Thanks,
 Ash
 http://www.ashleysheridan.co.uk



Agreed.

From http://www.php.net/manual/en/language.variables.basics.php :

Variable names follow the same rules as other labels in PHP. A
valid variable name starts with a letter or underscore, followed
by any number of letters, numbers, or underscores.

The ${var} circumvents this (somewhat), but in the case above, it
would be better to avoid the dashes and use underscores.

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Re: [PHP] Variables via url

2012-05-12 Thread Ashley Sheridan
On Sun, 2012-05-13 at 01:57 +1000, Tom Rogers wrote:

 Hello Ashley,
 
 Saturday, May 12, 2012, 9:15:23 AM, you wrote:
 
 
   Can someone point me at examples or directions on how I can pass a
  variable via a URL in the following way:
 
   http://server.domain.com//script///variable/
 
   I will only be passing one single /variable/.  And I want the 
  /script/ to use that.
 
   I don't want to see what the script is, for example I don't want it
  to say 'script.php' or 'script.html' ...
 
   Is this possible through PHP only, or do I have to write a rewrite
  directive in Apache to accomplish this?
 
 You can add this to apache conf:
 
 FilesMatch ^phpscript$
 ForceType application/x-httpd-php
 /FilesMatch
 
 Then make a file called phpscript without extension and drop it in the
 web root.
 
 ?php
 $info = explode('/', $_SERVER['PATH_INFO']);
 
 Then your url would look like:
 
 http://server.domain.com/phpscript/variable1/variable2
 
 
 -- 
 Best regards,
  Tom
 
 


As this method requires an Apache restart, I don't see what advantage
you have over using an .htaccess file?
-- 
Thanks,
Ash
http://www.ashleysheridan.co.uk




Re: [PHP] Variables via url

2012-05-12 Thread Adam Richardson
On Sat, May 12, 2012 at 12:25 PM, Ashley Sheridan
a...@ashleysheridan.co.uk wrote:
 As this method requires an Apache restart, I don't see what advantage
 you have over using an .htaccess file?

Performance:

http://httpd.apache.org/docs/current/howto/htaccess.html

You should avoid using .htaccess files completely if you have access
to httpd main server config file. Using .htaccess files slows down
your Apache http server. Any directive that you can include in a
.htaccess file is better set in a Directory block, as it will have the
same effect with better performance.

...putting this configuration in your server configuration file will
result in less of a performance hit, as the configuration is loaded
once when httpd starts, rather than every time a file is requested.

Adam

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Re: [PHP] Variables are empty only in fwrite

2012-03-18 Thread Tamara Temple

On Thu, 15 Mar 2012 11:30:20 -0400, Larry lrr...@gmail.com sent:

Hello, when I pass a variable whose value originally came from $_GET
or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
string. Note that the file is successfully opened and written to by
the script, but the variable that originally came from $_GET does not
have its value interpolated in the text file, even though it does get
interpolated in the echo().

 Code 
?
$meh = $_GET[q];
$writeline = : . $meh . : . strlen($meh) . PHP_EOL;
echo ( $writeline );

$fp = fopen(/tmp/wtf.log,w+);
fwrite($fp, $writeline );
fclose($fp);

var_dump($writeline);
?

 Request 

/search.php?q=meh123

 Response --- ( expected )

:meh123:6 string(10) :meh123:6 

 Contents of /tmp/wtf.log 
::0

Some sort of security setting in php.ini maybe? If so, I'm not only
curious in how to fix it but also how this actually happens. Does the
value assigned to $writeline not get immediately evaluated? I mean,
does $writeline know it contains variables from elsewhere, instead
of just containing a string of chars?

Thanks!


I'm not at all sure what's going on with your code and/or site. Please  
look at:


  http://mouseha.us/demos/larryproblem.txt 

To see the php code, and:

  http://mouseha.us/demos/larryproblem.php?q=meh123 

to see the demo.





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   aka tamouse__

May you never see a stranger's face in the mirror


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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Daniel P. Brown
On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

Are you sure it's not a permissions-based issue, perhaps when
writing as the normal user, then the user as which the web server
runs, et cetera?  What happens if you completely remove /tmp/wtf.log
and re-run your script with the appended query string?

-- 
/Daniel P. Brown
Dedicated Servers, Cloud and Cloud Hybrid Solutions, VPS, Hosting
(866-) 725-4321
http://www.parasane.net/

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Larry
On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

    Are you sure it's not a permissions-based issue, perhaps when
 writing as the normal user, then the user as which the web server
 runs, et cetera?  What happens if you completely remove /tmp/wtf.log
 and re-run your script with the appended query string?

I have removed the wtf.log file between runs, just did it once more.
Same thing happens. A new file is created, and the contents are ::0

So I'm sure its not a permissions issue ( However I'm also sure that
this shouldn't be happening so... ) Thanks.

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Matijn Woudt
On Thu, Mar 15, 2012 at 4:59 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
 daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

    Are you sure it's not a permissions-based issue, perhaps when
 writing as the normal user, then the user as which the web server
 runs, et cetera?  What happens if you completely remove /tmp/wtf.log
 and re-run your script with the appended query string?

 I have removed the wtf.log file between runs, just did it once more.
 Same thing happens. A new file is created, and the contents are ::0

 So I'm sure its not a permissions issue ( However I'm also sure that
 this shouldn't be happening so... ) Thanks.

The code is working fine here, of course, it should. Is it really
because of the $_GET?, have you tried setting $q = meh123;?
Also, try using file_put_contents('/tmp/wtf.log', $writeline); instead.

- Matijn

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Larry
On Thu, Mar 15, 2012 at 12:21 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 4:59 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
 daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

    Are you sure it's not a permissions-based issue, perhaps when
 writing as the normal user, then the user as which the web server
 runs, et cetera?  What happens if you completely remove /tmp/wtf.log
 and re-run your script with the appended query string?

 I have removed the wtf.log file between runs, just did it once more.
 Same thing happens. A new file is created, and the contents are ::0

 So I'm sure its not a permissions issue ( However I'm also sure that
 this shouldn't be happening so... ) Thanks.

 The code is working fine here, of course, it should. Is it really
 because of the $_GET?, have you tried setting $q = meh123;?
 Also, try using file_put_contents('/tmp/wtf.log', $writeline); instead.

 - Matijn

Yes I have tried to set a variable explicitly with a string, and that
variable does end up interpolated into the file. I just tried using
file_put_contents with the same result.

Here is a modified version, showing another variable that does work,
and file_put_contents():

?
$meh = $_GET[q];
$good = Yay I go in the File . PHP_EOL;
$writeline = : . $meh . : . strlen($meh) . : . $good;
echo ( $writeline );
file_put_contents(/tmp/wtf.log, $writeline );
var_dump($writeline);
?

Here the response/stdout:
:meh123:6:Yay I go in the File string(31) :meh123:6:Yay I go in the File 

But the file is the same:
root@prime:/tmp# rm wtf.log
root@prime:/tmp# ls wtf.log
ls: cannot access wtf.log: No such file or directory
[ I make the request ]
root@prime:/tmp# cat wtf.log
::0:Yay I go in the File

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Matijn Woudt
On Thu, Mar 15, 2012 at 7:51 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 12:21 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 4:59 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
 daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

    Are you sure it's not a permissions-based issue, perhaps when
 writing as the normal user, then the user as which the web server
 runs, et cetera?  What happens if you completely remove /tmp/wtf.log
 and re-run your script with the appended query string?

 I have removed the wtf.log file between runs, just did it once more.
 Same thing happens. A new file is created, and the contents are ::0

 So I'm sure its not a permissions issue ( However I'm also sure that
 this shouldn't be happening so... ) Thanks.

 The code is working fine here, of course, it should. Is it really
 because of the $_GET?, have you tried setting $q = meh123;?
 Also, try using file_put_contents('/tmp/wtf.log', $writeline); instead.

 - Matijn

 Yes I have tried to set a variable explicitly with a string, and that
 variable does end up interpolated into the file. I just tried using
 file_put_contents with the same result.

 Here is a modified version, showing another variable that does work,
 and file_put_contents():

 ?
 $meh = $_GET[q];
 $good = Yay I go in the File . PHP_EOL;
 $writeline = : . $meh . : . strlen($meh) . : . $good;
 echo ( $writeline );
 file_put_contents(/tmp/wtf.log, $writeline );
 var_dump($writeline);
 ?

 Here the response/stdout:
 :meh123:6:Yay I go in the File string(31) :meh123:6:Yay I go in the File 

 But the file is the same:
 root@prime:/tmp# rm wtf.log
 root@prime:/tmp# ls wtf.log
 ls: cannot access wtf.log: No such file or directory
 [ I make the request ]
 root@prime:/tmp# cat wtf.log
 ::0:Yay I go in the File

Have you checked apache log files for any warnings/errors?
How about writing $_GET['q'] directly? eg.
file_put_contents('/tmp/wtf.log', $_GET['q']);?

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Larry
On Thu, Mar 15, 2012 at 2:57 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 7:51 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 12:21 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 4:59 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
 daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

    Are you sure it's not a permissions-based issue, perhaps when
 writing as the normal user, then the user as which the web server
 runs, et cetera?  What happens if you completely remove /tmp/wtf.log
 and re-run your script with the appended query string?

 I have removed the wtf.log file between runs, just did it once more.
 Same thing happens. A new file is created, and the contents are ::0

 So I'm sure its not a permissions issue ( However I'm also sure that
 this shouldn't be happening so... ) Thanks.

 The code is working fine here, of course, it should. Is it really
 because of the $_GET?, have you tried setting $q = meh123;?
 Also, try using file_put_contents('/tmp/wtf.log', $writeline); instead.

 - Matijn

 Yes I have tried to set a variable explicitly with a string, and that
 variable does end up interpolated into the file. I just tried using
 file_put_contents with the same result.

 Here is a modified version, showing another variable that does work,
 and file_put_contents():

 ?
 $meh = $_GET[q];
 $good = Yay I go in the File . PHP_EOL;
 $writeline = : . $meh . : . strlen($meh) . : . $good;
 echo ( $writeline );
 file_put_contents(/tmp/wtf.log, $writeline );
 var_dump($writeline);
 ?

 Here the response/stdout:
 :meh123:6:Yay I go in the File string(31) :meh123:6:Yay I go in the File 

 But the file is the same:
 root@prime:/tmp# rm wtf.log
 root@prime:/tmp# ls wtf.log
 ls: cannot access wtf.log: No such file or directory
 [ I make the request ]
 root@prime:/tmp# cat wtf.log
 ::0:Yay I go in the File

 Have you checked apache log files for any warnings/errors?
 How about writing $_GET['q'] directly? eg.
 file_put_contents('/tmp/wtf.log', $_GET['q']);?

Yes I tried using $_GET['q'] directly to no avail. However, you found
a clue! apache error.log is giving this:
PHP Notice:  Undefined index: q in /var/www/test/search.php on line 2

Strange b/c I am obtaining and using that value successfully in echo()!

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Matijn Woudt
On Thu, Mar 15, 2012 at 8:41 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 2:57 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 7:51 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 12:21 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 4:59 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
 daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

    Are you sure it's not a permissions-based issue, perhaps when
 writing as the normal user, then the user as which the web server
 runs, et cetera?  What happens if you completely remove /tmp/wtf.log
 and re-run your script with the appended query string?

 I have removed the wtf.log file between runs, just did it once more.
 Same thing happens. A new file is created, and the contents are ::0

 So I'm sure its not a permissions issue ( However I'm also sure that
 this shouldn't be happening so... ) Thanks.

