Re: [PHP] generically accessing member variables problem
If I understand you, you need to have a basic class with the
one function and subclass it. Then you can reference the array
as $this-$passed_in_array_name
John Kenyon wrote:
I'm trying to write a function I can plop in a bunch of different
classes without having to modify it.
Basically I have classes like:
class Example
{
var $array1;
var $array2;
var $array3;
etc.
}
and I want to have a function in that class that looks something like
this:
function do_something_to_array($passed_in_array_name)
{
//this is what I've done so far, but which isn't working
$arr = '$this-' . $passed_in_array_name;
// now I want $passed_in_array_name to be evaluated as an array
eval (\$arr = \$arr\;);
// however even if 'array1' is the passed in value $arr is not the
// same as $this-array1
...
}
As a side note there is another aspect of this that confuses me -- if
I do a print_r($arr) before the eval it returns the string
'$this-array1', if I do it after it returns Array (which is what it
seems it should do. However, if I then pass $arr to a function that
requires an array as an argument, like array_push, for example, I get
an error that says that function takes an array. Can anyone explain
this to me? The only guess I have is that my eval function is turning it
into a string which reads as Array instead of either a String object
or the
value of the string.
More important though is the first problem of generically
accesing a member variable based on the passed in name of the
variable. In other words I want to be able to choose which array I
operate on by passing in the name of that array.
Any help on this problem is appreciated. I know there must be a way to
do this. Please let me know if I haven't formulated the problem
clearly enough.
jck
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Re: [PHP] generically accessing member variables problem
Thank you for replying, but I don't think I've made my problem clear
enough. Let me give it another shot.
What I want is a function that takes the name of an array as a parameter
so that it can be popped into any class that has arrays in it and work
without modification. The problem I am having is in converting the
passed in array name to the form which the class would recognize as its
own member variable, i.e. $this-passed_in_array_name. In other words,
it comes in as a string, just the name of the array, I append $this- to
it, but it still isn't getting interpreted the same as if I had written
the call explicitely to $this-memberarray. Does this make any more sense?
jck
Marek Kilimajer wrote:
If I understand you, you need to have a basic class with the
one function and subclass it. Then you can reference the array
as $this-$passed_in_array_name
John Kenyon wrote:
I'm trying to write a function I can plop in a bunch of different
classes without having to modify it.
Basically I have classes like:
class Example
{
var $array1;
var $array2;
var $array3;
etc.
}
and I want to have a function in that class that looks something like
this:
function do_something_to_array($passed_in_array_name)
{
//this is what I've done so far, but which isn't working
$arr = '$this-' . $passed_in_array_name;
// now I want $passed_in_array_name to be evaluated as an array
eval (\$arr = \$arr\;);
// however even if 'array1' is the passed in value $arr is not the
// same as $this-array1
...
}
As a side note there is another aspect of this that confuses me -- if
I do a print_r($arr) before the eval it returns the string
'$this-array1', if I do it after it returns Array (which is what it
seems it should do. However, if I then pass $arr to a function that
requires an array as an argument, like array_push, for example, I get
an error that says that function takes an array. Can anyone explain
this to me? The only guess I have is that my eval function is turning it
into a string which reads as Array instead of either a String object
or the
value of the string.
More important though is the first problem of generically
accesing a member variable based on the passed in name of the
variable. In other words I want to be able to choose which array I
operate on by passing in the name of that array.
Any help on this problem is appreciated. I know there must be a way to
do this. Please let me know if I haven't formulated the problem
clearly enough.
jck
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Re: [PHP] generically accessing member variables problem
You can do:
${this-$passed_in_array_name}
not sure right now of the correct syntaxing, I never do that - normally
I'd pass the element key.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
Thank you for replying, but I don't think I've made my problem clear
enough. Let me give it another shot.
