ID: 26585 Updated by: [EMAIL PROTECTED] Reported By: jsabater at linuxsilo dot net -Status: Open +Status: Bogus Bug Type: Documentation problem Operating System: Linux PHP Version: 4.3.3 New Comment:
Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php Second parameter of call_user_func_array() is an array of parameters. Thus you have to call: call_user_func_array ('myfunc', array(array ("first", "second", "third"))); to get expected result. Previous Comments: ------------------------------------------------------------------------ [2003-12-10 11:01:43] jsabater at linuxsilo dot net Description: ------------ When calling a defined function like this: call_user_func_array ('myfunc', $myarray); The $myarray array only contains the first value, but not the whole array. For instance: function myfunc ($myarray) { if (is_array($myarray)) print("It's an array"); else print ("It's not an array"); } call_user_func_array ('myfunc', array ("first", "second", "third")); Then you would receive the message "It's not an array". If you print_r the array, then you would only get "first". Then, if you change the call to this: call_user_func_array ('myfunc', array (array ("first", "second", "third"))); It works as expected. So, the documentation available at http://es.php.net/manual/en/function.call-user-func-array.php seems to be wrong. Thanks for your time. Hope this helps. Reproduce code: --------------- function myfunc ($myarray) { if (is_array($myarray)) print("It's an array"); else print ("It's not an array"); } call_user_func_array ('myfunc', array ("first", "second", "third")); Expected result: ---------------- It's an array Actual result: -------------- It's not an array ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=26585&edit=1
