Re: [PHP] Works in html, not when echoed in PHP

2002-11-13 Thread @ Edwin 

"Aaron Merrick" <[EMAIL PROTECTED]> wrote:

> You are right, there is a reason I am echoing it in php, it is one result
of
> an if statement.

Well, I thought so :)

...[snip]...

> I tried echoing with single quotes - no change. So I compared the view
> source of the double quoted php generated page and of the html generated
> page - they are identical:
>
>  onresize="window.location.reload(false)" topmargin="1" bottommargin="0"
> leftmargin="0" rightmargin="0">
>
> So I no longer think php is parsing the javascript incorrectly - the same
> error happens if I put the 'onoff()' function directly in html and only
put
> the 'start()' function in the if statement. The weird thing is that the
php
> page still gives the error and the html does not.

I can only guess...

What happens when you take out the start() then? I think it'd be a good idea
anyway to take away the js codes in your  tag (also the xxxmargin
stuffs) since your page wouldn't actually validate as valid xhtml (if you're
concerned of course...).

Is it not possible to put those inside the  tags, in-between

Re: [PHP] Works in html, not when echoed in PHP

2002-11-13 Thread Aaron Merrick 
I'm not constructing it with, it is just included in the file. Does that
clarify? Or did I misunderstand your point?

On 11/13/02 1:47 AM, "Ernest E Vogelsinger" <[EMAIL PROTECTED]> wrote:

> You didn't show how you construct the JavaScript string in PHP - I'm sure
> the problem is with quoting in there.
> 
> Have a look at your output in the browser (do a "View Source" or whatever
> your Browser calls it), and check the JS your PHP application constructed.
> You'll spot the error...
> 
> At 05:28 13.11.2002, Aaron Merrick said:
> [snip]
>> Folks,
>> 
>> Can't see an answer anywhere in the archives, so here goes.
>> 
>> This works fine in plain html:
>> 
>> > onresize="window.location.reload(false)" topmargin="1" bottommargin="0"
>> leftmargin="0" rightmargin="0">
>> 
>> When I put it in PHP thus:
>> 
>> echo "> onresize=\"window.location.reload(false)\" topmargin=\"1\"
>> bottommargin=\"0\" leftmargin=\"0\" rightmargin=\"0\">";
>> 
>> When the page loads, I get an "Error: 'menuObj' is null or not an object"
>> 
>> The onoff() function is what contains the menuObj, so I suspect the single
>> quotes around the parameters mainmenu and on, but have tried everyway I can
>> think of and can't get rid of the Error.
>> 
>> The function is thus:
>> 
>> function onoff (elemparent,elem,state) {
>> if (loaded) {
>> newstate = eval(elem+"_"+state);
>> if (n4) {
>> menuObj = eval (doc + elemparent + doc2 + elem);
>> }
>> else if (ie || n6) {
>> menuObj = eval (doc + elem + doc2);
>> }
>> 
>> I would be grateful for any tips.
>> 
>> Thanks,
>> Aaron
>> 
>> 
>> -- 
>> PHP General Mailing List (http://www.php.net/)
>> To unsubscribe, visit: http://www.php.net/unsub.php
> [snip] 


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Re: [PHP] Works in html, not when echoed in PHP

2002-11-13 Thread Aaron Merrick 
You are right, there is a reason I am echoing it in php, it is one result of
an if statement.  

";
} else {
echo "";
} 
?>


I tried echoing with single quotes - no change. So I compared the view
source of the double quoted php generated page and of the html generated
page - they are identical:



So I no longer think php is parsing the javascript incorrectly - the same
error happens if I put the 'onoff()' function directly in html and only put
the 'start()' function in the if statement. The weird thing is that the php
page still gives the error and the html does not.

Anyway, I thought I would see if there were any more ideas as to what I am
doing wrong.

