Oh? Different inputs for different users. That would explain it.
And it renews my confidence in your usual accuracy, too.
Thanks,
On Sat, Dec 12, 2015 at 10:05 PM, Henry Rich wrote:
> No typo by me; I suspect that users get different inputs.
>
> Henry Rich
> --
>
(B=)
--
No typo by me; I suspect that users get different inputs.
Henry Rich
On 12/12/2015 8:57 PM, Brian Schott wrote:
My attempt fails with a stack error after about power of 25, so I cannot
use it to solve day 10, really.
The code below can be used as follows, but 40 cannot replace 25. I tried M.
b
192
crashes for me at v^:24.
the string gets very long, and you are calling $:@tail 100k times+ on the list
at around 20 iterations. The combination with $: is deadly.
From: Brian Schott
To: Programming forum
Sent: Saturday, December 12, 2015 8:57 PM
Subject:
My attempt fails with a stack error after about power of 25, so I cannot
use it to solve day 10, really.
The code below can be used as follows, but 40 cannot replace 25. I tried M.
but with no effect. Any other recommendations would be appreciated.
NB. v ^: (25) 3 1 1 3 3 2 2 1 1 3
Notice that I
age -
From: Joe Bogner
To: programm...@jsoftware.com
Sent: Thursday, December 10, 2015 9:40 AM
Subject: Re: [Jprogramming] advent 10
Thanks, the fill is needed otherwise it would return the wrong result
if the last number is the same as the first. I don't think my version
is susceptible to t
I did not know fill on |. worked that way. I see it now. neat.
- Original Message -
From: Joe Bogner
To: programm...@jsoftware.com
Sent: Thursday, December 10, 2015 9:40 AM
Subject: Re: [Jprogramming] advent 10
Thanks, the fill is needed otherwise it would return the wrong result
( ((# , {. );. 1)~ 1 , 2 ~:/\ ])^:(40) 1 1 1 3 2 2 2 1 1 3
>
>
>
> - Original Message -
> From: Joe Bogner
> To: programm...@jsoftware.com
> Sent: Thursday, December 10, 2015 8:47 AM
> Subject: Re: [Jprogramming] advent 10
>
> Clever use of the state machine. I enjoy
7 AM
Subject: Re: [Jprogramming] advent 10
Clever use of the state machine. I enjoy seeing those...
Here's mine:
NB. part 1
# (,@((#,{.);.1~ _1&(|.!._) ~: ]))^:40 input=:(1 1 1 3 2 2 2 1 1 3)
252594
NB. part 2
# (,@((#,{.);.1~ _1&(|.!._) ~: ]))^:50 input=:(1 1 1 3 2 2 2 1 1 3)
3579328
Clever use of the state machine. I enjoy seeing those...
Here's mine:
NB. part 1
# (,@((#,{.);.1~ _1&(|.!._) ~: ]))^:40 input=:(1 1 1 3 2 2 2 1 1 3)
252594
NB. part 2
# (,@((#,{.);.1~ _1&(|.!._) ~: ]))^:50 input=:(1 1 1 3 2 2 2 1 1 3)
3579328
To explain, we are going to use cut to split the
Oops, typo in the title - this is for day 10, not 8.
On 10 Dec 2015, at 19:52, Ryan Eckbo wrote:
A previous advent answer got me thinking about state machines, so I
wrote
one for this problem. The extra initial state ruins the natural
mapping
between states and numbers, but I think it's unav
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