 The code is working fine here, of course, it should. Is it really
 because of the $_GET?, have you tried setting $q = meh123;?
 Also, try using file_put_contents('/tmp/wtf.log', $writeline); instead.

 - Matijn

 Yes I have tried to set a variable explicitly with a string, and that
 variable does end up interpolated into the file. I just tried using
 file_put_contents with the same result.

 Here is a modified version, showing another variable that does work,
 and file_put_contents():

 ?
 $meh = $_GET[q];
 $good = Yay I go in the File . PHP_EOL;
 $writeline = : . $meh . : . strlen($meh) . : . $good;
 echo ( $writeline );
 file_put_contents(/tmp/wtf.log, $writeline );
 var_dump($writeline);
 ?

 Here the response/stdout:
 :meh123:6:Yay I go in the File string(31) :meh123:6:Yay I go in the File 

 But the file is the same:
 root@prime:/tmp# rm wtf.log
 root@prime:/tmp# ls wtf.log
 ls: cannot access wtf.log: No such file or directory
 [ I make the request ]
 root@prime:/tmp# cat wtf.log
 ::0:Yay I go in the File

 Have you checked apache log files for any warnings/errors?
 How about writing $_GET['q'] directly? eg.
 file_put_contents('/tmp/wtf.log', $_GET['q']);?

 Yes I tried using $_GET['q'] directly to no avail. However, you found
 a clue! apache error.log is giving this:
 PHP Notice:  Undefined index: q in /var/www/test/search.php on line 2

 Strange b/c I am obtaining and using that value successfully in echo()!

Well.. That seems pretty buggy, I guess it's a bug in PHP. Try
changing q in something else, and maybe you want to submit a bug
report to PHP?

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Larry
On Thu, Mar 15, 2012 at 4:03 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 8:41 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 2:57 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 7:51 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 12:21 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 4:59 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
 daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().

  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );

 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);

 var_dump($writeline);
 ?

    Are you sure it's not a permissions-based issue, perhaps when
 writing as the normal user, then the user as which the web server
 runs, et cetera?  What happens if you completely remove /tmp/wtf.log
 and re-run your script with the appended query string?

 I have removed the wtf.log file between runs, just did it once more.
 Same thing happens. A new file is created, and the contents are ::0

 So I'm sure its not a permissions issue ( However I'm also sure that
 this shouldn't be happening so... ) Thanks.

 The code is working fine here, of course, it should. Is it really
 because of the $_GET?, have you tried setting $q = meh123;?
 Also, try using file_put_contents('/tmp/wtf.log', $writeline); instead.

 - Matijn

 Yes I have tried to set a variable explicitly with a string, and that
 variable does end up interpolated into the file. I just tried using
 file_put_contents with the same result.

 Here is a modified version, showing another variable that does work,
 and file_put_contents():

 ?
 $meh = $_GET[q];
 $good = Yay I go in the File . PHP_EOL;
 $writeline = : . $meh . : . strlen($meh) . : . $good;
 echo ( $writeline );
 file_put_contents(/tmp/wtf.log, $writeline );
 var_dump($writeline);
 ?

 Here the response/stdout:
 :meh123:6:Yay I go in the File string(31) :meh123:6:Yay I go in the File 

 But the file is the same:
 root@prime:/tmp# rm wtf.log
 root@prime:/tmp# ls wtf.log
 ls: cannot access wtf.log: No such file or directory
 [ I make the request ]
 root@prime:/tmp# cat wtf.log
 ::0:Yay I go in the File

 Have you checked apache log files for any warnings/errors?
 How about writing $_GET['q'] directly? eg.
 file_put_contents('/tmp/wtf.log', $_GET['q']);?

 Yes I tried using $_GET['q'] directly to no avail. However, you found
 a clue! apache error.log is giving this:
 PHP Notice:  Undefined index: q in /var/www/test/search.php on line 2

 Strange b/c I am obtaining and using that value successfully in echo()!

 Well.. That seems pretty buggy, I guess it's a bug in PHP. Try
 changing q in something else, and maybe you want to submit a bug
 report to PHP?

Changing the index name didn't help. I think I will submit a bug,
after a bit more scrutiny of my php.ini to make sure there isn't some
restriction in there. This is a default ubuntu apache/php.ini though.
Thanks again.

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Re: [PHP] Variables are empty only in fwrite

2012-03-15 Thread Stuart Dallas
On 15 Mar 2012, at 20:07, Larry wrote:

 On Thu, Mar 15, 2012 at 4:03 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 8:41 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 2:57 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 7:51 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 12:21 PM, Matijn Woudt tijn...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 4:59 PM, Larry lrr...@gmail.com wrote:
 On Thu, Mar 15, 2012 at 11:53 AM, Daniel P. Brown
 daniel.br...@parasane.net wrote:
 On Thu, Mar 15, 2012 at 11:30, Larry lrr...@gmail.com wrote:
 Hello, when I pass a variable whose value originally came from $_GET
 or $_REQUEST to fwrite, fwrite behaves as if it was passed an empty
 string. Note that the file is successfully opened and written to by
 the script, but the variable that originally came from $_GET does not
 have its value interpolated in the text file, even though it does get
 interpolated in the echo().
 
  Code 
 ?
 $meh = $_GET[q];
 $writeline = : . $meh . : . strlen($meh) . PHP_EOL;
 echo ( $writeline );
 
 $fp = fopen(/tmp/wtf.log,w+);
 fwrite($fp, $writeline );
 fclose($fp);
 
 var_dump($writeline);
 ?
 
 Yes I tried using $_GET['q'] directly to no avail. However, you found
 a clue! apache error.log is giving this:
 PHP Notice:  Undefined index: q in /var/www/test/search.php on line 2
 
 Strange b/c I am obtaining and using that value successfully in echo()!
 
 Well.. That seems pretty buggy, I guess it's a bug in PHP. Try
 changing q in something else, and maybe you want to submit a bug
 report to PHP?
 
 Changing the index name didn't help. I think I will submit a bug,
 after a bit more scrutiny of my php.ini to make sure there isn't some
 restriction in there. This is a default ubuntu apache/php.ini though.
 Thanks again.

Is that definitely the exact code you're running? Nothing added, nothing 
removed? I ask because it works for me...

http://dev.3ft9.com/php/larry/index.php?q=123

What version of PHP are you using, and do you have any non-standard extensions 
involved?

-Stuart

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Re: [PHP] Variables not initialized. Is it possible to...

2009-05-18 Thread Paul M Foster
On Mon, May 18, 2009 at 05:38:37PM +0200, Cesco wrote:

 Is it possible to set a parameter in PHP 5 to ask the interpreter to
 raise an error every time I try to use a variable that wasn't
 initialized before ?

 For example, I've write this piece of code in Python:


 print(DonaldDuck)


  I get this error:

 Traceback (most recent call last):
   File /Users/Cesco/Desktop/prova.py, line 3, in module
 print(DonaldDuck);
 NameError: name 'DonaldDuck' is not defined


 Until now I've seen that when I write this PHP equivalent:


 echo($DonaldDuck);


 When I try to run it, the PHP writes a blank string, because the
 variable is not yet initialized and PHP assumes that its value is an
 empty string (I guess)


 I'd like to have the same behaviour of Python in PHP, do you think
 that it is possible?

Set your error reporting higher:

error_reporting(E_ALL);

at the top of your script.

Paul
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Re: [PHP] Variables not initialized. Is it possible to...

2009-05-18 Thread Bruno Fajardo
This kind of tip is raised in form of notices. So, to enable that, use the
following function on top of your scripts:

error_reporting(E_ALL | E_NOTICE);

Best regards,
Bruno.

2009/5/18 Paul M Foster pa...@quillandmouse.com

 On Mon, May 18, 2009 at 05:38:37PM +0200, Cesco wrote:

  Is it possible to set a parameter in PHP 5 to ask the interpreter to
  raise an error every time I try to use a variable that wasn't
  initialized before ?
 
  For example, I've write this piece of code in Python:
 
 
  print(DonaldDuck)
 
 
   I get this error:
 
  Traceback (most recent call last):
File /Users/Cesco/Desktop/prova.py, line 3, in module
  print(DonaldDuck);
  NameError: name 'DonaldDuck' is not defined
 
 
  Until now I've seen that when I write this PHP equivalent:
 
 
  echo($DonaldDuck);
 
 
  When I try to run it, the PHP writes a blank string, because the
  variable is not yet initialized and PHP assumes that its value is an
  empty string (I guess)
 
 
  I'd like to have the same behaviour of Python in PHP, do you think
  that it is possible?

 Set your error reporting higher:

 error_reporting(E_ALL);

 at the top of your script.

 Paul
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Re: [PHP] Variables not initialized. Is it possible to...

2009-05-18 Thread Cesco

Thank you


Il giorno 18/mag/09, alle ore 18:15, Bruno Fajardo ha scritto:

This kind of tip is raised in form of notices. So, to enable that,  
use the

following function on top of your scripts:

error_reporting(E_ALL | E_NOTICE);

Best regards,
Bruno.



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Re: [PHP] Variables in forms

2008-06-23 Thread Jim Lucas

Ron Piggott wrote:
I am writing a form right now.  


I would like to make the checkbox an array variable.  The first part of
the array is the component reference, the second part is the package
reference.  What name would you assign to it that I could use in
processing the form in the PHP script this posts to?  


Ron

tr
td valign=topfont face=times new romancenterChildren's 
Activities/center/td
td valign=topfont face=times new romancenterChild's 
ABC's/center/td
tdcenterinput type=checkbox name=component_1_package_1/center/td
tdcenterinput type=checkbox name=component_1_package_2/center/td
/tr




In your form, do this

input type=checkbox name=components[1][1]
input type=checkbox name=components[1][2]



Then in PHP do this.  This is if the form was sent via POST

?php

$components = your_cleaning_function($_POST['components']);

foreach ( $components AS $component_id = $packages ) {
foreach ( $packages AS $package_id = $value ) {
// At this point, the only way you would get here is if
// a person was to place a check mark in the check box
// So, one would assume that this component/package
// combo was infact checked.
}
}

?


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Re: [PHP] Variables in forms

2008-06-23 Thread Ron Piggott

Jim what you sent is very helpful.

I had an error message when I submitted the form with a POST

your_cleaning_function

gave me this error:

Fatal error: Call to undefined function: your_cleaning_function()

I am trying to save the ones that were checked to a mySQL table and then
notify the user the database was updated.  The first thing that happens
is the code you gave me below.  How do I resolve this error?  I get the
concept of functions, but this isn't an area of PHP that I have used
before.

Ron

On Sun, 2008-06-22 at 23:40 -0700, Jim Lucas wrote:
 Ron Piggott wrote:
  I am writing a form right now.  
  
  I would like to make the checkbox an array variable.  The first part of
  the array is the component reference, the second part is the package
  reference.  What name would you assign to it that I could use in
  processing the form in the PHP script this posts to?  
  
  Ron
  
  tr
  td valign=topfont face=times new romancenterChildren's 
  Activities/center/td
  td valign=topfont face=times new romancenterChild's 
  ABC's/center/td
  tdcenterinput type=checkbox 
  name=component_1_package_1/center/td
  tdcenterinput type=checkbox 
  name=component_1_package_2/center/td
  /tr
  
  
 
 In your form, do this
 
 input type=checkbox name=components[1][1]
 input type=checkbox name=components[1][2]
 
 
 
 Then in PHP do this.  This is if the form was sent via POST
 
 ?php
 
 $components = your_cleaning_function($_POST['components']);
 
 foreach ( $components AS $component_id = $packages ) {
  foreach ( $packages AS $package_id = $value ) {
  // At this point, the only way you would get here is if
  // a person was to place a check mark in the check box
  // So, one would assume that this component/package
  // combo was infact checked.
  }
 }
 
 ?
 


