Re: [PHP] generating variable names
Hi Kevin,
I find it a bit awkward to mix variables and arrays in a pseudo
array. But I guess you have reasons...
Anyhow, maybe this is what you want:
$variable1="one";
$variable2="two";
$variable3 = array();
$variable3[0]="three";
$variable4 = array();
$variable4[0]="four";
$j=1;
while($j<5){
if (is_array(${"variable".$j})) {
print(${"variable".$j}[0] . "");
} else {
print(${"variable".$j} . "");
};
$j++;
}
Timo
Am Freitag den, 6. September 2002, um 20:37, schrieb Kevin Heflin:
> Hoping someone can help me with this. Below I have an example
> of what I'm trying to accomplish.
> Bottom line.. I need to print out $variable3[0] and $variable4[0]
> and my problem is that I'm trying to generate the variable
> name. I can get this to work with $variable1 and $variable2
> which are not arrays, however that doesn't help me much.
>
> Any suggestions would be appreciated.
>
> Kevin
>
>
>
>$variable1="one";
> $variable2="two";
> $variable3[0]="three";
> $variable4[0]="four";
>
> $j=1;
> while($j<5){
> print("${variable.$j} ");
> $j++;
> }
>
>
> $j=1;
> while($j<5){
> $k="\$variable".$j."[0]";
> print("$k ");
> print("${variable.$k} ");
> $j++;
> }
> ?>
>
>
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RE: [PHP] generating variable names
Hi ... You can make it like this:
If you have
$variable4[0]="four";
Then you can have a new variable
$$variable[0] , and the new variable´s name is four
Cordialmente
Daniel Massón => Ingeniero de desarollo
[EMAIL PROTECTED]
www.imagine.com.co
Tels: (57)(1) 2182064 - 6163218
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De: Kevin Heflin [mailto:[EMAIL PROTECTED]]
Enviado el: viernes, 06 de septiembre de 2002 13:38
Para: php-general
Asunto: [PHP] generating variable names
Hoping someone can help me with this. Below I have an example of what
I'm trying to accomplish.
Bottom line.. I need to print out $variable3[0] and $variable4[0] and my
problem is that I'm trying to generate the variable name. I can
get this to work with $variable1 and $variable2 which are not arrays,
however that doesn't help me much.
Any suggestions would be appreciated.
Kevin
");
$j++;
}
$j=1;
while($j<5){
$k="\$variable".$j."[0]";
print("$k ");
print("${variable.$k} ");
$j++;
}
?>
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Re: [PHP] Generating variable names 'on the fly'
You can allso do like this:
$i = 1;
${"test". $i} = "123";
echo $test1;
___
Marcus Rasmussen
[EMAIL PROTECTED]
On 21-09-01 at 11:21 _lallous wrote:
>you can always use eval to create a variable too!
>
>$i = 1;
>eval("\$test$i=123;");
>echo $test1;
>?>
>
>"Neil Freeman" <[EMAIL PROTECTED]> wrote in message
>[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>> Hi there,
>>
>> How do I generate variable names 'on the fly'? I wish to have variable
>> names along the lines of $genre_category_1, $genre_category_2,
>> $genre_category_3 etc.
>>
>> Ideally it would be along the lines of this...
>>
>> ###
>> $current_field_number = 1;
>> $genre_number_fields = 7;
>>
>> while ($current_field_number < $genre_number_fields)
>> {
>> //this var will change on every loop
>> $genre_desc = $db_movies_genres->Record[$current_field_number];
>>
>> //something along the lines of...(you get the idea)
>> $str_category = "genre_category_" . $current_field_number;
>> $$str_category = $genre_desc;
>>
>> $current_field_number++;
>> }
>> ###
>>
>> Any help would be greatly appreciated.
>>
>> Neil
>>
>> Email: [EMAIL PROTECTED]
>> [EMAIL PROTECTED]
>>
>>
>>
>
>
>
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