Re: [Jprogramming] rank by a key

2009-11-13 Thread Tirrell, Jordan (Consultant)
:25 PM To: programming@jsoftware.com Subject: Re: [Jprogramming] rank by a key In the following example, collection 0 is 10 30 20 20 and has ranks 3 0 1 1, while collection 1 is 200 100 300 and has ranks 1 2 0. The problem is the extra 0 appended to make them the same size, [...] The usual way

Re: [Jprogramming] rank by a key

2009-11-13 Thread Raul Miller
On Fri, Nov 13, 2009 at 1:10 PM, Tirrell, Jordan (Consultant) key=: 1 1,1 0,1 1,1 0,1 0,0 1,:1 1 data=: 0 1,1 1,0 2,0 2,2 0,0 0,:1 1   key rankbykey1 data 2 1 1 2 0 0 0   key rankbykey2 data 2 1 1 2 0 0 0 I cannot figure out how to use ~: to express this function as Raul Miller suggested,

Re: [Jprogramming] rank by a key

2009-11-13 Thread Tirrell, Jordan (Consultant)
It works great, and in a few seconds less. Thanks! Jordan -Original Message- From: programming-boun...@jsoftware.com [mailto:programming-boun...@jsoftware.com] On Behalf Of Raul Miller Sent: Friday, November 13, 2009 2:34 PM To: Programming forum Subject: Re: [Jprogramming] rank

[Jprogramming] rank by a key

2009-11-10 Thread Tirrell, Jordan (Consultant)
Given a key (in the sense of /.), I'd like to obtain the rank (the i.~\:~ kind, not the kind) of each item within the collection corresponding to its key. My first instinct was to try (i.~\:~)/. but this is not exactly what I want. In the following example, collection 0 is 10 30 20 20 and has

Re: [Jprogramming] rank by a key

2009-11-10 Thread Raul Miller
On Tue, Nov 10, 2009 at 4:23 PM, Tirrell, Jordan (Consultant) jtirr...@thomasnet.com wrote: Given a key (in the sense of /.), I'd like to obtain the rank (the i.~\:~ kind, not the kind) of each item within the collection corresponding to its key. My first instinct was to try (i.~\:~)/. but

Re: [Jprogramming] rank by a key

2009-11-10 Thread neitzel
In the following example, collection 0 is 10 30 20 20 and has ranks 3 0 1 1, while collection 1 is 200 100 300 and has ranks 1 2 0. The problem is the extra 0 appended to make them the same size, [...] The usual way to avoid those extra fills is to box the interim values and to flatten

Re: [Jprogramming] rank by a key

2009-11-10 Thread R.E. Boss
i.~ 8 4 4 4 8 8 8 0 1 1 1 0 0 0 8 4 4 4 8 8 8 (;@(@(i.~\:~)/.) /: i...@[) 10 200 100 300 30 20 20 3 1 2 0 0 1 1 All in all, this is not very different from what you did. Slighltly less boxing/unboxing. Can you measure any difference? or 8 4 4 4 8 8 8 (;@(@(i.~\:~)/.) \: