Micah Montoy wrote:
//get category info
$result = mssql_query(SELECT cat_id, cat_name FROM category WHERE cat_id =
'$cat_name');
$catID = mssql_result($result,0,cat_id); //line 32
$catName = mssql_result($result,0,cat_name); //line 33
I'm getting the error:
Warning: mssql_result(): Bad row
Micah,
Echo your SELECT statement to make certain it reads the way it should.
Test for number of rows returned, or an error - $result probably contains
nothing, that is it's not pointing to an array.
Miles
At 01:23 PM 7/7/2003 -0600, Micah Montoy wrote:
Anyone see what is wrong with this?
Well, I redid the code a bit but it is still blowing up with the same error
message. I also did the echo bit and it returned Resource id #10. What
ever that is. At least I know its returning something. But when I did
mssql_row_nums($result), it returned the value 0. I'm not sure if this is
On Jul 7, 2003, Micah Montoy claimed that:
|Well, I redid the code a bit but it is still blowing up with the same error
|message. I also did the echo bit and it returned Resource id #10. What
|ever that is. At least I know its returning something. But when I did
|mssql_row_nums($result), it
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