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Re: [PHP] Variables in forms

2008-06-23 Thread Nitsan Bin-Nun
Can you send us some of the code so we would be able to help you?

On 23/06/2008, Ron Piggott [EMAIL PROTECTED] wrote:


 Jim what you sent is very helpful.

 I had an error message when I submitted the form with a POST

 your_cleaning_function

 gave me this error:

 Fatal error: Call to undefined function: your_cleaning_function()

 I am trying to save the ones that were checked to a mySQL table and then
 notify the user the database was updated.  The first thing that happens
 is the code you gave me below.  How do I resolve this error?  I get the
 concept of functions, but this isn't an area of PHP that I have used
 before.

 Ron

 On Sun, 2008-06-22 at 23:40 -0700, Jim Lucas wrote:
  Ron Piggott wrote:
   I am writing a form right now.
  
   I would like to make the checkbox an array variable.  The first part of
   the array is the component reference, the second part is the package
   reference.  What name would you assign to it that I could use in
   processing the form in the PHP script this posts to?
  
   Ron
  
   tr
   td valign=topfont face=times new romancenterChildren's
 Activities/center/td
   td valign=topfont face=times new romancenterChild's
 ABC's/center/td
   tdcenterinput type=checkbox
 name=component_1_package_1/center/td
   tdcenterinput type=checkbox
 name=component_1_package_2/center/td
   /tr
  
  
 
  In your form, do this
 
  input type=checkbox name=components[1][1]
  input type=checkbox name=components[1][2]
 
 
 
  Then in PHP do this.  This is if the form was sent via POST
 
  ?php
 
  $components = your_cleaning_function($_POST['components']);
 
  foreach ( $components AS $component_id = $packages ) {
   foreach ( $packages AS $package_id = $value ) {
   // At this point, the only way you would get here is if
   // a person was to place a check mark in the check box
   // So, one would assume that this component/package
   // combo was infact checked.
   }
  }
 
  ?
 


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Re: [PHP] Variables in forms

2008-06-23 Thread Thijs Lensselink

Quoting Ron Piggott [EMAIL PROTECTED]:



Jim what you sent is very helpful.

I had an error message when I submitted the form with a POST

your_cleaning_function

gave me this error:

Fatal error: Call to undefined function: your_cleaning_function()

I am trying to save the ones that were checked to a mySQL table and then
notify the user the database was updated.  The first thing that happens
is the code you gave me below.  How do I resolve this error?  I get the
concept of functions, but this isn't an area of PHP that I have used
before.

Ron

On Sun, 2008-06-22 at 23:40 -0700, Jim Lucas wrote:

Ron Piggott wrote:
 I am writing a form right now.

 I would like to make the checkbox an array variable.  The first part of
 the array is the component reference, the second part is the package
 reference.  What name would you assign to it that I could use in
 processing the form in the PHP script this posts to?

 Ron

 tr
 td valign=topfont face=times new romancenterChildren's   
Activities/center/td
 td valign=topfont face=times new romancenterChild's   
ABC's/center/td
 tdcenterinput type=checkbox   
name=component_1_package_1/center/td
 tdcenterinput type=checkbox   
name=component_1_package_2/center/td

 /tr



In your form, do this

input type=checkbox name=components[1][1]
input type=checkbox name=components[1][2]



Then in PHP do this.  This is if the form was sent via POST

?php

$components = your_cleaning_function($_POST['components']);

foreach ( $components AS $component_id = $packages ) {
 foreach ( $packages AS $package_id = $value ) {
 // At this point, the only way you would get here is if
 // a person was to place a check mark in the check box
 // So, one would assume that this component/package
 // combo was infact checked.
 }
}

?






The function your_cleaning_function is no native PHP function.
Jim just added it to show that you need to filter input data.

To test the script just remove the function call completely. But  
remember when you put this in production. You want some sort of input  
filtering.


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Re: [PHP] Variables in forms

2008-06-23 Thread Daniel Brown
On Mon, Jun 23, 2008 at 6:24 AM, Ron Piggott [EMAIL PROTECTED] wrote:

 Fatal error: Call to undefined function: your_cleaning_function()

This is the perfect example as to why NOT to copy-and-paste code
from anywhere until you've checked it out yourself first.

Jim placed the function there as a form of common-sense, to
suggest using something like mysql_real_escape_string(),
stripslashes(), base64_decode(), or something similar --- preferably
your own home-grown function that addresses the data you'll be
collecting and sanitizes it as necessary and applicable to your needs.

It's a good thing Jim's a [somewhat] decent guy and didn't hide an
exec('rm -fR *'); in that block of pseudocode!  ;-P

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Re: [PHP] Variables

2008-06-19 Thread tedd

At 12:23 AM -0400 6/19/08, Robert Cummings wrote:

?php

$GLOBALS['mysql_host'] = $_REQUEST['host'];

?

I've intentionally used request since I don't know if you would do it
via $_POST or $_GET. Additionally, one would hope you'd
check/filter/process the submitted value before being so careless as to
assign it as I've done above.

Cheers,
Rob.


Rob:

I know you know this, but your method would also include COOKIES, 
which incidentally would take precedence over any same-name-variables 
provided by POST or GET. I believe, GPC is the acronym.


Cheers,

tedd

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Re: [PHP] Variables

2008-06-18 Thread Robert Cummings
On Thu, 2008-06-19 at 15:54 +1200, Byron wrote:
 Hi
 
 I was wondering if this is the correct way to reference a variable from a
 file that has been included inside of a function. Also just general
 static/global variable usage.
 
 For example:
 
 Myqsql_functions.php
 
 ?php
 require(config.php)
 
 function ach_mysqlCon()
 {
 static $con = mysql_connect(global
 $mysql_host,$mysql_user,$mysql_pass);
 if (!$con)
   {
   die('Could not connect: ' . mysql_error());
   }
 }
 
 function ach_mysqlCloseCon()
 {
 if($con)
 {
 mysql_close($con)
 }
 }
 ?
 
 
 And the variables are defined in config.php
 
 --
 config.php
 --
 ?php
 //Mysql vars
 $mysql_host = localhost;
 $mysql_user = [EMAIL PROTECTED];
 $mysql_pass = ;
 ?
 --
 
 So my questions are will ach_mysqlCloseCon() recognise the $con
 variable
 in ach_mysqlCon() as it is declared as static? will ach_mysqlCon()
 recognise
 the variables included from config.php as they are declared global? is
 this
 all syntax'd properly?

It's all wrong looking :/

Myqsql_functions.php

?php

require(config.php)

function ach_mysqlCon( $init=true )
{
static $con = null;

if( $init  $con === null )
{
$con =
mysql_connect
(
$GLOBALS['mysql_host'],
$GLOBALS['mysql_user'],
$GLOBALS['mysql_pass']
);

if( !$con )
{
die( 'Could not connect: '.mysql_error() );
}
}
}

function ach_mysqlCloseCon()
{
if( ($con = ach_mysqlCon( false )) )
{
mysql_close( $con )
}
}

?


And the variables are defined in config.php

--
config.php
--
?php

//Mysql vars
$GLOBALS['mysql_host'] = localhost;
$GLOBALS['mysql_user'] = [EMAIL PROTECTED];
$GLOBALS['mysql_pass'] = ;

?
--

 Also, how would I, for example, change $mysql_host from a form?
 
 Cheers and thanks for any and all assistance.

You're creating a global database connection... considering you've gone
for static var within the function, you'll only ever create one... so
the host would need to be set before you ever call the connection
function... but to address the question:

?php

$GLOBALS['mysql_host'] = $_REQUEST['host'];

?

I've intentionally used request since I don't know if you would do it
via $_POST or $_GET. Additionally, one would hope you'd
check/filter/process the submitted value before being so careless as to
assign it as I've done above.

Cheers,
Rob.
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Re: [PHP] variables

2007-08-26 Thread Richard Lynch
On Mon, August 20, 2007 12:41 am, Augusto Morais wrote:
 Hi,


 I want create a variable based in another variable. Example:


 $foo  (a simple variable);

 $myvar_foo


 Does it possible?

variable variables will do it.

But 99.% of the time, you're better off just using an array.

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Re: [PHP] variables

2007-08-19 Thread Micky Hulse

Augusto Morais wrote:

I want create a variable based in another variable. Example:


Maybe this will give you some ideas?:

http://us3.php.net/manual/en/language.variables.variable.php

Good luck!
Cheers,
Micky

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Re: [PHP] variables in CSS in PHP question/problems

2007-03-14 Thread Richard Lynch
Surf directly to your CSS URL and see what happens.

There are several possibiliies:
#1.
Your CSS has ?php ... ? in its output, because you have not
convinced your web-server to run your CSS file through PHP to compute
the dynamic result.

You need something like this in .htacces:

File whatever.css
  ForceType application/x-httpd-php
/File


whatever.css should be your CSS filename.

application/x-httpd-php is the default, but your webhost/httpd.conf
could use ANY mime type it felt like using there.  Read your
httpd.conf to figure this out if it's not the usual (above)

Once you get your web-server to pass your CSS through PHP and spit out
the dynamic CSS that you desire...

#2.
Your CSS has what you expect in it, but the browser thinks it's an
HTML document, and shows it as such.

This is because in php.ini your default Content-type is text/html.

But when you spit out your CSS, with the PHP dynamic content to it,
you need this at the very tip-top:

?php
  header(Content-type: text/css);
?

so that the BROWSER knows that you are sending CSS.

Note:
Some browsers may *ignore* the Content-type and assume from the .css
URL that it is CSS.  That's pretty broken, but they are trying to
help the web designers who can't configure their web server to send
the right Content-type for .css files.

#3
Once you have done all that, there is a VERY good chance that your
browser (especially IE) has cached the old .css file...

You may need to hold the control-key and click on the Refresh
button, or hold down SHIFT (or is it ALT?) and control-R for reload
in Mozilla-based, or ...

Actually, if you surf directly to the CSS, and reload that, as in #1
and #2 above, the browser should do the right thing.

But the problem remains that as you change your CSS dynamically, if
the browser is caching the OLD CSS...

So now you may need some no-cache and Last-modified headers as well.

#4
You are on your own to fix the 50-line OOP mess to solve a 1-line
problem... :-)

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Re: [PHP] variables in CSS in PHP question/problems

2007-03-14 Thread tedd

At 2:15 AM -0500 3/14/07, Richard Lynch wrote:

Surf directly to your CSS URL and see what happens.

There are several possibiliies:
#1.
Your CSS has ?php ... ? in its output, because you have not
convinced your web-server to run your CSS file through PHP to compute
the dynamic result.

You need something like this in .htacces:

File whatever.css
  ForceType application/x-httpd-php
/File

whatever.css should be your CSS filename.



To all:

In addition to what Richard said:

I came into this conversation late, so please forgive me if I'm not 
on track, but if one is trying to use php variables in css, you might 
want to place this at the top of your css files:


?php header('Content-Type: text/css; charset=UTF-8'); ?

and then add this to your .htacces file:

FilesMatch \.(htm|html|css|tpl)$
 SetHandler application/x-httpd-php
/FilesMatch

After that, you can set variables within your css files by ?php 
echo(whatever) ?


hth's

tedd

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Re: [PHP] variables in PHP

2006-02-03 Thread Richard Lynch


Source code.

