Re: [PHP] move_uploaded_file() does not return any value or warning

[Simon J Welsh]

On 15/10/2011, at 4:01 PM, Partha Chowdhury wrote:

 Then i set a check for the return value of move-uploaded_file.
 if(isset ($move_uploaded_file)):
   echo success;
   else:
   echo error in uploading;
   endif;
 But it does not print anything !

Assuming you did $move_uploaded_file = move_uploaded_file($filename, 
$destination);, then isset($move_uploaded_file) will always be true.

isset() just checks if the variable you past to it is set, not if it has a 
non-false value. You could simply use if(move_uploaded_file($filename, 
$destination)), or if($move_uploaded_file).
---
Simon Welsh
Admin of http://simon.geek.nz/


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Re: [PHP] move_uploaded_file() does not return any value or warning

[Partha Chowdhury]

On 15/10/11 08:35 AM, Simon J Welsh wrote:
Assuming you did $move_uploaded_file = move_uploaded_file($filename, 
$destination);, then isset($move_uploaded_file) will always be true. 
isset() just checks if the variable you past to it is set, not if it 
has a non-false value. You could simply use 
if(move_uploaded_file($filename, $destination)), or 
if($move_uploaded_file). 
My apologies - i forgot to include the $move_uploaded_file = 
move_uploaded_file($filename, $destination); line.


I saw in the manual that isset() isset --- Determine if a variable is 
set and is not NULL and thought if move_uploaded_file() returns false, 
the error checking will be triggered.But now i see the sample code in 
the manual and stand corrected.


So what was happening that $move_uploaded_file was set but empty.My 
understanding of isset() was wrong.


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