Great, thanks!
On 23 Dec 2015, at 14:29, Raul Miller wrote:
> Two reasons.
>
> One is that by default regex assumes utf8 and a. is not utf8. To
> disable that, you need to go:
> rxutf8 0
>
> The other is that the regex implementation we are using assumes C
> strings, which are null terminated. S
Two reasons.
One is that by default regex assumes utf8 and a. is not utf8. To
disable that, you need to go:
rxutf8 0
The other is that the regex implementation we are using assumes C
strings, which are null terminated. So you need to get rid of any
nulls if you want regex to go past them.
Why doesn't regex work on binary?
e.g.
load'regex'
'a' rxmatch a.
_1 0
'a' rxmatch AlphaNum_j_
26 1
--
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I didn't want to try to analyze this problem, because the question will
arise of when to stop protecting yourself and go for the kill (also the
question of what part 2 will bring). I just coded a solution that
checks all the possibilities. I can have high confidence that it will
give the righ
instead of solving this I made tools to interactively test the choice of
spells. These are hard coded to my boss damage of 8 and boss hp of 55.
mana =: +/@:{~
turnskill =: (6 %~ 55 - 4 2 0 +/@:{~ 3 4 -.~ ]) turnsdie =: 9 %~ 50 - 0 _2 0
_21 0 +/@:{~ ] turnsdie1 =: 8 %~ 50 - 0 _2 0 _21 0 +/
±1 or ±½ of course :)
Sorry didn't read all, just saw that -n/2 ... 0 ... n/2.
For odd n it's i:<.-:n
i:<.-:5
_2 _1 0 1 2
On Tue, Dec 22, 2015 at 8:20 PM, Moon S wrote:
> > NB. Creat a rotation vector from -n/2 ... 0 ... n/2
>
> Try i: -: y
>
> On Tue, Dec 22, 2015 at 7:50 PM, Richard Donova
> NB. Creat a rotation vector from -n/2 ... 0 ... n/2
Try i: -: y
On Tue, Dec 22, 2015 at 7:50 PM, Richard Donovan
wrote:
> Thanks Thomas, works very well!
>
> > From: tmcguir...@gmail.com
> > Date: Tue, 22 Dec 2015 12:14:31 -0500
> > To: programm...@jsoftware.com
> > Subject: Re: [Jprogramming
Thanks Thomas, works very well!
> From: tmcguir...@gmail.com
> Date: Tue, 22 Dec 2015 12:14:31 -0500
> To: programm...@jsoftware.com
> Subject: Re: [Jprogramming] Magic squares
>
> I haven't tried this in a while but here is one method from an APL book
> transcribed into J
>
> NB. Magic Squares
I haven't tried this in a while but here is one method from an APL book
transcribed into J
NB. Magic Squares the APL/J way
NB. From APL An Interactive Approach by Gilman and Rose
NB.
NB. Problem 19 page 177
NB.
NB. A magic square of order n made up of the integers from
NB. 1 through n.
NB.
NB.
Is there a J routine to construct magic squares of side n?
Thanks in advance.
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For information about J forums see http://www.jsoftware.com/forums.htm
Another remark,
I just ran the (original) algorithm again, for 20 cities, 100 chromosomes, and
modifying distances so 0,1,2,...,18,19 is the minimum path, for 500 iterations.
the "minimal" path found was
18 19 1 0 16 5 6 13 14 15 10 9 8 17 12 11 4 2 3 7
which is not too bad, all things conside
Thanks, Raul. It's a good point. This hasn't been validated at all. I suppose
the lazy way to validate would be to force a single path to be minimal:
modifydistance =: 3 : 0
'from to distance' =. y
if. to = >: from do.
distance =. 1
elseif. distance < 10 do.
distance =. 10
end.
from, to, distanc
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