Thanks Julian, this is Good Advice™
My cloumsy answer was meant to say
“that’s not the J way”
without actually spelling that out.
But maybe it didn’t come across.
Sometimes the best answer to “how?” is just “don’t!”
Am 27.01.22 um 15:44 schrieb Julian Fondren:
J doesn't have lexical scope so
J doesn't have lexical scope so you're cutting against the grain of the
language to want internal definitions like this. Those internal verbs are also
defined every single time the function is called. The entire APL family of
languages have their own ways of achieving readability and
and the last expression as a "parameterized function" that is adverb instead of
dyad
2 (,^:)~ 1 2 3
1 2 3 1 2 3 1 2 3
On Thursday, January 27, 2022, 09:11:22 a.m. EST, 'Pascal Jasmin' via
Programming wrote:
J has a repeat conjunction ^: A repeat adverb that repeats n times is
Is something like this what you want?
repeat =: 4 : 0
rshowx =. 'This is x inside repeat:',LF, ": x
rshowy =. 'This is y inside repeat:',LF, ": y
f =. [;@#{.@]
d =. y
rshowf =. 'These are x and y for f; and its result:',LF,,LF,.":x
(;;f) d;d
rshowx,LF,rshowy,LF,rshowf
)
3
J has a repeat conjunction ^: A repeat adverb that repeats n times is (^:n)
or to use x instead of n (^:[)
this won't behave as your original function, but produces the square of x
copies of y. ie. each function call changes/expands y such that the next call
is on the larger y
2 ,~@]^:[
I am wondering how to embed definition of `f` inside `repeat`. so I would
call `x repeat d` and inside this function `x f (d;d)` would be called. On
both levels, repeat and f, we have names x and y.And I wonder what are the
techniques to (a) reuse them at both `repeat` and `f` level, (b) separate
1. To debug a sentence, use Dissect.
2. To print expressions during execution, a quick way is
load'printf' NB. just once per session
qprintf'x '
qprintf'x $y '
The last character of the argument is the delimiter between expressions.
Henry Rich
On 1/27/2022 8:23 AM, Pawel Jakubas wrote:
'only x less than 10 is accepted' assert 0
|only x less than 10 is accepted: assert
| 'only x less than 10 is accepted' assert 0
3 (] $~ [ * $@]) 1 2 3
1 2 3 1 2 3 1 2 3
13 'only x less than 10 accepted'"_`(] $~ [ * $@])@.(10 > [) 1 2 3
only x less than 10 accepted
builtin assert
You can box y, repeat it with dyadic #, and then raze the boxes:
3 ([: ; [#<@]) 'hi'
hihihi
3 ([: ; [#<@]) 1 2 3
1 2 3 1 2 3 1 2 3
3 {{ ; x # wrote:
> Dear J enthusiasts,
>
> I am defining `x repeat y` function, that is appending y to itself x times.
>
> And defined something like
One way to get the simple repeat function is this:
] d =: >: i.3
1 2 3
f =: [ ;@# {.@]
1 f d;d
1 2 3
2 f d;d
1 2 3 1 2 3
3 f d;d
1 2 3 1 2 3 1 2 3
If you don’t call f with d;d but simply with d,
then you can just define
f =: ;@#
which I consider an answer to your question 3.
2. you could try
echo 'this'
and
smoutput 'that'
3. look up the definition of dyadic # (and $)
(or just try it)
4. I don’t know exactly which behavior you want
could you give some example in- and output
of the more general function you’re after?
Am 27.01.22 um 14:23 schrieb Pawel Jakubas:
Dear
Dear J enthusiasts,
I am defining `x repeat y` function, that is appending y to itself x times.
And defined something like below (on intention like that to ask a couple of
questions).
f=: 4 : 0
assert (x < 10)
segment=.>0{y
if. (x = 1) do. (>1{y) else. (x-1) f (segment;( (>1{y),segment) )
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