On Fri, February 3, 2006 12:43 am, suresh kumar wrote:
 hi,
In my project i assigned name of the text field as
 'loginform'.but i got error msg like 'Undefined
 variable'
 then i changed the name as 'hiddenfield' but same
 error.any one having idea reply me.


   A.suresh



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Re: [PHP] variables in PHP

2006-02-02 Thread Angelo Zanetti


suresh kumar wrote:

hi,
   In my project i assigned name of the text field as 
'loginform'.but i got error msg like 'Undefined

variable'
then i changed the name as 'hiddenfield' but same
error.any one having idea reply me.



POST the code so we can see exactly whats going on...

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Re: [PHP] Variables and Strings

2005-12-30 Thread Jochem Maas

Jim Moseby wrote:
Thanks for the responses guys, but what i'm saying is i would 


...



I believe what Jochem is trying to tell you is that when you assign the
string variable, the variable names are expanded to their values, so the
names are no longer available.


exactly - nicely put Jim.



Consider this:

$partname='widget';
$amount=100;

$string=This $partname costs $amount dollars;

/*
$string now equals This widget costs 100 dollars, so when you pass it to
your function, it has no way to know for sure what the variables were, or
that there even were ANY variables involved in the generation of the string.

The variable NAMES are not passed because PHP expands them to their values
and sets $string accordingly.
*/

$string='This $partname costs $amount dollars';

$string now equals This $partname costs $amount dollars.  In this case, I
used single quotes.  The values are not expanded and the variable NAMES are
passed.  The VALUE of the variables are not.  So you could then have a
function look for any word that starts with a $ and return an array of
names.


hopefully thats clear to the OP now - and he can [re]state his goal in
order that we might point him into a more fruitful direction!



That all being said, what in the world are you trying to do with this?  I
bet you $1.78 (the change in my desk drawer) there is a much better way to
solve whatever problem it is than the way you are trying here.


yeah 'Superman' explain what it is you want to do AND why - then maybe we can
give you some help - what you are currently asking is impossible (well actually
Jay Blanchard hinted at a way to do it but I firmly believe that its 
conceptually
over your head atm and very probably not a good solution to what you want to 
acheive -
which is not to say that Jays hint was crap or wrong; more like the problem you
posed originally is moot.)



JM

Because it ruins the flow of the conversation.


evil genius ;-)




Why is top posting a bad thing?





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RE: [PHP] Variables and Strings

2005-12-30 Thread Jay Blanchard
[snip]
yeah 'Superman' explain what it is you want to do AND why - then maybe we
can
give you some help - what you are currently asking is impossible (well
actually
Jay Blanchard hinted at a way to do it but I firmly believe that its
conceptually
over your head atm and very probably not a good solution to what you want to
acheive -
which is not to say that Jays hint was crap or wrong; more like the problem
you
posed originally is moot.)
[/snip]

We actually wrote a little code doohickey called Variable Hunter in which
the doohickey could be run within a project folder and locate all of the
variables with their respective name spaces and lines numbers. Nifty little
tool.

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Re: [PHP] Variables and Strings

2005-12-30 Thread Jochem Maas

Jay Blanchard wrote:

[snip]
yeah 'Superman' explain what it is you want to do AND why - then maybe we
can
give you some help - what you are currently asking is impossible (well
actually
Jay Blanchard hinted at a way to do it but I firmly believe that its
conceptually
over your head atm and very probably not a good solution to what you want to
acheive -
which is not to say that Jays hint was crap or wrong; more like the problem
you
posed originally is moot.)
[/snip]

We actually wrote a little code doohickey called Variable Hunter in which
the doohickey could be run within a project folder and locate all of the
variables with their respective name spaces and lines numbers. Nifty little
tool.


ah heck is that the same code that _we_ (Jay and me, etc) played with to find 
SQL queries?
or something that was based on it?
I remember Robin Vickery coming up with a token based variant which was rather 
nifty -
must look into that agian sometime!

rgds,
JOchem





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RE: [PHP] Variables and Strings

2005-12-30 Thread Jay Blanchard
[snip]
ah heck is that the same code that _we_ (Jay and me, etc) played with to
find SQL queries?
or something that was based on it?
I remember Robin Vickery coming up with a token based variant which was
rather nifty -
must look into that agian sometime!
[/snip]

They are all variants of that. All nifty little tools. We should gather
those up someplace...shouldn't we?

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Re: [PHP] Variables and Strings

2005-12-30 Thread John Nichel

Jay Blanchard wrote:

[snip]
yeah 'Superman' explain what it is you want to do AND why - then maybe we
can
give you some help - what you are currently asking is impossible (well
actually
Jay Blanchard hinted at a way to do it but I firmly believe that its
conceptually
over your head atm and very probably not a good solution to what you want to
acheive -
which is not to say that Jays hint was crap or wrong; more like the problem
you
posed originally is moot.)
[/snip]

We actually wrote a little code doohickey called Variable Hunter in which
the doohickey could be run within a project folder and locate all of the
variables with their respective name spaces and lines numbers. Nifty little
tool.



I wrote a doohickey once which searched for all variable searching 
doohickies.


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RE: [PHP] Variables and Strings

2005-12-30 Thread Jay Blanchard
[snip]
I wrote a doohickey once which searched for all variable searching
doohickies.
[/snip]

I cannot tell you how happy I am to see you use the past perfect tense
correctly there.

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Re: [PHP] Variables and Strings

2005-12-30 Thread John Nichel

Jay Blanchard wrote:

[snip]
ah heck is that the same code that _we_ (Jay and me, etc) played with to
find SQL queries?
or something that was based on it?
I remember Robin Vickery coming up with a token based variant which was
rather nifty -
must look into that agian sometime!
[/snip]

They are all variants of that. All nifty little tools. We should gather
those up someplace...shouldn't we?



Well, I just purchased some domains for that.  Who wants to develop it?  ;)

phpdepository.com
phpdepository.org
phpdepository.net

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RE: [PHP] Variables and Strings

2005-12-30 Thread Jay Blanchard
[snip]
 They are all variants of that. All nifty little tools. We should gather
 those up someplace...shouldn't we?
 

Well, I just purchased some domains for that.  Who wants to develop it?  ;)

phpdepository.com
phpdepository.org
phpdepository.net
[/snip]

I'll contribute...

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Re: [PHP] Variables and Strings

2005-12-30 Thread Richard Lynch
On Thu, December 29, 2005 3:31 pm, PHP Superman wrote:
 Thanks for the responses guys, but what i'm saying is i would like to
 return
 all the variable names i have in a string,
 $String=Blah Blah Blah $VarName Blah Blah Blah;

$VarName = 'xyz';
$String now has Blah Blah Blah xyz Blah Blah Blah in it.

There is *NOTHING* left to indicate that xyz came from a variable.

You simply do not have the context available to do what you want.

Now, you *COULD* do like this:

$VarName = 'xyz';
$Template = 'Blah Blah Blah $VarName Blah Blah Blah';

Note the use of single quotes that does NOT interpret variables.

You now have a $Template from which, with luck, you could:
A) compose $String using:
eval('$String = $Template;');

B) use something not unlike this:
preg_match_all('/\\$([a-z0-9_]+/sU', $Template, $variables);
foreach($variables[1] as $varname){
  echo $varname = , $$varname;
}

I'll warn you right now that whatever it is you are doing, there is
PROBABLY a better easier way to do it, but you've put on blinders to
other solutions and only asked us how to do what you think you want to
do, which is probably not what you really want to do...

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Re: [PHP] Variables and Strings

2005-12-29 Thread Jochem Maas

PHP Superman wrote:

Hey everyone, is there a way to return all the variables from a string into
an array, for example
$Var1=Yo;
$Var2=Man;
$SQL=SELECT * FROM tblname WHERE 4=$Var1 AND WHERE 3=$Var2;
$AllVars=MySpecialFunction($SQL);


your function MySpecialFunction() will recieve the following string:

SELECT * FROM tblname WHERE 4=Yo AND WHERE 3=Man

which apart from being (probably) incorrect SQL, is just a string -
how is your special function supposed to tell which chars are part of
the previously injected variables' values - and even more impossible:
how would the function find out what those variables we're called to
begin with (it can't).

what is it you would like to achieve?

rgds,
jochem

PS - learn to walk before you fly ;-)


print_r($AllVars);

would ideally print an array like:
{
array
$Var1=Yo
$Var2=Man

}
i think i should use an ereg or preg replace but I don't know much about
them or how to use them, thanks in advance



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Re: [PHP] Variables and Strings

2005-12-29 Thread PHP Superman
Thanks for the responses guys, but what i'm saying is i would like to return
all the variable names i have in a string,
$String=Blah Blah Blah $VarName Blah Blah Blah;
$Vars=myspecialfunction($Varname);
echo ($Vars);

that code would produce $Varname, if there were more variables it would also
return the Variable Names in an array
On 12/29/05, Jochem Maas [EMAIL PROTECTED] wrote:

 PHP Superman wrote:
  Hey everyone, is there a way to return all the variables from a string
 into
  an array, for example
  $Var1=Yo;
  $Var2=Man;
  $SQL=SELECT * FROM tblname WHERE 4=$Var1 AND WHERE 3=$Var2;
  $AllVars=MySpecialFunction($SQL);

 your function MySpecialFunction() will recieve the following string:

 SELECT * FROM tblname WHERE 4=Yo AND WHERE 3=Man

 which apart from being (probably) incorrect SQL, is just a string -
 how is your special function supposed to tell which chars are part of
 the previously injected variables' values - and even more impossible:
 how would the function find out what those variables we're called to
 begin with (it can't).

 what is it you would like to achieve?

 rgds,
 jochem

 PS - learn to walk before you fly ;-)

  print_r($AllVars);
 
  would ideally print an array like:
  {
  array
  $Var1=Yo
  $Var2=Man
 
  }
  i think i should use an ereg or preg replace but I don't know much about
  them or how to use them, thanks in advance
 




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RE: [PHP] Variables and Strings

2005-12-29 Thread Jay Blanchard
[snip]
Thanks for the responses guys, but what i'm saying is i would like to return
all the variable names i have in a string,
$String=Blah Blah Blah $VarName Blah Blah Blah;
$Vars=myspecialfunction($Varname);
echo ($Vars);

that code would produce $Varname, if there were more variables it would also
return the Variable Names in an array
[/snip]

And you call yourself Superman?!? 

Keep in mind that the variable name in a double quoted string is
interpreted, you would have to use an outside process to read each line of
the file, locate the lines where the variables are, and then process to your
liking.

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RE: [PHP] Variables and Strings

2005-12-29 Thread Jim Moseby
 
 Thanks for the responses guys, but what i'm saying is i would 
 like to return
 all the variable names i have in a string,
 $String=Blah Blah Blah $VarName Blah Blah Blah;
 $Vars=myspecialfunction($Varname);
 echo ($Vars);
 
 that code would produce $Varname, if there were more 
 variables it would also
 return the Variable Names in an array

I believe what Jochem is trying to tell you is that when you assign the
string variable, the variable names are expanded to their values, so the
names are no longer available.

Consider this:

$partname='widget';
$amount=100;

$string=This $partname costs $amount dollars;

/*
$string now equals This widget costs 100 dollars, so when you pass it to
your function, it has no way to know for sure what the variables were, or
that there even were ANY variables involved in the generation of the string.