What I want is a function that takes the name of an array as a parameter
so that it can be popped into any class that has arrays in it and work
without modification. The problem I am having is in converting the
passed in array name to the form which the class would recognize as its
own member variable, i.e. $this-passed_in_array_name. In other words,
it comes in as a string, just the name of the array, I append $this- to
it, but it still isn't getting interpreted the same as if I had written
the call explicitely to $this-memberarray. Does this make any more sense?
jck
Marek Kilimajer wrote:
If I understand you, you need to have a basic class with the
one function and subclass it. Then you can reference the array
as $this-$passed_in_array_name
John Kenyon wrote:
I'm trying to write a function I can plop in a bunch of different
classes without having to modify it.
Basically I have classes like:
class Example
{
var $array1;
var $array2;
var $array3;
etc.
}
and I want to have a function in that class that looks something like
this:
function do_something_to_array($passed_in_array_name)
{
//this is what I've done so far, but which isn't working
$arr = '$this-' . $passed_in_array_name;
// now I want $passed_in_array_name to be evaluated as an array
eval (\$arr = \$arr\;);
// however even if 'array1' is the passed in value $arr is not the
// same as $this-array1
...
}
As a side note there is another aspect of this that confuses me -- if
I do a print_r($arr) before the eval it returns the string
'$this-array1', if I do it after it returns Array (which is what it
seems it should do. However, if I then pass $arr to a function that
requires an array as an argument, like array_push, for example, I get
an error that says that function takes an array. Can anyone explain
this to me? The only guess I have is that my eval function is turning it
into a string which reads as Array instead of either a String object
or the
value of the string.
More important though is the first problem of generically
accesing a member variable based on the passed in name of the
variable. In other words I want to be able to choose which array I
operate on by passing in the name of that array.
Any help on this problem is appreciated. I know there must be a way to
do this. Please let me know if I haven't formulated the problem
clearly enough.
jck
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Re: [PHP] generically accessing member variables problem
Thanks, that may be what I was looking for.
jck
Maxim Maletsky wrote:
You can do:
${this-$passed_in_array_name}
not sure right now of the correct syntaxing, I never do that - normally
I'd pass the element key.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
Thank you for replying, but I don't think I've made my problem clear
enough. Let me give it another shot.
What I want is a function that takes the name of an array as a parameter
so that it can be popped into any class that has arrays in it and work
without modification. The problem I am having is in converting the
passed in array name to the form which the class would recognize as its
own member variable, i.e. $this-passed_in_array_name. In other words,
it comes in as a string, just the name of the array, I append $this- to
it, but it still isn't getting interpreted the same as if I had written
the call explicitely to $this-memberarray. Does this make any more sense?
jck
Marek Kilimajer wrote:
If I understand you, you need to have a basic class with the
one function and subclass it. Then you can reference the array
as $this-$passed_in_array_name
John Kenyon wrote:
I'm trying to write a function I can plop in a bunch of different
classes without having to modify it.
Basically I have classes like:
class Example
{
var $array1;
var $array2;
var $array3;
etc.
}
and I want to have a function in that class that looks something like
this:
function do_something_to_array($passed_in_array_name)
{
//this is what I've done so far, but which isn't working
$arr = '$this-' . $passed_in_array_name;
// now I want $passed_in_array_name to be evaluated as an array
eval (\$arr = \$arr\;);
// however even if 'array1' is the passed in value $arr is not the
// same as $this-array1
...
}
As a side note there is another aspect of this that confuses me -- if
I do a print_r($arr) before the eval it returns the string
'$this-array1', if I do it after it returns Array (which is what it
seems it should do. However, if I then pass $arr to a function that
requires an array as an argument, like array_push, for example, I get
an error that says that function takes an array. Can anyone explain
this to me? The only guess I have is that my eval function is turning it
into a string which reads as Array instead of either a String object
or the
value of the string.
More important though is the first problem of generically
accesing a member variable based on the passed in name of the
variable. In other words I want to be able to choose which array I
operate on by passing in the name of that array.
