Re: [PHP] take date and convert to day of year fixed!

2001-11-14 Thread sundogcurt
OK GOT IT!! $utine = strtotime(26-Nov-2001); $bday=(int)$utine; $utoday = strtotime(); $btoday = (int)$utoday; if((($bday-$btoday) = 1209600 ($bday-$btoday)0)){ print you have . round(($bday-$btoday)/86400). Days till 'blanks' bdaybr; print you are within the two week range.; }else{

RE: [PHP] take date and convert to day of year

2001-11-13 Thread Martin Towell
looking at the manual, getdate() is meant to be passed a unix time stamp, so, you'll need to use strtotime() first thus: $utime = strtotime(30-Nov-1971); $dob = getdate($utime); $dobnum = $dob['yday']; print $dobnum; Notice I changed the format of the date, when I tried using the original

Re: [PHP] take date and convert to day of year

2001-11-13 Thread sundogcurt
I have tried to implement your code Martin, and I do thank you VERY MUCH for the help, but your code seems to have the same trouble as mine, it doesn't matter what date I start with, I end up with 364 as the day of the year, I am on win32 though I don't know if that matters. Here is what I

RE: [PHP] take date and convert to day of year

2001-11-13 Thread Martin Towell
I'm running on WinNT4 w/ PHP 4.0.6 and the code I supplied came back with 333 and for today I get 317 dunno why you're getting 364 anyone, any eye-dears ?? -Original Message- From: sundogcurt [mailto:[EMAIL PROTECTED]] Sent: Wednesday, November 14, 2001 12:14 PM To: GENERAL PHP LIST