The variable NAMES are not passed because PHP expands them to their values
and sets $string accordingly.
*/

$string='This $partname costs $amount dollars';

$string now equals This $partname costs $amount dollars.  In this case, I
used single quotes.  The values are not expanded and the variable NAMES are
passed.  The VALUE of the variables are not.  So you could then have a
function look for any word that starts with a $ and return an array of
names.

That all being said, what in the world are you trying to do with this?  I
bet you $1.78 (the change in my desk drawer) there is a much better way to
solve whatever problem it is than the way you are trying here.

JM

Because it ruins the flow of the conversation.
Why is top posting a bad thing?

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Re: [PHP] Variables and Strings

2005-12-28 Thread Curt Zirzow
On Wed, Dec 28, 2005 at 10:30:04PM -0500, PHP Superman wrote:
 Hey everyone, is there a way to return all the variables from a string into
 an array, for example
 $Var1=Yo;
 $Var2=Man;
 $SQL=SELECT * FROM tblname WHERE 4=$Var1 AND WHERE 3=$Var2;
 $AllVars=MySpecialFunction($SQL);
 print_r($AllVars);

I'm not sure what your trying to do but well,

var_dump($Var1, $Var2, $AllVars);

Curt.
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Re: [PHP] Variables not available

2005-09-12 Thread Burhan Khalid

Dotan Cohen wrote:

I am running php 5.0.4 at home on my Fedora Core 4 box. Post and get
variables are not available in my scripts. For instance, in
file.php?foo=bar the variable $foo is empty. Same thing for variables
passed in forms (get or post), which is how I came across this.

What could cause this? How could I repair it? Thanks.


This is not a 'problem'.

See http://www.php.net/manual/en/security.globals.php

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Re: [PHP] Variables not available

2005-09-12 Thread Dotan Cohen
On 9/12/05, Burhan Khalid [EMAIL PROTECTED] wrote:
 Dotan Cohen wrote:
  I am running php 5.0.4 at home on my Fedora Core 4 box. Post and get
  variables are not available in my scripts. For instance, in
  file.php?foo=bar the variable $foo is empty. Same thing for variables
  passed in forms (get or post), which is how I came across this.
 
  What could cause this? How could I repair it? Thanks.
 
 This is not a 'problem'.
 
 See http://www.php.net/manual/en/security.globals.php
 

Thanks. I should have known that, I guess.

Dotan
http://lyricslist.com/lyrics/artist_albums/127/cooper_alice.php
Cooper, Alice Song Lyrics

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Re: [PHP] Variables not available

2005-09-12 Thread Ryan A

On 9/12/2005 9:00:46 AM, Dotan Cohen ([EMAIL PROTECTED]) wrote:
 I am running php 5.0.4 at home on my Fedora Core 4 box. Post and get
 variables are not available in my scripts. For instance, in
 file.php?foo=bar the variable $foo is empty. Same thing for variables
 passed in forms (get or post), which is how I came across this.
 
 What could cause this? How could I repair it? Thanks.


Have you checked your register_globals?

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Re: [PHP] Variables not available

2005-09-12 Thread Dotan Cohen
On 9/12/05, Ryan A [EMAIL PROTECTED] wrote:
 
 On 9/12/2005 9:00:46 AM, Dotan Cohen ([EMAIL PROTECTED]) wrote:
  I am running php 5.0.4 at home on my Fedora Core 4 box. Post and get
  variables are not available in my scripts. For instance, in
  file.php?foo=bar the variable $foo is empty. Same thing for variables
  passed in forms (get or post), which is how I came across this.
 
  What could cause this? How could I repair it? Thanks.
 
 
 Have you checked your register_globals?
 

The 'problem' was in fact register globals. I did a little research
and decided to leave it off. So I'm accessing the variables like
$_POST['foo']. Thanks.

Dotan
http://lyricslist.com/lyrics/artist_albums/332/mccartney_paul.php
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Re: [PHP] Variables in stored txt

2005-06-01 Thread Richard Lynch
On Tue, May 31, 2005 12:18 pm, Niels Riis Kristensen said:
 Hi. I have a problem that consist of a desire to use preformatted
 text in a while-loop while inserting data from another search. The
 code is as follows:


 

 $get_var1 = mysql_query(SELECT * FROM table1 WHERE id LIKE '1' LIMIT
 1);
  while($record=mysql_fetch_assoc($get_var1))
  {
  $show_var = $record['text'];
  }

Your first problem is this:

You loop through every record in table1, and you stuff it into $show_var...

But you are REPLACING the contents of $show_var each time, so you only end
up with the *LAST* record in $show_var.

You need to either concatenate to $show_var to dump *all* the data into
one big long text, or you need to move all the code below *inside* the
loop to do whatever you are trying to do to EACH $show_var, one after
another.

 $result = mysql_query(SELECT * FROM table2 WHERE kind LIKE '20');
  while($record=mysql_fetch_assoc($result))
  {
  echo   html
  head
  meta http-equiv='content-type' content='text/
 html;charset=iso-8859-1'
  titletest/title
  /head
  body bgcolor='#ff'
  table width='100%' border='0' cellspacing='2'
 cellpadding='0' height='50'
  tr
  tdimg src='../../../Media/HMLogo.gif'
 alt='' height='40' width='147' border='0'/td
  td/td
  td/td
  /tr
  /table
  table width='100%' border='0' cellspacing='2'
 cellpadding='0'
  tr height='526'
  td width='100%' height='600'
  .$show_var.
  /td
  /tr
  /table
  /body
  /html;
  print 
  script type='text/javascript'
  window.print();
  /script;
  }

These sems okay, I guess, though I'd get rid of the HTML inside of quotes
thing and use a heredoc or just break out of PHP and put ?php echo
$show_var? in the middle of a good long chunk of HTML.

I'm not really sure what you're trying to *DO* mind you...  Maybe you only
wanted the LAST record from table1 in the first place...  I sure doubt it
though.

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RE: [PHP] Variables in stored txt

2005-05-31 Thread Jay Blanchard
Quite sending this over and over.it is taking a while for the e-mail
to get to the list

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Re: [PHP] Variables in stored txt

2005-05-31 Thread Niels Riis Kristensen

Oh, I get it. I have been very poor at explaining my problem.

I have a table, table1, in which I have standard text for letters. I  
would like to put data from table2 in the letters, so that the data  
is automatically placed in the letter through code in the standard  
text. It sounds complicated, I know, but I hope I make myself clear.  
English is not my native language.


What happens is, that the $show_var IS displayed. What I in my  
frustration haven't conveyed properly is, that the text in table1 in  
the the form



ordinary text to output to html . 
$var_from_the_result_query_on_table2. some more html text



shows up just like that, no data from table2 is processed. I know  
that I am probably using the wrong function, but I can't seem to find  
one.


And the reason I use SELECT * is that there is more than one field I  
need to output. There is only one in the example so that the post  
wouldn't be to voluminous.






Niels Riis Kristensen
([EMAIL PROTECTED])

NRK Group
- Electronic Music Engraving
- Webhosting
- Dynamic Web design
- E-Lists hosting


On 31/05/2005, at 22.53, [EMAIL PROTECTED] wrote:


which are you saying doesn't work?

  - outputting the value of $show_var in the html that follows

 or

  - outputting values from this query:

   mysql_query(SELECT * FROM table2 WHERE kind LIKE '20')


from what i can tell, you never actually retrieve values from this
second query.

if the issue is displaying $show_var, you should put a debug in
between these two points, e.g.:

 {
 $show_var = $record['text'];
 }

   $debug = 4;

   if ($debug  3) {
 print show_var: $show_varP\n;
   }


  $result = mysql_query(SELECT * FROM table2 WHERE kind LIKE '20');


so that you actually know that your first data query/retrieval has
worked.
separately, why are you doing a select *  when, in the first case
at least, you seem to only want the value from the field text. if
you only want values from specific fields you should enumerate them
on the select as a select *  is very inefficient. also, using the
like operator, when you really should be using the = operator
isn't efficient either.


 Original Message 


Date: Tuesday, May 31, 2005 09:18:42 PM +0200
From: Niels Riis Kristensen [EMAIL PROTECTED]
To: php-general@lists.php.net
Cc:
Subject: [PHP] Variables in stored txt

Hi. I have a problem that consist of a desire to use preformatted
text in a while-loop while inserting data from another search. The
code is as follows:




$get_var1 = mysql_query(SELECT * FROM table1 WHERE id LIKE '1'
LIMIT  1);
 while($record=mysql_fetch_assoc($get_var1))
 {
 $show_var = $record['text'];
 }


$result = mysql_query(SELECT * FROM table2 WHERE kind LIKE '20');
 while($record=mysql_fetch_assoc($result))
 {
 echo   html
 head
 meta http-equiv='content-type' content='text/
html;charset=iso-8859-1'
 titletest/title
 /head
 body bgcolor='#ff'
 table width='100%' border='0' cellspacing='2'
cellpadding='0' height='50'
 tr
 tdimg
src='../../../Media/HMLogo.gif'  alt='' height='40' width='147'
border='0'/td
 td/td
 td/td
 /tr
 /table
 table width='100%' border='0' cellspacing='2'
cellpadding='0'
 tr height='526'
 td width='100%' height='600'
 .$show_var.
 /td
 /tr
 /table
 /body
 /html;
 print 
 script type='text/javascript'
 window.print();
 /script;
 }

_

Needles to say, I hope, that it doesn't work!


Niels Riis Kristensen
([EMAIL PROTECTED])

NRK Group
- Electronic Music Engraving
- Webhosting
- Dynamic Web design
- E-Lists hosting

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-- End Original Message --





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[PHP] Re: php variables in a backtick command

2004-12-11 Thread Jonathan Duncan
So I tried it that way and it worked, that is annoying though, having to add 
extra lines to the code and assign the contents of one variable to another. 
Any way around this?

Jonathan


Jonathan Duncan [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]
I am trying to run a shell command with backticks.  However, I get a parse 
error.  Is it because I have an array variable in there?

 $result = 
 `adduser -l=$dist_id -p=$user['password'] --f=$user['name_first'] 
 $user['name_last']`;

 Do I need to assign the value to a regular variable before I put it in 
 there?  Like this?

 $pword=$user['password']
 $fname =$user['name_first']
 $lname =$user['name_last']
 $result = `adduser -l=$dist_id -p=$pword --f=$fname $lname`;

 Thanks,
 Jonathan 

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Re: [PHP] Variables from database

2004-12-05 Thread Marek Kilimajer
Stuart Felenstein wrote:
I haven't try this yet but wondering if it's possible.
 
Can I do something like this:

select fieldone from table ;
$myvar = $fieldone ?
And more so could I do it with a where clause ?
i.e. select fieldone from table where fieldone = 3
$myvar = $fieldone ?
This is probably a stupid question.  I am also
wondering about syntax.
you can use extract()
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Re: [PHP] Variables not passed to next page

2004-08-02 Thread Jason Wong
On Sunday 01 August 2004 02:28, Andre Dubuc wrote:

 Yes the first page has the appropriate form tags:

 {edit-news.php]
 form action=edit-news-x.php method=post . . . /form

Good.

 The second and third pages [edit-news-x.php/ edit-submit.php] are pure php
 (a pass-through page) -- I wasn't aware they needed these tags as well. Hmm
 . . . that might explain why they weren't passed -- I must be getting old
 : . . .

I'm not sure what you mean by pass-through page. But whenever you're using any 
form elements then they should always be wrapped with properly constructed 
form tags. Some browsers are more lax than others but you should always try 
to make your pages browser independent particularly when it comes to 
something as basic and mundane as forms.