Any help on this problem is appreciated. I know there must be a way to
do this. Please let me know if I haven't formulated the problem
clearly enough.
jck
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Re: [PHP] generically accessing member variables problem
Tom Rogers [EMAIL PROTECTED] wrote... :
Amazing what you learn on this list :)
This works:
class Example
{
var $array1 = array();
var $array2 = array();
var $array3 = array();
function add2array($array_name,$val){
$this-{$array_name}[] = $val;
}
}
$t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
echo 'pre';
print_r($t);
echo '/pre';
Yet, this is not a such elegant way doing it. It can be helpful in a lot
of cases, but most often, element key is enough. Try rethinking your
logic:
class Example {
var $array = array();
function add2array($element_name, $val){
$this-$array[$element_name] = $val;
}
}
$t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
echo 'pre';
print_r($t);
echo '/pre';
Cleaner and more scalable, no?
--
Maxim Maletsky
[EMAIL PROTECTED]
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Re: [PHP] generically accessing member variables problem
Tom Rogers [EMAIL PROTECTED] wrote... :
Hi,
Thursday, November 7, 2002, 3:45:34 AM, you wrote:
MM Yet, this is not a such elegant way doing it. It can be helpful in a lot
MM of cases, but most often, element key is enough. Try rethinking your
MM logic:
MM class Example {
MM var $array = array();
MM function add2array($element_name, $val){
MM $this-$array[$element_name] = $val;
MM }
MM }
MM $t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
MM echo 'pre';
MM print_r($t);
MM echo '/pre';
MM Cleaner and more scalable, no?
Yes and to fit the original 3 seperate arrays it would be
function add2array($element_name, $val){
$this-$array[$element_name][] = $val;
}
No, because you pass it the name and data. This way every name will
become element's name containing the relevant data. Your way just makes
it an associative array without a way of directly accessing it.
--
Maxim Maletsky
[EMAIL PROTECTED]
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Re: [PHP] generically accessing member variables problem
See below:
MM class Example {
MM var $array = array();
MM function add2array($element_name, $val){
MM $this-$array[$element_name] = $val;
MM }
MM }
MM $t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
MM echo 'pre';
MM print_r($t);
MM echo '/pre';
MM Cleaner and more scalable, no?
Yes and to fit the original 3 seperate arrays it would be
function add2array($element_name, $val){
$this-$array[$element_name][] = $val;
}
No, because you pass it the name and data. This way every name will
become element's name containing the relevant data. Your way just makes
it an associative array without a way of directly accessing it.
--
Maxim Maletsky
[EMAIL PROTECTED]
But my problem is that I have several arrays already and I want to be
able to act on a specific array depending on the name I pass in. I don't
see how your solution solves that issue.
jck
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Re: [PHP] generically accessing member variables problem
You pass it the name of the element, and whatever the data inside. You
do not need to add other sub-elements to it automatically, as you would
need to be searching through the elements later for the right data.
Whatever your need is - it's a good idea using arrays, and add other
arrays into it. But, it is a bad idea cloning variables and auto-assign
array's elements when you know that you will need that specific piece
you store alone.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
See below:
MM class Example {
MM var $array = array();
MM function add2array($element_name, $val){
MM $this-$array[$element_name] = $val;
MM }
MM }
MM $t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
MM echo 'pre';
MM print_r($t);
MM echo '/pre';
MM Cleaner and more scalable, no?
Yes and to fit the original 3 seperate arrays it would be
function add2array($element_name, $val){
$this-$array[$element_name][] = $val;
}
No, because you pass it the name and data. This way every name will
become element's name containing the relevant data. Your way just makes
it an associative array without a way of directly accessing it.
--
Maxim Maletsky
[EMAIL PROTECTED]
But my problem is that I have several arrays already and I want to be
able to act on a specific array depending on the name I pass in. I don't
see how your solution solves that issue.
jck
--
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Re: [PHP] generically accessing member variables problem
I am not really sure I understand what you are saying here, and I would
like to. Let me first say that I think the syntax you came up with
earlier will solve my immediate problem, but if I could design this in a
better way I'd like to know. Let me give you a few more details:
I have a large class that contains multiple instances of various
different classes, in turn, each of these instances could contain
multiple instances of other classes. A big tree. In order to keep track
of the various instances of the classes I use arrays, so each class that
contains instances of other classes keeps like classes within an array.
