Ah that makes sense. Thank you! Slowly getting it…
Appreciate all the help and patience.
> On Jan 16, 2022, at 8:58 PM, Hauke Rehr wrote:
>
> No, u&v works differently:
>
> a silly example:
> - 4
> _4
> - 5
> _5
> NB. these all do the same:
> _4 + _5
> _9
> (- 4) + (- 5)
> _9
> 4 +&
No, u&v works differently:
a silly example:
- 4
_4
- 5
_5
NB. these all do the same:
_4 + _5
_9
(- 4) + (- 5)
_9
4 +&- 5
_9
So dyadic x u&v y applies v monadicly to both x and y,
u then applies dyadicly to (v x) and (v y)
x u&v y ←→ (v x) u (v y)
eg pythagoras
%: 3 +&*: 4
What I don’t quite understand was the expansion of
-.&;:&’-‘ y
to
y (-.&;:) ‘-‘
and then
(;: y) -. (;: ‘-‘)
So I was thinking the -.&;: is a hook.
Complete newbie, so apologies.
> On Jan 16, 2022, at 8:46 PM, Hauke Rehr wrote:
>
> I don’t quite understand.
> LHS is just the result of applyi
I don’t quite understand.
LHS is just the result of applying ;: to the value 'start-A'.
Am 17.01.22 um 05:45 schrieb P Padilcdx:
That helps. What rule applies for making the LHS? Is it a hook?
Thank You!!
On Jan 16, 2022, at 8:09 PM, Hauke Rehr wrote:
Maybe I should elaborate on this a bit
That helps. What rule applies for making the LHS? Is it a hook?
Thank You!!
> On Jan 16, 2022, at 8:09 PM, Hauke Rehr wrote:
>
> Maybe I should elaborate on this a bit more:
>
> ] LHS =: ;: 'start-A'
> ┌─┬─┬─┐
> │start│-│A│
> └─┴─┴─┘
> ] RHS =: ;: '-'
> ┌─┐
> │-│
> └─┘
> LHS -. RHS
Maybe I should elaborate on this a bit more:
] LHS =: ;: 'start-A'
┌─┬─┬─┐
│start│-│A│
└─┴─┴─┘
] RHS =: ;: '-'
┌─┐
│-│
└─┘
LHS -. RHS
┌─┬─┐
│start│A│
└─┴─┘
(;: 'start-A') -. (;: '-')
┌─┬─┐
│start│A│
└─┴─┘
Or was the missing link for you somewhere else?
Am 17.01.
First, you apply ;._2
Then it’s just a row-wise -.&;:
eg
'start-A' (-.&;:) '-'
┌─┬─┐
│start│A│
└─┴─┘
Am 17.01.22 um 04:01 schrieb P Padilcdx:
Slowly following the discussion. I confess I’m stuck at how the composition of
-.&;:&’-‘ work in the unpack verb. Try to read the descripti
Slowly following the discussion. I confess I’m stuck at how the composition of
-.&;:&’-‘ work in the unpack verb. Try to read the description of & in NuVoc
and LJ, but i confess to still be clueless as to how J parses it. I
experimented a bit but still perplexed. Can someone point me in the ri
Also pretty crude, in one self-contained routine, "move" .
It was fast and slim enough for its purpose!
$data
137 139
ts'move data'
0.0623268 1.69075e6
timer'move data'
+-+---+
|0.0669937|412|
+-+---+
move =: 3 : 0 NB. long-winded but never mind
_ move y N
On Sun, Jan 16, 2022 at 12:34 PM 'Michael Day' via Programming
wrote:
> OK - your approach is far more efficient than mine! I suspect you did
> what I had in mind, but couldn't quite get that mind to produce.
I should perhaps add..
My first (reverse) pass through the possibilities did not conce
On Sun, Jan 16, 2022 at 12:34 PM 'Michael Day' via Programming
wrote:
> I see that you (Raul) didn't bother with truncating divide towards
> zero. In testing, I fell foul of this,
> and used
> divt =: {{ s * y <.@%~ | x [ s =. * x }}
> ... but I think you're ok in the actual "program" as d
OK - your approach is far more efficient than mine! I suspect you did
what I had in mind, but
couldn't quite get that mind to produce.
I see that you (Raul) didn't bother with truncating divide towards
zero. In testing, I fell foul of this,
and used
divt =: {{ s * y <.@%~ | x [ s =. *
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