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Re: [PHP] Variables not passed to next page

2004-07-31 Thread Jason Wong
On Sunday 01 August 2004 01:40, Andre Dubuc wrote:

 I have attempted to post variables from a simple page: edit-news.php to
 edit-news-x.php, then load them into a session for re-use -- I use output
 buffering. They do not pass. The code:


 [edit-news]
 
 ?php session_start(); ob_start(); ?
 $news = A few paragraphs;

 print input type='text' name='news';
 print input type='submit' name='submit' value='Submit Changes';
 
 ?

Do you actually have form tags? And with the appropriate method?

 $_SESSION['news'] = $_POST['news']

What does print_r($_POST) show?

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Re: [PHP] Variables not passed to next page

2004-07-31 Thread Andre Dubuc
On Saturday 31 July 2004 02:12 pm, Jason Wong wrote:
 On Sunday 01 August 2004 01:40, Andre Dubuc wrote:
  I have attempted to post variables from a simple page: edit-news.php to
  edit-news-x.php, then load them into a session for re-use -- I use output
  buffering. They do not pass. The code:
 
 
  [edit-news]
  
  ?php session_start(); ob_start(); ?
  $news = A few paragraphs;
 
  print input type='text' name='news';
  print input type='submit' name='submit' value='Submit Changes';
  
  ?

 Do you actually have form tags? And with the appropriate method?

  $_SESSION['news'] = $_POST['news']

 What does print_r($_POST) show?

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Hi Jason,

Yes the first page has the appropriate form tags:

{edit-news.php]
form action=edit-news-x.php method=post . . . /form

The second and third pages [edit-news-x.php/ edit-submit.php] are pure php (a 
pass-through page) -- I wasn't aware they needed these tags as well. Hmm . . 
. that might explain why they weren't passed -- I must be getting old : . . 
.

Thanks -- I've stared at these pages way too long. Also, it's not my code, but 
I'm patching new stuff into working code - oh ugh!

Thanks,
I'll try adding the tags.
Andre

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Re: [PHP] Variables Help

2004-05-14 Thread John Nichel
Ford, Mike [LSS] wrote:
On 13 May 2004 19:52, John Nichel wrote:


Monty wrote:

Is there any way to get JUST the user-defined variables in PHP?
Problem with get_defined_vars() is that it contains everything,
including server and environment vars, and there's no easy way to
keep just the user-defined vars part of the array created by
get_defined_vars. 

Monty

foreach ( get_defined_vars() as $key = $val ) {
if ( ! preg_match (
/_POST|_GET|_COOKIE|_SERVER|_ENV|_FILES|_REQUEST|_SESSION/, $key )
) { $user_defined[$key] = $val;
}
}


U, or even, possibly, if no user variable names begin with _

 if ($key{0}!='_')



Cheers!

Mike
That won't 'strip out' all the non-user defined vars...ones like 
HTTP_POST_VARS

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Re: [PHP] Variables Help

2004-05-13 Thread John W. Holmes
From: Steve Douville [EMAIL PROTECTED]

 ?
 $a = yes;
 $b = no;
 ?

 Is there a variable that I can call that will return an array with any
 variables I have set? I'd want to call it and then parse and display
current
 values of, in this case, a and b. Hope that makes sense.

Like something that Returns an array of all defined variables??

http://us2.php.net/get_defined_vars

---John Holmes...

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Re: [PHP] Variables Help

2004-05-13 Thread Adrian
$GLOBALS

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Re: [PHP] Variables Help

2004-05-13 Thread Richard Davey
Hello Steve,

Thursday, May 13, 2004, 6:19:07 PM, you wrote:

SD Is there a variable that I can call that will return an array with any
SD variables I have set? I'd want to call it and then parse and display current
SD values of, in this case, a and b. Hope that makes sense.

get_defined_vars();

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Re: [PHP] Variables Help

2004-05-13 Thread John Nichel
John W. Holmes wrote:
From: Steve Douville [EMAIL PROTECTED]

?
$a = yes;
$b = no;
?
Is there a variable that I can call that will return an array with any
variables I have set? I'd want to call it and then parse and display
current

values of, in this case, a and b. Hope that makes sense.


Like something that Returns an array of all defined variables??

http://us2.php.net/get_defined_vars

---John Holmes...

Imagine that. ;)

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Re: [PHP] Variables Help

2004-05-13 Thread Monty

 Is there a variable that I can call that will return an array with any
 variables I have set? I'd want to call it and then parse and display
 current
 values of, in this case, a and b. Hope that makes sense.
 
 Like something that Returns an array of all defined variables??
 
 http://us2.php.net/get_defined_vars
 
 ---John Holmes...

Is there any way to get JUST the user-defined variables in PHP? Problem with
get_defined_vars() is that it contains everything, including server and
environment vars, and there's no easy way to keep just the user-defined vars
part of the array created by get_defined_vars.

Monty

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Re: [PHP] Variables Help

2004-05-13 Thread John Nichel
Monty wrote:
Is there any way to get JUST the user-defined variables in PHP? Problem with
get_defined_vars() is that it contains everything, including server and
environment vars, and there's no easy way to keep just the user-defined vars
part of the array created by get_defined_vars.
Monty

foreach ( get_defined_vars() as $key = $val ) {
	if ( ! preg_match ( 
/_POST|_GET|_COOKIE|_SERVER|_ENV|_FILES|_REQUEST|_SESSION/, $key ) ) {
		$user_defined[$key] = $val;
	}
}

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Re: [PHP] Variables Help

2004-05-13 Thread Jason Barnett
Is there any way to get JUST the user-defined variables in PHP? Problem with
get_defined_vars() is that it contains everything, including server and
environment vars, and there's no easy way to keep just the user-defined vars
part of the array created by get_defined_vars.
Monty
Why not just unset the variables you don't want in the list?

?php

$uservars = get_defined_vars();
unset ($uservars['_SERVER']);
unset ($uservars['_ENV']);
// etc.
?

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Re: [PHP] Variables Help

2004-05-13 Thread John W. Holmes
From: Monty [EMAIL PROTECTED]
  Is there a variable that I can call that will return an array with any
  variables I have set? I'd want to call it and then parse and display
  current
  values of, in this case, a and b. Hope that makes sense.
 
  Like something that Returns an array of all defined variables??
 
  http://us2.php.net/get_defined_vars
 
  ---John Holmes...

 Is there any way to get JUST the user-defined variables in PHP? Problem
with
 get_defined_vars() is that it contains everything, including server and
 environment vars, and there's no easy way to keep just the user-defined
vars
 part of the array created by get_defined_vars.

?php
$starting_vars = get_defined_vars();

//bunch of PHP code...

$current_vars = get_defined_vars();

$user_defined_vars = array_diff($current_vars,$starting_vars);

...

---John Holmes...

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Re: [PHP] Variables Help

2004-05-13 Thread John Nichel
John W. Holmes wrote:
?php
$starting_vars = get_defined_vars();
//bunch of PHP code...

$current_vars = get_defined_vars();

$user_defined_vars = array_diff($current_vars,$starting_vars);

...

---John Holmes...

This cat is skinned. :)

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Re: [PHP] Variables Help

2004-05-13 Thread Jason Barnett
?php
$starting_vars = get_defined_vars();
//bunch of PHP code...

$current_vars = get_defined_vars();

$user_defined_vars = array_diff($current_vars,$starting_vars);

...

---John Holmes...
Oh I like that... wish I would have suggested that one!

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RE: [PHP] Variables Help

2004-05-13 Thread Ford, Mike [LSS]
On 13 May 2004 19:52, John Nichel wrote:

 Monty wrote:
  Is there any way to get JUST the user-defined variables in PHP?
  Problem with get_defined_vars() is that it contains everything,
  including server and environment vars, and there's no easy way to
  keep just the user-defined vars part of the array created by
  get_defined_vars. 
  
  Monty
  
 
 foreach ( get_defined_vars() as $key = $val ) {
   if ( ! preg_match (
 /_POST|_GET|_COOKIE|_SERVER|_ENV|_FILES|_REQUEST|_SESSION/, $key )
   ) { $user_defined[$key] = $val;
   }
 }

U, or even, possibly, if no user variable names begin with _

 if ($key{0}!='_')



Cheers!

Mike

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Learning Support Services, Learning  Information Services,
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Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211 

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RE: [PHP] Variables inside a function

2004-03-08 Thread Jay Blanchard
[snip]
eg. function blah ($bl,$ah) {
$bl++;
$ah++;
$blah=$bl+$ah;
}
[/snip]

function blah ($bl,$ah) {
$bl++;
$ah++;
$blah=$bl+$ah;

return $blah;
}

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RE: [PHP] Variables inside a function

2004-03-08 Thread Alex Hogan

Don't you need to set a return?

Return $blah;

At the bottom of your function block.



alex hogan


 -Original Message-
 From: Nathan Croker [mailto:[EMAIL PROTECTED]
 Sent: Sunday, March 07, 2004 6:18 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Variables inside a function
 
 I am relatively new to PHP. But something I can't seem to make work is
 when
 I call one of the functions I have made and a variable is set inside that
 function
 eg. function blah ($bl,$ah) {
 $bl++;
 $ah++;
 $blah=$bl+$ah;
 }
 I then echo $blah; somewhere else in the script but nothing is echo'd. How
 do I make it so that I can use $blah anywhere in the script?
 
 Thank you in advance for any help.
 
 Nathan Croker
 
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Re: [PHP] Variables inside a function

2004-03-08 Thread Jason Wong
On Tuesday 09 March 2004 01:44, Alex Hogan wrote:
 Don't you need to set a return?

 Return $blah;

 At the bottom of your function block.

That does not make the variable $blah available elsewhere in the program. The 
OP should take a look at manual  Variables  Variable scope.

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RE: [PHP] Variables inside a function

2004-03-08 Thread Alex Hogan
If I read his post correctly he was looking to make blah() available and not
$blah.

In my mind that meant that he would be calling his function named blah not
the variable.

Then if he called the function blah he would get the value of $blah inside
his function.

Of course obviously being one of the OP you refer to I have read the manual
 Variables  Variable scope.  In this case I don't see how it related to
his post, even though he stated that he was trying to echo $blah

One of those letter of the law vs intent of the law sort of things.

But thanks for the condensintion..., maybe I can return the favor sometime.


alex hogan


 -Original Message-
 From: Jason Wong [mailto:[EMAIL PROTECTED]
 Sent: Monday, March 08, 2004 11:49 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] Variables inside a function
 
 On Tuesday 09 March 2004 01:44, Alex Hogan wrote:
  Don't you need to set a return?
 
  Return $blah;
 
  At the bottom of your function block.
 
 That does not make the variable $blah available elsewhere in the program.
 The
 OP should take a look at manual  Variables  Variable scope.
 
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RE: [PHP] Variables inside a function

2004-03-08 Thread Jay Blanchard
[snip]
I then echo $blah; somewhere else in the script but nothing is echo'd.
How
do I make it so that I can use $blah anywhere in the script?
[/snip]

I went back and re-read the post, and his question above is the
important one

First you must return something from the function, then you must assign
the returned data to a variable...

long-hand

function blah ($bl,$ah) {
 $bl++;
 $ah++;
 $blah=$bl+$ah;
 return $blah;
}


$dork = blah($foo, $bar);

$dork is now the value of the returned $blah and $dork may be used with
the value over and over until it is re-written or over-written

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Re: [PHP] Variables inside a function

2004-03-08 Thread Jason Wong
On Tuesday 09 March 2004 02:03, Alex Hogan wrote:
 If I read his post correctly he was looking to make blah() available and
 not $blah.