Sometimes a class has multiple arrays, each holding instances of a
different type of class. Each of these classes is being used to generate
html forms and I want to have a way to have the user check a checkbox
and remove a particular instance of a class. I want to have one function
that I can plop into each class (in some cases it may be possible to
have children inherit the function from a parent class) and which will
delete the correct instance of the correct class by passing in the name
of the array the instance is held in and its index in that array.
I hope this provides you with a little more context and if your advice
still pertains, please explain it if you would.
jck
Maxim Maletsky wrote:
You pass it the name of the element, and whatever the data inside. You
do not need to add other sub-elements to it automatically, as you would
need to be searching through the elements later for the right data.
Whatever your need is - it's a good idea using arrays, and add other
arrays into it. But, it is a bad idea cloning variables and auto-assign
array's elements when you know that you will need that specific piece
you store alone.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
See below:
MM class Example {
MM var $array = array();
MM function add2array($element_name, $val){
MM $this-$array[$element_name] = $val;
MM }
MM }
MM $t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
MM echo 'pre';
MM print_r($t);
MM echo '/pre';
MM Cleaner and more scalable, no?
Yes and to fit the original 3 seperate arrays it would be
function add2array($element_name, $val){
$this-$array[$element_name][] = $val;
}
No, because you pass it the name and data. This way every name will
become element's name containing the relevant data. Your way just makes
it an associative array without a way of directly accessing it.
--
Maxim Maletsky
[EMAIL PROTECTED]
But my problem is that I have several arrays already and I want to be
able to act on a specific array depending on the name I pass in. I
don't see how your solution solves that issue.
jck
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Re: [PHP] generically accessing member variables problem
Well, if, say, one class has this function:
function inherit($class_name, $pointer) {
$this-objects[$class_name] = $pointer;
}
then you end up knowing that, whenever you need to access an instance
for a class, you can use $this-objects['that_class']-that_array.
What I picked on, was that you were assigning keys automatically with
($array[] = ...) and that makes it impossible pointing to the right
element directly without having to loop the whole array, which is an
overkill.
The rest of your logic is pretty complex but doable. As long as you plan
off well the complete OOD for that.
So, my conclusion is: It is OK storing all objects in one single array,
but name then the way you can find them later. If you have multiple
instances of the same class, use numeric keys but assign them under a
certain logic - not automatically, so you can find/use/destroy them at
any point.
can't give you more info here as that is all I know of it. Check out the
CVs tree for ZoomStats - www.zoomstats.org, it is a 100% OOP PHP app and
can give you some hints.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
I am not really sure I understand what you are saying here, and I would
like to. Let me first say that I think the syntax you came up with
earlier will solve my immediate problem, but if I could design this in a
better way I'd like to know. Let me give you a few more details:
I have a large class that contains multiple instances of various
different classes, in turn, each of these instances could contain
multiple instances of other classes. A big tree. In order to keep track
of the various instances of the classes I use arrays, so each class that
contains instances of other classes keeps like classes within an array.
Sometimes a class has multiple arrays, each holding instances of a
different type of class. Each of these classes is being used to generate
html forms and I want to have a way to have the user check a checkbox
and remove a particular instance of a class. I want to have one function
that I can plop into each class (in some cases it may be possible to
have children inherit the function from a parent class) and which will
delete the correct instance of the correct class by passing in the name
of the array the instance is held in and its index in that array.
I hope this provides you with a little more context and if your advice
still pertains, please explain it if you would.
jck
Maxim Maletsky wrote:
You pass it the name of the element, and whatever the data inside. You
do not need to add other sub-elements to it automatically, as you would
need to be searching through the elements later for the right data.
Whatever your need is - it's a good idea using arrays, and add other
arrays into it. But, it is a bad idea cloning variables and auto-assign
array's elements when you know that you will need that specific piece
you store alone.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
See below:
MM class Example {
MM var $array = array();
MM function add2array($element_name, $val){
MM $this-$array[$element_name] = $val;
MM }
MM }
MM $t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
MM echo 'pre';
MM print_r($t);
MM echo '/pre';
MM Cleaner and more scalable, no?
