Cool ... I think I am getting a hang of it!
Regards,
Kashyap
On Sat, Nov 23, 2019 at 10:04 AM Alexander Burger
wrote:
> On Sat, Nov 23, 2019 at 09:45:56AM -0800, C K Kashyap wrote:
> > Quick follow up - I altered the tags like this -
> >
> > (class +Item +Entity)
> > (rel ttl (+IdxFold +String))
On Sat, Nov 23, 2019 at 09:45:56AM -0800, C K Kashyap wrote:
> Quick follow up - I altered the tags like this -
>
> (class +Item +Entity)
> (rel ttl (+IdxFold +String))
> (rel tgs (+List +Joint) itm (+Tag))
> (rel sts (+IdxFold +String))
>
> (class +Tag +Entity)
> (rel itm (+Joint) tgs (+Item))
>
Got it. sorry I copied from the email.
Quick follow up - I altered the tags like this -
(class +Item +Entity)
(rel ttl (+IdxFold +String))
(rel tgs (+List +Joint) itm (+Tag))
(rel sts (+IdxFold +String))
(class +Tag +Entity)
(rel itm (+Joint) tgs (+Item))
(rel v (+Ref +Link) NIL +TagVal)
On Sat, Nov 23, 2019 at 09:10:26AM -0800, C K Kashyap wrote:
> Okay ... just to clarify. (collect 'nm '+Tag "BLUE" NIL T 'itm) is the
> recommended way to get to all items for a given Tag.
Well, yes, but this is the previous version which I wrote in a
wrong way.
To get all blue ones: (collect 'n
Thanks Alex/Beneroth,
Okay ... just to clarify. (collect 'nm '+Tag "BLUE" NIL T 'itm) is the
recommended way to get to all items for a given Tag.
I should perhaps use an indirection to +Tag class so that I do not repeat
it every time.
After some thinking it seems that perhaps I could just go with
On Sat, Nov 23, 2019 at 05:11:15PM +0100, andr...@itship.ch wrote:
> +Idx is for +String, actually a special variant of the general
> non-unique index +Ref.
Correct, makes sense only for strings, as it indexes substrings.
> Now I'm currently unsure if +Ref and +Joint can be combined... might be
Hi Kashyap
Try: (rel tgs (+List +Ref +Joint) NIL itm (+Tag))
+Idx is for +String, actually a special variant of the general
non-unique index +Ref.
Be aware that the relation classes may have parameters - in same order
as the prefix classes:
(rel ( ... )
...
)
Now I'm currently unsure if +Ref
On Sat, Nov 23, 2019 at 07:49:43AM -0800, C K Kashyap wrote:
> How can I add +Idx to tgs? That should be possible right?
No, it makes no sense to add an index to a +Joint. Because the object *is*
already reachable via the joint's back link.
What *does* make sense is (+Ref +Link), which is equival
Thanks Alex,
How can I add +Idx to tgs? That should be possible right?
When I add +Idx to tgs, I get "tgs -- No Link" error.
Regards,
Kashyap
On Fri, Nov 22, 2019 at 11:07 PM Alexander Burger
wrote:
> Hi Kashyap,
>
> > (collect 'tgs '+Item (db 'nm '+Tag "BLUE")) does not seem to work for
> me -
Hi Kashyap,
> (collect 'tgs '+Item (db 'nm '+Tag "BLUE")) does not seem to work for me -
Sorry, my fault! I did not test.
> returns NIL. For that matter, even (collect 'tgs '+Item) returns NIL. I
> wonder if its because 'tgs does not have +Idx in the relation
>
> (class +Item +Entity)
> (rel t
No problem Alex,
(collect 'tgs '+Item (db 'nm '+Tag "BLUE")) does not seem to work for me -
returns NIL. For that matter, even (collect 'tgs '+Item) returns NIL. I
wonder if its because 'tgs does not have +Idx in the relation
(class +Item +Entity)
(rel ttl (+IdxFold +String))
(rel tgs (+List +J
Hi Kashyap,
sorry, I was busy! I did not find the time to install and deeply check all your
code.
> 1. Query all open items that have the given tag
>> I think I have a workaround for my question 1 :) - if I use the status as
>> an inline relation instead of a link that is.
I think it makes no
Okay - I've got the answer to the second question as well. I am not sure of
the efficiency though - I essentially collect all items that have the tag
RED and then collect all the items that have the BLUE and then do "sect" on
the output lists. Is this reasonable?
(setq L1 (mapcar '( (I) (get I 'i
Hi Alex,
I think I have a workaround for my question 1 :) - if I use the status as
an inline relation instead of a link that is. I can use use "filter" in the
select to get only items of a given state. I was wondering if there is a
way to filter based on a Link relation though. My question 2 is sti
Hi Alex,
I have a couple of follow up Pilog questions.I've been doing some trial and
error and I don't see it converging :)
I have written a statndalone script for this so that you can easily tell me
how to do it in it. In the script below, the entity relation defines three
types - Item, Status an
Thanks Alex,
The concatenation of multiple collects is just what I need :)
Regards,
Kashyap
On Tue, Nov 5, 2019 at 4:59 AM Alexander Burger wrote:
> Hi Kashyap,
>
> > My ER model looks like this -
> > (class +Task +Entity)
> > (rel ttl (+IdxFold +String))
> > ...
> > (rel upds (+List +Joint) tsk
Hi Kashyap,
> My ER model looks like this -
> (class +Task +Entity)
> (rel ttl (+IdxFold +String))
> ...
> (rel upds (+List +Joint) tsk (+Update))
> ...
> (class +Update +Entity)
> (rel tsk (+Joint) upds (+Task) )
> (rel dsc (+Sn +IdxFold +String))
> ...
> How can I select all the Tasks that have
Hi,
My ER model looks like this -
(class +Task +Entity)
(rel nr (+Need +Key +Number))
(rel ttl (+IdxFold +String))
(rel sts (+Sn +IdxFold +String))
(rel tgs (+Sn +IdxFold +String))
(rel dt (+Need +Ref +Date))
(rel upds (+List +Joint) tsk (+Update))
(dm url> (Tab)
(and (list "app/tsk.l"
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