Hi Alex,
Thanks for your reply.
> On 14. nov. 2014, at 17.37, Alexander Burger <a...@software-lab.de> wrote:
>
> Hi Jon,
>
>> Is it possible to write a 'match' expression that will recognize
>> (Java) strings like these two?
>>
>> @foo("bar")
>> whitespace@someother("text")
>
> Usually 'match' is not the optimal way to operate on strings. What is
> the situation where you need this?
>
I’m just scanning .java files in a big project, trying to spot "text" literals
that should have been coded for localization, and the literals in Java
annotations of the form @foo("bar") are ones that I just want to skip.
Efficiency is not a big thing here. I will probably do as you suggest below,
checking for the @ manually.
/Jon
> If you parse this from a file or stream, it is usually easier and more
> efficient to use 'from', 'till' and/or 'echo', because it works directly
> on the input data without building s-expressions first.
>
>
>> I don’t know how to escape the @ so that it will not be handled as a
>> wildcard symbol.
>
> 'match' doesn't support an escape mechanism. You can check for the "@"
> manually:
>
> (let Str "@foo(\"bar\")"
> (use (@A @X @Z)
> (and
> (match '(@A "(" @X ")" @Z) (chop Str))
> (member "@" @A)
> ... do something ...
>
>> The "whitespace" in the second line doesn’t necessarily have to be
>> whitespace. The important thing is that the @ isn’t always in pos. 1.
>
> So this can be handled with the 'member' call above.
>
>
> Operating on the characters is also possible in many ways, e.g. with
> 'split':
>
> (let L (split (chop "whitespace@someother(\"text\")") "@" "(" ")")
> ... operate on the fragments with list functions ...
> ("w" "h" "i" "t" "e" "s" "p" "a" "c" "e")
> ("s" "o" "m" "e" "o" "t" "h" "e" "r")
> ("\"" "t" "e" "x" "t" "\"")
>
> ♪♫ Alex
> --
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