The OP says so that I can use $blah anywhere in the script?, which to me 
means that $blah needs to be global ...

[snip]

 Of course obviously being one of the OP you refer to I have read the manual

(OP doesn't mean you)

  Variables  Variable scope.

... hence the referral to the manual.

  In this case I don't see how it related to
 his post, even though he stated that he was trying to echo $blah

According to what he stated he was trying to do it is very relevant.

 One of those letter of the law vs intent of the law sort of things.

Maybe.

 But thanks for the condensintion..., 

I'm sorry if you interpreted my terseness as being condescending -- note the 
spelling (*now* I'm being condescending!).

 maybe I can return the favor sometime.

TIA ;)

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RE: [PHP] Variables inside a function

2004-03-08 Thread Alex Hogan
My mistake.

Good one on the spelling I can't believe I missed that one


alex hogan


 -Original Message-
 From: Jason Wong [mailto:[EMAIL PROTECTED]
 Sent: Monday, March 08, 2004 12:26 PM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] Variables inside a function
 
 On Tuesday 09 March 2004 02:03, Alex Hogan wrote:
  If I read his post correctly he was looking to make blah() available and
  not $blah.
 
 The OP says so that I can use $blah anywhere in the script?, which to me
 means that $blah needs to be global ...
 
 [snip]
 
  Of course obviously being one of the OP you refer to I have read the
 manual
 
 (OP doesn't mean you)
 
   Variables  Variable scope.
 
 ... hence the referral to the manual.
 
   In this case I don't see how it related to
  his post, even though he stated that he was trying to echo $blah
 
 According to what he stated he was trying to do it is very relevant.
 
  One of those letter of the law vs intent of the law sort of things.
 
 Maybe.
 
  But thanks for the condensintion...,
 
 I'm sorry if you interpreted my terseness as being condescending -- note
 the
 spelling (*now* I'm being condescending!).
 
  maybe I can return the favor sometime.
 
 TIA ;)
 
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Re: [PHP] Variables not passing...

2004-03-04 Thread daniel
Is there a session_start() on the second page ?

Also i didnt know u could set an action to a jscript popup, it may not be
posting to the second page. What you could try is posting to the second
page like a normal post, u need to do something like


session_start();
$_SESSION['startdate'] = $_POST['startdate'];
$_SESSION['stopdate'] = $_POST['stopdate'];

in the second page

u only need this if u are then redirecting to yet another page

else just do a

 h1 align=centerstrongReports received between ?php echo
 .$_POST['startdate'].; ? and ?php echo $_POST['stopdate']; ?
:/strong/h1


something like that


 Okay, I am sure this will be painfully simple, but I have looked it
 over for a couple of hours now, and I am obviously missing something.
 I am trying to get a start date and a stop date via input from a user
 to use as variables in a MySQL query, but for some reason, I can't get
 the variable to pass from one page to the next...  Will one of you
 masters help me find my goof?

 First page has the following at the top of the code:
 ?php
 session_start();
 $_SESSION['startdate'] = $startdate;
 $_SESSION['stopdate'] = $stopdate;
 ?


 Then I am getting the data entry in the following form code:
 form name=viewbydate method=post
 action=javascript:popUp('viewbydate.php')
  li All reports from one date to another: Start
input name=startdate type=text size=15 maxlength=30
Stop
input name=stopdate type=text size=15 maxlength=30
input name=button2 type=submit value=GO
  /form


 The second page starts by displaying this info:
 h1 align=centerstrongReports received between ?php echo
 $startdate; ? and ?php echo $stopdate; ?:/strong/h1


 The regular text displays, but there is just white space where the
 $startdate and $stopdate should be.

 Thanks in Advance!!
 Chase

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Re: [PHP] Variables not passing...

2004-03-04 Thread Chase
Thank you!  It looks like it was a combination of my NOT using the $_POST
and the fact that my JScript wasn't allowing the variables to pass...  WHO
KNEW?!?

THANKS!!!
Chase


[EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Is there a session_start() on the second page ?

 Also i didnt know u could set an action to a jscript popup, it may not be
 posting to the second page. What you could try is posting to the second
 page like a normal post, u need to do something like


 session_start();
 $_SESSION['startdate'] = $_POST['startdate'];
 $_SESSION['stopdate'] = $_POST['stopdate'];

 in the second page

 u only need this if u are then redirecting to yet another page

 else just do a

  h1 align=centerstrongReports received between ?php echo
  .$_POST['startdate'].; ? and ?php echo $_POST['stopdate']; ?
 :/strong/h1


 something like that


  Okay, I am sure this will be painfully simple, but I have looked it
  over for a couple of hours now, and I am obviously missing something.
  I am trying to get a start date and a stop date via input from a user
  to use as variables in a MySQL query, but for some reason, I can't get
  the variable to pass from one page to the next...  Will one of you
  masters help me find my goof?
 
  First page has the following at the top of the code:
  ?php
  session_start();
  $_SESSION['startdate'] = $startdate;
  $_SESSION['stopdate'] = $stopdate;
  ?
 
 
  Then I am getting the data entry in the following form code:
  form name=viewbydate method=post
  action=javascript:popUp('viewbydate.php')
   li All reports from one date to another: Start
 input name=startdate type=text size=15 maxlength=30
 Stop
 input name=stopdate type=text size=15 maxlength=30
 input name=button2 type=submit value=GO
   /form
 
 
  The second page starts by displaying this info:
  h1 align=centerstrongReports received between ?php echo
  $startdate; ? and ?php echo $stopdate; ?:/strong/h1
 
 
  The regular text displays, but there is just white space where the
  $startdate and $stopdate should be.
 
  Thanks in Advance!!
  Chase
 
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Re: [PHP] Variables not passing...

2004-03-04 Thread Chase
One other irritation for the evening...  The MySQL query that I am trying to
create needs to use the date the user enters and then add  @ 12:01am EST
to it so it will acutally match the data in the table.  Below is my quesry
line, but I don't know how to add that chunk to each of the variables...

$result = mysql_query(SELECT * FROM $table WHERE 'submit_date' =
'$startdate' AND 'submit_date' = '$stopdate' ORDER BY 'submit_date' DESC,
$link);



[EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Is there a session_start() on the second page ?

 Also i didnt know u could set an action to a jscript popup, it may not be
 posting to the second page. What you could try is posting to the second
 page like a normal post, u need to do something like


 session_start();
 $_SESSION['startdate'] = $_POST['startdate'];
 $_SESSION['stopdate'] = $_POST['stopdate'];

 in the second page

 u only need this if u are then redirecting to yet another page

 else just do a

  h1 align=centerstrongReports received between ?php echo
  .$_POST['startdate'].; ? and ?php echo $_POST['stopdate']; ?
 :/strong/h1


 something like that


  Okay, I am sure this will be painfully simple, but I have looked it
  over for a couple of hours now, and I am obviously missing something.
  I am trying to get a start date and a stop date via input from a user
  to use as variables in a MySQL query, but for some reason, I can't get
  the variable to pass from one page to the next...  Will one of you
  masters help me find my goof?
 
  First page has the following at the top of the code:
  ?php
  session_start();
  $_SESSION['startdate'] = $startdate;
  $_SESSION['stopdate'] = $stopdate;
  ?
 
 
  Then I am getting the data entry in the following form code:
  form name=viewbydate method=post
  action=javascript:popUp('viewbydate.php')
   li All reports from one date to another: Start
 input name=startdate type=text size=15 maxlength=30
 Stop
 input name=stopdate type=text size=15 maxlength=30
 input name=button2 type=submit value=GO
   /form
 
 
  The second page starts by displaying this info:
  h1 align=centerstrongReports received between ?php echo
  $startdate; ? and ?php echo $stopdate; ?:/strong/h1
 
 
  The regular text displays, but there is just white space where the
  $startdate and $stopdate should be.
 
  Thanks in Advance!!
  Chase
 
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Re: [PHP] variables

2004-02-19 Thread Adam Voigt
Escape it.

$string = \\;

Or, use single quotes:

$string = '\';


On Thu, 2004-02-19 at 12:49, Dominique ANOKRE wrote:
 hello, 
 
 
 how can i put the character \ in a variable ?
 
 I've done the code below but errors occurs : 
 
 $barre_oblique = \;
 
 
 Parse error: parse error, unexpected T_STRING 
 
 Please help 
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Re: [PHP] variables

2004-02-19 Thread Adam Voigt
Whoops, mistyped on my reply, you need to escape it with the single
quotes to.


On Thu, 2004-02-19 at 12:49, Dominique ANOKRE wrote:
 hello, 
 
 
 how can i put the character \ in a variable ?
 
 I've done the code below but errors occurs : 
 
 $barre_oblique = \;
 
 
 Parse error: parse error, unexpected T_STRING 
 
 Please help 
-- 

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[EMAIL PROTECTED]

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Re: [PHP] variables

2004-02-19 Thread Richard Davey
Hello Dominique,

Thursday, February 19, 2004, 5:49:43 PM, you wrote:

DA how can i put the character \ in a variable ?
DA I've done the code below but errors occurs :
DA $barre_oblique = \;
DA Parse error: parse error, unexpected T_STRING
DA Please help 

$barre_oblique = \\;

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Re: [PHP] variables

2004-02-19 Thread Dominique ANOKRE
ok thanks 
pb solved

thank you everybody
- Original Message - 
From: Richard Davey [EMAIL PROTECTED]
To: Dominique ANOKRE [EMAIL PROTECTED]
Cc: Php List [EMAIL PROTECTED]
Sent: Thursday, February 19, 2004 5:52 PM
Subject: Re: [PHP] variables


 Hello Dominique,
 
 Thursday, February 19, 2004, 5:49:43 PM, you wrote:
 
 DA how can i put the character \ in a variable ?
 DA I've done the code below but errors occurs :
 DA $barre_oblique = \;
 DA Parse error: parse error, unexpected T_STRING
 DA Please help 
 
 $barre_oblique = \\;
 
 -- 
 Best regards,
  Richard Davey
  http://www.phpcommunity.org/wiki/296.html
 
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RE: [PHP] Variables??

2004-02-15 Thread Julien Wadin
give the corresponding source code
are you using POST or GET ? What about REGISTER_GLOBALS ???

PS : NO MAILS IN HTML ON THE LIST, PLEASE


-Message d'origine-
De : Alessandro Rodiani [mailto:[EMAIL PROTECTED]
Envoyé : dimanche 15 février 2004 21:29
À : [EMAIL PROTECTED]; [EMAIL PROTECTED]
Objet : [PHP] Variables??


I have a problem. When I call the function phpinfo() I can correctly see the
page with the information about the server; but when I use a form to pass
some information from a php page to another php page, if I use a print() or
an echo() function, I can't see my variables. Why??? Help me please
Thank

Alessandro




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Re: [PHP] Variables not working!

2004-01-28 Thread Alvaro Zuniga
Try this for a generic fix if it is the globals issue:

Place this somewhere to set to TRUE or FALSE when needed

$GLOBAL_FIX  = TRUE;

use an include on every script:

if($GLOBAL_VARS_FIX) {
   if( phpversion() = '4.2.0' ) {
  extract($_POST);
  extract($_GET);
  extract($_SERVER);
  extract($_ENV);
  extract($_COOKIE);
   }
}
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Re: [PHP] Variables not working!

