Re: [PHP] explode? (table field to a variable of same name)
oi ... typo! see below. sorry :(
~Chris
On Tue, 19 Feb 2002, Christopher William Wesley wrote:
> This may not be what you want to do, but should give you some hints.
> (This is my code which I use to simply dump any SQL table into an HTML
> table I can view in a browser ... for small tables, of course.)
>
> Using MySQL as an example:
> // assuming you ran a query and stored results in $mysql_result_set
>
> // Get the number of fields to work with
> $num_fields = mysql_num_fields( $mysql_result_set );
> // http://www.php.net/manual/en/function.mysql-num-fields.php
>
> // Print out a row of column headers
> print( "" );
> for( $i = 0; $i < $num_fields; $i++ ){
> $fieldName = mysql_fetch_field( $mysql_result_set, $i );
> // http://www.php.net/manual/en/function.mysql-fetch-field.php
> print( "" . $fieldName->name . "" );
> }
> print( "" );
>
> // Print out the data from the result records
> while( $record = mysql_fetch_row( $mysql_result_set ) ){
> // http://www.php.net/manual/en/function.mysql-fetch-row.php
> print( "" );
I screwed it up here ... this foreach() loop should be as follows
> foreach( $record as $fieldName=>$field ){
> ${$fieldName} = $field;
> // The above is unnecessary, but answers your question.
> // It assigns a variable, named after a table column,
> //the value of that column (in this record).
> print( "${field}" );
> }
> print( "" );
> }
Again ... sorry about that. Oi ... and I see that someone else, wrote
that bit of code correctly to the list just now :) (thx, Rasmus).
>
> Hope that gives you something to work with.
>
> g.luck,
> ~Chris
>
> On Tue, 19 Feb 2002, Baloo :0) wrote:
>
> > How can I assign automatically all fields of a database to a variable of
> > the same name?
> >
> > Instead of having to manually do
> > $user_id=$row["user_id"];
> > etc
> >
> > Then how could I know the number of fields in the table so I can do a
> > loop to print them all in html?
>
>
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Re: [PHP] explode? (table field to a variable of same name)
This creates all the variables you asked for and also prints each one in a
column of a table.
foreach($row as $key=>$val) {
$$key = $val;
echo "$val";
}
-Rasmus
On Tue, 19 Feb 2002, Baloo :0) wrote:
> How can I assign automatically all fields of a database to a variable of
> the same name?
>
> Instead of having to manually do
> $user_id=$row["user_id"];
> etc
>
> Then how could I know the number of fields in the table so I can do a
> loop to print them all in html?
>
> In advance, thanks for your help.
>
> Alfredo
>
>
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> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] explode? (table field to a variable of same name)
This may not be what you want to do, but should give you some hints.
(This is my code which I use to simply dump any SQL table into an HTML
table I can view in a browser ... for small tables, of course.)
Using MySQL as an example:
// assuming you ran a query and stored results in $mysql_result_set
// Get the number of fields to work with
$num_fields = mysql_num_fields( $mysql_result_set );
// http://www.php.net/manual/en/function.mysql-num-fields.php
// Print out a row of column headers
print( "" );
for( $i = 0; $i < $num_fields; $i++ ){
$fieldName = mysql_fetch_field( $mysql_result_set, $i );
// http://www.php.net/manual/en/function.mysql-fetch-field.php
print( "" . $fieldName->name . "" );
}
print( "" );
// Print out the data from the result records
while( $record = mysql_fetch_row( $mysql_result_set ) ){
// http://www.php.net/manual/en/function.mysql-fetch-row.php
print( "" );
foreach( $record as $field ){
${$field} = $field;
// The above is unnecessary, but answers your question.
// It assigns a variable, named after a table column,
//the value of that column (in this record).
print( "${field}" );
}
print( "" );
}
Hope that gives you something to work with.
g.luck,
~Chris
On Tue, 19 Feb 2002, Baloo :0) wrote:
> How can I assign automatically all fields of a database to a variable of
> the same name?
>
> Instead of having to manually do
> $user_id=$row["user_id"];
> etc
>
> Then how could I know the number of fields in the table so I can do a
> loop to print them all in html?
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] explode? (table field to a variable of same name)
First grab an associative array of the variables from the database with mysql_fetch_array() Then use extract($array); to extract all of the variables in the array to the symbol table: www.php.net/extract Simon Baloo :0) wrote: >How can I assign automatically all fields of a database to a variable of >the same name? > >Instead of having to manually do >$user_id=$row["user_id"]; >etc > >Then how could I know the number of fields in the table so I can do a >loop to print them all in html? > >In advance, thanks for your help. > >Alfredo > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] explode? (table field to a variable of same name)
This isn't exactly what you want, but it is close: list($user_id,$field2,$field3,$field4) = $row; where $row was retrieved via mysql_fetch_array() Just list each of the variable names in the list() function; include ALL fields' names included in $row -Original Message- From: Baloo :0) [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 19, 2002 3:41 PM To: [EMAIL PROTECTED] Subject: [PHP] explode? (table field to a variable of same name) How can I assign automatically all fields of a database to a variable of the same name? Instead of having to manually do $user_id=$row["user_id"]; etc Then how could I know the number of fields in the table so I can do a loop to print them all in html? In advance, thanks for your help. Alfredo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