Thanks for the help,
Aaron

On 11/13/02 12:50 AM, "@ Edwin" <[EMAIL PROTECTED]> wrote:

> echo ' onresize="window.location.reload(false)" topmargin="1" bottommargin="0"
> leftmargin="0" rightmargin="0">';


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Re: [PHP] Works in html, not when echoed in PHP

2002-11-12 Thread Ernest E Vogelsinger 
You didn't show how you construct the JavaScript string in PHP - I'm sure
the problem is with quoting in there.

Have a look at your output in the browser (do a "View Source" or whatever
your Browser calls it), and check the JS your PHP application constructed.
You'll spot the error...

At 05:28 13.11.2002, Aaron Merrick said:
[snip]
>Folks,
>
>Can't see an answer anywhere in the archives, so here goes.
>
>This works fine in plain html:
>
>onresize="window.location.reload(false)" topmargin="1" bottommargin="0"
>leftmargin="0" rightmargin="0">
>
>When I put it in PHP thus:
>
>echo "onresize=\"window.location.reload(false)\" topmargin=\"1\"
>bottommargin=\"0\" leftmargin=\"0\" rightmargin=\"0\">";
>
>When the page loads, I get an "Error: 'menuObj' is null or not an object"
>
>The onoff() function is what contains the menuObj, so I suspect the single
>quotes around the parameters mainmenu and on, but have tried everyway I can
>think of and can't get rid of the Error.
>
>The function is thus:
>
>function onoff (elemparent,elem,state) {
>if (loaded) {
>newstate = eval(elem+"_"+state);
>if (n4) {
>menuObj = eval (doc + elemparent + doc2 + elem);
> }
>else if (ie || n6) {
>menuObj = eval (doc + elem + doc2);
> }
>
>I would be grateful for any tips.
>
>Thanks,
>Aaron
>
>
>-- 
>PHP General Mailing List (http://www.php.net/)
>To unsubscribe, visit: http://www.php.net/unsub.php
[snip] 

-- 
   >O Ernest E. Vogelsinger
   (\)ICQ #13394035
^ http://www.vogelsinger.at/



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Re: [PHP] Works in html, not when echoed in PHP

2002-11-12 Thread @ Edwin 

"Chris Shiflett" <[EMAIL PROTECTED]> wrote:


...[snip]...

> Yes, this is the same code that "works fine in plain html". Why echo it in
PHP if it is static?

Good question ;)

But I'm sure there's a good a answer :) Besides, why would anybody want to
do that if there's no good reason?

- E


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Re: [PHP] Works in html, not when echoed in PHP

2002-11-12 Thread Chris Shiflett 
@ Edwin wrote:


"Aaron Merrick" <[EMAIL PROTECTED]> wrote:


This works fine in plain html:



When I put it in PHP thus:

echo "";

When the page loads, I get an "Error: 'menuObj' is null or not an object"


I think php is parsing your js code. Have you tried echoing with single
quotes?

echo '';



Or better yet, try this:



Yes, this is the same code that "works fine in plain html". Why echo it in PHP if it is static?

Chris



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Re: [PHP] Works in html, not when echoed in PHP

2002-11-12 Thread @ Edwin 
Hello,

"Aaron Merrick" <[EMAIL PROTECTED]> wrote:

> Folks,
>
> Can't see an answer anywhere in the archives, so here goes.
>
> This works fine in plain html:
>
>  onresize="window.location.reload(false)" topmargin="1" bottommargin="0"
> leftmargin="0" rightmargin="0">
>
> When I put it in PHP thus:
>
> echo " onresize=\"window.location.reload(false)\" topmargin=\"1\"
> bottommargin=\"0\" leftmargin=\"0\" rightmargin=\"0\">";
>
> When the page loads, I get an "Error: 'menuObj' is null or not an object"
>
> The onoff() function is what contains the menuObj, so I suspect the single
> quotes around the parameters mainmenu and on, but have tried everyway I
can
> think of and can't get rid of the Error.
>
> The function is thus:
>

I think php is parsing your js code. Have you tried echoing with single
quotes?

echo '';

- E


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