This really isn't a PHP question at all. Anyway, you just need to give nicknames to multiple instances of the same table (here I use e1 and e2). Something like...
select order_id, e1.last_name, e2.last_name from tools.orders, hr.emp_master e1, hr.emp_master e2 where orders.emp_id=e1.emp_id and orders.approved_by=e2.emp_id; miguel On Thu, 9 May 2002, Dan Vande More wrote: > Good evening all, > I have a strange situation which I cannot think myself out of. To make > it simple my db looks like this > (hr db, emp_master table) > +--------+---------------+ > | emp_id | last_name | > +--------+---------------+ > | 1 | smith | > | 3 | wesson | > | 4 | doe | > | 6 | clinton | > | 7 | bush | > +--------+---------------+ > (tools db, orders table) > +--------+---------+---------+ > | order_id | emp_id |approved_by | > +--------+---------+---------+ > | 1 | 1 | 6 | > | 2 | 4 | 7 | > | 3 | 3 | 4 | > | 4 | 7 | 3 | > | 5 | 6 | 1 | > +--------+---------+---------+ > I want my query results to be similiar to this: > if I'm selecting all, this is what I want: > 1 smith clinton > 2 doe bush > 3 wesson doe > 4 bush wesson > 5 clinton smith > It seems so easy, but I've tried hard and cannot get it to work I've > been going along the lines (changed several times) of > Select tools.orders.order_id, hr.emp_master.last_name as ordered_by, > hr.emp_master.last_name as approved_by from tools.orders, hr.emp_master > where ((tools.orders.emp_id=hr.emp_master.emp_id) and > (tools.orders.approved_by=hr.emp_master.emp_id)) > > (I hope I wrote that right, it was freehand, not in db) > Thank you for any direction you can give me! > Dam > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
