This isn't exactly what you want, but it is close:
list($user_id,$field2,$field3,$field4) = $row;
where $row was retrieved via mysql_fetch_array()
Just list each of the variable names in the list() function; include ALL
fields' names included in $row
-Original Message-
From: Baloo :0)
First grab an associative array of the variables from the database with
mysql_fetch_array()
Then use extract($array); to extract all of the variables in the array
to the symbol table:
www.php.net/extract
Simon
Baloo :0) wrote:
How can I assign automatically all fields of a database to a
This may not be what you want to do, but should give you some hints.
(This is my code which I use to simply dump any SQL table into an HTML
table I can view in a browser ... for small tables, of course.)
Using MySQL as an example:
// assuming you ran a query and stored results in
This creates all the variables you asked for and also prints each one in a
column of a table.
foreach($row as $key=$val) {
$$key = $val;
echo td$val/td;
}
-Rasmus
On Tue, 19 Feb 2002, Baloo :0) wrote:
How can I assign automatically all fields of a database to a variable of
the same
oi ... typo! see below. sorry :(
~Chris
On Tue, 19 Feb 2002, Christopher William Wesley wrote:
This may not be what you want to do, but should give you some hints.
(This is my code which I use to simply dump any SQL table into an HTML
table I can view in a browser ... for small
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