Yes and to fit the original 3 seperate arrays it would be
function add2array($element_name, $val){
$this-$array[$element_name][] = $val;
}
No, because you pass it the name and data. This way every name will
become element's name containing the relevant data. Your way just makes
it an associative array without a way of directly accessing it.
--
Maxim Maletsky
[EMAIL PROTECTED]
But my problem is that I have several arrays already and I want to be
able to act on a specific array depending on the name I pass in. I
don't see how your solution solves that issue.
jck
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Re: [PHP] generically accessing member variables problem
Ok. I think I got it. Now I have to look at my code again to see if I
can implement it.
Thanks for your time.
jck
Maxim Maletsky wrote:
Well, if, say, one class has this function:
function inherit($class_name, $pointer) {
$this-objects[$class_name] = $pointer;
}
then you end up knowing that, whenever you need to access an instance
for a class, you can use $this-objects['that_class']-that_array.
What I picked on, was that you were assigning keys automatically with
($array[] = ...) and that makes it impossible pointing to the right
element directly without having to loop the whole array, which is an
overkill.
The rest of your logic is pretty complex but doable. As long as you plan
off well the complete OOD for that.
So, my conclusion is: It is OK storing all objects in one single array,
but name then the way you can find them later. If you have multiple
instances of the same class, use numeric keys but assign them under a
certain logic - not automatically, so you can find/use/destroy them at
any point.
can't give you more info here as that is all I know of it. Check out the
CVs tree for ZoomStats - www.zoomstats.org, it is a 100% OOP PHP app and
can give you some hints.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
I am not really sure I understand what you are saying here, and I would
like to. Let me first say that I think the syntax you came up with
earlier will solve my immediate problem, but if I could design this in a
better way I'd like to know. Let me give you a few more details:
I have a large class that contains multiple instances of various
different classes, in turn, each of these instances could contain
multiple instances of other classes. A big tree. In order to keep track
of the various instances of the classes I use arrays, so each class that
contains instances of other classes keeps like classes within an array.
Sometimes a class has multiple arrays, each holding instances of a
different type of class. Each of these classes is being used to generate
html forms and I want to have a way to have the user check a checkbox
and remove a particular instance of a class. I want to have one function
that I can plop into each class (in some cases it may be possible to
have children inherit the function from a parent class) and which will
delete the correct instance of the correct class by passing in the name
of the array the instance is held in and its index in that array.
I hope this provides you with a little more context and if your advice
still pertains, please explain it if you would.
jck
Maxim Maletsky wrote:
You pass it the name of the element, and whatever the data inside. You
do not need to add other sub-elements to it automatically, as you would
need to be searching through the elements later for the right data.
Whatever your need is - it's a good idea using arrays, and add other
arrays into it. But, it is a bad idea cloning variables and auto-assign
array's elements when you know that you will need that specific piece
you store alone.
--
Maxim Maletsky
[EMAIL PROTECTED]
John Kenyon [EMAIL PROTECTED] wrote... :
See below:
MM class Example {
MM var $array = array();
MM function add2array($element_name, $val){
MM $this-$array[$element_name] = $val;
MM }
MM }
MM $t = new Example();
$t-add2array('array1',25);
$t-add2array('array2',26);
$t-add2array('array3',Hello);
MM echo 'pre';
MM print_r($t);
MM echo '/pre';
MM Cleaner and more scalable, no?
Yes and to fit the original 3 seperate arrays it would be
function add2array($element_name, $val){
$this-$array[$element_name][] = $val;
}
No, because you pass it the name and data. This way every name will
become element's name containing the relevant data. Your way just makes
it an associative array without a way of directly accessing it.
--
Maxim Maletsky
[EMAIL PROTECTED]
But my problem is that I have several arrays already and I want to be
able to act on a specific array depending on the name I pass in. I
don't see how your solution solves that issue.
jck
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