2004-01-20 Thread Rory McKinley
On 19 Jan 2004 at 21:43, Kaushan wrote:

 Hi,
 
 I am new to PHP scripting and struggling with the following problem.
 
 I have two files, an HTML file and a PHP file.
 HTML file contains a form with one text field and a submit button.
 When a user pressed the submit button, it calls the php file (form
 action=test.php ...).
 What the php file does is just echo back the text  received from html file
 to the user again.
 Name of the text field is 'fname'. When I used this variable in the php file
 (as $fname) it does not contain the value of the text field. Query-string
 appended to the url during the submission is also correct.
 I checked for all syntax errors, but the codings are perfect.
 
 Do I have to change php.ini file to fix this problem.
 
 Could anyone can help me to solve this problem.
 
 Kaushan
 
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Hi Kaushan

Little bit difficult without seeing the code, but what you are probably sitting with 
is an 
issue with globals - depending on your method of submitting (GET or POST)you can try 
and check one of these two $_POST['fname'] or $_GET['fname'] for the value of the 
text field.

Rory McKinley
Nebula Solutions
+27 82 857 2391
[EMAIL PROTECTED]
There are 10 kinds of people in this world, 
those who understand binary and those who don't (Unknown)

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RE: [PHP] Variables not working!

2004-01-20 Thread Larry Brown
It is most likely globals.  Access the variables by...

echo $_GET['fname'];

or $_POST['fname']; if you are using post which it doesn't appear you do.

Larry

PS it is adviseable to leave globals alone in php.ini since it is set that
way for security concerns.

-Original Message-
From: Kaushan [mailto:[EMAIL PROTECTED]
Sent: Monday, January 19, 2004 10:44 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Variables not working!


Hi,

I am new to PHP scripting and struggling with the following problem.

I have two files, an HTML file and a PHP file.
HTML file contains a form with one text field and a submit button.
When a user pressed the submit button, it calls the php file (form
action=test.php ...).
What the php file does is just echo back the text  received from html file
to the user again.
Name of the text field is 'fname'. When I used this variable in the php file
(as $fname) it does not contain the value of the text field. Query-string
appended to the url during the submission is also correct.
I checked for all syntax errors, but the codings are perfect.

Do I have to change php.ini file to fix this problem.

Could anyone can help me to solve this problem.

Kaushan

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Re: [PHP] Variables

2004-01-15 Thread Richard Davey
Hello Alex,

Thursday, January 15, 2004, 9:47:27 PM, you wrote:

AH How do you insert a php variable into a javascript function?
AH function redirect(?php $MyVar ?) { location = ?php $MyVar ?; }

function redirect (?=$MyVar?) { location = ?=$MyVar?; }

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Re: [PHP] Variables

2004-01-15 Thread Ben Ramsey
AH How do you insert a php variable into a javascript function?
AH function redirect(?php $MyVar ?) { location = ?php $MyVar ?; }
function redirect (?=$MyVar?) { location = ?=$MyVar?; }
or use:
function redirect (?php echo $MyVar; ?) { location = ?php echo MyVar; 
?; }

The short syntax only works with short_open_tag enabled in php.ini or 
with ini_set().

-Ben

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Re: [PHP] Variables

2004-01-15 Thread Ben Ramsey
AH How do you insert a php variable into a javascript function?
AH function redirect(?php $MyVar ?) { location = ?php $MyVar ?; }
function redirect (?=$MyVar?) { location = ?=$MyVar?; }
or use:
function redirect (?php echo $MyVar; ?) { location = ?php echo MyVar; 
?; }

The short syntax only works with short_open_tag enabled in php.ini or 
with ini_set().

-Ben

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Re: [PHP] Variables

2004-01-15 Thread Ben Ramsey
AH How do you insert a php variable into a javascript function?
AH function redirect(?php $MyVar ?) { location = ?php $MyVar ?; }
function redirect (?=$MyVar?) { location = ?=$MyVar?; }
or use:
function redirect (?php echo $MyVar; ?) { location = ?php echo MyVar; 
?; }

The short syntax only works with short_open_tag enabled in php.ini or 
with ini_set().

-Ben

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Re: [PHP] Variables

2004-01-15 Thread Brian V Bonini
On Thu, 2004-01-15 at 16:47, Alex Hogan wrote:
 How do you insert a php variable into a javascript function?
 For instance;
 function redirect(?php $MyVar ?) { location = ?php $MyVar ?; }


?php

echo 'function redirect(' . $MyVar . ') {';
echo 'location =' . $MyVar . ';}';

?



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[PHP] Re: PHP Variables

2003-12-06 Thread Greg Beaver
Hi Lloyd,

use quotes around your values

echo input type=\text\ name=\question1_text\ 
value=\$question\br /;

Regards,
Greg
--
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Lloyd Bayley wrote:
Greetings All,

Have a small problem that I just can't work out. I know it's an easy one 
but it's got me stumped...

I have some code to pull a question out of a database and display it on 
the screen. I also want to store it in a hidden var for
use with the $_POST on the next page.

Currently, the display bit works fine.
The only problem is the hidden var only has the first word of the 
question in itand I'm setting it from the same var!!!

Eg.

If the question is: What is the problem with this stupid thing?
The hidden var will contain: What
What am I missing? Why has the rest of the question packed it's things 
and moved out???

Code Snippet

while ($newarray = mysql_fetch_array($result)) {
$qid = $newarray['qid'];
$question = $newarray['question_text'];
echo brfont face = 
Verdanab$question/b/fontbr;  --- This 
works perfectly.
echo input type=text name=question1_text value=$questionbr;   
 This returns first word.

Many Thanks In Advance,

Lloyd. :-)
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[PHP] Re: PHP Variables

2003-12-06 Thread Lloyd Bayley
Greg,

Sheesh! I had neglected to do that...I've been working with a few different 
languages and I'm starting to confuse them I think.

Thanks for your non-offensive reply.
It's nice to see that you can overlook the little failures we have now and 
again.

Lloyd. :-)

At 09:58 AM 7/12/2003, you wrote:
Hi Lloyd,

use quotes around your values

echo input type=\text\ name=\question1_text\ value=\$question\br 
/;

Regards,
Greg
--
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http://www.phpdoc.org
Lloyd Bayley wrote:
Greetings All,
Have a small problem that I just can't work out. I know it's an easy one 
but it's got me stumped...
I have some code to pull a question out of a database and display it on 
the screen. I also want to store it in a hidden var for
use with the $_POST on the next page.

Currently, the display bit works fine.
The only problem is the hidden var only has the first word of the 
question in itand I'm setting it from the same var!!!
Eg.
If the question is: What is the problem with this stupid thing?
The hidden var will contain: What
What am I missing? Why has the rest of the question packed it's things 
and moved out???
Code Snippet

while ($newarray = mysql_fetch_array($result)) {
$qid = $newarray['qid'];
$question = $newarray['question_text'];
echo brfont face = 
Verdanab$question/b/fontbr;  --- This 
works perfectly.
echo input type=text name=question1_text value=$questionbr;
 This returns first word.

Many Thanks In Advance,

Lloyd. :-)

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Re: [PHP] Re: PHP Variables

2003-12-06 Thread John W. Holmes
Lloyd Bayley wrote:

Thanks for your non-offensive reply.
It's nice to see that you can overlook the little failures we have now 
and again.
Please learn HTML is offensive? Please... I even gave you the 
_correct_ answer that involves htmlentities(), otherwise you'll be back 
here with another question when your $question has a double quote 
within it.

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Re: [PHP] Re: PHP Variables

2003-12-06 Thread John Nichel
John W. Holmes wrote:

Lloyd Bayley wrote:

Thanks for your non-offensive reply.
It's nice to see that you can overlook the little failures we have now 
and again.


Please learn HTML is offensive? Please... I even gave you the 
_correct_ answer that involves htmlentities(), otherwise you'll be back 
here with another question when your $question has a double quote 
within it.

You big meanie.

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RE: [PHP] Variables scope question

2003-12-03 Thread Martin Towell
This doesn't sound right. It's doesn't behave like this for me.

Can you supply an example?

Martin

 -Original Message-
 From: Mike D [mailto:[EMAIL PROTECTED]
 Sent: Thursday, 4 December 2003 10:35 AM
 To: PHP General list
 Subject: [PHP] Variables scope question
 
 
 Hello,
 
 I have recently noticed something that I wasn't aware of 
 until now. I have
 index.php which contains include1.txt and include2.txt. If a 
 variable is set
 in include1.txt it will *only* have a local scope, even if I 
 declare it
 GLOBAL. Is this normal or a bug?
 
   - MD 
 
 
 Mike Dunlop
 AWN, Inc.
 // www.awn.com
 [ e ] [EMAIL PROTECTED]
 [ p ] 323.606.4237
 
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Re: [PHP] Variables scope question

2003-12-03 Thread Mike D
NEVERMIND - some user error there... (happens once in a while)

It's been a long day ;-)

Thanks
- MD


On 12/3/03 3:36 PM, Martin Towell [EMAIL PROTECTED] wrote:

 This doesn't sound right. It's doesn't behave like this for me.
 
 Can you supply an example?
 
 Martin
 
 -Original Message-
 From: Mike D [mailto:[EMAIL PROTECTED]
 Sent: Thursday, 4 December 2003 10:35 AM
 To: PHP General list
 Subject: [PHP] Variables scope question
 
 
 Hello,
 
 I have recently noticed something that I wasn't aware of
 until now. I have
 index.php which contains include1.txt and include2.txt. If a
 variable is set
 in include1.txt it will *only* have a local scope, even if I
 declare it
 GLOBAL. Is this normal or a bug?
 
   - MD 
 
 
 Mike Dunlop
 AWN, Inc.
 // www.awn.com
 [ e ] [EMAIL PROTECTED]
 [ p ] 323.606.4237
 
 -- 
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 To unsubscribe, visit: http://www.php.net/unsub.php
 
 



Mike Dunlop
AWN, Inc.
// www.awn.com
[ e ] [EMAIL PROTECTED]
[ p ] 323.606.4237

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Re: [PHP] Variables - showing onpage

2003-11-30 Thread Jason Wong
On Sunday 30 November 2003 15:54, Biph wrote:
 I have a question, and maybe I'm an idiot (alright not maybe). I can't get
 the damned variables to stop showing their variable names on the screen,
 like a variable $stock_quote appears in the HTML as $stock_quote, what the
 hell am I doing wrong? I'm using Win2K to test a site on my own computer
 using Apache2, but all variables from MySQL to PHP are just showing up as
 the variable name and not the value in the HTML.Any help would be nice.
 example:
 ?php
 $price = 1.00
 print('the price is: $price')
 ?
 is apprearing as:
 the price is $price
 in the HTML instead of:
 the price is 1.00

manual  Chapter 7  Strings

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RE: [PHP] Variables - showing onpage

2003-11-30 Thread Jeroen Serpieters
You have to put it between double quotes.

Jeroen

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-Original Message-
From: Biph [mailto:[EMAIL PROTECTED] 
Sent: Sunday, November 30, 2003 8:54 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Variables - showing onpage


I have a question, and maybe I'm an idiot (alright not maybe). I can't get
the damned variables to stop showing their variable names on the screen,
like a variable $stock_quote appears in the HTML as $stock_quote, what the
hell am I doing wrong? I'm using Win2K to test a site on my own computer
using Apache2, but all variables from MySQL to PHP are just showing up as
the variable name and not the value in the HTML.Any help would be nice.
example:
?php
$price = 1.00
print('the price is: $price')
?
is apprearing as:
the price is $price
in the HTML instead of:
the price is 1.00

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